THERMOCHEMISTRY Energy in Chemical Reactions
Mar 20, 2016
THERMOCHEMISTRYEnergy in Chemical Reactions
COMPARISONS OF ENERGY RELEASE Name a chemical reaction that releases
heat or light energy. Which would have more energy in those cases, the reactants or products?
Think of reaction that absorbs heat and think about the reactants and products energy.
http://www.artisanbreadbaking.com/images/altamura/altamura_13.jpghttp://images.search.yahoo.com/images/view?back=http%3A%2F%2Fimages.search.yahoo.com%2Fsearch%2Fimages%3Fp%3Dcandle%2Bburning%26
THERMODYNAMICS “Thermo” means “heat” “Dynamics” means “power: The study of energy and its transformations Energy- the capacity to do work or to
transfer heat Work-the energy used to cause an object
with mass to move against a force Heat- energy used to cause the
temperature an object to increase
ENERGY (P 8-9) Kinetic –energy of motion Ek = ½ mv2 m = mass v = velocity Potential – energy of position Ep = mgh m=mass g=gravity(9.8m/s2)
h=height Electrostatic energy- opposite charges attract
each other, and like charges repel each other Eel =κ Q1 Q2 κ = proportionality constant 8.99x109J-m/C2
D Q=electrical charges magnitude of electronD = distance
ELECTROSTATIC Example:
ENERGY FLOW System- the part of the universe of
interest Surroundings-everything relevant to
system Example: system might be reactants in a beaker while the surroundings would be the room temperature, pressure and humidity
INTERNAL ENERGY Energy within the system is found by: ∆E =Efinal – Einitial = Eproducts - Ereactants ∆E = ∆U : internal energy If Eproducts > Ereactants E= “+” If Eproducts < Ereactants E= “-”
HEAT – THERMAL ENERGY/WORK Heat – q; Energy transferred between a
system and it’s surroundings due to ______difference
Work- w; Energy transferred when an object is moved by a force∆E = q + w
Energy moving into a system is “ “Energy moving out of a system is “ “
+-
ENTHALPY Sum of internal energy plus the product
of the pressure and volume ∆H = ∆E + P∆V (remember liquids and solids undergo
negligible volume change)(note that if gases are present-volume ∆
small!) Therefore- often ∆H = ∆E or close to
it
CALORIMETRY Heat change absorbed by water can be
measured as: Specific Heat Capacity (c)- Which had higher c : Al vs. water ?
q = c x mass x ∆T q = quantity of heat
c = specific heat capacity
∆T = change in temperature
STOICHIOMETRY IN THERMOCHEM Heats of reaction correspond in
magnitude to the amount reacted in moles and their states of matter (solid/liquid/gas)
For example: 2H2O(l) 2H2(g) + O2(g) ∆Hrxn =
572kJ Reverse: 2H2(g) +O2(g) 2H2O(l) =-
572kJ Or… H2(g) + ½ O2(g) H2O(l)
∆Hrxn=-286kJ
Do all our reactions with exactly one mole? Create a potential problem with one of the above 3 equations giving the mass which would then be converted into moles. How much energy would be absorbed or released?
HESS’S LAW OF SUMMATION The overall enthalpy is the sum of
enthalpy steps leading to the final product.
The enthalpy of the combustion of C to CO2 is -393.5 kJ/mol C and the enthalpy for the combustion of CO2 is -283.0 kJ/mol CO:
(1) C(s) + O2(g) CO2(g) ∆H1 = -393.5 kJ
(2) CO(g) + ½ O2 CO2(g) ∆H2 = -283.0 kJ
This data can be found in Appendix B Calculate the enthalpy for the combustion of C to
CO: (3) C(s) + ½ O2(g) CO(g) ∆H3 =
-110.5 kJ
STANDARD STATE ASSUMPTIONS: Gases- are at 1 atm pressure Aqueous solutions-are 1 M concentration Pure substances-1 atm pressure; 298 K— What state are they in now?
Standard Heat of formation ∆Hf Take apart the equation pg 254…what is
the enthalpy?
SUM TOTAL! ∆Hrxn = ∑ m∆Hf - ∑ n∆Hi
Try to find the total enthalpy of the reaction:
4NH3(g) + 5O2(g) 4NO(g) + 6H2O(l)
LOOK AGAIN… Entropy: S ∆Srxn = ∑ m Sproducts - ∑ n Sreactants
How are they similar?Calculate ∆S for the synthesis of ammonia from N2(g) and H2(g) at 298 K
N2(g) + 3 H2(g) 2 NH3(g)
∆S = -198.3 J/K
PREDICTING ENTROPY SIGNS Temperature increases causes entropy
increase –directly proportional Physical state/phase change-as a
compd absorbs heat (q>0) S˚increases Dissolving a solid/liquid-increases
disorder and therefore S˚ Dissolving a gas dispersion increases
S˚ Increase in atomic size/complexity
increases
SPONTANEOUS EXOTHERMIC REACTIONS In Exothermic- (∆H < 0) the heat released
by the system increases the total entropy (S) of the system + surroundings: ∆Suniverse > 0;
∆Ssystem + ∆Ssurroundings > 0 In Exothermic- (∆H < 0) the heat released
by the system increases the entropy of the surroundings such that it overwhelms the decrease in the system then ∆Suniverse>0
SPONTANEOUS ENDOTHERMIC REACTIONS For an endothermic reaction the
∆Suniverse is positive if the ∆Ssystem large enough (∆S >>0) to overwhelm the ∆Ssurroundings (∆Ssurroundings<0)
http://patrickking.org/tug.htm
SPONTANEOUS VALUE? Brainstorm an equation that would
combine the concepts of entropy & enthalpy to determine if a reaction is spontaneous-Enter Gibbs Free Energy!
∆G = measure of the spontaneity of a process and of the useful energy available from it.
G = H – TSH = Enthalpy T= Temperature S = EntropyTHE SIGN OF G TELLS US WHETHER A REACTION IS SPONTANEOUS!
SIGNS OF S & G ∆Suniverse>0 Spontaneous ∆Suniverse<0 Non-spontaneous ∆Suniverse =0 Equilibrium ∆G < 0 Spontaneous ∆G > 0 Non-spontaneous ∆G = 0 Equilbrium
CALCULATING GIBBS FREE ENERGY ∆G˚ = ∆H˚sys - T∆S˚sys
Also: ∆G˚ = ∑m∆G˚f(products) - ∑n∆G˚f(reactants)
With your shoulder partner, read Sample Problem 20.4. After attempting it and following through the solution. Try Follow-up Problem 20.4
ENTROPY/GIBBS FUN! http://www.youtube.com/watch?v=OsldTzBaIEw
http://www.youtube.com/watch?v=V48r4IArzLc&feature=related