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TM-1381 0302.000 0402.000 THE BEAM AND THE BUCKET - A Handbook for the Analysis of Longitudinal Motion - S. Ohnuma January 22, 1986 This handbook is intended primarily for people working in the accelerator control rooms. "Convenience" is the only criterion observed in compiling this note. All materials are available in various sources but not everything is in one place; hence this enterprise. Errors of any sort you find should be promptly commu- nicated to me.
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Page 1: TM-1381 0302.000 0402.000 THE BEAM AND THE BUCKET - A … · 2002. 11. 25. · TM-1381 0302.000 0402.000 THE BEAM AND THE BUCKET - A Handbook for the Analysis of Longitudinal Motion

TM-1381 0302.000 0402.000

THE BEAM AND THE BUCKET

- A Handbook for the Analysis of Longitudinal Motion -

S. Ohnuma

January 22, 1986

This handbook is intended primarily for people working in the

accelerator control rooms. "Convenience" is the only criterion

observed in compiling this note. All materials are available in

various sources but not everything is in one place; hence this

enterprise. Errors of any sort you find should be promptly commu-

nicated to me.

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-l-

List of Frequently Occuring Symbols

+ and E = moc2y = rf phase and energy of a~ particle*

$s and ES = moc2ys = rf phase and energy of the synchronous particle

q 5 @ - +s ; AE -E-ES

Yf = 2nfrf = 2nhfrev (frev = revolution frequency); h = harmonic number':

y : AE/w,-~ = (R/hc)(cp)(Ap/p) ; 2?rR =-machine circumference?

p = particle momentum

Yt = trans

n 5 (l/YE

V = peak rf accelerating voltage (per turn)

ition gamma** 5.446 Booster (design value)

18.7 - 18.75 Main Ring and Tevatron

- l/u:) l **

fs = synchrotron oscillation frequency

A = total bunch length in radians

r = sin(Gs)

($, and o,) = two limiting values of $ for a rf bucket

* At $ = 0, the rf voltage is zero and rising. The convention used for linacs

is different; $I = 0 when the rf voltage is.at its maximum value.

** weak focusing machine Y ' Yt

linac Y < Yt (since yt + m) sector-focused cyclotron ence the name "isochronous") (yt,varies with y)

Y=Y~ (h

*** Below transition n < 0, cos(Q > 0

Above transition n ' 0, cosL$s) < 0 n*cos($s) < 0

Booster Main Ring Tevatron

h= 84 1113 1113

R(m) = 84 1OOOX~ 1000 1000

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-2-

1. Hamiltonian and equations of motion

H(q,y;t) = $Ay2 + BIcos(os+q) + q.sin(o,) - COG)

The last term, COS(I$~), is added to make H = 0 at the origin, q=y=O.

Note: (AP/P) = (hc/R)$ *Y ( 'y is in eV-s, cp is in eV)

A f (hclR)2(n/Es) and B s (eV/2nh) (13

dq/dt = A-y , dy/dt =,BIsin(oS+q) - sin(+s)1

2. Stationary Bucket ( r = sin($s) = 0; os = 0 or n)

bucket area = 16.(B/lAl))i in (q,y) phase space, eV-s (2)

bucket height (=max. y) = k 2*(B/1Al)?i , eV-s (3)

max. Ap/p = i 2.(B/IAI)'(hc/R)$ ( ?a 1

From now on, we consider the case below transition only. Above transition,

all phases should be regarded as (n - $I). Instead of n, we use InI. With

this convention,

two limiting phases of bucket: $1 < $ < $2 ; $I En-l$S 2

3. Moving Bucket ( r.= sin($,) f 0)

bucket area in (q,y) phase space :(stationary bucket area)x a(r)

= 16.(B//A+ x cc(I), eV-s (4)

bucket height E (stationary bucket height)x B(r)

max. y = + 2.(B/lAl+ x E(r), in eV-s (5)

max. Ap/p = t 2*(B/IAl~)'(hc/R)c\x B(r) (5a)

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-3-

a(r) and B(r)

If you need better-than-l% accuracy, see

C. Bovet, et al.; A SELECTION OF FORMULAE AND DATA USEFUL FOR THE DESIGN OF A.G. SYNCHROTRONS,

CERN/MPS-SI/Int. DL/70/4, 23 April, 1970

06 l-6 0.3 a(r) = (l.-r)(1.- 1.1695r + 1.3865r2)

.3 < r Q .6 a(r) = (l.-r)(l.- 0.8644r + 0.3831r2)

.6 6 r 6 .a5 a(r) = (l.-r)(l.- 0.632Gr - o.odior2)

I-= .86 .a7 .88 .89 .9D .92 .94 .96 .98

dr)= .0627 .0570 .0515 .0461 .0409 .0308 .0214 .0129 .00539

06 l-6 .65 B(r) = 1. - 0.7703r - 0.1227r2

.65~,< I' 4 .85 6(r) = 1. - 0.694Or - 0.2406r2

r= .86 .a7 .88 .89 .90 .92 .94 .96 .98 6(r)= .223 .211 .199 .186 .173. .146 .lla .0869 .0517

I$, in degrees (Remember a2 = pi - es)

06 rd .45 $, = qs ( .25.809 - 3.351r t 7.050r2) - 180’

.4% r 4 .9 c$, = J;as ( 25.761 - 1.784r + 3.717r2) - 180'

Note! c$~ in degrees! r = sin(os)

.9 6 r I$, = 2.Q; (1. - 0.0657r + o.0677r2) - 90’

(Of course, for r= 1, $, = $s = 42 = 90')

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-4-l

4. Beam in a Bucket; Stationary

Beam Area = (Stationary Bucket Area)x(&)A2(l. - & A2)

A s total bunch length in radians 4 4 radians

For large A, see Figs. 1 & 4.

(6)

Beam Height = (Stationary Bucket Height)x sin(A/4)

This relation is exact for all values of A. (7)

For a<<l, q2 + (IAI/Wy2 = (A/2)2 (8)

max. y =';A (B/IA/P, eV-s (9)

max. Ap/p = *i A(BIIAl)~'(hc/R)$ (9a)

synchrotron oscillation frequency ( r = 0 only!)

fs = (1/2n)(I~/B)+ -J-- (%)K(A)

--- This is exact for any A! (10)

where K(A) is the complete elliptic integral of the first kind,

K(A) = J"'2(1 - m sin26)+ de ; 0 . m = sin2(A/4) (11)

For A<<1 , (2/n)K(A) 1 1 + _?_A? 64 (Remember, A= total bunch length)

so that fs ? (1/2n)(lA/ B)' ( 1. - & A2) (12)

Actually, this relation is surprisingly good up to A ‘L 300'. See Fig. 3.

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- 5 J

5. Beam in a Moving Bucket

For a<<l,

q2 + ( - PI

).y2 = (A/2)2 (13) B COS(~~)

max. y = kk A ( WS) ~1% , eV-s (14)

max. Ap/p = + A (+ )'(hc,'R)& (14a),

For A not too small, use Fig. 1 for area and Fig. 2 for height:

Beam Area s (Stationary Bucket Area)x(&)Jq)x.b2 x(1. - KA) (15)

Beam Height I (Stationary Bucket Height)x$ Jcos($~),x(~. - KH) (16)

(A in radians!)

synchrotron oscillation frequency

fS E (1/2n)IIAI B COS($,))~ (1. - K A2) --- A in radians! (17)

The parameter K is shown in Fig. 3. We have already stated that

K = l/64 for r = 0, see Eq. (12).

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6. Beam in a Moving Bucket: Alternative Way __-__ -_-

Some people may prefer this alternative way of estimating the beam

area and the beam height. The reference is the corresponding moving

bucket (instead of the stationary bucket used in Figs. 1 and 2).

Beam Area s (Moving Bucket Area)x( :EEti ~~$t'~$$h)2x CA ('8)

Beam Height : (Moving Bucket Height)x(ii:ii $&l~r$$h)~CH (19)

CA : Fig. 4 CH: Fig. 5

(This alternative has been suggested to me by Jim Crisp.)

7. Matching from oneringto the next __-_

In transfering the bunch from Ring 1 to Ring 2, we should have

v cos(tJs)

I,

v COS(~J =

hn 1 hn 2 (20)

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-7-

Appendix I : Longitudinal Phase Space and the Particle Distribution*

There is no unique choice of two canonical~variables to describe the

phase space. The most commonly used ones are:

1. q=+- Gs and y = (E - Es)/wrf

The unit of phase space area is then eV-s which is also the

unit for y since q is dimensionless.

2. q and (Ap/m,c) = (yB)(Ap/p)

All quantities are dimensionless. CERN people favored this

but they may prefere 1. above now.

The phase space areas defined in two ways are of course related to each other

but the relation is dependent on machine parameters,

R(m) area in (q, y) = 3.13 eV-s x-h-- x area in q, (yB)(Ap/p)

= 2.81 eV-5 x(area)2 for Booster;Main Ring, Tevatron

For electron beams, people use bi-Gaussian distribution in two canonical

variables (q,y), or more generally,

p(q,y) = e -kH(q>y)

with the Hamiltonian H(q,y)'of the motion. For proton bunches, it is more

common to use finite distributions. One such distribution called "elliptic"

is dq .Y) y/m

where y = yB(q) defines the boundary of the finite bunch in (q,y) space.

The local current density is

* This is essentially the same as Appendix B~of EXP-111, November 28, 1983.

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-8-

yB 1(q) a J dy p(qa') a Y;(q)

-yB

An appealing feature of this distribution is discussed in TM-749 in connection

with the longitudinal instabilities with Landau cavities. The simplest

specification of the bunch shape to be used for the distribution is

yB(q) = f (max.y){l - TA$)-2 1' ; A = total bunch length

The normalized (to unity) distribution is

P(q.Y) = &$- m

tY;(d - Y2W “2

where y m

= max.y and the emittance S = nym(A/2).

Appendix II: Higher-Order Effects

On page 1, it is stated that the equation of motion for y is

simply dq/dt = A.y . This is not exact. One should write

dq/dt = -h ( w - ws)

where w is the angular frequency of a particle and os that of the synchronous

particle. If the right-hand-side is expanded in (AE/E) and only the lowest-

order term is retained, we get Ay. Note that A is proportional to n so

that it vanishes at the transition. One must considerlthe next term in the

expansion near the transition where In/ is very small. For this, it is

convenient to use the parameter introduced by Johnsen,'

L(P) = Lo {l + a,(Aplp)(l + "2p 9 }

where L(p) is the path length of a particle with the momentum p and Lo = 2nR.

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-9-

From the definition of transition energy, a, = l/v: where, strictly speaking,

yt is for the synchronous particle. Johnsen pointed out that the proper time

of transition for a particle with momentum p different from p, is

tP =

@=O) -.;So

(;+a,@ 2 P

if the transition for the synchronous particle is at t = 0. The acceleration

rate is assumed to be dEs/dt = moc2+s . The "ideal" machine should have

"2 = -1.5 so that all particles cross the transition at the same time. Since

iAP/p Imax is believed to be around (3%4)x10m3 at transition,

Booster Itplmax = t.04 % .05)msx(l.5+ai),

Main Ring (.6 Q .a)msx(1.5+a2)

If u2 is different from -1.5, one must add a higher-order term in the

Hamiltonian H(q,y;t),

AH = (hc/R)3 F y3& 3

F = ? (8_5_)2 + a2 n

2 Ys 7-2 -- 2

t Yt

Since the higher-order term Is important only near the transition where n= 0,

the last term in F can be dropped.

There is no easy way to calculate a2 for any given machine. One must know

the sextupole field since a2 represents the second-order effect. Even in

the absence of nonlinear field, it is necessary to compute the off-momentum

closed orbit beyond the customary first-order approximation in (Ap/p).

The value of C+ has been calculated by W. W. Lee for the booster with and

without sextupole component.'

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- 10 -

He used the second-order TRANSPORT to find

a2 = 1.63 linear booster,

= 0.843 with the design value of sextupole component"

The calculation has been repeated with the step-by-step numerical integration

of the orbit in linear magnets.and the result is in good agreement with Lee's

value, a2 (numerical integration, linear) = 1.619

The calculation with sextupole field is not so straightforward. There are

indications from various measurements that booster magnets are different from

the designed ones. Furthermore, correction sextupoles may not be entirely

negligible near transition. For these reasons, a2 with sextupole field has

been estimated using an approx,imate relation'

"2 = -1 - 25, - At, (A.11

5, = horizontal chromaticity(CERN style) of the linear machine

= (Av,/v,) 'divided by (Ap/p),

A5 = change in 5 due to sextupole field.

This relation is derived by retaining only the average terms in the Fourier

expansion of relevant quantities. The step-by-step integration of orbit

yields 5, = -1.3683 (Booster, linear)

so that -1 - 25, = 1.737 which should be compared with the exact value 1.619.

The chromaticity of the booster near the transition with the standard setting

of correction sextupole has been measured by C. Hojvat:

5 = 5, + AE = 0.502

so that AC = 1.87. From (A.l),

a2 ^I -1 - 2(-1.3683) - 1.87 = -0.13 .

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- 11 -

On the other hand, one might interpret (A.1) to mean cx2 = a2(linear) - AS.

According to this interpretation, we find

a2 = 1.619 - 1.87 = -0.25.

In either way, the value of a2 for the booster seems to be far from the ideal

value, -1.5. To the best of my knowledge, a2 of the main ring is unknown.

references

1. K.R. Symon and A.M. Sessler,proceedinas of the CERN Svmoosium on the Hiah-Enerav Accelerators and Pion PhvsicS, 1956, vol. 1, p.46.

2. K. Johnsen, ibid., p.106.

3. W.W. Lee, TM-333, Decemberl, 1971.

4. S.C. Snowdon, TM-156, March 1969.

5. P.E. Faugeras, A. Faugier and J. Gareyte, SPS Improvement Report No.130, CERN, 24 May 1978.

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- 12 -

I__l_il___l_ill-~:; :~~:!~.~:~:~.~~l~~~~~i~~.~:.~,t~ j :: II-1 1;; _ / ~. :tl~"_~l.-~~--~~~ / :::.::~:j~~~,~::x .~;~~ ::

' I I 1

I :~/I1 .L, I 1~ 1~ 1~ ;a)/ ! : /: I -~-----I--

/--L--z+-

.-

QQ 1. ~-I

--:j - OS ~/

/

4 ,~I., 4

j pi ~! $ : j s F-. i s” j;r .~, ~-2+-y- ” I : 1.~ ;..~..I.~. ~~i~~~~.~l~.~

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- 13 -

SF

IO&

152 ~.’

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~0.b ;~ .: i I-’ ~J in a4 ~1 pi Ii

i ~’

+j1.+j I++&++ ‘+j+ >~: ,~ Jo j~/~~,~, :, fI, j ,, 1 ~;~ i/: ~I~:/ ~,:I~: 1~ )#~~,;y (1~ y :” ,,, ,, :, 1~:~ ~I:/! ::qf:r ~~I~ : I -1~ 0.65 i

70.6b

~ .~ !

!~ ~:~ 1~ Jo

I

! !,

_~-~_- CRY;: ) ;~,* i ,~ ~: 1. ~~.~.:~..--;-~--’

1 :,,, 4 ,’

lAG+!q! $L; ~~~,~~

---~:--~. ..~.,g .~. :..y~::.m~,.. ~:. ,..j :.~.~-~ ~-:~~~~T~ ..,

! :‘~iL ;~~~~~~<,l+?$,ix* ; ,.:y 1 _ lJ :/

-,

i j

iii; i- : 1~ ~,

1

i :

: 1 : /~ :~~I~~.;~~ :. Jo ~; ~, I - : .I __ / i / ‘~ id

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L-2. -A..-!

~+j++~~~ ---g,.p;;;;;&; :b&L-p tmmm.~~~.. ..I ~~,~1~ --- j ~~~~~-. ..~.~. ..--& j [: j zj&$g

t ,” .w rn,a i l-5, .I,

r j _ : 1 -Ii 1 .i.~,..L ,... 1.

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- 16 - -_-.- ::( i,~i~ j i ALES!

,___-.;.---1. ;... ,.,.-.

~~.~_~~~~r~~~ ..,.. .l~~~~ ~..~,;.~~~.~mm~;+ .~... .~...~:t-... 1 4

::i :::/::I;; ~~~_:i-.,i..~~~:~~..~.~~~~~~~~~~~.~ .i..: yL~:q-y ,!,

'0 I . ~~~~~~,.~ ~.~~_ -1

d-7 : 7

~: / +&&----LA] ~._.ll_~~.'lI:.~~._~~...l,~~ .i~~;-.~ .~~ ~I .~

~y'~'":~

::/~~~~~~~~~~~~~ : kc-: :" ~ : *----- -- ~

+

Us rl ~~': 2 I I A-- ~~~i~~-,.-..l-.'~~~~-~~. ~-~~L;= 1s Lni :'

4 I L ~: l ~~~I~L i !~ c u : Xl I

-'~~I

I ,u, h .--.-.7. : ~..m-~.~~-.~-~,.~. ..I

L: 1 I ids ,j E!~~gi~:r,I ::~~I : i fl i/ I

I

.~--$ j .~~~~ ~~~-~~~~r- I~:: :::~~ D: ,~,:: ::: :~,:jy:

b’ :

-&---+-l...f j h/ y Jo. j -- --~.: ,~.l.~__-l-~;~~.~~:~~~~~~~.. ~~; /y,p7”-1~~-y

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- 17 -

r

.-

I I I Fuji/:]: ~ j j i

j .: 1 /-

.’

I I ~

! .~~.~~I~~~. ~.~ ,, i :/i j

‘*3!tn~‘/ :i~:~1 ~1 j /I : j : j :, ~,~, V”L?C “, :I c ~I ., I I .~

~~~m~~mm~i~~~.l :.~~ !‘LL-~’ iI, .A+~iL;‘: . ~irn..~ i., .: ~Lkm~~~~ ~~~~ ~! I~~~~--~~~~~--------J !

; -.A :I~ .’ I j i : ~ .y ~j

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- 18 -

Fp~d~~~--i,s'-very~jrveak~. : -- ~~~ ~-i

t- i : / ::Y 1~ / .~

~--~-L ..I, il/, I ~ i I

i j / ~:i:~yy!L 1,~: / i 1, 1~ :::~~~i:1_1_:1ii~-::,,:-~1-:~:::~~,~:~ ;,~/ j I : j : j ,~:

:A,: j: j _ j :: ,,I ; 1~ ! j 1 F’F. :‘l

:zt ! ~. :~ -~~A.-.~~ 1~, .j ~~~~-~~~ +I-.~ ~ --T--- -~-+jy+:: ~~:~,: : ! + ; TV.-------..--,---? . . ..h^i. 7,. ^ iI: .,.. l.-~~-,+---~~~i ~;~ ~-Y--j , : ,/~I ,~I ,~ ~, ~1 ,./I ~:;~~~/~ :: ~:,~~ti~“!‘“l’l::.~~~~~)! ~: ;~ ~1’ ,; ! ! 1

L

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TM-1381-A 0302.000 0402.000

ELLIPTIC DISTRIBUTION IN LONGITUDINAL PHASE SPACE (Supplement to TM-1381, "The Beam and the Bucket")

S. Ohnuma

April 1986

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TM-1381-A

0302 0402

ELLIPTIC DISTRIBUTION IN LONGITUDINAL PHASE SPACE

(Supplement to TM-1381,"THE BEAM AND THE BUCKET")

Summary

As an alternative to either the uniform distribution (which is not

really physical) or the Gaussian distribution (which is not finite),

a finite distribution called "elliptic" is proposed and its main proper-

ties are presented. With canonical variables (q+$-$s,y=Ap/p), this

distribution takes the form

p(q,Y) cc &(d - Y2

where yB(q) defines the boundary of a finite bunch in (q,y) space. It is

assumed that the boundary is determined by the condition "Hamiltonian in

(q,y) = constant" so that the shape is in general not symmetric in phase.

This report is intended as's supplemnt to the previous one, "The Beam and

the Bucket" and, as such, it is primarily for people working in the accele-

rator control rooms.

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-l-

I.

A certain degree of "awkwardness" exists when Gaussian distributions are

assumed in the longitudinal phase space for rf bunches of protons since the

bunches must be confined within finite bucket boundaries. This is especially

the case when the bunch occupies asubstantial fraction of the bucket area.

On the other hand, a uniform distribution within a finite bunch boundary can

hardly be regarded as physical. For many years, people at CERN (some of them,

at least) have been advocating a distribution called "elliptic" as something

not only convenient but realistic as well. For example, there is a beautiful

picture of the CERN Booster bunches in an article by Frank Sacherer, Proc. -~ of the IXth Int. Conf. on High Ene- Accelerators, SLAC, 1974, p.347.

When a pair of canonical variables are* q f $ -I$~ and Y- (R/hc)(cp)(Ap/p), this distribution takes the form

o(q,y) = JYpl) -7

where y,(q) is the boundary of a finite bunch. One particularly appealing

feature of this distribution is that the resulting local.current density is

proportional to y;(q):

YB I(q) = f dy p(y,q) = y;(q)

-yB

As a consequence, the effect of the beam-induced voltage (which arises from

a distributed wall inductance) can be treated in a simple and consistent manner.

(See, for example, S. Ohnuma, TM-749, "EXPECTED BUNCH LENGTH AND MOMENTUM

SPREAD OF THE BEAM IN THE MAIN RING WITH CEA CAVITIES", October 24, 1977.)

II..

The Hamiltonian in (q,y) space is given in TM.-1381, p. 2:

H(q,y;t) = -%IAly* + BIcos(@,+q) + q.sin(e,)} ~__--

(1)

* Unless otherwise noted, all notations are identical to what I used in TM-1381.

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-2-

where a constant term, COS($~), is dropped from the original expression.

Two parameters A and B are

A = (hc/R~2h/Es) and B E (eV/2nh) (2)

Since we are considering the case below transition, n and A are negative.

The corresponding bucket and an example of bunch are shown on p. 3.

The bucket extends from @ =$L to $R (:.'i-es) and the beam from @, to G2.

The bucket boundary is specified by the relation

-kiJAly* + BIcos($fq)+Pq} '= BIcos($R)+T.qR) (3)

where r : sin(es) and qR s I$~ -$I~. Similarly, the bunch boundary is

-J$IA/y; + Btcos($+q) + T.q) = BIcos(@,) + T.q,}

= B{cos(02) + r.q21 (4)

It is convenient to use i z (lA1/2B)15.y instead of y so that the bunch

boundary is

with

-2 yB

= cos(gstq) + r'q - c (5)

c : cos(a,) t r.9, = COD t r.q2 (6)

If the total number of particles in the bunch is nB, the distribution is

p(y,q) = nB(2/n).k I$ - ;*I", (7)

with D q sin($,+q) + ?il?q*

42

- Q

q1

The local current density is

I(q) a (nB/D)$i(q) = (nB/D)Icos(GS+q) + r'q - Cl

(8)

(9)

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,, .~ ~Lll

:~ ~~~,~~ ~.~~~~I&~, .~ ,. ,,, ,: ,~ f. ., ~~. ~~~ , ~I ~ ,i ,, ,: ,~ ~/ ~~~~ , I~,,: ,:

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In particular, the maximum (local) current is*

I(q=O) = (nB/D)Icos($S) - Cl (10)

III.

We start with the assumption that the synchronous phase $I~ is known

so that the bucket length (I$, - I$,) is also known. The upper part of p. 3

is meant to be a typical picture of a bunch one sees on a scope. If we can

tell where the baseline is (which is not easy most of .the time!), we can

find the bunch length as well as various length corresponding to the relative

current density h. Remember that the current density (so that the parameter

h) is proportional to yi. It is easy to show that when the bunch length

(I$, - @,) is much less than the bucket length ($, - I$,),

Q(h) =(l - h)' x (bunch length), (11)

and the number of particles within the phase distance Q(h) relative to the

total number nB in the bunch is

f,(h) = (1 f h/2)(1 - h)' (12)

As the bunch length increases, these relations must be modified by a factor

(l+k). Fig. 1 shows k as a function of (bunch length)/(bucket length)

when h = 0.5, solid curves for &$(h=O.5), Eq.(ll.), and dashed curves for

fn(h=0.5), Eq.(l2). One sees that the approximate relation for fn, Eq.(l2),

* The maximum longitudinal charge density (which is proportional to the maximum current density) is an important quantity in the discussion of space-charge de- tuning by the self field., It is interesting to note that, when the bunch shape is symmetric ($I =O), the 'maximum density of the Gaussian distribution (nBlJ2ToZ) is very close t8 the maximum density of the elliptic distribution if uz is interpreted to be one-quarter of the total bunch length. For the Gaussian distribution, 95% of the beam is containedthin ?2u,.

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-5-

is good with less than 5% error for r =sin($s)>O.l and (bunch length)< Cl.gr

(bucket length).

IV.

Lt is often difficult to determine where the baseline is for a picture

such as the one on p. 3. Fig. 1 is then not so useful in practical situations.

The suggested procedures for such a case are as follows:

1) From thebunchshape, make a guess on where h is one-half. Based on

this guess, find Q(h=0.25), Q(h=0.5) and Q(h=0.75). Fig. 2 shows the ratios

&$(h=0.25)/6$(h=0.5) and &$(h=0.75)/6$(h=0.5) as a function of Q(h=0.5).

If the guessed values~ of 6$~ for h=0.25, 0.5 and 0.75 are not consistent with

these curves, try another guess until the best consistency is obtained. Since.

the distribution is unlikely to be exactly elliptic, this method may not always

yield a unique solution.

2) Since Q's for h=0.25, h=0.5 and h=0.75 are found (approximately),

find the corresponding bunch length from Fig. 3. When the bunch length is

comparable to the bucket length, Q(h=0.25) should be used instead of &$(h=.5)

or Q(h=.75).

3) Finally, find how many particles are contained within each phase in-

terval 6@(h) using Fig. 4.

4) From the bunch length, one can estimate the phase space area of the

bunch using, for example, Fig. 6 of TM-1381.

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----iv

-.Oj

~+ I

1 .,i,

------I------

.+10

~ -;15

lki ! I ! I

..~~~~~~.~~~plJ

~~...~~I~.~~~:.~.......................~

Jo :

~~++ ” ” -‘~~

_-! Fi . ---.._..~...~.._...,

H-j Ebb _

; 3, (of il actional :nu ~~~~~~=i.~(l+k)fl.~hl~~'(l+h/

~: .~j “\~ ~1 \~, / 1-.--~’ ---

of the ~ i \i ~ \ \ I

&- -

_~~~ ~~~~ ~~.~~~ ~~.~ . . . . . . . . . . . . . . . . .._....

!~.~~~:.~~~.I.~ i- .,.. :~ . ~~~L...~~.1~~~--~~~-.~~~~----~-l.-.~.-~

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Fig.

4;.26,

~~~ ~&#,;rOr )~~ ~~: ~: I Gu ke 1 ngth ,, ~

! +12 ,~ ,;~~ .3 ~" .4 15 ~

~~~ ~/;. ~. ~?. ~~...~,.~.. .:., ...~~~.~~~~~~~~..~~ ~~~~ ~~~~ ~~~~ :~ 1~~

r:

,

.6S =.l ~

' '!

I

/ i 2, .5 ~

~. ..~~ ~. 1

.

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..~.

;= ..-

d

_ 8 _. I 1

1.~~

+-’ .y a,

x2

f .,

+ -2.

z a

_I_..

/

1 -,

1~ a..‘.~~, 3t

1,

.! _~._*_~~_ 3

e-..-

=I~

n’ 2

a 3

3: .~I,..~ 3,

N: .~..__~~ 3

I sl.- o!

in

I-~- -1 I-.~

: I 1. 1.~~

I

I--’ I

. .

._ ..-

._._~~ .e

h

I .-

~ i :

--+r7 . ..I . . . . . . . . . . . . . . ~~1 ~ ..I ,,.

++$ I :, ,,

“\ ]~f.~~ ~~~~~_~

~.~j...:.~1-..::

~~~.j.~ . ..j \-, ~~~.. 5 i ~~1

p ‘/ ” 1 :

.-.i i .._...._. “-; *

~.~--~-~~-

---j-----l---------,

I~-‘~ ~/~ -t+

‘.I~ .~~” ,~~/ .L .._..

..,. ~I..... ~ ..,., :, [~

1,

~~+.- 1~~~~

.~ ~~.~ 1~~

..I,

1 ~‘i’!’ I..... + . . . ..I -..~.A.---.-

~~~~~~+I: .,.. L&i 2 1 1~ ~~~

,.~.. \ \ \

I . j

q s

i

1 II : 1~~~~~~ c

~~~~.~~~~~il ._.. ~.1... ~: ~~~

~~.~~~~~~~~~jj j -...

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------I-

..~ ,..~..

.“-~---I~----~~----- --------------“- ~: ..I

/ 40.05 / ~

1’ 1~1 /; (buckit ength) ~

1 I

i~ ,,, ,.~ ~. ~~1