Oct27

Oct 27th

Lab12.String methods

Debugging

http://www.slideshare.net/takyeon

String methods

String str = "studytonight";

System.out.println(str.charAt(2)); // => u

charAt(int i) returns the character at the index i position

String a = "a";

String b = "b";

System.out.println(a.compareTo(b)); // => -1

System.out.println(b.compareTo(a)); // => 1

System.out.println(a.compareTo(a)); // => 0

a.compareTo(b) compares a and b lexicographically.

String methods

String str = "The quick brown fox jumps over the lazy dog";

System.out.println(str.indexOf('u')); // => 5

System.out.println(str.indexOf('&')); // => -1

System.out.println(str.indexOf(' ')); // => 3

System.out.println(str.indexOf(' ',3)); // => 3

System.out.println(str.indexOf(' ',4)); // => 9

a.indexOf(int ch) returns the first index of ch within a

a.indexOf(String s) returns the first index of s within a

a.indexOf(int ch, int fromIndex)

returns the first index of ch within a, starting search at the fromIndex

String methods

String str = "1-2-3-4-5";

System.out.println(str.replace('-',' ')); // => "1 2 3 4 5"

a.replace(char oldCh, char newCh)

returns a new string resulting from replacing all oldCh in a with newCh

String str = "aaaaa";

System.out.println(str.replace('a','b')); //=> "bbbbb"

System.out.println(str.replace("aa","b")); //=> "bba"

System.out.println(str.replace("aaa","a")); //=> "aaa"

a.replace(CharSequence o, CharSequence n)

returns a new string resulting from replacing all o in a with n

Can be CharBuffer, Segment, String, StringBuffer, StringBuilder

Newly added string will not be evaluated.

String methods

String str = "0-2-4-6-8";

System.out.println(str.substring(4)); // => "4-6-8"

a.substring(int beginIndex)

returns a new string from beginIndex till the end

String str = "0-2-4-6-8";

System.out.println(str.substring(4,8)); // => "4-6-"

a.substring(int beginIndex, int endIndex)

returns a new string from beginIndex (inclusive) till endIndex (exclusive)

http://codingbat.com/java

DebuggingTrace program's behavior line-by-line

Step 1. Set "break point" at the suspicious line

Step 2. Run the debugger

next line into

Step 3.

- Examine the contents of memory- Decide how to proceed with running/debugging the program by either stepping "over", "into", or "out of" code segments

out of

Debugging

Conditional breakpoint

Oct 20th

Lab11.Mid-term #1 review

Javadoc


Midterm review

Regrading request

- Write it on a separate sheet of paper

- Hand it in to professor with your exam.

- The entire exam will be regraded.

- Will our culture really be defined by interfaces?

- What "uses" are there for information visualization interms of explaining things to the general public.

- Mechanical Turk* ethics (pay is below US minimum wage)* what would they want to do using Mechanical Turk* origins of the name (interesting con around a chess playing

machine around 200 years ago)

- Art and Computer Science* can CS people create art? can Art people create CS?* what ideas do they have in terms of CS changing the Art world* ask if any of them have been to the 3rd floor of CSIC and seen

the Treemap art gallery

Javadoc: Java Documentation Comments

Javadoc is a tool which comes with JDK and it is used for generating Java code documentation in HTML format from Java source code which has required documentation in a predefined format.

source code

generated documentation web page

block comment that starts with /**

@tagName to add special tags

Javadoc: Java Documentation Comments

@param Adds a parameter with the specified parameter-name followed by the specified description to the "Parameters" section.@return Adds a "Returns" section with the description text. @return description@see Adds a "See Also" heading with a link or text entry that points to reference.@throws Adds a Throws subheading to the generated documentation, with the class-name and description text..

Oct 13th

Lab09.Stack, Heap, and Metaspace


public class Student {

public String name;

public int tokenLevel;

private static int currentCount = 0;

private static final int DEFAULT_TOKENS = 3;

public Student() {

name = "unknown";

tokenLevel = DEFAULT_TOKENS;

currentCount++;

}

}

Student s1 = new Student();

s1.name = "Tak";

STACK HEAP META SPACE

DEFAULT_TOKENS

0

3

currentCount 1 Xs1

name

tokenLevel 3

"unknown"

"Tak"

constructor

All static fields of a class live in Metaspace.

All local variables (both primitives and references) live on the stack. Non-primitive data objects are stored in the heap, and referenced by variables on the stack.

All non-primitive objects live on the heap.Primitive instance variables of those objects are stored inside the object. Non-primitive variables are stored outside of the object, and referenced by the instance variable.

Size? 5

*

***

*****

*******

*********

Scanner sc = new Scanner(System.in);

int size = sc.nextInt();

for(int row=0; row<size; row++) {

for(int col=0;col<4-row;col++) {

System.out.print(" ");

}

for(int col=0;col<row*2+1;col++) {

System.out.print("*");

}

System.out.println();

}

sc.close();

row col : 1st

spaces before *

col : 2nd

number of *

0 4 1

1 3 3

2 2 5

3 1 7

4 0 9

int x,y;

x=2; y=5;

System.out.println(x++ * y++);

System.out.println(++x * ++y);

System.out.println(++x * y++);

System.out.println(x++ * ++y);

System.out.println("1 + 2 = " + 1 + 2);System.out.println("1 + 2 = " + (1 + 2));

1 + 2 = 121 + 2 = 3

year % 4 == 0 && year % 100 != 0 || year % 400 == 0

((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0)

Any question?

Oct 8th

Lab08.

Quiz review

Triangle and Stripes


Quiz review

No

i++

++i

Use and then increase

int i = 3;

int a = i++; // a = 3, i = 4

int b = ++a; // b = 4, a = 4

Increase and then use

Quiz review

maxCount 100

str

"Hello"

"HELLO"

• Whenever a new variable is declared, it is added to STACK.

• Primitive data types are stored in STACK• byte, short, int, long, float, double, boolean, char

• Other data types are stored in HEAP. • String, Integer, Scanner, …

• Data in HEAP are not immediately deleted but unlinked, and will be garbage-collected.

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

int size = sc.nextInt();

for(int row=1;row<=size;row++) {

for(int col=1;col<=size;col++) {

System.out.print(row*col + " ");

}


}

}

Lab – 2D drawing

Two methods.

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

M1. Iterate pixels to paint

for (int i=0; i<size; i++) {grid.setColor(i, i, Color.BLUE);

}

Intuitive and efficient

M2. Iterate every pixel, use if conditionals to check pixels to paint

for (int row=0; row<size; row++) {for (int col=0; col<size; col++) {

if(row==col) {grid.setColor(row, col, Color.BLUE);

}}

}

Complex and inefficient BUT! More generalizable

Lab – 2D drawing

Two methods.

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4M2. Iterate every pixel, use if conditionals to check pixels to paint

for (int row=0; row<size; row++) {for (int col=0; col<size; col++) {

if(row!=col) {grid.setColor(row, col, Color.BLUE);

}}

}

You can simply inverse the conditional logic

M1. Iterate pixels to paint

Very difficult

Now you want to paint all the pixels except the diagonal line.

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

More examples.

row>2

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

row%2 == 1

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

col%2 == 1

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

(row-col)>=0

0 -1 -2 -3 -4

1 0 -1 -2 -3

2 1 0 -1 -2

3 2 1 0 -1

4 3 2 1 0

row-col

Diagonal shapes require both row

and col

Linear shapes require either row or col.

Transformation > Move

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

(row+1, col)

(row+1)-col >= 0

-1 -2 -3 -4 -5

0 -1 -2 -3 -4

1 0 -1 -2 -3

2 1 0 -1 -2

3 2 1 0 -1

(row+1)-col

0,1 0,2 0,3 0,4 0,5

1,1 1,2 1,3 1,4 1,5

2,1 2,2 2,3 2,4 2,5

3,1 3,2 3,3 3,4 3,5

4,1 4,2 4,3 4,4 4,5

To move a shape to left by 1 pixel,

replace "row" with "row+1"

Transformation > Horizontal Flip.

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

0,4 0,3 0,2 0,1 0,0

1,4 1,3 1,2 1,1 1,0

2,4 2,3 2,2 2,1 2,0

3,4 3,3 3,2 3,1 3,0

4,4 4,3 4,2 4,1 4,0

HorizontalFlip

(row, 4-col)

(row-(4-col))>=0

-4 -3 -2 -1 0

-3 -2 -1 0 1

-2 -1 0 1 2

-1 0 1 2 3

0 1 2 3 4

row-(4-col)

To flip a shape, multiple row or column by -1, and add size

-col

size-col

col

col

4 := size of the shape – 1Why -1? Because our row and

col index started from 0.

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

VerticalFlip

(4-row, col)

(4-row)-col >= 0

4 3 2 1 0

3 2 1 0 -1

2 1 0 -1 -2

1 0 -1 -2 -3

0 -1 -2 -3 -4

(4-row)-col

4,0 4,1 4,2 4,3 4,4

3,0 3,1 3,2 3,3 3,4

2,0 2,1 2,2 2,3 2,4

1,0 1,1 1,2 1,3 1,4

0,0 0,1 0,2 0,3 0,4

Transformation > Vertical Flip.

(row-col)>=0

0 -1 -2 -3 -4

1 0 -1 -2 -3

2 1 0 -1 -2

3 2 1 0 -1

4 3 2 1 0

(row-(4-col))>=0

-4 -3 -2 -1 0

-3 -2 -1 0 1

-2 -1 0 1 2

-1 0 1 2 3

0 1 2 3 4

HorizontalFlip

(4-row)-col >= 0

4 3 2 1 0

3 2 1 0 -1

2 1 0 -1 -2

1 0 -1 -2 -3

0 -1 -2 -3 -4

Vertical flip

(4-row)-(4-col) >= 0

0 1 2 3 4

-1 0 1 2 3

-2 -1 0 1 2

-3 -2 -1 0 1

-4 -3 -2 -1 0

HorizontalFlip

col-row >= 0

Vertical flip

Oct 6th

Lab07.

Loop applications

public void commonFactor(int n1, int n2) {

for(int i=1; i<=min(n1,n2); i++) {

if(n1%i==0 && n2%i==0) {

System.out.println(i);

}

}

}

Finding common factors of two numbers

Common factors can divide both numbers.E.g. Common factors of 9 and 12 1 and 3

Common factors of 24 and 78 1, 2, 3, and 6

compareTo method

String s1 = "aaa";

String s2 = "aac";

int k = s1.compareTo(s2); // k => -2

Compares s1 and s2 lexicographically. Negative if s1 precedes s2

Positive if s1 follows s2

Zero if s1 is equal to s2

Get multiple words, find the first and the last words

1) Using while loop, keep asking words until "STOP"2) Using compareTo, update the first and the last words3) Print out

Oct 1st

Lab06.

2D drawing

SquareGrid.java

ExampleDriver.java• Prompt a shape question• Create an empty grid• Draw the requested shape

OperatorMaker.java

drawOp (SquareGrid grid, int symbol)

minus, plus, divide, multiply (SquareGrid grid) You will change only these methods

Drawing shapes on 2D grid

Single loop for drawing a line

1) How can we get the middle row number?0

size : 7

3

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

int size = grid.getHt();int midRow = size / 2;

2) How to draw a line?• Iterate over columns (0 – 4)

• Paint the middle cell

for (int iCol=0; iCol<size; iCol++) {grid.setColor(midRow, iCol, Color.BLUE);

}


1) How can we get the middle column number?0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

int size = grid.getWd();int midCol = size / 2;

2) How to draw a line?• Iterate over rows (0 – 4)

• Paint the middle cell

for (int iRow=0; iRow<size; iRow++) {grid.setColor(iRow, midCol, Color.BLUE);

}

Notice that drawing horizontal and vertical lines are quite similar. We just switched row and column variables.


0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

1) How to draw a line?• Iterate over rows or columns (0-4)

• Paint diagonal cells.

for (int iRow=0; iRow<size; iRow++) {grid.setColor(iRow, iRow, Color.BLUE);

}

for (int iCol=0; iCol<size; iCol++) {grid.setColor(midRow, iCol, Color.BLUE);

}

for (int iRow=0; iRow<size; iRow++) {grid.setColor(iRow, midCol, Color.BLUE);

}

for (int iRow=0; iRow<size; iRow++) {grid.setColor(iRow, iRow, Color.BLUE);

}

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

0,0 0,1 0,2 0,3 0,4

1,0 1,1 1,2 1,3 1,4

2,0 2,1 2,2 2,3 2,4

3,0 3,1 3,2 3,3 3,4

4,0 4,1 4,2 4,3 4,4

for (int iCol=0; iCol<size; iCol++) {grid.setColor(iCol, iCol, Color.BLUE);

}

or


Iterating over the columns, paint the middle cell.

Iterating over the columns, paint the middle cell.

Iterating over the rows, paint the center cell.

Iterating over the columns, paint i-th cell.

Draw Plus, Divide, and Divide (rotated).

Sep 29th

Lab05.1. Recap the quiz #1

2. String Class

3. static vs. instance method

Recap quiz #1.

PRINT your names in the grade server. NO nicknames.

Recap quiz #1.

Use specific technical keywordse.g. What does CVS “do” for us?

1. Check out / Download the starter files2. Store / Save multiple versions of the source codeshare, deliver, get, access, connected people, ...

Penalties for inaccurate extra infoe.g. CVS runs our code and give us grades. -1 for incorrect extra info.

String Class

String s = “hello”;

Create a new String object with an initial value “hello”

String objects have many convenient methods,

upperS = s.toUpperCase(); // will set upperS to “HELLO”

whereIsl= s.indexOf(‘l’); // will find the position of the first ‘l’

newS = s.replace(‘e’,’a’); // will set newS to “hallo”

int type vs. Integer Class

int i=0;

Primitive data type

Integer i = 17;

Wrapper Class

don’t have much method provide methods

- convert to string

- generate hash codes

Faster A little slower

Static vs. Instance method

Intance methods need a sheep as a subject.

bob.eat();

bob.smileTo(clara);

bob.getPenNumber();

Static methods are about all the sheeps.

Sheep.getTotalSheep();

Sheep.removeAll();

Sheep.addSheep(‘evan’);

Sep 24th

Lab04.Loop

Flow of Control

1. Top-to-bottom statements

2. Method calls

3. Conditional statements

4. Iteration (loop)for, while, ...

Two goals of iteration

1. AutomationReduce repetition of code

System.out.println(“****”);



How can we reduce?for(int i=0;i<3;i++) {


}

2. AbstractionCode for various situations


How can we print n-number of “*”?

From manual & concrete to automatic & abstract

Level 1. Draw 30 by 10 rectangle (hard-coded) System.out.println(“**********”);

System.out.println(“**********”);


... 27 more lines

Level 2. Draw 30 by 10 rectangle (single-loop)

Too many copy & paste. Hard to modify.

int row=0;

while(row<30) {


row++;

}

A little more compact. Still too many * for each line.

From manual & concrete to automatic & abstract

Level 3. Draw 30 by 10 rectangle (nested-loop) int row=0, col=0;

while(row<30) {

while(col<10) {

System.out.print(“*”);

}


}

Much compact. Cannot change # of row and col

Level 4. Draw height by width (nested-loop, parameterized) int row=0, col=0;

int height=30, width=10;

while(row<height) {

while(col<width) {

System.out.print(“*”);

}


} Compact Can draw any sized rectangle

iterartorline 1

0

valueline 2

0

targetline 4

answerline 1

1

iline 1

1

jline 1

0

Oct27

Engineering