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Linear Equation Simple Trick by using Solve
3

Solve linear equation by using this simple trick

Jan 23, 2017

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Pratham Surani
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Page 1: Solve linear equation by using this simple trick

Linear Equation

Simple Trickby using

Solve

Page 2: Solve linear equation by using this simple trick

8π‘₯ + 5𝑦 = 11 β†’ 8π‘₯ + 5𝑦 – 11 = 0

3π‘₯ – 4𝑦 10 β†’ 3π‘₯ 4𝑦 10 = 0

Tricks

A

Let’s solve two simultaneous equations

First write coefficients of equation in form of presentation below

Now Formula goes like this

How to remember and use this method to solve equation within 30 Seconds

π‘Ž π‘₯ + 𝑏 𝑦 + 𝑐 = 0

π‘Ž π‘₯ + 𝑏 𝑦 + 𝑐 = 0

π‘₯ (b₁cβ‚‚ βˆ’ bβ‚‚c₁)(a₁bβ‚‚ βˆ’ aβ‚‚b₁)

= 𝑁𝐷

𝑦 (c₁aβ‚‚ βˆ’ cβ‚‚a₁)(a₁bβ‚‚ βˆ’ aβ‚‚b₁)

= 𝑁𝐷

π‘Ž 1 𝑏 1 𝑐 1 π‘Ž 1

π‘Ž 2 𝑏 2 𝑐 2 π‘Ž 2

8 5 βˆ’11 8

3 βˆ’4 βˆ’10 3

Page 3: Solve linear equation by using this simple trick

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Now to find x and y, let’s divide the above boxes into three compartments and cross multiply numbers. Starting from left as shown below.

𝐷 8 βˆ— (βˆ’4) βˆ’ 5 βˆ— 3 𝑁 1 = βˆ’5 βˆ— (βˆ’10) βˆ’ (βˆ’4) βˆ— (βˆ’11) 𝑁 2 = βˆ’11 βˆ— (3) βˆ’ (βˆ’10) βˆ— 8

𝐷 βˆ’32 βˆ’ 15 ==

=

βˆ’47 𝑁 1 = βˆ’50 βˆ’ 44 = βˆ’94 𝑁 2 = βˆ’33 + 80 = 47

So 𝑋 𝑁 1𝐷

βˆ’94βˆ’47

=== 2 π‘Œ 𝑁 2𝐷

βˆ’4747

== = βˆ’1

8 5 βˆ’11 8

3 βˆ’4 βˆ’10 3

8 5 βˆ’11 8

3 βˆ’4 βˆ’10 3

8 5 βˆ’11 8

3 βˆ’4 βˆ’10 3

π‘Ž 1 𝑏 1 𝑐 1 π‘Ž 1

π‘Ž 2 𝑏 2 𝑐 2 π‘Ž 2

π‘Ž 1 𝑏 1 𝑐 1 π‘Ž 1

π‘Ž 2 𝑏 2 𝑐 2 π‘Ž 2

π‘Ž 1 𝑏 1 𝑐 1 π‘Ž 1

π‘Ž 2 𝑏 2 𝑐 2 π‘Ž 2

Tricks