6.003: Signals and Systems Modulation December 6, 2011 1
6.003: Signals and Systems
Modulation
December 6, 2011 1
Communications Systems
Signals are not always well matched to the media through which we
wish to transmit them.
signal applications
audio telephone, radio, phonograph, CD, cell phone, MP3
video television, cinema, HDTV, DVD
internet coax, twisted pair, cable TV, DSL, optical fiber, E/M
Modulation can improve match based on frequency.
2
Amplitude Modulation
Amplitude modulation can be used to match audio frequencies to
radio frequencies. It allows parallel transmission of multiple channels.
x1(t)
x2(t)
x3(t)
z1(t)
z2(t) z(t)y(t)
z3(t)
cos w1t
cos w2t cos wct
cos w3t
LPF
3
Superheterodyne Receiver
Edwin Howard Armstrong invented the superheterodyne receiver,
which made broadcast AM practical.
Edwin Howard Armstrong also invented and
patented the “regenerative” (positive feedback)
circuit for amplifying radio signals (while he was
a junior at Columbia University). He also invented wide-band FM.
4
Amplitude, Phase, and Frequency Modulation
There are many ways to embed a “message” in a carrier.
Amplitude Modulation (AM) + carrier: y1(t) = x(t) + C cos(ωct)
Phase Modulation (PM): y2(t) = cos(ωct + kx(t)) tFrequency Modulation (FM): y3(t) = cos ωct + k −∞ x(τ )dτ
PM: signal modulates instantaneous phase of the carrier.
y2(t) = cos(ωct + kx(t))
FM: signal modulates instantaneous frequency of carrier. t y3(t) = cos ωct + k x(τ)dτ ' −∞v "
φ(t)d
ωi(t) = ωc + φ(t) = ωc + kx(t)dt
5
Frequency Modulation
sin(ωmt))
Advantages of FM:
• constant power
Compare AM to FM for x(t) = cos(ωmt).
AM: y1(t) = x(t) + C cos(ωct) = (cos(ωmt) + 1.1) cos(ωct)
t
FM: y3(t) = cos ωct + k −∞ x(τ )dτ = cos(ωct +t k ωm
t
• no need to transmit carrier (unless DC important)
• bandwidth? 6
∫
Frequency Modulation
Early investigators thought that narrowband FM could have arbitrar
ily narrow bandwidth, allowing more channels than AM.
t y3(t) = cos ωct + k x(τ)dτ
−∞' v " φ(t)
d ωi(t) = ωc + φ(t) = ωc + kx(t)
dt
Small k → small bandwidth. Right?
7
( ∫ )
Frequency Modulation
Early investigators thought that narrowband FM could have arbitrar
ily narrow bandwidth, allowing more channels than AM. Wrong! 0 t y3(t) = cos ωct + k x(τ)dτ
−∞0 0 t t = cos(ωct) × cos k x(τ)dτ − sin(ωct) × sin k x(τ )dτ
−∞ −∞
If k → 0 then0 t cos k x(τ)dτ → 1
−∞0 t t sin k x(τ )dτ → k x(τ)dτ
−∞ −∞0 t y3(t) ≈ cos(ωct) − sin(ωct) × k x(τ)dτ
−∞
Bandwidth of narrowband FM is the same as that of AM!
(integration does not change the highest frequency in the signal) 8
∫∫ ∫
∫∫ ∫
∫
1
0
−1
1 sin(ωmt)
t
1
0
−1
cos(1 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
9
2
0
−2
2 sin(ωmt)
t
1
0
−1
cos(2 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
10
3
0
−3
3 sin(ωmt)
t
1
0
−1
cos(3 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
11
4
0
−4
4 sin(ωmt)
t
1
0
−1
cos(4 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
12
5
0
−5
5 sin(ωmt)
t
1
0
−1
cos(5 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
13
6
0
−6
6 sin(ωmt)
t
1
0
−1
cos(6 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
14
7
0
−7
7 sin(ωmt)
t
1
0
−1
cos(7 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
15
8
0
−8
8 sin(ωmt)
t
1
0
−1
cos(8 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
16
9
0
−9
9 sin(ωmt)
t
1
0
−1
cos(9 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
17
10
0
−10
10 sin(ωmt)
t
1
0
−1
cos(10 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
18
20
0
−20
20 sin(ωmt)
t
1
0
−1
cos(20 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
19
50
0
−50
50 sin(ωmt)
t
1
0
−1
cos(50 sin(ωmt))
t
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
20
m
0
−m
m sin(ωmt)
t
1
0
−1
cos(m sin(ωmt))
t
increasing m
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore cos(m sin(ωmt)) is periodic in T .ωm
21
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 0
22
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 1
23
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 2
24
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 5
25
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 10
26
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 20
27
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 30
28
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 40
29
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore cos(m sin(ωmt)) is periodic in T .
1
0
−1
cos(m sin(ωmt))
t
|ak|
k0 10 20 30 40 50 60
m = 50
30
|Ya(jω)|
ωωcωc
100ωm
m = 50
Phase/Frequency Modulation
Fourier transform of first part.
x(t) = sin(ωmt)
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))' v " ya(t)
31
m
0
−m
m sin(ωmt)
t
1
0
−1
sin(m sin(ωmt))
t
increasing m
increasing m
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π , therefore sin(m sin(ωmt)) is periodic in T .ωm
32
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 0
33
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 1
34
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 2
35
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 5
36
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 10
37
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 20
38
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 30
39
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 40
40
Phase/Frequency Modulation
Find the Fourier transform of a PM/FM signal.
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))
x(t) is periodic in T = 2π ωm
, therefore sin(m sin(ωmt)) is periodic in T .
1
0
−1
sin(m sin(ωmt))
t
|bk|
k0 10 20 30 40 50 60
m = 50
41
' v "ya(t)
|Yb(jω)|
ωωcωc
100ωm
m = 50
Phase/Frequency Modulation
Fourier transform of second part.
x(t) = sin(ωmt)
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))' v " yb(t)
42
|Y (jω)|
ωωcωc
100ωm
m = 50
Phase/Frequency Modulation
Fourier transform.
x(t) = sin(ωmt)
y(t) = cos(ωct + mx(t)) = cos(ωct + m sin(ωmt))
= cos(ωct) cos(m sin(ωmt))) − sin(ωct) sin(m sin(ωmt)))' v " ' v " ya(t) yb(t)
43
Frequency Modulation
Wideband FM is useful because it is robust to noise.
AM: y1(t) = (cos(ωmt) + 1.1) cos(ωct)
t
FM: y3(t) = cos(ωct + m sin(ωmt))
t
FM generates a redundant signal that is resilient to additive noise.
44
Summary
Modulation is useful for matching signals to media.
Examples: commercial radio (AM and FM)
Close with unconventional application of modulation – in microscopy.
45
6.003 Microscopy
Dennis M. Freeman Stanley S. Hong Jekwan Ryu Michael S. Mermelstein Berthold K. P. Horn
46Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
6.003 Model of a Microscope
microscope
Microscope = low-pass filter
47
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
Phase-Modulated Microscopy
microscope
48
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
49
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
50
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
51
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
52Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
53Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
many frequencies + many orientations = many images
low resolution high resolution
wx
wy
wx
wy
wx
wy
54
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
55
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
56
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
57
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
58
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
59
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
60
Courtesy of Stanley Hong, Jekwan Ryu, Michael Mermelstein, and Berthold K. P. Horn. Used with permission.
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6.003 Signals and SystemsFall 2011
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