Statics CEE 331 March 13, 2022
Dec 22, 2015
StaticsStaticsCEE 331
April 19, 2023
CEE 331
April 19, 2023
Definitions and ApplicationsDefinitions and Applications
Statics: no relative motion between adjacent fluid layers. Shear stress is zero Only _______ can be acting on fluid surfaces
Gravity force acts on the fluid (____ force) Applications:
Pressure variation within a reservoir Forces on submerged surfaces Tensile stress on pipe walls Buoyant forces
Statics: no relative motion between adjacent fluid layers. Shear stress is zero Only _______ can be acting on fluid surfaces
Gravity force acts on the fluid (____ force) Applications:
Pressure variation within a reservoir Forces on submerged surfaces Tensile stress on pipe walls Buoyant forces
pressure
body
Motivation?Motivation?
What are the pressure forces behind the Hoover Dam?
What are the pressure forces behind the Hoover Dam?
Upstream face of Hoover DamUpstream face of Hoover DamUpstream face of Hoover DamUpstream face of Hoover Dam
Upstream face of Hoover Dam in 1935Upstream face of Hoover Dam in 1935
Crest thickness: 13.7 m Base thickness: 201 mWHY???
What do you think?What do you think?
Lake Mead, the lake behind Hoover Dam, is the world's largest artificial body of water by volume (35 km3). Is the pressure at the base of Hoover Dam affected by the volume of water in Lake Mead?
What do we need to know?What do we need to know?
Pressure variation with direction Pressure variation with location How can we calculate the total force on a
submerged surface?
Pressure variation with direction Pressure variation with location How can we calculate the total force on a
submerged surface?
Pressure Variation with Direction(Pascal’s law)
Pressure Variation with Direction(Pascal’s law)
yy
xx
pss
pxy
pyx
y
x
s
2yx
2yx
Body forces
Surface forcesEquation of Motion
xF xF
F = ma
02
m xx ayx
a 02
m xx ayx
a
y sin s y sin s
0y p -y p sx 0y p -y p sx
pxy - pss sin
Independent of direction!
Pressure FieldPressure Field
In the absence of shearing forces (no relative motion between fluid particles) what causes pressure variation within a fluid?
Consider a soda can in space… Throw the soda can to another astronaut… Throw the soda can toward the moon
1 minute… What causes pressure gradients?
In the absence of shearing forces (no relative motion between fluid particles) what causes pressure variation within a fluid?
Consider a soda can in space… Throw the soda can to another astronaut… Throw the soda can toward the moon
1 minute… What causes pressure gradients?
ppz
zx y
FH IK 2
Pressure FieldPressure Field
ppy
yx z
FHG
IKJ
2
m x y zji
zz
yy
xx
k
ppz
zx y
FH IK 2
ppy
yx z
FHG
IKJ
2
Small element of fluid in Small element of fluid in pressure pressure gradientgradient with arbitrary __________. with arbitrary __________.
Forces acting on surfaces of elementPressure is Pressure is pp at at
center of elementcenter of element
acceleration
Mass…Mass…
Same in x!Same in x!Now let’s sum the forces in the y direction
Simplify the expression for the force acting on the element
Simplify the expression for the force acting on the element
Fpy
x y zy
Fpx
x y zx
Fpz
x y zz
F i j k
FHG
IKJ
px
py
pz
x y z
px
py
pz
p i j k
F p x y z
Same in xyz!Same in xyz!
This begs for vector notation!This begs for vector notation!
Forces acting on element of Forces acting on element of fluid due to pressure gradientfluid due to pressure gradient
2 2y
p y p yF p x z p x z
y yd d
d d d d d¶ ¶æ ö æ ö
= - - +ç ÷ ç ÷è ø è ø¶ ¶
Apply Newton’s Second LawApply Newton’s Second Law
F a m
p x y z x y z a
p a
F p x y z
m x y za ad rd d d= Mass of element of fluidMass of element of fluid
Substitute into Newton’s 2nd Law
Obtain a general vector expression Obtain a general vector expression relating pressure gradient to relating pressure gradient to accelerationacceleration and write the 3 component equations.and write the 3 component equations.
Note that we are effectively Note that we are effectively accelerating upward at g when we accelerating upward at g when we are “at rest” on earth’s surface!are “at rest” on earth’s surface!
x y z
p p pa a a
x y zr r r
¶ ¶ ¶= =- -
¶=-
¶ ¶
dpdz
g
ˆp r g- Ñ = +a k Text version of eq.Text version of eq.
At restAt rest
3 component equations3 component equations
Compressible fluid - changing density
Changing gravity
Pressure Variation When the Specific Weight is ConstantPressure Variation When the Specific Weight is Constant
What are the two things that could make specific weight () vary in a fluid?
What are the two things that could make specific weight () vary in a fluid?
= g
Piezometric head
dp dz
dp dzp
p
z
z
1
2
1
2z z
p p z z2 1 2 1 a f pz
pz1
12
2
Constant specific weight!
Generalize to any a!
p hgD =
Example: Pressure at the bottom of a Tank of Water?
Example: Pressure at the bottom of a Tank of Water?
Does the pressure at the bottom of the tank increase if the diameter of the tank increases?
h
11
22
p p z z2 1 2 1 a f
What is the pressure at the top of the tank?What is the pressure at the top of the tank?
Suppose I define pressure and elevation as zero at the water surface. Suppose I define pressure and elevation as zero at the water surface. What is the piezometric head everywhere in the tank? ______What is the piezometric head everywhere in the tank? ______Zero!
No!
6894.76 Pa/psi
Units and Scales of Pressure Measurement
Units and Scales of Pressure Measurement
Standard atmospheric pressure
Local atmospheric pressure
Absolute zero (complete vacuum)
Absolute pressureGage pressure
1 atmosphere101.325 kPa14.7 psi______ m H20760 mm Hg
Suction vacuum(gage pressure)Local baromet
er reading10.3410.34
atmph
g= =
3
3
101 109806 /
x PaN m
Mercury Barometer (team work)Mercury Barometer (team work)
22
11 z
p z
p 2
21
1 zp
zp
6.13HgS 6.13HgSWhat is the local atmospheric pressure (in kPa) when R is 750 mm Hg?
R
1
2
1221 zzp p Hg 1221 zzp p Hg P2 = Hg vapor pressure
R p Hg1 R p Hg1
waterHgHg S waterHgHg S
RS p Hg1 RS p Hg1
PammN p 000,10075.0/98066.13 31 PammN p 000,10075.0/98066.13 31
fluid
water
r
r= fluid
water
r
r=
Assume constant
1000 kg/m3
1 x10-3 N·s/m2
9800 N/m3
101.3 kPa
A few important constants!A few important constants!
Properties of water Density: _______ Viscosity: ___________ Specific weight: _______
Properties of the atmosphere Atmospheric pressure ______ Height of a column of water that can be
supported by atmospheric pressure _____
Properties of water Density: _______ Viscosity: ___________ Specific weight: _______
Properties of the atmosphere Atmospheric pressure ______ Height of a column of water that can be
supported by atmospheric pressure _____10.3 m
Pressure Variation in a Compressible Fluid
Pressure Variation in a Compressible Fluid
Perfect gas at constant temperature (Isothermal)
Perfect gas with constant temperature gradient
Perfect gas at constant temperature (Isothermal)
Perfect gas with constant temperature gradient
Perfect Gas at Constant Temperature (Isothermal)Perfect Gas at Constant
Temperature (Isothermal)
nRTpV nRTpV gaspM
RTgaspM
RT
g g
dzRT
gpMdp gas dz
RT
gpMdp gas
dzRT
gM
pdp
z
z
gasp
p
2
1
2
1
dzRT
gM
pdp
z
z
gasp
p
2
1
2
1
121
2ln zzRT
gM
pp gas 12
1
2ln zzRT
gM
pp gas
e
zzRT
gM gas
pp
12
12
e
zzRT
gM gas
pp
12
12
Mgas is molecular mass
is function of pdp dz
gasnM
Vr = =gasnM
Vr = =
Integrate…Integrate…
= 0.00650 K/m
Perfect Gas with Constant Temperature Gradient
Perfect Gas with Constant Temperature Gradient
The atmosphere can be modeled as having a constant temperature gradient
The atmosphere can be modeled as having a constant temperature gradient
zTT a zTT a
dzRT
gM
pdp gas dz
RT
gM
pdp gas
dzzTR
gM
pdp
a
gas
dzzTR
gM
pdp
a
gas
z
a
gasp
p zTdz
R
gM
pdp
a 0
z
a
gasp
p zTdz
R
gM
pdp
a 0
a
agas
a TzT
R
gM
pp
ln
1ln
a
agas
a TzT
R
gM
pp
ln
1ln
R
gM
aa
gas
Tz
pp
1
R
gM
aa
gas
Tz
pp
1
0
20
40
60
80
100
0 5000 10000 15000Elevation (m)
Pre
ssur
e (k
Pa)
Lapse rateLapse rate
Mt. Everest
Pressure MeasurementPressure Measurement
Barometers Manometers
Standard Differential
Pressure Transducers
Barometers Manometers
Standard Differential
Pressure Transducers
Measure atmospheric pressure
Pressure relative to atm.
Pressure difference between 2 pts.
A
Standard ManometersStandard Manometers
What is the pressure at A given h?
Pressure in water distribution systems commonly varies between 25 and 100 psi (175 to 700 kPa). How high would the water rise in a manometer connected to a pipe containing water at 500 kPa?
What is the pressure at A given h?
Pressure in water distribution systems commonly varies between 25 and 100 psi (175 to 700 kPa). How high would the water rise in a manometer connected to a pipe containing water at 500 kPa?
h
p = h
h = p/h = 500,000 Pa/9800 N/m3
h = 51 m Why is this a reasonable pressure?Why is this a reasonable pressure?
gage
P1 = 0P1 = 0 hh11
??
hh22
Manometers for High PressuresManometers for High Pressures
Find the gage pressure in the center of the sphere. The sphere contains fluid with 1 and the manometer contains fluid with 2.
What do you know? _____
Use statics to find other pressures.
Find the gage pressure in the center of the sphere. The sphere contains fluid with 1 and the manometer contains fluid with 2.
What do you know? _____
Use statics to find other pressures.
11
22
33
=P3=P3
1
2
For small h1 use fluid with high density. Mercury!Mercury!
+ h12+ h12 - h21- h21P1P1
- h2Hg- h2Hg- h3w- h3w
Differential ManometersDifferential Manometers
h1
h3
Mercury
Find the drop in pressure between point 1 and point 2.
p1p2Water
h2
orificeorifice
= p2= p2
p1 - p2 = (h3-h1)w + h2Hg
p1 - p2 = h2(Hg - w)
p1p1 + h1w+ h1w
Procedure to keep track of pressures
Procedure to keep track of pressures
Start at a known point or at one end of the system and write the pressure there using an appropriate symbol
Add to this the change in pressure to the next meniscus (plus if the next meniscus is lower, and minus if higher)
Continue until the other end of the gage is reached and equate the expression to the pressure at that point
Start at a known point or at one end of the system and write the pressure there using an appropriate symbol
Add to this the change in pressure to the next meniscus (plus if the next meniscus is lower, and minus if higher)
Continue until the other end of the gage is reached and equate the expression to the pressure at that point
p1 + p = p2
Pressure TransducersPressure Transducers
Excitation: 10 Vdc regulated Output: 100 millivolts Accuracy: ±1% FS Proof Pressure: 140 kPa (20 psi) for 7 kPa model No Mercury! Can be monitored easily by computer Myriad of applications
Volume of liquid in a tank Flow rates Process monitoring and control
Excitation: 10 Vdc regulated Output: 100 millivolts Accuracy: ±1% FS Proof Pressure: 140 kPa (20 psi) for 7 kPa model No Mercury! Can be monitored easily by computer Myriad of applications
Volume of liquid in a tank Flow rates Process monitoring and control
Full Scale
Strain gageStrain gage
What happens to the resistance thru the strain gage if it is stretched in the y direction? ________________
In the x direction? ________________
Strain gage can be made of wire that is then bonded to the objected that is undergoing strain
Or diffused into a crystalline silicon diaphragm (___________)
What happens to the resistance thru the strain gage if it is stretched in the y direction? ________________
In the x direction? ________________
Strain gage can be made of wire that is then bonded to the objected that is undergoing strain
Or diffused into a crystalline silicon diaphragm (___________)
x
y
Little change
Great change
Piezoresistive
Types of Diaphragms Used for Pressure Measurements
Types of Diaphragms Used for Pressure Measurements
Stainless Steel Strain gages bonded to the stainless steel Typical full scale output of 3 mV/V
Piezoresistive Strain gage diffused into silicon wafers Typical full scale output of 10 mV/V
Stainless Steel Strain gages bonded to the stainless steel Typical full scale output of 3 mV/V
Piezoresistive Strain gage diffused into silicon wafers Typical full scale output of 10 mV/V
Piezoresistive DiaphragmsPiezoresistive Diaphragms
Excitation +
Excitation -Signal -
Signal +
R is function of ____________ on crystal and strain.orientation
R+R R+R
R-R
R-R
SiliconSilicon
Ideal material for receiving the applied force
Perfect crystal Returns to its initial shape (no hysteresis) Good elasticity No need for special bonding between
material receiving force and strain gage
Ideal material for receiving the applied force
Perfect crystal Returns to its initial shape (no hysteresis) Good elasticity No need for special bonding between
material receiving force and strain gage
Pressure Sensor FailurePressure Sensor Failure
High pressures – rupture crystal (beware of resulting leak!)
Water hammer – High speed pressure waves (speed of sound) Result from flow transients such as rapidly
shutting valves Install pressure snubber!
Incompatible materials
High pressures – rupture crystal (beware of resulting leak!)
Water hammer – High speed pressure waves (speed of sound) Result from flow transients such as rapidly
shutting valves Install pressure snubber!
Incompatible materials
Absolute vs. Gage vs. Differential
Absolute vs. Gage vs. Differential
Absolute Port 2 sealed with vacuum
on bottom side of silicon crystal
Gage Port 2 open to atmosphere
Differential Both ports connected to
system
Absolute Port 2 sealed with vacuum
on bottom side of silicon crystal
Gage Port 2 open to atmosphere
Differential Both ports connected to
system
Port 1
Port 2
Pressure is independent of Pressure increases with
constant density gas at constant temperature gas with constant temperature gradient
Pressure scales units datum
Pressure measurement
Pressure is independent of Pressure increases with
constant density gas at constant temperature gas with constant temperature gradient
Pressure scales units datum
Pressure measurement
direction
depthp = h
Use ideal gas law
Summary for StaticsSummary for Statics
dzdp dzdp
ReviewReview
Pressure increases or decreases as we move in direction of acceleration vector?
The free surface is _______ to the acceleration vector.
What is an equation that describes the change in pressure with depth in a fluid?
Suppose a tank of fuel is accelerating upward at 2g. What is the change in pressure with depth in the fuel?
Pressure increases or decreases as we move in direction of acceleration vector?
The free surface is _______ to the acceleration vector.
What is an equation that describes the change in pressure with depth in a fluid?
Suppose a tank of fuel is accelerating upward at 2g. What is the change in pressure with depth in the fuel?
normal
dp adzr=-
Statics exampleStatics example
What is the air pressure in the cave air pocket?What is the air pressure in the cave air pocket?
Statics LabStatics Lab
How did the bubbler work? How did the bubbler work?
“Somebody finally got smart and came up with an above-ground pool that’s got a deep end and a shallow end.”
“Somebody finally got smart and came up with an above-ground pool that’s got a deep end and a shallow end.”