1 © 2006 Thomson/South-Western © 2006 Thomson/South-Western Slides Prepared by Slides Prepared by JOHN S. LOUCKS JOHN S. LOUCKS St. Edward’s St. Edward’s University University
Jan 04, 2016
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Slides Prepared bySlides Prepared by
JOHN S. LOUCKSJOHN S. LOUCKSSt. Edward’s UniversitySt. Edward’s University
Slides Prepared bySlides Prepared by
JOHN S. LOUCKSJOHN S. LOUCKSSt. Edward’s UniversitySt. Edward’s University
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Chapter 6Chapter 6 Continuous Probability Distributions Continuous Probability Distributions
Uniform Probability DistributionUniform Probability Distribution Normal Probability DistributionNormal Probability Distribution Exponential Probability DistributionExponential Probability Distribution
f (x)f (x)
x x
UniformUniform
xx
f f ((xx)) NormalNormal
xx
f (x)f (x) ExponentialExponential
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Continuous Probability DistributionsContinuous Probability Distributions
A A continuous random variablecontinuous random variable can assume any can assume any value in an interval on the real line or in a value in an interval on the real line or in a collection of intervals.collection of intervals.
It is not possible to talk about the probability of the It is not possible to talk about the probability of the random variable assuming a particular value.random variable assuming a particular value.
Instead, we talk about the probability of the random Instead, we talk about the probability of the random variable assuming a value within a given interval.variable assuming a value within a given interval.
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Continuous Probability DistributionsContinuous Probability Distributions
The probability of the random variable The probability of the random variable assuming a value within some given interval assuming a value within some given interval from from xx11 to to xx22 is defined to be the is defined to be the area under area under the graphthe graph of the of the probability density functionprobability density function betweenbetween x x11 andand x x22..
f (x)f (x)
x x
UniformUniform
xx11 xx11 xx22 xx22
xx
f f ((xx)) NormalNormal
xx11 xx11 xx22 xx22
xx11 xx11 xx22 xx22
ExponentialExponential
xx
f (x)f (x)
xx11
xx11
xx22 xx22
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Uniform Probability DistributionUniform Probability Distribution
where: where: aa = smallest value the variable can assume = smallest value the variable can assume
bb = largest value the variable can assume = largest value the variable can assume
f f ((xx) = 1/() = 1/(bb – – aa) for ) for aa << xx << bb = 0 elsewhere= 0 elsewhere f f ((xx) = 1/() = 1/(bb – – aa) for ) for aa << xx << bb = 0 elsewhere= 0 elsewhere
A random variable is A random variable is uniformly distributeduniformly distributed whenever the probability is proportional to the whenever the probability is proportional to the interval’s length. interval’s length.
The The uniform probability density functionuniform probability density function is: is:
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Var(Var(xx) = () = (bb - - aa))22/12/12Var(Var(xx) = () = (bb - - aa))22/12/12
E(E(xx) = () = (aa + + bb)/2)/2E(E(xx) = () = (aa + + bb)/2)/2
Uniform Probability DistributionUniform Probability Distribution
Expected Value of Expected Value of xx
Variance of Variance of xx
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Uniform Probability DistributionUniform Probability Distribution
Example: Slater's BuffetExample: Slater's BuffetSlater customers are Slater customers are
chargedchargedfor the amount of salad they take. for the amount of salad they take. Sampling suggests that theSampling suggests that theamount of salad taken is amount of salad taken is uniformly distributeduniformly distributedbetween 5 ounces and 15 ounces.between 5 ounces and 15 ounces.
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Uniform Probability Density FunctionUniform Probability Density Function
ff((xx) = 1/10 for 5 ) = 1/10 for 5 << xx << 15 15
= 0 elsewhere= 0 elsewhere
ff((xx) = 1/10 for 5 ) = 1/10 for 5 << xx << 15 15
= 0 elsewhere= 0 elsewhere
where:where:
xx = salad plate filling weight = salad plate filling weight
Uniform Probability DistributionUniform Probability Distribution
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Expected Value of Expected Value of xx
Variance of Variance of xx
E(E(xx) = () = (aa + + bb)/2)/2
= (5 + 15)/2= (5 + 15)/2
= 10= 10
E(E(xx) = () = (aa + + bb)/2)/2
= (5 + 15)/2= (5 + 15)/2
= 10= 10
Var(Var(xx) = () = (bb - - aa))22/12/12
= (15 – 5)= (15 – 5)22/12/12
= 8.33= 8.33
Var(Var(xx) = () = (bb - - aa))22/12/12
= (15 – 5)= (15 – 5)22/12/12
= 8.33= 8.33
Uniform Probability DistributionUniform Probability Distribution
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Uniform Probability DistributionUniform Probability Distributionfor Salad Plate Filling Weightfor Salad Plate Filling Weight
f(x)f(x)
x x55 1010 1515
1/101/10
Salad Weight (oz.)Salad Weight (oz.)
Uniform Probability DistributionUniform Probability Distribution
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f(x)f(x)
x x55 1010 1515
1/101/10
Salad Weight (oz.)Salad Weight (oz.)
P(12 < x < 15) = 1/10(3) = .3P(12 < x < 15) = 1/10(3) = .3
What is the probability that a customerWhat is the probability that a customer
will take between 12 and 15 ounces of will take between 12 and 15 ounces of salad?salad?
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Uniform Probability DistributionUniform Probability Distribution
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Normal Probability DistributionNormal Probability Distribution
The The normal probability distributionnormal probability distribution is the most is the most important distribution for describing a important distribution for describing a continuous random variable.continuous random variable.
It is widely used in statistical inference.It is widely used in statistical inference.
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HeightsHeightsof peopleof peopleHeightsHeights
of peopleof people
Normal Probability DistributionNormal Probability Distribution
It has been used in a wide variety of It has been used in a wide variety of applications:applications:
ScientificScientific measurementsmeasurements
ScientificScientific measurementsmeasurements
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AmountsAmounts
of rainfallof rainfall
AmountsAmounts
of rainfallof rainfall
Normal Probability DistributionNormal Probability Distribution
It has been used in a wide variety of It has been used in a wide variety of applications:applications:
TestTest scoresscoresTestTest
scoresscores
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Normal Probability DistributionNormal Probability Distribution
Normal Probability Density FunctionNormal Probability Density Function
2 2( ) / 21( )
2xf x e
2 2( ) / 21( )
2xf x e
= mean= mean
= standard deviation= standard deviation
= 3.14159= 3.14159
ee = 2.71828 = 2.71828
where:where:
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The distribution is The distribution is symmetricsymmetric; its skewness; its skewness measure is zero.measure is zero. The distribution is The distribution is symmetricsymmetric; its skewness; its skewness measure is zero.measure is zero.
Normal Probability DistributionNormal Probability Distribution
CharacteristicsCharacteristics
xx
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The entire family of normal probabilityThe entire family of normal probability distributions is defined by itsdistributions is defined by its meanmean and its and its standard deviationstandard deviation . .
The entire family of normal probabilityThe entire family of normal probability distributions is defined by itsdistributions is defined by its meanmean and its and its standard deviationstandard deviation . .
Normal Probability DistributionNormal Probability Distribution
CharacteristicsCharacteristics
Standard Deviation Standard Deviation
Mean Mean xx
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The The highest pointhighest point on the normal curve is at the on the normal curve is at the meanmean, which is also the , which is also the medianmedian and and modemode.. The The highest pointhighest point on the normal curve is at the on the normal curve is at the meanmean, which is also the , which is also the medianmedian and and modemode..
Normal Probability DistributionNormal Probability Distribution
CharacteristicsCharacteristics
xx
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Normal Probability DistributionNormal Probability Distribution
CharacteristicsCharacteristics
-10-10 00 2020
The mean can be any numerical value: negative,The mean can be any numerical value: negative, zero, or positive.zero, or positive. The mean can be any numerical value: negative,The mean can be any numerical value: negative, zero, or positive.zero, or positive.
xx
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Normal Probability DistributionNormal Probability Distribution
CharacteristicsCharacteristics
= 15= 15
= 25= 25
The standard deviation determines the width of theThe standard deviation determines the width of thecurve: larger values result in wider, flatter curves.curve: larger values result in wider, flatter curves.The standard deviation determines the width of theThe standard deviation determines the width of thecurve: larger values result in wider, flatter curves.curve: larger values result in wider, flatter curves.
xx
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Probabilities for the normal random variable areProbabilities for the normal random variable are given by given by areas under the curveareas under the curve. The total area. The total area under the curve is 1 (.5 to the left of the mean andunder the curve is 1 (.5 to the left of the mean and .5 to the right)..5 to the right).
Probabilities for the normal random variable areProbabilities for the normal random variable are given by given by areas under the curveareas under the curve. The total area. The total area under the curve is 1 (.5 to the left of the mean andunder the curve is 1 (.5 to the left of the mean and .5 to the right)..5 to the right).
Normal Probability DistributionNormal Probability Distribution
CharacteristicsCharacteristics
.5.5 .5.5
xx
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Normal Probability DistributionNormal Probability Distribution
CharacteristicsCharacteristics
of values of a normal random variableof values of a normal random variable are within of its mean.are within of its mean.
of values of a normal random variableof values of a normal random variable are within of its mean.are within of its mean.68.26%68.26%68.26%68.26%
+/- 1 standard deviation+/- 1 standard deviation+/- 1 standard deviation+/- 1 standard deviation
of values of a normal random variableof values of a normal random variable are within of its mean.are within of its mean.
of values of a normal random variableof values of a normal random variable are within of its mean.are within of its mean.95.44%95.44%95.44%95.44%
+/- 2 standard deviations+/- 2 standard deviations+/- 2 standard deviations+/- 2 standard deviations
of values of a normal random variableof values of a normal random variable are within of its mean.are within of its mean.
of values of a normal random variableof values of a normal random variable are within of its mean.are within of its mean.99.72%99.72%99.72%99.72%
+/- 3 standard deviations+/- 3 standard deviations+/- 3 standard deviations+/- 3 standard deviations
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Normal Probability DistributionNormal Probability Distribution
CharacteristicsCharacteristics
xx – – 33 – – 11
– – 22 + 1+ 1
+ 2+ 2 + 3+ 3
68.26%68.26%95.44%95.44%99.72%99.72%
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Standard Normal Probability DistributionStandard Normal Probability Distribution
A random variable having a normal distributionA random variable having a normal distribution with a mean of 0 and a standard deviation of 1 iswith a mean of 0 and a standard deviation of 1 is said to have a said to have a standard normal probabilitystandard normal probability distributiondistribution..
A random variable having a normal distributionA random variable having a normal distribution with a mean of 0 and a standard deviation of 1 iswith a mean of 0 and a standard deviation of 1 is said to have a said to have a standard normal probabilitystandard normal probability distributiondistribution..
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00zz
The letter The letter z z is used to designate the standardis used to designate the standard normal random variable.normal random variable. The letter The letter z z is used to designate the standardis used to designate the standard normal random variable.normal random variable.
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Converting to the Standard Normal Converting to the Standard Normal DistributionDistribution
Standard Normal Probability DistributionStandard Normal Probability Distribution
zx
zx
We can think of We can think of zz as a measure of the number of as a measure of the number ofstandard deviations standard deviations xx is from is from ..
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Standard Normal Probability DistributionStandard Normal Probability Distribution
Standard Normal Density FunctionStandard Normal Density Function
2 / 21( )
2zf x e
2 / 21( )
2zf x e
z z = ( = (xx – – )/)/ = 3.14159= 3.14159
ee = 2.71828 = 2.71828
where:where:
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Standard Normal Probability DistributionStandard Normal Probability Distribution
Example: Pep ZoneExample: Pep Zone
Pep Zone sells auto parts and supplies Pep Zone sells auto parts and supplies includingincluding
a popular multi-grade motor oil. When thea popular multi-grade motor oil. When the
stock of this oil drops to 20 gallons, astock of this oil drops to 20 gallons, a
replenishment order is placed.replenishment order is placed. PepZone5w-20Motor Oil
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The store manager is concerned that sales The store manager is concerned that sales are beingare being
lost due to stockouts while waiting for an order.lost due to stockouts while waiting for an order.
It has been determined that demand duringIt has been determined that demand during
replenishment lead-time is normallyreplenishment lead-time is normally
distributed with a mean of 15 gallons anddistributed with a mean of 15 gallons and
a standard deviation of 6 gallons. a standard deviation of 6 gallons.
The manager would like to know theThe manager would like to know the
probability of a stockout, probability of a stockout, PP((xx > 20). > 20).
Standard Normal Probability DistributionStandard Normal Probability Distribution
PepZone5w-20Motor Oil
Example: Pep ZoneExample: Pep Zone
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zz = ( = (xx - - )/)/ = (20 - 15)/6= (20 - 15)/6 = .83= .83
zz = ( = (xx - - )/)/ = (20 - 15)/6= (20 - 15)/6 = .83= .83
Solving for the Stockout ProbabilitySolving for the Stockout Probability
Step 1: Convert Step 1: Convert xx to the standard normal distribution. to the standard normal distribution.Step 1: Convert Step 1: Convert xx to the standard normal distribution. to the standard normal distribution.
PepZone5w-20
Motor Oil
Step 2: Find the area under the standard normalStep 2: Find the area under the standard normal curve to the left of curve to the left of zz = .83. = .83.Step 2: Find the area under the standard normalStep 2: Find the area under the standard normal curve to the left of curve to the left of zz = .83. = .83.
see next slidesee next slide see next slidesee next slide
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Cumulative Probability Table for Cumulative Probability Table for the Standard Normal Distributionthe Standard Normal Distribution
z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09
. . . . . . . . . . .
.5 .1915 .1950 .1985 .2019 .2054 .2088 .2123 .2157 .2190 .2224
.6 .2257 .2291 .2324 .2357 .2389 .2422 .2454 .2486 .2517 .2549
.7 .2580 .2611 .2642 .2673 .2704 .2734 .2764 .2794 .2823 .2852
.8 .2881 .2910 .2939 .2967 .2995 .3023 .3051 .3078 .3106 .3133
.9 .3159 .3186 .3212 .3238 .3264 .3289 .3315 .3340 .3365 .3389
. . . . . . . . . . .
z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09
. . . . . . . . . . .
.5 .1915 .1950 .1985 .2019 .2054 .2088 .2123 .2157 .2190 .2224
.6 .2257 .2291 .2324 .2357 .2389 .2422 .2454 .2486 .2517 .2549
.7 .2580 .2611 .2642 .2673 .2704 .2734 .2764 .2794 .2823 .2852
.8 .2881 .2910 .2939 .2967 .2995 .3023 .3051 .3078 .3106 .3133
.9 .3159 .3186 .3212 .3238 .3264 .3289 .3315 .3340 .3365 .3389
. . . . . . . . . . .
PepZone5w-20
Motor Oil
PP(.00 (.00 << zz << .83) .83)
Standard Normal Probability DistributionStandard Normal Probability Distribution
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PP((z z > .83) = .5 – > .83) = .5 – PP(.00 (.00 << zz << .83) .83) = .5 = .5 .2967 .2967
= .2033= .2033
PP((z z > .83) = .5 – > .83) = .5 – PP(.00 (.00 << zz << .83) .83) = .5 = .5 .2967 .2967
= .2033= .2033
Solving for the Stockout ProbabilitySolving for the Stockout Probability
Step 3: Compute the area under the standard normalStep 3: Compute the area under the standard normal curve to the right of curve to the right of zz = .83. = .83.Step 3: Compute the area under the standard normalStep 3: Compute the area under the standard normal curve to the right of curve to the right of zz = .83. = .83.
PepZone5w-20
Motor Oil
ProbabilityProbability of a of a
stockoutstockoutPP((xx > > 20)20)
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Solving for the Stockout ProbabilitySolving for the Stockout Probability
00 .83.83
Area = .2967Area = .2967Area = .5 Area = .5 .2967 .2967
= .2033= .2033
zz
PepZone5w-20
Motor Oil
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Standard Normal Probability DistributionStandard Normal Probability Distribution
If the manager of Pep Zone wants the If the manager of Pep Zone wants the probability of a stockout to be no more probability of a stockout to be no more than .05, what should the reorder point be?than .05, what should the reorder point be?
PepZone5w-20
Motor Oil
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Solving for the Reorder PointSolving for the Reorder Point
PepZone5w-20
Motor Oil
00
Area = .4500Area = .4500
Area = .0500Area = .0500
zzzz.05.05
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Solving for the Reorder PointSolving for the Reorder Point
PepZone5w-20
Motor Oil
Step 1: Find the Step 1: Find the zz-value that cuts off an area of .05-value that cuts off an area of .05 in the right tail of the standard normalin the right tail of the standard normal distribution.distribution.
Step 1: Find the Step 1: Find the zz-value that cuts off an area of .05-value that cuts off an area of .05 in the right tail of the standard normalin the right tail of the standard normal distribution.distribution.
z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09
. . . . . . . . . . .
1.5 .4332 .4345 .4357 .4370 .4382 .4394 .4406 .4418 .4429 .4441
1.6 .4452 .4463 .4474 .4484 .4495 .4505 .4515 .4525 .4535 .4545
1.7 .4554 .4564 .4573 .4582 .4591 .4599 .4608 .4616 .4625 .4633
1.8 .4641 .4649 .4656 .4664 .4671 .4678 .4686 .4693 .4699 .4706
1.9 .4713 .4719 .4726 .4732 .4738 .4744 .4750 .4756 .4761 .4767
. . . . . . . . . . .
z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09
. . . . . . . . . . .
1.5 .4332 .4345 .4357 .4370 .4382 .4394 .4406 .4418 .4429 .4441
1.6 .4452 .4463 .4474 .4484 .4495 .4505 .4515 .4525 .4535 .4545
1.7 .4554 .4564 .4573 .4582 .4591 .4599 .4608 .4616 .4625 .4633
1.8 .4641 .4649 .4656 .4664 .4671 .4678 .4686 .4693 .4699 .4706
1.9 .4713 .4719 .4726 .4732 .4738 .4744 .4750 .4756 .4761 .4767
. . . . . . . . . . .We look up .5 minusWe look up .5 minusthe tail area (.5 - .05 the tail area (.5 - .05
= .45)= .45)
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Solving for the Reorder PointSolving for the Reorder Point
PepZone5w-20
Motor Oil
Step 2: Convert Step 2: Convert zz.05.05 to the corresponding value of to the corresponding value of xx..Step 2: Convert Step 2: Convert zz.05.05 to the corresponding value of to the corresponding value of xx..
xx = = + + zz.05.05
= 15 + 1.645(6)= 15 + 1.645(6)
= 24.87 or 25= 24.87 or 25
xx = = + + zz.05.05
= 15 + 1.645(6)= 15 + 1.645(6)
= 24.87 or 25= 24.87 or 25
A reorder point of 25 gallons will place the probabilityA reorder point of 25 gallons will place the probability of a stockout during leadtime at (slightly less than) .05.of a stockout during leadtime at (slightly less than) .05.
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Solving for the Reorder PointSolving for the Reorder Point
PepZone5w-20
Motor Oil
By raising the reorder point from 20 gallons to By raising the reorder point from 20 gallons to 25 gallons on hand, the probability of a stockout25 gallons on hand, the probability of a stockoutdecreases from about .20 to .05.decreases from about .20 to .05. This is a significant decrease in the chance that PepThis is a significant decrease in the chance that PepZone will be out of stock and unable to meet aZone will be out of stock and unable to meet acustomer’s desire to make a purchase.customer’s desire to make a purchase.
Standard Normal Probability DistributionStandard Normal Probability Distribution
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Exponential Probability DistributionExponential Probability Distribution
The exponential probability distribution is The exponential probability distribution is useful in describing the time it takes to useful in describing the time it takes to complete a task.complete a task.
The exponential random variables can be used The exponential random variables can be used to describe:to describe:
Time betweenTime betweenvehicle arrivalsvehicle arrivalsat a toll boothat a toll booth
Time betweenTime betweenvehicle arrivalsvehicle arrivalsat a toll boothat a toll booth
Time requiredTime requiredto completeto complete
a questionnairea questionnaire
Time requiredTime requiredto completeto complete
a questionnairea questionnaire
Distance betweenDistance betweenmajor defectsmajor defectsin a highwayin a highway
Distance betweenDistance betweenmajor defectsmajor defectsin a highwayin a highway
SLOW
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Density FunctionDensity Function
Exponential Probability DistributionExponential Probability Distribution
where: where: = mean = mean
ee = 2.71828 = 2.71828
f x e x( ) / 1
f x e x( ) / 1
for for xx >> 0, 0, > 0 > 0
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Cumulative ProbabilitiesCumulative Probabilities
Exponential Probability DistributionExponential Probability Distribution
P x x e x( ) / 0 1 o P x x e x( ) / 0 1 o
where:where:
xx00 = some specific value of = some specific value of xx
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Exponential Probability DistributionExponential Probability Distribution
Example: Al’s Full-Service PumpExample: Al’s Full-Service Pump
The time between arrivals of carsThe time between arrivals of carsat Al’s full-service gas pump followsat Al’s full-service gas pump followsan exponential probability distributionan exponential probability distributionwith a mean time between arrivals of with a mean time between arrivals of 3 minutes. Al would like to know the3 minutes. Al would like to know theprobability that the time between two successiveprobability that the time between two successivearrivals will be 2 minutes or less.arrivals will be 2 minutes or less.
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xx
f(x)f(x)
.1.1
.3.3
.4.4
.2.2
1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10Time Between Successive Arrivals (mins.)Time Between Successive Arrivals (mins.)
Exponential Probability DistributionExponential Probability Distribution
PP((xx << 2) = 1 - 2.71828 2) = 1 - 2.71828-2/3-2/3 = 1 - .5134 = .4866 = 1 - .5134 = .4866 PP((xx << 2) = 1 - 2.71828 2) = 1 - 2.71828-2/3-2/3 = 1 - .5134 = .4866 = 1 - .5134 = .4866
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Exponential Probability DistributionExponential Probability Distribution
A property of the exponential distribution is thatA property of the exponential distribution is that the mean, the mean, , and standard deviation, , and standard deviation, , are equal., are equal. A property of the exponential distribution is thatA property of the exponential distribution is that the mean, the mean, , and standard deviation, , and standard deviation, , are equal., are equal.
Thus, the standard deviation, Thus, the standard deviation, , and variance, , and variance, 22, for, forthe time between arrivals at Al’s full-service pump are:the time between arrivals at Al’s full-service pump are:
= = = 3 = 3 minutesminutes
2 2 = (3) = (3)2 2 = 9 = 9
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Exponential Probability DistributionExponential Probability Distribution
The exponential distribution is skewed to the right.The exponential distribution is skewed to the right. The exponential distribution is skewed to the right.The exponential distribution is skewed to the right.
The skewness measure for the exponential distributionThe skewness measure for the exponential distribution is 2.is 2. The skewness measure for the exponential distributionThe skewness measure for the exponential distribution is 2.is 2.
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Relationship between the PoissonRelationship between the Poissonand Exponential Distributionsand Exponential Distributions
The Poisson distributionThe Poisson distributionprovides an appropriate descriptionprovides an appropriate description
of the number of occurrencesof the number of occurrencesper intervalper interval
The Poisson distributionThe Poisson distributionprovides an appropriate descriptionprovides an appropriate description
of the number of occurrencesof the number of occurrencesper intervalper interval
The exponential distributionThe exponential distributionprovides an appropriate descriptionprovides an appropriate description
of the length of the intervalof the length of the intervalbetween occurrencesbetween occurrences
The exponential distributionThe exponential distributionprovides an appropriate descriptionprovides an appropriate description
of the length of the intervalof the length of the intervalbetween occurrencesbetween occurrences
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End of Chapter 6End of Chapter 6