Map and Compass
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Bearing:anangleindegreesmeasuredclockwisefromanorthreferencelinetoyourdestinationline.
Bearingof90°shownbelow.
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Bearingofappr.315°shownbelow.
Final Exam and Practice Map -provided in class -
Taking Map Bearing in - 3 Steps
• Whatisthebearingfromcenterof“C”inLakeCtocenterof“D”inLakeD?
Step 1 - Intersect two points with side edge of compass with direction of travel arrow pointing towards destination
Step 2 - Rotate compass housing until orienting lines align N-S, with north end of line pointing north. Ignore the magnetic needle!
Step 3 - read the bearing at index line (in line with direction of travel arrow).
• Whatisthebearingfromcenterof“D”inLakeDtocenterof“F”inLakeF?
Step 1 - Intersect two points with side edge of compass with direction of travel arrow pointing towards destination
Step 2 - Rotate compass housing until orienting lines align N-S, with north end of line pointing north. Ignore the magnetic needle!
Step 3 - read the bearing at index line (in line with direction of travel arrow).
index line
Depiction of 340° bearing (always measure clockwise from N).
• Bearingfromcenterof“F”inLakeFtosummitofPeak2= 266°
• BearingfromthesummitofPeak2tocampsite“Z”= 135°
• WhatistheelevationofPeak2? 5700’
• WhatistheelevationofCampsiteX? 3900’
• WhatistheelevationofLakeD? 4700’
• WhatisthenetelevationdifferencebetweenCampsitesYandZ?
CampsiteY=5100’ CampsiteZ=4700’ Netelevationdifference=400’
How many feet of elevation will you gain hiking SE along the trail from campsite Y to the top of Peak 4? How many feet will you lose?
A
Uphill from B to C
B
Downhill along trail from A to B
C
- +
4 8
- 4 x 200 = -800
+ 8 x 200= +1600
Net elevation diff = +800
Elevation of Y = 5100’
Elevation of 4 = 5900’
Net elev. difference = 800
What is the length of trail between Peak 5
and Peak 4?
What is the trail distance between Campsites Y and x?
2.8 miles
• Bearingfromcenterof“C”inLakeCtocenterof“D”inLakeD=62°TRUENORTHBEARING.
• WhatistheMNbearingifdeclinationis15°E?
x
x
62°
15°
47°
MN bearing = 47°
Bearingfromcenterof“D”inLakeDtocenterof“F”inLakeF=342°TN
Declination=15°E
x342°TN
15°
MN bearing = 327°
• WhenPLOTTINGABEARINGthemissingpieceofinformationisthedestinationpoint.
• Weknowourlocationandthebearingvalue.Here’sanexampleplottingproblem:
WhatfeatureliesataTNbearingof70°and1.65milesFROMcampsitex?
Plotting A Bearing
• Acompletedmapandcompassproblemconsistsof3piecesofinformation:
• startingpoint
• destinationpoint• bearing
• WhenTAKINGABEARINGweknowourstartingpointandthedestinationpoint.
• Wecalculatethebearingvalue.Forexample:
Whatisthebearingfromcenterof“C”inLakeCtocenterof“D”inLakeD?
Plotting A Bearing
WhatfeatureliesataTNbearingof70°and1.65milesFROMcampsitex? Step1?
Rotatecompasshousinguntil70°isatthe“readbearingheremarker”.
Intersectsideedgeofcompasswithpointx.SincebearingisFROMxtothefeature,placexnearbackendofcompass
Step2?
Step3RotateENTIRECOMPASSuntilorienteeringlinesinthecompasshousingareparalleltoN-Slinesonthemap.Makesurethattheorienteeringarrowpointsnorth,ANDtheedgeofthecompassintersectspointx.
Step4Usingthescalediagram,measure1.65linearmilesalongtheedgeofapieceofpaper.
Step5Placepieceofpaperwithdistancemarkersalongthesideedge.Thefeaturethatlies1.65milesatabearingof70°frompointxisPeak4.
• Whatfeatureliesatabearingof242°and1.92milesfromthesummitofPeak3?
Peak2
• Whatfeatureliesatabearingof63°and1.68milesfromthe“C”inLakeC?
Peak4
• Whatfeatureliesatabearingof302°and1.61milesfromtheCampsiteX?
Peak2
• Whatfeatureliesatabearingof150°and4.5milesfromtheCampsiteY?
CampsiteZ