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Untitled.notebook January 27, 2017 angles of a parallelogram are equal so ZQPS = 500. Therefore LQPT = 1120 and, as triangle QPT is isosceles, ZPQT = (1800 - 1120) +2 = 340. As PQRS

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Untitled.notebook January 27, 2017 angles of a parallelogram are equal so ZQPS = 500. Therefore LQPT = 1120 and, as triangle QPT is isosceles, ZPQT = (1800 - 1120) +2 = 340. As PQRS

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Page 1: Untitled.notebook January 27, 2017 angles of a parallelogram are equal so ZQPS = 500. Therefore LQPT = 1120 and, as triangle QPT is isosceles, ZPQT = (1800 - 1120) +2 = 340. As PQRS

Untitled.notebook January 27, 2017

Page 2: Untitled.notebook January 27, 2017 angles of a parallelogram are equal so ZQPS = 500. Therefore LQPT = 1120 and, as triangle QPT is isosceles, ZPQT = (1800 - 1120) +2 = 340. As PQRS

Untitled.notebook January 27, 2017

Page 3: Untitled.notebook January 27, 2017 angles of a parallelogram are equal so ZQPS = 500. Therefore LQPT = 1120 and, as triangle QPT is isosceles, ZPQT = (1800 - 1120) +2 = 340. As PQRS

Untitled.notebook January 27, 2017

Page 4: Untitled.notebook January 27, 2017 angles of a parallelogram are equal so ZQPS = 500. Therefore LQPT = 1120 and, as triangle QPT is isosceles, ZPQT = (1800 - 1120) +2 = 340. As PQRS

Untitled.notebook January 27, 2017

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