PATTERN QUESTION * *** ***** ******* ********* We have shown five rows above, in the program you will be asked to enter the numbers of rows you want to print in the pyramid of stars. C programming code #include<stdio.h> main() { int row, c, n, temp; printf("Enter the number of rows in pyramid of stars you wish to see "); scanf("%d",&n); temp = n; for ( row = 1 ; row <= n ; row++ ) { for ( c = 1 ; c < temp ; c++ ) printf(" "); temp--; for ( c = 1 ; c <= 2*row - 1 ; c++ ) printf("*"); printf("\n"); }//loop end return 0; }
31

# Pattern Question C-1

Dec 08, 2015

## Documents

AnjaliSaxena

pattern of C

#### pattern question

Welcome message from author
Transcript

PATTERN QUESTION

* *** ***** ****************

We have shown five rows above, in the program you will be asked to enter the numbers of rows you want to print in the pyramid of stars.

C programming code

#include<stdio.h> main(){ int row, c, n, temp;  printf("Enter the number of rows in pyramid of stars you wish to see "); scanf("%d",&n);  temp = n;  for ( row = 1 ; row <= n ; row++ ) { for ( c = 1 ; c < temp ; c++ ) printf(" ");  temp--;  for ( c = 1 ; c <= 2*row - 1 ; c++ ) printf("*");  printf("\n"); }//loop end  return 0;}

Program to print   the pattern

***************

Program Code:

#include<stdio.h> main(){ int n, c, k;  printf("Enter number of rows\n"); scanf("%d",&n);  for ( c = 1 ; c <= n ; c++ ) { for( k = 1 ; k <= c ; k++ ) printf("*");  printf("\n"); } //end of loop  }

Program to print the below number pattern11 21 2 31 2 3 4

Program Code:

#include<stdio.h>

main(){      int number = 1, n, c, k;

printf("Enter number of rows\n");

scanf("%d",&n);

for ( c = 1 ; c <= n ; c++ )    {         for( k = 1 ; k <= c ; k++ )        {           printf("%d ", number);           number++;         }

number = 1;

printf("\n");    } getch();

}

Program to print

* * * * ** * ** **

Program Code:

#include<stdio.h>

main(){    int n, c, k, temp;

printf("Enter number of rows\n");    scanf("%d",&n);

temp = n;

for ( c = 1 ; c <= n ; c++ )   {        for( k = 1 ; k <= temp ; k++ )            printf("* ");

temp--;

printf("\n");   }//end of outer for loopgetch();

}

Program to print the below pattern

* ** *** **** *****

Program Code:

#include<stdio.h> main(){ int n, c, k, space;  printf("Enter number of rows\n"); scanf("%d",&n);  space = n;  for ( k = 1 ; k <= n ; k++ ) { for ( c = 1 ; c < space ; c++ ) printf(" ");  space--;   for( c = 1 ; c <= k ; c++ ) printf("*");  printf("\n"); }  return 0;

}

Program to get output 1 232 34543 4567654 567898765 Program Code:

#include<stdio.h> main(){ int n, c, d, num = 1, space;  scanf("%d",&n);  space = n - 1;  for ( d = 1 ; d <= n ; d++ ) { num = d;  for ( c = 1 ; c <= space ; c++ ) printf(" ");  space--;  for ( c = 1 ; c <= d ; c++ ) { printf("%d", num); num++; } num--; num--; for ( c = 1 ; c < d ; c++) { printf("%d", num); num--; } printf("\n");

}  return 0;}

program to get the output as follows:

1121123211234321123454321

Program Code:

#include<stdio.h> main(){ int n, c, k, x = 1;  scanf("%d", &n);  for ( c = 1 ; c <= n ; c++ ) { for ( k = 1 ; k <= c ; k++ ) { printf("%d", x); x++; }  x--;  for ( k = 1 ; k <= c - 1 ; k++ ) { x--; printf("%d", x); }  printf("\n"); x = 1; }  return 0;}

Write a Program to print

12345678901234567890-----

----

Program Code:

main(){    int i,j,n,temp;        printf("enter number of lines");        scanf("%d",&n);   j=n*4;

for(i=0,temp=0;i<j;i++,temp++)    {        if(temp!=4)        {                printf("%d",i%10);        }        else        {             printf("\n%d",i%10);             temp=0;        }     }return 0;}

Write a Program to Print

* * * * * ** * * *

Program Code:

/* This is a simple mirror-image of a right angle triangle */

#include<stdio.h>int main() { char prnt = '*'; int i, j, nos = 4, s; for (i = 1; i <= 5; i++) { for (s = nos; s >= 1; s--) { // Spacing factor printf(" "); } for (j = 1; j <= i; j++) { printf("%2c", prnt); } printf("\n"); --nos; // Controls the spacing factor } return 0;}

Write a Program to Print

* *

* * * * * *

* * * * * * * * * *

* * * * * * * * * * *

Program Code:

#include<stdio.h>int main() { char prnt = '*'; int i, j, k, s, c = 1, nos = 9; for (i = 1; c <= 4; i++) { // As we want to print the columns in odd sequence viz. 1,3,5,.etc if ((i % 2) != 0) { for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (s = nos; s >= 1; s--) { //The spacing factor if (c == 4 && s == 1) { break; } printf(" ");

} for (k = 1; k <= i; k++) { if (c == 4 && k == 5) { break; } printf("%2c", prnt); } printf("\n"); nos = nos - 4; // controls the spacing factor ++c; } } return 0;}

Write a Program to Print* *

* *

* * * *

* * * *

* * * * *

* * * *

* * * *

* *

* *

Program code:

#include<stdio.h>int main() { char prnt = '*'; int i, j, k, s, p, r, nos = 7;

for (i = 1; i <= 5; i++) { for (j = 1; j <= i; j++) { if ((i % 2) != 0 && (j % 2) != 0) { printf("%3c", prnt); }

else if ((i % 2) == 0 && (j % 2) == 0) { printf("%3c", prnt); } else { printf(" "); } } for (s = nos; s >= 1; s--) { // for the spacing factor printf(" "); } for (k = 1; k <= i; k++) { //Joining seperate figures if (i == 5 && k == 1) { continue; } if ((k % 2) != 0) { printf("%3c", prnt); } else { printf(" "); } } printf("\n"); nos = nos - 2; // space control } nos = 1; // remaining half.. for (p = 4; p >= 1; p--) { for (r = 1; r <= p; r++) { if ((p % 2) != 0 && (r % 2) != 0) { printf("%3c", prnt); } else if ((p % 2) == 0 && (r % 2) == 0) { printf("%3c", prnt);

} else { printf(" "); } } for (s = nos; s >= 1; s--) { printf(" "); } for (k = 1; k <= p; k++) { if ((k % 2) != 0) { printf("%3c", prnt); }else { printf(" "); } } nos = nos + 2; // space control printf("\n"); } return 0;}

Write a Program to Print

* * * * *

* * * *

* * *

* *

*

* *

* * *

* * * *

* * * * *

Program code:

#include<stdio.h>int main() {

char prnt = '*'; int i, j, s, nos = 0; for (i = 9; i >= 1; (i = i - 2)) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { if ((i % 2) != 0 && (j % 2) != 0) { printf("%2c", prnt); } else { printf(" "); } } printf("\n"); nos++; } nos = 3; for (i = 3; i <= 9; (i = i + 2)) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) {

if ((i % 2) != 0 && (j % 2) != 0) { printf("%2c", prnt); } else { printf(" "); } } nos--; printf("\n"); } return 0;}

Write a C program to print the following pattern:

*

* * *

* * * * *

* * * * * * *

* * * * * * * * *

* * * * * * *

* * * * *

* * *

*

* * *

* * * * *

Program Code:

#include<stdio.h>int main() { char prnt = '*'; int i, j, k, s, nos = 4; for (i = 1; i <= 5; i++) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (k = 1; k <= (i - 1); k++) { if (i == 1) { continue; } printf("%2c", prnt); } printf("\n"); nos--; } nos = 1; for (i = 4; i >= 1; i--) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (k = 1; k <= (i - 1); k++) { printf("%2c", prnt); } nos++;

printf("\n"); } nos = 3; for (i = 2; i <= 5; i++) { if ((i % 2) != 0) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { printf("%2c", prnt); } } if ((i % 2) != 0) { printf("\n"); nos--; } } return 0;}

Write a C program to print the following pattern:

*

* *

* * *

* * * *

* * *

* *

*

Program Code:/* This can be seen as two right angle triangles sharing the same base which is modified by adding few extra shifting spaces*/#include<stdio.h>// This function controls the inner loop and the spacing// factor guided by the outer loop index and the spacing index.int triangle(int nos, int i) {

char prnt = '*'; int s, j; for (s = nos; s >= 1; s--) { // Spacing factor printf(" "); } for (j = 1; j <= i; j++) { //The inner loop printf("%2c", prnt); } return 0;}

int main() { int i, nos = 5; //draws the upper triangle for (i = 1; i <= 4; i++) { triangle(nos, i); //Inner loop construction nos++; // Increments the spacing factor printf("\n"); } nos = 7; //Draws the lower triangle skipping its base. for (i = 3; i >= 1; i--) { int j = 1; triangle(nos, i); // Inner loop construction nos = nos - j; // Spacing factor printf("\n"); } return 0;}

Write a C program to print the following pattern:

* * * * * * * * *

* * * * * * * *

* * * * * *

* * * *

* *

* * * *

* * * * * *

* * * * * * * *

* * * * * * * * *

Program Code:

#include<stdio.h>

int main() { char prnt = '*'; int i, j, k, s, nos = -1; for (i = 5; i >= 1; i--) { for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (s = nos; s >= 1; s--) { printf(" "); } for (k = 1; k <= i; k++) { if (i == 5 && k == 5) { continue; } printf("%2c", prnt); } nos = nos + 2; printf("\n"); } nos = 5; for (i = 2; i <= 5; i++) { for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (s = nos; s >= 1; s--) { printf(" "); } for (k = 1; k <= i; k++) { if (i == 5 && k == 5) { break; } printf("%2c", prnt); } nos = nos - 2; printf("\n"); } return 0;}

Write a C program to print the following pattern:

* * * * * * * * * * * * * * * * *

* * * * * * * * * * * * * *

* * * * * * * * * *

* * * * * *

* * * * * * * * *

* * * * * * *

* * * * *

* * *

*

Program code:

#include<stdio.h>int main() { char prnt = '*'; int i, j, k, s, sp, nos = 0, nosp = -1; for (i = 9; i >= 3; (i = i - 2)) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (sp = nosp; sp >= 1; sp--) { printf(" "); } for (k = 1; k <= i; k++) { if (i == 9 && k == 1) { continue; } printf("%2c", prnt); } nos++; nosp = nosp + 2; printf("\n"); } nos = 4;

for (i = 9; i >= 1; (i = i - 2)) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { printf("%2c", prnt); } nos++; printf("\n"); }

return 0;}

Write a C program to print the following pattern:

*

* * *

* * * * *

* * * * * * *

* *

* * * *

* * * * * *

* * * * * * *

* * * * * *

* * * *

* *

* * * * * * *

* * * * *

* * *

*

Program code:

#include<stdio.h>/* * nos = Num. of spaces required in the triangle. * i = Counter for the num. of charcters to print in each row * skip= A flag for checking whether to * skip a character in a row. *

*/int triangle(int nos, int i, int skip) { char prnt = '*'; int s, j; for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { if (skip != 0) { if (i == 4 && j == 1) { continue; } } printf("%2c", prnt); } return 0;}

int main() { int i, nos = 4; for (i = 1; i <= 7; (i = i + 2)) { triangle(nos, i, 0); nos--; printf("\n"); } nos = 5; for (i = 1; i <= 4; i++) { triangle(1, i, 0); //one space needed in each case of the formation triangle(nos, i, 1); //skip printing one star in the last row. nos = nos - 2; printf("\n"); } nos = 1; for (i = 3; i >= 1; i--) { triangle(1, i, 0); triangle(nos, i, 0); nos = nos + 2; printf("\n"); } nos = 1;

for (i = 7; i >= 1; (i = i - 2)) { triangle(nos, i, 0); nos++; printf("\n"); } return 0;}

Write a C program to print the following pattern:

* * * * * * * * * * * * * * * * * * * * * * * * *

* * * * * *

* * * * * *

* * * * * *

* * *

* * * * * *

* * * * * *

* * * * * *

* * * * * * * * * * * * * * * * * * * * * * * * *

Program code:

#include<stdio.h>

/* * nos = Num. of spaces required in the triangle. * i = Counter for the num. of characters to print in each row * skip= A flag for check whether to * skip a character in a row. * */

int triangle(int nos, int i, int skip) { char prnt = '*'; int s, j; for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { if (skip != 0) {

if (i == 9 && j == 1) { continue; } } if (i == 1 || i == 9) { printf("%2c", prnt); } else if (j == 1 || j == i) { printf("%2c", prnt); } else { printf(" "); } } return 0; } int main() { int i, nos = 0, nosp = -1, nbsp = -1; for (i = 9; i >= 1; (i = i - 2)) { triangle(nos, i, 0); triangle(nosp, i, 1); triangle(nbsp, i, 1); printf("\n"); nos++; nosp = nosp + 2; nbsp = nbsp + 2; } nos = 3, nosp = 5, nbsp = 5; for (i = 3; i <= 9; (i = i + 2)) { triangle(nos, i, 0); triangle(nosp, i, 1); triangle(nbsp, i, 1); printf("\n"); nos--; nosp = nosp - 2; nbsp = nbsp - 2; }

return 0;}

Write a Program to print 5

5 4

5 4 3

5 4 3 2

5 4 3 2 1

Program code:

main() { int i,j;

for(i=5;i>=1;i--) { for(j=5;j>=i;j--) { printf("%d",j);

}

printf("\n"); } }

Write a program to print 333

22

1

Program code:main(){ int i,a=5,j;

for(i=5;i>=1;i--) { for(j=1;j<=i;j++) { printf("%d",i);

} printf(" "); } }

Write a program to print

1

22

333

4444

55555

Program code:main() { int n, c, k;

printf("Enter number of rows\n"); n=5;

for ( c = 1 ; c <= n ; c++ ) { for( k = 1 ; k <= c ; k++ ) printf("%d",c);

printf("\n"); }

}

Program to print the below number pattern

1 2 3 4 5 2 3 4 5 3 4 5 4 5 5Program Code:

#include<stdio.h>> void main() { int i,j,n; clrscr();

printf("enter the no \n"); scanf("%d",&n);

for(i=1;i<=n;i++) { for(j=i;j<=n;j++) { printf("%d",j); } //innner loop printf("\n"); }//outer loop

}

C program to print a pattern like below:

* * * * * * * * *

Program Code:

main () {     int i,j,k;                            for (i=1; i<=10; i+=2)          {                                                  for(k=10; k > i; k-=2)   /* small inner loop for the spaces */                  {                                  printf(" ");                  }                  for (j=0; j <i; j++)                  {

if(j==0)

printf("*");

else if(j==i-1)

printf("*");

printf(" ");

} /* end of inner loop */              printf("\n"); /* new line */         } /* End of outer loop */  }

Program to print the below pattern of numbers101101010110101

int main(){ int n, i, c, a = 1;  printf("Enter the number of rows of Floyd's triangle to print\n"); scanf("%d", &n);  for (i = 1; i <= n; i++) { for (c = 1; c <= i; c++) { printf("%d ",a); a++; } printf("\n"); }  return 0;

Write a Program to print the following pattern1 1 0 0 1 0 0 1 0 1 1 0 1 0 1

int main(){      int n=5, i, c, a =1;

clrscr();      for (i = 1; i <= n; i++)     {          for (c = 1; c <= i; c++)          {                         printf("%d ",a%2);                         a++;           }//inner for loop

printf("\n");          a=a-1;    }//outer for loop

return 0;}

Write a program to print :

#include<stdio.h>/*calling the header files*/int main(){ int i,j,k,n,c,c1=0; /*initializing the variables which are needed*/ printf("Please enter the rows for the right and led triangle \n"); scanf("%d",&n); /*Loop for the upper part of the pattern*/  for(i=n;i>=1;i--)  {  c=64;  for(j=1;j<=i;j++)  {  printf("%c",c+j);  }  for(k=n;k>i;k--)  {  printf(" ");  }  c=65+n-c1;  for(j=1;j<=i;j++)  {  printf("%c",c-j);

}  c1++;  printf("\n"); } /*loop for lower part */ c1=2;  for(i=2;i<=n;i++)  {  c=64;  for(j=1;j<=i;j++)  {  printf("%c",c+j);  }  for(k=i;k<n;k++)  {  printf(" ");  }  c=65+c1; for(j=1;j<=i;j++) { printf("%c",c-j); } c1++; printf("\n"); } return 0; }

C Program To Perform Character Design :

# # # # #

# # # #

# # #

# #

#

/* Declaration Of Header Files */ #include<stdio.h>#include<conio.h>

/* Start Of Main Program */int main(){

/* Declaration Of Variables */ int num, row = 1, col = 0, space = 0;

/* Asking For The Input From User */ printf(" \n Enter Number of Rows For Design : ");  scanf("%d",&num);

/* Source Code For Computing ----- */ for(; num>=1; num--, row++) {  for(space = row; space>1; space--)     printf(" ");  for(col=1; col<=num; col++)    printf("#");  printf("\n"); } getch(); return 0;}/* End Of Main Program */

Output :~

Enter Number of Rows For Design :  5

# # # # # # # # #  # # #   # #    #

C program to print 5555554444543335432254321

Code:

#include<stdio.h>void main(){    int i,j,n,k;   clrscr();

printf("enter the no \n");   scanf("%d",&n);

for(i=5;i>=1;i--)   {         for(j=n;j>=i;j--)       {              printf("%d",j);       } //innner loop

for(k=j;k>=1;k--)           printf("%d",j+1);

printf("\n");    }//outer loop

}