1) Express the Voltage Sources as a phasor. 2) Find the Impedance values for the given elements. a. Let = b. Let = /c. Let = /132.63 mH 193.42 Β΅F 80.5 β¦ . (β ) V + - **Make sure to convert the Amplitude to the RMS value. 21.21 β2 = 15 β΄ β‘β =2= (2)(60) = 377 /= = (377)(132.6310 β3 )= β¦ = β 1 = β 1 (235)(193.4210 β6 ) = β β¦ = = . β¦ EE301 Exam 2 Review Exam 2 Review
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Exam 2 Review Review Packets...1)Express the Voltage Sources as a phasor. 2)Find the Impedance values for the given elements. a. Let π= πππππππ b. Let π
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1) Express the Voltage Sources as a phasor.
2) Find the Impedance values for the given elements.
a. Let π = ππππ πππ
b. Let π = ππππππ ππ³π³π³π³/ππ
c. Let π = ππππππππ ππ³π³π³π³/ππ
7) When solving Thevenin Equivalent problems there are logical steps that hold true no matter ifthe circuit is DC or AC. Answer the following with True or False.
a. ____ If a Load is shown on the circuit, the first step is to remove the Load.b. ____ The Thevenin Impedance is always the impedance as seen by the Source.c. ____ When solving the Thevenin Impedance, we must βturn offβ the sources by
replacing both current and voltage sources as SHORTS.d. ____ When solving the Thevenin Impedance, we must βturn offβ the sources by
replacing the current source a SHORT and the voltage sources as an OPEN.e. ____ When solving the Thevenin Impedance, we must βturn offβ the sources by
replacing the current source an OPEN and the voltage sources as a SHORT.f. ____ When finding the Thevenin Voltage we use the open terminals were the Thevenin
perspective is.
8) Find the Thevenin Impedance and Voltage external to ZLoad for the circuit below. Draw theThevenin circuit with the Load attached.
9) Is Maximum Power being delivered to the Load and why?
πππΆπΆππ = πππ³π³β
3.2β π6.4 = 3.2 + π6.4
7.15β‘β63.43π = 7.15β‘63.43π
10) The acronym used for Capacitors in AC circuits is βICEβ. Explain what is meant with thisacronym.
Current LEADS Voltage for a capacitive circuit. If we are just analyzing a Capacitorβs current andvoltage relationship we will see the current LEADS the voltage by 900.
This implies the Current Angle (π½π½ππ) equals to π½π½π½π½ + ππππππ.
ππππ
YES!
11) The acronym used for Inductors in AC circuits is βELIβ. Explain what is meant with this acronym.
Voltage LEADS Current for an inductive circuit. If we are just analyzing an Inductorβs current andvoltage relationship we will see the voltage LEADS the current by 900.
The Graph and circuit below are for questions 12 through 15
16) The following circuit is operating at a frequency of π = 500 rad/s.
a. Draw the Power Triangle for the Load and label the Apparent, Real, and ReactivePower. Also include the Complex Power angle.
b. Find the source current (π°π°ππ).
c. Typically we like to reduce the source current. This can be accomplished by connectinga Capacitor in parallel to an Inductive Load. The Capacitor component value (πͺπͺ) isdetermined by choosing a Capacitance Reactive Power (πΈππ) equal to the InductanceReactive Power (πΈπ³π³).
Find the Capacitor component value so all of the Reactive Power at the Load iscancelled. In other words, what component value will correct the power factor tounity?
d. Find the source current (π°π°ππ) when a Capacitor is connected in parallel with the Load.Assume the Capacitance Reactive Power is βππππππ π½π½π½π½π½π½.