1 PERATURAN PEMARKAHAN BIOLOGI KERTAS 3 _ 2018 MPSM KEDAH QUESTION QUESTION QUESTION QUESTION 1 No No No No Mark Mark Mark Mark Scheme Scheme Scheme Scheme Score Score Score Score KB0603 KB0603 KB0603 KB0603 - Measuring Measuring Measuring Measuring Using Using Using Using Number Number Number Number 1(a) Able Able Able Able to to to to record record record record all all all all 6 readings readings readings readings for for for for the the the the diameter diameter diameter diameter of of of of balloon balloon balloon balloon 1 and and and and balloon balloon balloon balloon 2 correctly correctly correctly correctly Sample answer The concentration of sucrose solution, % Number of air bubbles release in 5 minutes 0.5 5 1.0 13 1.5 17 3 Able Able Able Able to to to to record record record record any any any any 4-5 4-5 4-5 4-5 readings readings readings readings correctly correctly correctly correctly 2 Able Able Able Able to to to to record record record record any any any any 2-3 2-3 2-3 2-3 reading reading reading reading correctly correctly correctly correctly 1 No No No No response response response response or or or or incorrect incorrect incorrect incorrect response response response response 0 Scoring Scoring Scoring Scoring for for for for observation observation observation observation and and and and inference inference inference inference Correct Inaccurate Idea Wrong Score 2 - - - 3 1 1 - - 2 - 2 - - 1 - 1 - 1 - - 2 - 1 - - 1 - 1 1 - - 1 - 1 0 - - 1 1 KBO6O1 KBO6O1 KBO6O1 KBO6O1 - Observation Observation Observation Observation (b) (i) Able Able Able Able to to to to state state state state two two two two different different different different observations observations observations observations correctly correctly correctly correctly P1 - Concentration of sucrose solution P2 – Number of air bubbles release in 5 minutes Sample Answers Horizontal observation: 1.In 0.5% sucrose solution, the tnumber of air bubbles release is 5 2.In 1.5% sucrose solution , the number of air bubbles release is 17 Vertical observation: 1. The number of air bubble release in 5 minutes in 1.5% is the highest compared to in 0.5% and 1.0% of sucrose solution. 2. When the concentration of sucrose solution used increases, the number of air bubbles release in 5 minutes increases. 3 Able Able Able Able to to to to state state state state one one one one observation observation observation observation correctly correctly correctly correctly and and and and two two two two inaccurate inaccurate inaccurate inaccurate observations. observations. observations. observations. Sample answers 1. In 0.5% sucrose solution, the number of air bubbles release is lower 2. The number of air bubbles release in 5 minutes is 17 in higher 2
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P1 - Concentration of sucrose solutionP2 – Number of air bubbles release in 5 minutesSample AnswersHorizontal observation:1.In 0.5% sucrose solution, the tnumber of air bubbles release is 52.In 1.5% sucrose solution , the number of air bubbles release is 17Vertical observation:1. The number of air bubble release in 5 minutes in 1.5% is the highest
compared to in 0.5% and 1.0% of sucrose solution.2. When the concentration of sucrose solution used increases, the number
of air bubbles release in 5 minutes increases.
3
AbleAbleAbleAble totototo statestatestatestate oneoneoneone observationobservationobservationobservation correctlycorrectlycorrectlycorrectly andandandand twotwotwotwo inaccurateinaccurateinaccurateinaccurateobservations.observations.observations.observations.Sample answers1. In 0.5% sucrose solution, the number of air bubbles release is lower2. The number of air bubbles release in 5 minutes is 17 in higher
concentration of sucrose solutionAbleAbleAbleAble totototo statestatestatestate thethethethe observationsobservationsobservationsobservations atatatat ideaideaideaidea levellevellevellevelSample answer1. In high concentration of sucrose solution, the number of air bubbles
release is higher2. The number of air bubbles release is depends on the concentration of
AbleAbleAbleAble totototo makemakemakemake twotwotwotwo inferencesinferencesinferencesinferences correctlycorrectlycorrectlycorrectlyCriteria:P1 : Infer on concentration of sucrose solution – less sugar/ nutrientP2 : Infer on number of air bubbles release – more/less gas producedP3 : activity in yeast/anaerobic respiration/growth less/more
Sample answers1. In lower concentration of sucrose solution, less sugar/nutrient content,
so the number of air bubbles /carbon dioxide release is lower ,activityin yeast/ anaerobic respiration/growth of yeast is lower.
2. In higher concentration of sucrose solution, more sugar/nutrientcontent, so the number of air bubbles release/ carbon dioxide producedis higher, activity in yeast/anaerobic respiration/ growth of yeast ishigher.
KBO6KBO6KBO6KBO6 10101010 ---- ControllingControllingControllingControlling variablesvariablesvariablesvariables(c) Able to state all 3 variables and 3 methods to handle the variable.
UseUseUseUse differentdifferentdifferentdifferent concentration of sucrose (solution)ChangeChangeChangeChange 0.5% sucrose solution with 1.0% and1.5% of sucrose solutionUseUseUseUse variousvariousvariousvarious concentration of sucrose solution
Responding variableThe number of airbubbles release in 5minutes
The rate activity inyeast
RecordRecordRecordRecord the number of air bubbles release byusing stopwatch
CalculateCalculateCalculateCalculate the rate of activity in yeast byusing formula= the number of air bubbles release
Time takenControlled variable
Volume of sucrosesolution
Volume of warmwater
Temperature
Amount of yeast
FixFixFixFix the volume of sucrose solution, 30 ml.
Sample answer1. The number of air bubble release increases.
1
NoNoNoNo responseresponseresponseresponse orororor incorrectincorrectincorrectincorrect responseresponseresponseresponseIf no P1 and P2, no mark for H 0
R1 - Able to state the relationshipR2 – more nutrients/ sucrose concentrationR3 - more gas producedSample answerThe rate of activity in yeast in 1.5% sucrose solution is the highest comparedto the rate activity in yeast in 1.0% and 1.5% of sucrose solution becausemore nutrient / sucrose concentration is used. So, more gas / carbon dioxideis produced .
criteria:criteria:criteria:criteria:Pl – An anaerobic respiration which produced gasP2- Shown by the number of bubbles release in 5 minutesP3 – Affected by the concentration of sucrose solutionSample answerActivity in yeast is an anaerobic respiration /growth in yeast that produced gas/ carbon dioxide which is shown by the number of bubbles release in 5minutes. The activity in yeast is affected by the concentration of sucrosesolution
KB0605KB0605KB0605KB0605 ---- PredictingPredictingPredictingPredicting(h) Able to predict correctly and explain the prediction based on the following
criteria:El - predict the rate of activity in yeastE2 – reason – carbon dioxide is acidic mediumE3 - more growth / activity in yeast //anaerobic respiration
Sample answerThe rate of activity in yeast is more than 3.4min-1 because the activity in yeastis suitable in acidic medium . So more growth / activity in yeast // anaerobicrespiration
Sample answer:1. How does colour camouflage help in the survival of a species2. What is the effect of colour camouflage to the species?3. What factor affects the survival of a species?
C1: colour camouflage / the difference in colours between the clothand button
C2: survival of a species / the number of contrasting button choosenH : Relationship
Sample answer:1. The greater the difference in colours between the cloth and
button, the greater the number of contrasting button choosenSemakin ketara perbezaan warna antara kain dengan butang,semakin banyak butang berkontras yang dipilih
Piece of black, white and multicoloured floral cloth measuring 50cmX 50cm, 20 black buttons, 20 white buttons, 20 yellow buttons, 20red buttons and 20 blue buttonsKain berwarna hitam, putih, dan berwarna-warni yang berukuran50cm X 50cm, 20 butang hitam, 20 butang putih, 20 butang kuning,20 butang merah dan 20 butang biru
Apparatus:Radas
TileJubin
3
Able to list out 5-7 Materials and 1 Apparatus correctly 2
Able to list out 2-4 Materials and 1 Apparatus correctly 1
K1 : Setting apparatus (at least 4 steps / 4K1)K2 : Operating constant variable ( 1 K2)K3 : Operating responding variable ( 1 K3 )K4 : Operating manipulated variable ( 1 K4 )K5 : Precaution or procedure to get accurate result ( 1 K5)
AbleAbleAbleAble totototo statestatestatestate allallallall thethethethe 5555 KKKK1. Students work in pairs.
Murid bekerja secara berpasangan
2. Students X turns and faces the wall of the laboratoryMurid X berdiri mengadap dinding makmal
3. Students Y scatters various coloured buttons randomly on apiece of white clothMurid Y menabur butang yang berlainan warna secararawak di atas kain berwarna putih
4. Students X turns quickly and picks a button to put on a tileMurid X berpusing dengan cepat dan memilih satu butanglalu meletakkannya di atas jubin
5. Repeat steps 4 nine timesUlang langkah 4 sebanyak sembilan kali
6. Repeat step 2 to 5 using a black cloth followed by amulticoloured floral clothUlang langkah 2 hingga 5 dengan menggunakan kainberwarna hitam diikuti dengan kain berwarna-warni
7. Record the number of buttons of each colour taken from eachpiece of cloth in a tableRekodkan bilangan butang untuk setiap warna yang diambildaripada setiap kain dalam satu jadual
K1, K2
K4
K1, K3
Able to state 3K - 4 K 2Able to state 1K - 2 K 1No response or wrong answer 0
2(vi) AbleAbleAbleAble totototo tabulatetabulatetabulatetabulate aaaa tabletabletabletable containingcontainingcontainingcontaining thethethethe followingfollowingfollowingfollowing aspects:aspects:aspects:aspects:T : title with correct unitsS : value of manipulated variablesSample data:
Colour ofbuttons
Warnabutang
Colourof clothWarna kain
Number of buttons pickedBilangan butang yang dipilih
BlackHitam
WhitePutih
YellowKuning
RedMerah
BlueBiru
WhitePutih
BlackHitam
MulticolouredBerwarna-warni
2
Able to state any one aspect 1No response or wrong answer 0
How does colour camouflage help in the survival of a species?Bagaimanakah penyamaran warna dapat membantu kemandirian spesies?
HypothesisHipotesis
The greater the difference in colours between the cloth and button, the greater the number ofcontrasting button choosenSemakin ketara perbezaan warna antara kain dengan butang, semakin banyak butangberkontras yang dipilih
VariablesPembolehubah
Manipulated variables : Colour of clothPembolehubah dimanipulasikan: Warna kain
Responding variables:Pembolehubah bergerakbalas
Number of button chosenBilangan butang yang dipilih
Constant Variables:Pembolehubah dimalarkan
Size of cloth, the same student choosing the buttonsSaiz kain, murid yang memilih butang
Materials:Bahan
Piece of black, white and multicoloured floral cloth measuring 50cm X 50cm, 20 black buttons,20 white buttons, 20 yellow buttons, 20 red buttons and 20 blue buttonsKain berwarna hitam, putih, dan berwarna-warni yang berukuran 50cm X 50cm, 20 butanghitam, 20 butang putih, 20 butang kuning, 20 butang merah dan 20 butang biru
1. Students work in pairs.Murid bekerja secara berpasangan
2. Students X turns and faces the wall of the laboratoryMurid X berdiri mengadap dinding makmal
3. Students Y scatters various coloured buttons randomly on a piece of white clothMurid Y menabur butang yang berlainan warna secara rawak di atas kain berwarnaputih
4. Students X turns quickly and picks a button to put on a tileMurid X berpusing dengan cepat dan memilih satu butang lalu meletakkannya di atasjubin
5. Repeat steps 4 nine timesUlang langkah 4 sebanyak sembilan kali
6. Repeat step 2 to 5 using a black cloth followed by a multicoloured floral clothUlang langkah 2 hingga 5 dengan menggunakan kain berwarna hitam diikuti dengankain berwarna-warni
7. Record the number of buttons of each colour taken from each piece of cloth in a tableRekodkan bilangan butang untuk setiap warna yang diambil daripada setiap kain dalamsatu jadual
Presentation of dataPersembahan data
Colour of buttonsWarna butang
Colourof clothWarna kain
Number of buttons pickedBilangan butang yang dipilih