3. PERENCANAAN IKATAN ANGINDiketahui :W angin : 30 kg/mc Angin tekan : 0.2c Angin Hisap : 0.4L (jarak kuda - kuda) : 3 mJarak horisontal antar gording : 2 m 30cos : 0.87sin 0.5R (jarak miring antar gording : 2.29885057 mh (jarak vertikal gording x 2) 2.29885057 m - Beban angin pada kuda - kuda W : c. w.h 27.5862069 - Mutu Baja 37fu : 370 Mpa : 37 kg/mm2fy :240 Mpa : 24 kg /mm2R1 : R2 = 0,5 . W. L 41.3793103tg =0.56 :24.7cos : 0.9 - Gaya yang bekerja pada ikatan angin :S1 = S2 : 45.9770115Nu = 1,3 . S : 59.7701149 kgNu= 0,9 (Ag.fy)59.77011494 = 0,9 (Ag.24)Ag= 2.767134951 mm2Ag= 1/4 . .d22.767134951 = 1/4..d2d2 = 3.525012676d = 1.88 mmNu= 0,75 (0,75.Ag)fu59.77011494 = 0,75 (0,75.Ag) 3759.77011494 = 21 . AgAg= 2.871837355 mm2Ag= 1/4 . .d22.871837355 = 1/4 . .d2d2 = 3.658391535d= 1.91 mm =Dari dua hasil kombinasi Nu tersebut di ambil yang terbesar, jadi untuk Ikatan Angin ini dipakai profil baja bulat dengan Diameter0,75 inc0,75 incJarak antar kuda-kuda (a) = 3 m cos 30 = 0.866(b) = 1.5 m sin 30 = 0.5Panjang setengah kuda-kuda (c ) = 10 m(d) = 2 m(e) = 1.5 m(f) = 30 1c/10 = 1 = mCos 30 0.866Dicoba profil C 3x4.1Berat = 6.2 kg/m Ix = 69.1 cm4Wx = 21 cm3 Iy = 8.2 cm4Wy = 7 cm3= 37 fu = 370 Mpafy = 240 Mpa1-= 11 kg/m2= 12.7- = 6.2qd = 18.9- qdy ==- qdx ==2W Angin = 30 kg/mh = R x sin = m- = 0.02-0.4 - Koefisien angin hisap= 0.2 - Wx Hisap- = cTekan x W x h= 3.46 kg/m- Wy Tekan = 03 Beban HujanH = (40-0.8x)R - Hy= 12.3 kg/m- Hx4 Beban HidupDimensi GordingJarak Miring Gording ( R )jarak trekstang (jarak antar gording)Panjang tritisankemiringan atapMutu BajaBeban MatiPenutup AtapW asbesqd x sin 309.451039261 kg/m1.154734411W penutup Atap x R kg/mBeban sendiri kg/mkg/m0.577367206Wx Tekanqd x cos 3016.3692 kg/mBeban AnginKoefisien angin tekanP = 100 kg- Px = P cos 30= 86.6 kg- Py = P sin 30= 50 kgBidang MomenI = 2 mI2 = 4 m- MDlx = 1/8.qx.I2= 8.1846 kgm- MWtknx = 1/8.Wtkn.I2= 1.7321 kgm- Mwisapx = 1/8.Wisap.I2= 3.4642- Mhjnx = 1/8.Hx.I2= 5.32 kgm- MLx = 1/4.Px.I= 43.3 kgmKombinasi pembebanan- 1.4D = 11.46 kgm- 1.2D+1.6L+0.5La = 39.98 kgm- 1.2D+1.6La+0.8W = 21.10 kgm- 1.2D+1.3W+0.5La = 16.98 kgm- 1,2D+1,3W+0,5L+0,5 La = 38.635 kgmDari kombinasi pembebanan di atas beban yang terbesar =Mux = kgmMux < MnMn tergantung pada kelangsingan batang ( )Diketahui : tf = 6.93 mmtw = 4.32 mmfy = 240 Mpafu = 370 MpaFlens : b/(2 . Tf) = 0.1p : 170/Fy = 11r : 370/FY-fr = 28Badan : hw/tw = 18p : 1680/Fy = 108r : 2250/Fy = 145jika p maka Mn=Mp*Z*Fy dimana Z=1,15Sjika p 6.40E-03Koefisien angin hisap = 0.4= cHisap x W x h= 6.9 kg/m= H x sin 30= 6.1 kg/m= H x cos 30= 11 kg/m39.98 kgmh = 76.2 mmb = 35.814 mmW = 18025.77 mm3L = 3 m (jarak kuda-kuda)E = 2E+10 N/m2qx = 16.3692 kg/mqy = 9.45104 kg/mPx = 87 kgPy = 50 kgL = 1.5 m (jarak trekstang)Ix = 69.1 cm4 6.91E-07 m4Iy = 8.2 cm4 8.20E-08 m42 PERENCANAAN TREKSTANG- Atap Asbes = 11 Kg/m- Hujan = ( 40 - 0.8 ) R18 Kg/m- Jarak Trekstang = 1.5 m- Jarak Miring antar gording = 2 m- Mutu Baja 37 fu = 370 MpaFy = 240 MpaBeban Gording = q gording x a (jarak antar Trekstang= 9.3 kgBeban Atap = q atap x a x b= 27.9 kgD = Beban Gording + Beban Atap= 37 kg= 1.4D= 52 kgNu = P . Sin = 50 Kgfy = 240 Mpa 24fu = 370 Mpa 37Nunx buxnuMMNN| |+22 , 0 (((
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