Prof. David R. Jackson ECE Dept. Spring 2014 Notes 36 ECE 6341 1.

1

Prof. David R. JacksonECE Dept.

Spring 2014

Notes 36

ECE 6341

2

Radiation Physics in Layered Media

Note: TMz and also TEy (since )0z

00 0

0

11

4y x

z

jk y jk xTEx x

y

A

Ik e e dk

j k

For y > 0:

ˆ ,zE z E x y

y

0Ix

rh

Line source on grounded substrate

3

Reflection Coefficient

0

0

TE TEin x xTE

x TE TEin x x

Z k Z kk

Z k Z k

1 1tanTE TEin x yZ k jZ k h

01

1

TE

y

Zk

1/ 22 2

1 1y xk k k

where

00

0

TE

y

Zk

1/ 22 2

0 0y xk k k

00TEZ

01TEZ

I V+ -

z

4

Poles

Poles:

0

0

TE TEin x xTE

x TE TEin x x

Z k Z kk

Z k Z k

0TE TEin xp xpZ k Z k

This is the same equation as the TRE for finding the wavenumber of a surface wave:

kxp = roots of TRE = kxSW

x xpk k

0TE SW TE SWin x xZ k Z k 00

TEZ

01TEZ

I V+ -

z

5

If a slight loss is added, the SW poles are shifted off the real axis as shown.

Poles (cont.)

Complex kx plane

Cxrk

xik

SW0k1k0k1k

SW

x xr xik k jk

6

Poles (cont.)

C

xrk

xik

0k1k

0k1k

For the lossless case, two possible paths are shown here.

C

xrk

xik

0k1k

0k1k

7

Review of Branch Cuts and Branch Points

In the next few slides we review the basic concepts of branch points and branch cuts.

8

Consider 1/ 2f z z jz r e

1/21/2 /2j jz r e r e

1z 0 : 1/2 1z

2 : 1/2 1z

4 : 1/2 1z

There are two possible values.

Choose

Branch Cuts and Points (cont.)

9

The concept is illustrated for 1/ 2f z z jz r e

1/ 2 / 2jz r e

x

y

AB C

r = 1

Consider what happens if we encircle the origin:


10


1/ 2 / 2jz r e

1/2

A 0 1

B +

C 2 -1

z

j

point

We don’t get back the same result!

x

y

AB C

r = 1

11

Now consider encircling the origin twice:

1/ 2 / 2jz r e

1/2

A 0 1

B +

C 2 -1

D 3 -

E 4 1

z

j

j

point

We now get back the same result!

Hence the square-root function is a double-valued function.


x

y

AB CD

E

r = 1

r

12

In order to make the square-root function single-valued, we must put a “barrier” or “branch cut”.

The origin is called a branch point: we are not allowed to encircle it if we wish to make the square-root function single-valued.

x

Branch cut

y

Here the branch cut was chosen to lie on the negative real axis (an arbitrary choice)


13

We must now choose what “branch” of the function we want.

jz r e 1/ 2 / 2jz r e

x

Branch cut

y

1z 1/ 2 1z


This is the "principle" branch, denoted by z

MATLAB :

14

Here is the other choice of branch.

jz r e 1/ 2 / 2jz r e

x

Branch cut

y

3

1z 1/ 2 1z


15

Note that the function is discontinuous across the branch cut.

jz r e 1/ 2 / 2jz r e

x

Branch cut

y

1z 1/2 1z

1,z

1,z

1/ 2z j

1/ 2z j


16

The shape of the branch cut is arbitrary.

jz r e 1/ 2 / 2jz r e

x

Branch cut

y

/ 2 3 / 2

1z 1/2 1z


17

The branch cut does not even have to be a straight line

jz r e 1/ 2 / 2jz r e

In this case the branch is determined by requiring that the square-root function (and hence the angle ) change continuously as we start from a specified value (e.g., z = 1).

x

Branch cut

y

1z 1/2 1z

1z 1/ 2z j

z j 1/ 2 / 4 1 / 2jz e j

z j

1/ 2 / 4 1 / 2jz e j


18

Consider this function:

1/ 22( ) 1f z z


What do the branch points and branch cuts look like for this function?

(similar to our wavenumber function)

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1/ 2 1/ 21/ 2 1/ 2 1/ 22( ) 1 1 1 1 1f z z z z z z


x

y

1

1

There are two branch cuts: we are not allowed to encircle either branch point.

20

1/ 21/ 2 1/ 2 1/ 21 2( ) 1 1f z z z w w


Geometric interpretation

x

y

1

11w

2w

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1 2/ 2 / 21 2( ) j jf z r e r e

1

2

1 1

2 2

1

( 1)

j

j

w z r e

w z r e

The function f (z) is unique once we specify its value at any point. (The function must change continuously away from this point.)

21

Riemann Surface

Georg Friedrich Bernhard Riemann (September 17, 1826 – July 20, 1866) was an influential German mathematician who made lasting contributions to analysis and differential geometry, some of them enabling the later development of general relativity.

The function z1/2 is continuous everywhere on this surface (there are no branch cuts). It also assumes all possible values on the surface.

The Riemann surface is really multiple complex planes connected together.

The function z1/2 has a surface with two sheets.

http://en.wikipedia.org/wiki/File:Georg_Friedrich_Bernhard_Riemann.jpeg

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Riemann Surface

The concept of the Riemann surface is illustrated for

1/ 2f z z

( 1 1)

3 ( 1 1)

Top sheet:

Bottom sheet:

Consider this choice:

jz r e

23

Riemann Surface (cont.)x

y

BD

Top

Bottom

BD

D

B

B

Dside view

x

y

top view

24

Riemann Surface (cont.)

Bottom sheet

Top sheet

Branch cut

(where it used to be)

Branch point

25

Riemann Surface (cont.)

x

y

AB CD

EBD

Connection betweensheets

1/2

A 0 1

B +

C 2 -1

D 3 -

E 4 1

z

j

j

point

r = 1

26

Branch Cuts in Radiation Problem

Now we return to the original problem:

1

2 2 20 0y xk k k

00 0

0

11

4y x

z

jk y jk xTEx x

y

A

Ik e e dk

j k

Note: There are no branch points from ky1:

1

2 2 21 1y xk k k 1 1tanTE TE

in x yZ k jZ k h 01

1

TE

y

Zk

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Branch Cuts

1 1 12 2 2 2 2

0 0 0 0

1 1

2 20 0

y x x x

x x

k k k k k k k

j k k k k

Branch points appear at 0xk k

No branch cuts appear at 1xk k (The integrand is an even function of ky1.)

Note: It is arbitrary that we have factored out a –j instead of a +j, since we have not yet determined the meaning of the square roots.

28

Branch Cuts (cont.)

1 1

2 20 0 0y x xk j k k k k

Cxrk

xik

0k

0k

1k1k

Branch cuts are lines we are not allowed to cross.

29

For 0

0 0

,x

y y

k k

k j k

real

xrk

xik

0k

0k

Choose

0

0

arg 0

arg 0

x

x

k k

k k

This choice then uniquely defines ky0

everywhere in the complex plane.

1/22 20 0y xk k k

1 1

2 20 0 0y x xk j k k k k

Branch Cuts (cont.)

at this point

0 0y yk j k

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For

0

,

0x

x

k

k k

real we have

0

0

arg

arg 0

x

x

k k

k k

/ 20 0 0

jy x xk j k k e k k

0 0y yk k

Hence

Branch Cuts (cont.)

xik

xrk0k 0k

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Riemann Surface

1/22 20 0y xk k k

There are two sheets, joined at the blue lines.

xik

xrk

0k

0k

Top sheet

Bottom sheet

0 0y yk j k

0 0y yk j k

32

Proper / Improper Regions

Let

“Proper” region:

0 0 0

x xr xik k jk

k k jk

1

2 2 20 0y xk k k

“Improper” region:

0

0

Im 0

Im 0

y

y

k

k

Boundary: 0Im 0yk

2 2 20 0 real >0y xk k k

The goal is to figure out which regions of the complex plane are "proper" and "improper."

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Proper / Improper Regions (cont.)

Hence

One point on curve:

2 2 2 20 0 0 02 2 real 0xr xi xr xik k k k j k k k k

0 0xr xik k k k

0

0

xr

xi

k k

k k

xik

0k

0 k

xrk

2

2

0 0 real 0xr xik jk k jk

Therefore

0 0 0xk k k jk

(hyperbolas)

0 0 0k k jk

34


Also2 2 2 2

0 0 0xr xik k k k

xik

0k

0 k

xrk

The solid curves satisfy this condition.

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Complex plane: top sheet

xik

0k

0 k

xrk

Improper region

Proper

On the complex plane corresponding to the bottom sheet, the proper and improper regions are reversed from what is shown here.


36

Sommerfeld Branch Cuts

Complex plane corresponding to top sheet: proper everywhereComplex plane corresponding to bottom sheet: improper everywhere

xik

0k

0 k

xrk

Hyperbola

37

Sommerfeld Branch Cuts

Note: We can think of a single complex plane with branch cuts, or a Riemann surface with hyperbolic-shaped “ramps” connecting the two sheets.

xik

0k

0 k

xrk

Riemann surface

xik

0k

0 k

xrk

Complex plane

The Riemann surface allows us to show all possible poles, both proper (surface-wave) and improper (leaky-wave).

38

Sommerfeld Branch Cut

Let

xik

0k

0 k

xrk

0 0k

The branch cuts now lie along the imaginary axis, and part of the real axis.

39

Path of Integration

xik

0k

0 k

xrk

1k

1 kC

The path is on the complex plane corresponding to the top Riemann sheet.

40

Numerical Path of Integration

xik

0k

0 k

xrk1k

1 k

C

41

Leaky-Mode Poles

(improper)

0

0Im 0

LW LWin x x

y

Z k Z k

k

Note: TM0 never becomes improper

Review of frequency behavior

xik

0k

xrk1k

cf f

SW

ISW

LW

0f

sf f

TRE:

Bottom sheet

42

Riemann Surface

xik

0k

0 k

xrk1k

1 kC

SWPLWP

BP

0 0Re LWxpk k k

The LW pole is then “close” to the path on the Riemann surface (and it usually makes an important contribution).

We can now show the leaky-wave poles!

LW LW LWxpk j

ReLW LWxpk

43

SW and CS Fields

Total field = surface-wave (SW) field + continuous-spectrum (CS) field

xik

0k

xrk1k

SWLW

bC

CS fieldSW field

pC

Note: The CS field indirectly accounts for the LW pole.

44

Leaky Waves

LW poles may be important if

0 0Re LWxpk k k

0Im xpk k

Physical Interpretation

Re( )LWLW xpk

0

leaky wave

radiation

0 0sinLW k

The LW pole is then “close” to the path on the

Riemann surface.

45

Improper Nature of LWs

The rays are stronger near the beginning of the wave: this gives us exponential growth vertically.

Region of strong leakage fields

LWxpk j

“leakage rays”

46

Improper Nature (cont.)Mathematical explanation of exponential growth (improper behavior):

Equate imaginary parts:

12 2 2

0 0

2 220 0

2 220

LW LWy xp

LW LWy xp

y y

k k k

k k k

j k j

y y

yy

(improper)0 0y

Prof. David R. Jackson ECE Dept. Spring 2014 Notes 36 ECE 6341 1.

Documents

choice of branch

principle branch

review of branch cuts

arbitrary choice branch

function z

grounded substrate slide

wavenumber function

function f z