1 | P a g e Program: T.E. (ELECTRONICS AND TELECOMMUNICATION) Curriculum Scheme: Revised 2012(CBSGS) Examination: Third Year Semester VI Course Code: ETC606 and Course Name: VLSI Design Time: 1hour Max. Marks: 50 ============================================================================== SAMPLE MCQ Note to the students:- All the Questions are compulsory and carry equal marks . Q1. Which type of CMOS circuits are good and better? Option A: p well Option B: n well Option C: P+ well Option D: N+well Q2. Wrong readings are recorded due to reset input being Option A: dependent of clock signal Option B: independent of clock signal Option C: dependent of gate signal Option D: independent of gate signal Q3. The fast rise and fall times give cross-talk problems if Option A: they are in close proximity Option B: if they are far away Option C: it always gives rise to cross-talk problems Option D: does not allow cross-talk problems Q4. With partitioning, bypassing is performed using Option A: buffers Option B: multiplexers Option C: multipliers Option D: dividers Q5. In which of the memories, does the data disappear? Option A: SRAM Option B: DRAM Option C: Flash memory Option D: EPROM Q6. What does VRAM stand for? Option A: video RAM Option B: Verilog RAM Option C: virtual RAM Option D: volatile RAM
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Note to the students:- All the Questions are compulsory and carry equal marks .
Q1. Which type of CMOS circuits are good and better?Option A: p wellOption B: n wellOption C: P+ wellOption D: N+well
Q2. Wrong readings are recorded due to reset input beingOption A: dependent of clock signalOption B: independent of clock signalOption C: dependent of gate signalOption D: independent of gate signal
Q3. The fast rise and fall times give cross-talk problems ifOption A: they are in close proximityOption B: if they are far awayOption C: it always gives rise to cross-talk problemsOption D: does not allow cross-talk problems
Q4. With partitioning, bypassing is performed usingOption A: buffersOption B: multiplexersOption C: multipliersOption D: dividers
Q5. In which of the memories, does the data disappear?Option A: SRAMOption B: DRAMOption C: Flash memoryOption D: EPROM
Q6. What does VRAM stand for?Option A: video RAMOption B: Verilog RAMOption C: virtual RAMOption D: volatile RAM
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Q7. The dynamic component of power dissipation is given by:Option A: P = I2.RdOption B: P = Vdd2/RdOption C: P = Eg.foOption D: P=VI
Q8. Contact cuts are made in ____________Option A: sourceOption B: drainOption C: metal layerOption D: diffusion layer
Q9. Which is used for the interconnection?Option A: boronOption B: oxygenOption C: aluminumOption D: silicon
Q10. Maximum transit time occurs when the size of the transistor isOption A: minimumOption B: maximumOption C: does not depend on sizeOption D: double
Q11. The breakdown voltage can be reduced by _____ electric field strengthOption A: increasingOption B: decreasingOption C: does not dependOption D: exponentially decreasing
Q12. Which level of system implementation includes the specific function oriented registers, counters & multiplexers?
Q13. Which among the following is/are taken into account for post-layout simulation?Option A: Interconnect delaysOption B: Propagation delaysOption C: Logic cellsOption D: Logic gates
Q14. In MOS devices, the current at any instant of time is ______of the voltage across their terminals.
Q15. The scaling factor of power dissipation per unit area in constant field model is:Option A: 1Option B: 1/α2
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Option C: 1/ β.α2
Option D: α2/β2
Q16. The transit time can be given asOption A: 2dOption B: 2d/µEOption C: µE/dOption D: µE/2d
Q17. Which is the commonly used bulk substrate in nMOS fabrication?Option A: silicon crystalOption B: silicon-on-sapphireOption C: phosphorusOption D: silicon-di-oxide
Q18. Source and drain in nMOS device are isolated by ____Option A: single diodeOption B: two diodesOption C: Three diodesOption D: four diodes
Q19. Which of the following is the main factor which determines the memory capacity?Option A: number of transistorsOption B: number of capacitorsOption C: size of the transistorOption D: size of the capacitor
Q20. Who proposed the miniature card format?Option A: IntelOption B: IBMOption C: MIPSOption D: Apple
Q21. In which method regularity is used to reduce complexity?Option A: random approachOption B: hierarchical approachOption C: algorithmic approachOption D: semi-design approach
Q22. The serial shift register is driven usingOption A: one over-lapping clockOption B: two over-lapping clockOption C: one non over-lapping clockOption D: two non over-lapping clock
Q23. Which is not the function of LSSD method?Option A: eliminates hazardsOption B: eliminates racesOption C: simplifies fault generationOption D: stores the data
Q24. Pass transistor can be driven through _____ pass transistors.Option A: one
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Option B: noOption C: moreOption D: two
Q25. Which of the following can access data even when the power supply is lost?Option A: Non-volatile SRAMOption B: DRAMOption C: SRAMOption D: RAM
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Program: TE EXTC Engineering
Curriculum Scheme: Revised 2012
Examination: Third Year Semester VI
Course Code: ETC604 and Course Name: Television EngineeringTime: 1 hour Max. Marks: 50
Note to the students:- All the Questions are compulsory and carry equal marks .
Q1. In Composite Video signal 0 to 10% isOption A: Darker than DarkOption B: DarkOption C: Whiter than whiteOption D: White
Q2. The period of Front porch is Option A: 5.2µsOption B: 52µsOption C: 5.8µsOption D: 1.5µs
Q3. In America in NTSC system the lines per frame isOption A: 625Option B: 525Option C: 25Option D: 50
Q4. For sound modulation what is usedOption A: FMOption B: AMOption C: PMOption D: SM
Q5. In an Electron Gun Grid 2 is also called asOption A: Screen gridOption B: Control gridOption C: Focusing gridOption D: Magnetic grid
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Q6. CCIR stands forOption A: Consolidated committee for International RadioOption B: Consultative committee for International RadioOption C: Compiled committee for International RadioOption D: Cognitive committee for International Radio
Q7. In Subtractive mixing of colours white - Blue =Option A: MagentaOption B: YellowOption C: CyanOption D: violet
Q8. 0.3R+0.59G+0.11B=Option A: YOption B: IOption C: UOption D: V
Q9. MPEG & JPEG stands forOption A: Moving photographic Expert group & Joint photography Extended GroupOption B: Moving picture Expert group & Joint photographic Expert GroupOption C: Multiple picture Expert group & Joint picture Expert GroupOption D: Moving photographic Extraction group & Joint photographic Extraction Group
Q10. Which of the following is a picture tubeOption A: OrthiconOption B: VidiconOption C: PlumbiconOption D: Trintron
Q11. CVS stands forOption A: Composite video signalOption B: Colour vestigial signalOption C: Compose Vestigial signalOption D: Common video signal
Q12. The colour burst is of Option A: 2 to 12 cyclesOption B: 5 to 15 cyclesOption C: 0 to 30 cyclesOption D: 8 to 11 cycles
Q13. The difference in intensity between black and white parts of the picture over and above the brightness level is
Option A: Aspect RatioOption B: Brightness Ratio
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Option C: ContrastOption D: Contrast Ratio
Q14. ………………. Is a special application in which camera signals are made available over cable circuits to a specified destinations
Q15. In the 625-B monochrome TV the field frequency isOption A: 50Option B: 128Option C: 60Option D: 64
Q16. In America(NTSC) the line frequency in Hz isOption A: 15625Option B: 625Option C: 525Option D: 15750
Q17. The colour system used in FranceN(SECAM) uses which sound signal modulationOption A: AMOption B: FMOption C: PMOption D: CM
Q18. In HDTV standard the aspect ratio isOption A: 4:3Option B: 16:9Option C: 21:9Option D: 16:20
Q19. The predominant spectral colour of the received light is Option A: BrightnessOption B: HUEOption C: LuminanceOption D: Saturation
Q20. In subtractive mixing white – green =Option A: MagentaOption B: YellowOption C: CyanOption D: Black
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Q21. Frequency deviation / modulating frequencyOption A: Modulating toneOption B: Channel BandwidthOption C: Bessel functionOption D: Modulation index
Q22. In …………….picture tube there are three guns aligned in horizontal lineOption A: Delta gunOption B: PILOption C: TrintronOption D: Vidicon
Q23. Which of the following is not a type of sampling and sub samplingOption A: 4:0:0Option B: 4:4:4Option C: 4:1:1Option D: 4:2:2
Q24. The highest approximate modulating frequency that 625 lines TV system must be capable of handling for successful transmission and reception of signal is
Note to the students:‐ All the Questions are compulsory and carry equal marks .
Q1. The Z-Transform X(z) of a discrete time signal x(n) is defined as ____________
Option A:
Option B:
Option C:
Option D:
Q2. What is the z-transform of the signal x(n)= u(n)? Option A: ; ROC |z|> 0.5
Option B: ; ROC |z|< 0.5
Option C: ; ROC |z|> 0.5
Option D: ; ROC |z|< 0.5
Q3. The complex valued twiddle factor can be represented as Option A: e-i(2π/N) Option B: e-i(2πN) Option C: e-i2π Option D: e-i2πkN Q4. Overlap-Add Method Deals with principles that Option A: The linear convolution of a discrete-time signal of length L and a discrete-time
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signal of length M produces a discrete-time convolved result of length L + M - 1
Option B: The linear convolution of a discrete-time signal of length L and a discrete-time signal of length M produces a discrete-time convolved result of length L + M
Option C: The linear convolution of a discrete-time signal of length L and a discrete-time signal of length M produces a discrete-time convolved result of length 2L +M-1
Option D: The linear convolution of a discrete-time signal of length L and a discrete-time signal of length M produces a discrete-time convolved result of length 2L + 2M – 1
Q5. DIT algorithm divides the sequence into Option A: Positive and negative values Option B: Even and odd samples Option C: Upper higher and lower spectrum Option D: Small and large samples Q6. Convolution of two discrete time sequences (n) and (n) is equivalent to Option A: (K)* (K) Option B: (K)* (K)} Option C: (K)* (K)}/N Option D: (K)* (K)} Q7. The condition for the impulse response to be anti-symmetric is Option A: h(n)= -h(N-1-n) Option B: h(n)= h(N-1-n) Option C: h(n)= -h(N+1-n) Option D: h(n)= h(N--n) Q8. The DFT of sequence x(n)={1,3,2,0} is Option A: { 6, -2+i2 , 2, -2-i2} Option B: { 6, 2-i2 , 2, 2+i2} Option C: { 6, -2-i2 , 2, -2+i2} Option D: { 6, -2+i2 , 2, -2+i2} Q9. Linear convolution y(n) of sequences x(n)={1,2} and h(n)={2,1} Option A: {5,5,2} Option B: {5,2,5} Option C: {2,2,5} Option D: {2,5,2} Q10. For a linear phase filter, if Z1 is zero then what would be the value of Z1
-1 or 1/ Z1?
Option A: Zero Option B: Unity
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Option C: Infinity Option D: Unpredictable Q11. In an N point sequence , if N=16 , the total number of complex additions and
multiplications using Radix-2 FFT are Option A: 64 and 80 Option B: 80 and 64 Option C: 64 and 32 Option D: 24 and 12 Q12. With n-bit binary the possible binary codes are Option A: Option B: Option C: Option D: Q13. The down sampling is called as Option A: Decimation Option B: Interpolation Option C: Filtering Option D: Shifting Q14. To avoid aliasing at output during decimation by D ,the input signal of decimator
should be band-limited to Option A:
Option B:
Option C:
Option D:
Q15. Which of the following is true with respect to rounding error ? Option A: Rounding error of a positive number is always negative. Option B: Rounding error of a negative number is always positive. Option C: Rounding error is same in all the formats of fixed point representation. Option D: Rounding error is zero. Q16. If x(n) and y(n) are input and output of an interpolator with sampling rate
conversion factor B ,then Option A: y(n)=x(Bn) Option B: y(n)=x(n)/B Option C: y(n)=x(n/B) Option D: y(n)=x(n)B Q17. A Linear phase FIR filter has response given by the order of the filter will
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be
Option A: 5 Option B: 4 Option C: 6 Option D: 3 Q18. Specification of analog filter for Butterworth Approximation Option A: tan
Option B: tan
Option C: tan
Option D: tan
Q19. The disadvantage of impulse invariant method is that mapping from analog
frequency ‘ ’ to digital frequency ‘w’ is Option A: One to one Option B: Many to many Option C: One to many Option D: Many to one Q20. The impulse response of FIR filter is given by h(n)={1,-5,6}. The filter is Option A: Minimum phase Option B: Maximum phase Option C: Mixed phase Option D: Zero phase Q21. The group delay is the delayed response of filter as a function of Option A: Phase Option B: Frequency Option C: Amplitude Option D: length Q22. All zeros are lying outside the unit circle ,then filter is Option A: Maximum phase Option B: Minimum phase Option C: Mixed phase Option D: Unity phase Q23. Condition for digital filter to be causal and stable Option A: Poles should lie outside the unit circle Option B: Zeros ≥ poles Option C: Poles should lie on the circle Option D: Poles should lie inside the unit circle
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Q24. In Chebyshev Type-1 filter Option A: The poles lies on square Option B: The poles lies on circle Option C: The poles lies on ellipse Option D: The poles lies on rectangle Q25. The inverse Fourier transform Option A: converts from the frequency domain to the time domain Option B: converts from the time domain to the frequency domain Option C: converts from the phasor domain to the magnitude domain Option D: is used to make real-time spectrum analyzers
Program: BE Electronics & Telecommunication Engineering
Curriculum Scheme: CBSGS Revised 2012
Examination: Third Year Semester VI
Subject Code: ETC601 and Subject Name: Digital Communication