Burbank, Osage County, Oklahoma
I. Background of the Field II. Primary Recovery: Solution-Gas Drive
III. Secondary Recovery: WaterfloodIV. Enhance Oil Recovery: MIcellar Polymer Flooding
Introduction
Location of Burbank Field on the Map
The burbank field is located principally in Osage County, but with a small extension into Kay
County
Some of the companies involved in Burbank Field
History
Elbridge Ayer Burbank
Ernest Witworth Marland
The Osage Tribe
Reservoir Geology
East Burbank Pool
Fluid and Rock Properties
Solution Gas Drive
Stages of Production
Stage 1
Production while undersaturated
Stage 2
Production while saturated but the free gas is immobile
Stage 3
Production while saturated and the free gas is mobile and the producing gas-oil ratio (GOR) is increasing
Stage 4
Production while saturated and the free gas is mobile and the producing GOR is decreasing
Waterflood
III. Secondary Recovery: Waterflood
A. Reservoir Geology Considerations
• understanding the reservoir rocks • the diagenetic history of the reservoir rocks must be
ascertained• the structure and faulting of the reservoir must be
determined • the water/oil/rock characteristics need to be
understood
B. Waterflooding Considerations
• Oil properties • viscosity and density at reservoir
conditions• the mobility of a fluid is defined as its
endpoint relative permeability divided by its viscosity
THE FORMULA FOR OVERALL WATERFLOOD OIL-RECOVERY EFFICIENCY ER
C. Rationale for Waterflooding• The waterflood performance of this stratified reservoir can
prove reasonably accurate. • Permeability values in this reservoir range from less than 0.1
md to nearly 3 darcys and 90 percent of the permeability capacity is contained in approximately 26 percent of the reservoir volume.
• Nearly 70 percent of the recovery can be achieved at water-cut values greater than 95 percent.
D .Reservoir Data & Criteria Comparison
E. Waterflood Production Facilities• 250-600 psia• Equipped either with staged centrifugal pumps or
multistage pot turbine pump• Water treatment- sodium hexametaphospate
THE OIL PRODUCTION WILL BE GATHERED AND MONITORED AT SEPARATE FACILITIES. THEIR LOCATIONS WILL BE EQUIPPED WITH LACT UNITS AND CONVENTIONAL TANK BATTERIES.
The high productivity indices of most of the
producing wells have permitted wide application of
large-volume, submergible, multi-stage centrifugal
pumps. Individual producing well potentials of 3,000 to
4,000 BFPD are not uncommon and several will be
operated in the 5,000 to 7,000 BFPD range.
OIL RECOVERY
• Ultimate primary and secondary will be 302 bbl/acre-ft which is approximately 40 percent of the OSTOIP
Enhanced Oil Recovery
Micellar Polymer Flooding
A. Screening Criteria for Micellar Polymer Flooding
• API Gravity >20o
• Viscosity <35cp• Composed of light and/or intermediate oils• Oil Saturation >35%• Net Thickness is no critical• Average Permeability of >10md• Depth of >9000ft• Temperature >80oF
B. Reservoir Data & Criteria Comparison
C. Surfactant Design
The proposed surfactant-polymer project will
cover approximately 90 acres, and would
comprise of inverted five-spot patterns of
approximately ten acres each.
Major Concerns and Solutions:
1. High salinity and hardness of the formation
water
2. Fractures
3. Oil-wet nature of rocks
D. Recovery Efficiency
Volumetric Determination of Original Oil in Place
Calculation of N:
N = 7758Aho(1-Sw)/Boi
= 7758(164,816 acre-ft)(0.18)(0.22)/1.050
= 48.2231 MMSTB
Sweep Efficiency
• Vertical Sweep Efficiency
• Areal Sweep Efficiency
Displacement Efficiency
Vertical Sweep Efficiency• Using production data and the Dykstra-
Parsons Chart
Vertical Sweep Efficiency
The Ev value is approximately 0.27.
Areal Sweep Efficiency
Inverted Five-Spot Pattern
Areal Sweep Efficiency
Displacement Efficiency
Displacement Efficiency
Core Data
Calculation of Ed
Ed = (So – Sor)/So
= (1-0.63) / 1
Ed = 0.37
Calculation of Recovery Efficiency
Formula for overall flood oil-recovery efficiency ER
Calculation of ER
ER = EDEIEA
= 0.37 x 0.27 x 1.17
ER = 0.1169 = 11.69%
Volume of Oil that can be further Recovered
NR = NER
Calculation of NR
NR = NER
= 48.2231 x 0.1169
NR = 5.6373 MMSTB
