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Copyright 2001, Agrawal & Bushne ll VLSI Test: Lecture 13/12a lt 1 Lecture 13 Sequential Circuit ATPG Time-Frame Expansion (Lecture 12alt in the Alternative Sequence) Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic ATPG implementation and drivability Complexity of ATPG Cycle-free and cyclic circuits Asynchronous circuits Summary and Exercise
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Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

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Lecture 13 Sequential Circuit ATPG Time-Frame Expansion (Lecture 12alt in the Alternative Sequence). Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic ATPG implementation and drivability Complexity of ATPG Cycle-free and cyclic circuits Asynchronous circuits - PowerPoint PPT Presentation
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Page 1: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 1

Lecture 13Sequential Circuit ATPGTime-Frame Expansion

(Lecture 12alt in the Alternative Sequence)

Lecture 13Sequential Circuit ATPGTime-Frame Expansion

(Lecture 12alt in the Alternative Sequence)

Problem of sequential circuit ATPG Time-frame expansion

Nine-valued logic ATPG implementation and drivability Complexity of ATPG Cycle-free and cyclic circuits Asynchronous circuits

Summary and Exercise

Page 2: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 2

Sequential CircuitsSequential Circuits

A sequential circuit has memory in addition to combinational logic.

Test for a fault in a sequential circuit is a sequence of vectors, which

Initializes the circuit to a known state Activates the fault, and Propagates the fault effect to a primary output

Methods of sequential circuit ATPG Time-frame expansion methods Simulation-based methods

Page 3: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 3

Example: A Serial Adder

Example: A Serial Adder

FF

An Bn

Cn Cn+1

Sn

s-a-0

11

1

1

1

X

X

X

D

D

Combinational logic

Page 4: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 4

Time-Frame ExpansionTime-Frame Expansion

An Bn

FF

Cn Cn+1

1X

X

Sn

s-a-011

1

1

D

D

Combinational logicSn-1

s-a-011

1

1 X

D

D

Combinational logic

Cn-1

1

1

D

D

X

An-1 Bn-1 Time-frame -1 Time-frame 0

Page 5: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 5

Concept of Time-Frames

Concept of Time-Frames

If the test sequence for a single stuck-at fault contains n vectors,

Replicate combinational logic block n times Place fault in each block Generate a test for the multiple stuck-at fault using

combinational ATPG with 9-valued logic

Comb.block

Fault

Time-frame

0

Time-frame

-1

Time-Frame- n+1

Unknownor givenInit. state

Vector 0Vector – 1 Vector – n +1

PO 0PO – 1 PO – n +1

Statevariables

Nextstate

Page 6: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 6

Example for Logic Systems

Example for Logic Systems

FF2

FF1

A

B

s-a-1

Page 7: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 7

Five-Valued Logic (Roth)0,1, D, D, X

Five-Valued Logic (Roth)0,1, D, D, X

A

B

X

X

X

0

s-a-1

D

A

B

X X

X

0

s-a-1

D

FF1 FF1

FF2 FF2D D

Time-frame -1 Time-frame 0

Page 8: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 8

Nine-Valued Logic (Muth)0,1, 1/0, 0/1, 1/X, 0/X, X/0, X/1,

X

Nine-Valued Logic (Muth)0,1, 1/0, 0/1, 1/X, 0/X, X/0, X/1,

XA

B

X

X

X

0

s-a-1

0/1

A

B

0/X 0/X

0/1

X

s-a-1X/1

FF1 FF1

FF2 FF20/1 X/1

Time-frame -1 Time-frame 0

Page 9: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 9

Implementation of ATPG

Implementation of ATPG

Select a PO for fault detection based on drivability analysis. Place a logic value, 1/0 or 0/1, depending on fault type and

number of inversions. Justify the output value from PIs, considering all necessary

paths and adding backward time-frames. If justification is impossible, then use drivability to select

another PO and repeat justification. If the procedure fails for all reachable POs, then the fault is

untestable. If 1/0 or 0/1 cannot be justified at any PO, but 1/X or 0/X can

be justified, the the fault is potentially detectable.

Page 10: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 10

Drivability ExampleDrivability Example

d(0/1) = 4d(1/0) =

(CC0, CC1)= (6, 4)

s-a-1

(4, 4)

(10, 15)(11, 16)

(10, 16)(22, 17)

(17, 11)(5, 9)

d(0/1) = 9d(1/0) = d(0/1) = 109

d(1/0) =

d(0/1) = 120d(1/0) = 27

d(0/1) = d(1/0) = 32

(6, 10) 8

8

8

8

FF

d(0/1) = d(1/0) = 20

8

CC0 and CC1 are SCOAP combinational controllabilities

d(0/1) and d(1/0) of a line are effort measures for driving a specific fault effect to that line

Page 11: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 11

Complexity of ATPGComplexity of ATPG Synchronous circuit -- All flip-flops controlled by clocks; PI and

PO synchronized with clock: Cycle-free circuit – No feedback among flip-flops: Test

generation for a fault needs no more than dseq + 1 time-frames, where dseq is the sequential depth.

Cyclic circuit – Contains feedback among flip-flops: May need 9Nff time-frames, where Nff is the number of flip-flops.

Asynchronous circuit – Higher complexity!

Time-Frame

0

Time-Framemax-1

Time-Framemax-2

Time-Frame

-2

Time-Frame

-1

S0S1S2S3Smax

max = Number of distinct vectors with 9-valued elements = 9Nff

Page 12: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 12

Cycle-Free CircuitsCycle-Free Circuits

Characterized by absence of cycles among flip-flops and a sequential depth, dseq.

dseq is the maximum number of flip-flops on any path between PI and PO.

Both good and faulty circuits are initializable. Test sequence length for a fault is bounded by

dseq + 1.

Page 13: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 13

Cycle-Free ExampleCycle-Free Example

F1

F2

F3

Level = 1

2

F1

F2

F3

Level = 1

2

3

3

dseq = 3s - graph

Circuit

All faults are testable in this circuit.

Page 14: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 14

Cyclic Circuit ExampleCyclic Circuit Example

F1 F2CNTZ

Modulo-3 counter

s - graph

F1 F2

Page 15: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 15

Modulo-3 CounterModulo-3 Counter

Cyclic structure – Sequential depth is undefined. Circuit is not initializable. No tests can be

generated for any stuck-at fault. After expanding the circuit to 9Nff = 81, or fewer,

time-frames ATPG program calls any given target fault untestable.

Circuit can only be functionally tested by multiple observations.

Functional tests, when simulated, give no fault coverage.

Page 16: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 16

Adding Initializing Hardware

Adding Initializing Hardware

F1 F2CNTZ

Initializable modulo-3 counter

s - graph

F1 F2

CLR

s-a-0

s-a-1

s-a-1s-a-1 Untestable faultPotentially detectable faults

Page 17: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 17

Benchmark CircuitsBenchmark CircuitsCircuitPIPOFFGatesStructureSeq. depthTotal faultsDetected faultsPotentially detected faultsUntestable faultsAbandoned faultsFault coverage (%)Fault efficiency (%)Max. sequence lengthTotal test vectorsGentest CPU s (Sparc 2)

s1196 14 14 18 529

Cycle-free 412421239 0 3 0

99.8 100.0

3 313 10

s1238 14 14 18 508

Cycle-free 413551283 0 72 0

94.7 100.0

3 308 15

s1488 8 19 6 653

Cyclic--

14861384 2 26 76

93.1 94.8

24 52519941

s1494 8 19 6 647

Cyclic--

15061379 2 30 97

91.6 93.4

28 55919183

Page 18: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 18

Asynchronous CircuitAsynchronous Circuit An asynchronous circuit contains unclocked memory

often realized by combinational feedback. Almost impossible to build, let alone test, a large

asynchronous circuit. Clock generators, signal synchronizers, flip-flops are

typical asynchronous circuits. Many large synchronous systems contain small

portions of localized asynchronous circuitry. Sequential circuit ATPG should be able to generate

tests for circuits with limited asynchronous parts, even if it does not detect faults in those parts.

Page 19: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 19

Asynchronous ModelAsynchronous Model

ClockedFlip-flops

Feedbackdelays

Synchronous PIs

Synchronous POs

SystemClock, CK

Fast modelClock, FMCK

CK

CK

Feedback-freeCombinational

Logic

C

CombinationalFeedback Paths:

Feedback set

Modeling circuit isShown in orange.

PPOPPI

Page 20: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 20

Time-Frame ExpansionTime-Frame Expansion

Time-frame kTime-frame

-k+1Time-frame

-k-1

CFMCK

CFMCK

CFMCK

CCK

Asynchronous feedbackstabilization

PI

PO

FeedbacksetPPI PPO

Feedbackset

Vector k

Page 21: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 21

Asynchronous ExampleAsynchronous Example

s-a-0

s-a-0

s-a-0

s-a-0

s-a-0s-a-0

s-a-0

s-a-1

1

0

1

1

0

0

0

1

Vectors1 2 3 4

1

0

1

X

X

0

1

0

1

1

0

1

Outputs1 2 3 4Gentest results:

Faults: total 23, detected 15, untestable 8 (shown in red), potentially detectable noneVectors: 4Sparc 2 CPU time: test generation 33ms, fault simulation 16ms

Page 22: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 22

SummarySummary Combinational ATPG algorithms are extended:

Time-frame expansion unrolls time as combinational array Nine-valued logic system Justification via backward time

Cycle-free circuits: Require at most dseq + 1 time-frames Always initializable

Cyclic circuits: May need 9Nff time-frames Circuit must be initializable Partial scan can make circuit cycle-free (Chapter 14)

Asynchronous circuits: High complexity Low coverage and unreliable tests Simulation-based methods are more useful (Section 8.3)

Page 23: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 23

ExerciseExercise Which type of circuit is easier to test? Circle one in each:

Combinational or sequential Cyclic or cycle-free Synchronous or asynchronous

What is the maximum number of input vectors that may be needed to initialize a cycle-free circuit with k flip-flops?

Page 24: Problem of sequential circuit ATPG Time-frame expansion Nine-valued logic

Copyright 2001, Agrawal & Bushnell

VLSI Test: Lecture 13/12alt 24

Answers to ExerciseAnswers to Exercise Which type of circuit is easier to test? Circle one in

each: Combinational or sequential Cyclic or cycle-free Synchronous or asynchronous

What is the maximum number of input vectors that may be needed to initialize a cycle-free circuit with k flip-flops?

k vectors. Because that is the maximum sequential depth possible. An example is a k bit shift register.