Laporan Sieving

8/19/2019 Laporan Sieving

1/12


2/12

0."1 0.3"&2" 0.3$3" 3$3.# 0.3$2

1

0.3$23

1

0.& 0.3"#% 0.3$2%

3$1.# 0.3$31&

0.3$12$

pan 0.2%#$ 0.$$# #0.%

1

0.#0#%

3

0.#0$2

$

VI. PENGOLAHAN DATA

&. P'!'!a! B'*a J'!%s

• Massa piknometer kosong (a) = 23.001 g

• Massa piknometer ! air (b) = ".##$% g

• Massa piknometer ! padatan () = 3&."%# g

• Massa piknometer ! padatan ! air (d)= ##.101" g

• Massa *enis air ( ρ ¿ (31+,) = 0.$$#3 g-ml

• Massa air (e) = b a = ".##$% g / 23.001 g = 2.#1$" g

• olume Air () =e

ρ =

24.5197 g

0.99534 g

ml

= 2.&3$&"# ml = olume

piknometer • Massa airan (g) = d = ##.101" g / 3&."%# g = 1%.3#32 g

• olume airan (h) =g

ρ =

18.3532g

0.99534 g

ml

= 1%.3$12&33 ml

• olume padatan (i) = h = 2.&3$&"# ml / 1%.3$12&33 ml =

&.1$#3"02& ml

• Massa padatan (*) = a = 3&."%# g / 23.001 g = 13."0% g

• Massa jenis Padatan = ji= 13.7084 g6.195370426ml

=¿ 2.212&%%2 gml

=

2212.&%%2kg

m3

+. + M'!%


3/12

&.& Penentuan P

OP=

OP1

M 1 =

0.02521 kg

0.39788 kg=0.063361

1.2 Penentuan P

P = OP

1

d (dp)1

=0.063361 kg

0.3kg =0.211203

1.3 Penentuan ,P

C%OP=∑i=1

n

OP1=0.245878

1.4 Penentuan 1/,P (,4P)

C%OP=1−C%OP1=0.754121846

1.5 Penentuan 5uas 6pesiik

dA B M

=6× P × d(dp)

ρ × d p=

6×0.211203 1

mm ×0.3mm

2212.684482 kg

m3

×1.4 mm× 1m

1000mm

=0.240536248 m

3

Kg

7engan menggunakan ara ang sama pada data selan*utna8 didapatkan

data seperti tabel diba9ah.

2 min

dp

(mm

)

∆

dp

(mm

)

P

(:g)P ,P

Pi

(1-mm)1/,P

5uas6pesiik (

m3

Kg¿

1." /0.0"2&

2

0.1%2#1

"

0.1%2#1

";7/

0#

0."1 0.10.01"

3

0.03%0

"

0.2133

3

0.312$0

%

0.#"%&&&$3

#

%.303>/

0#


4/12

0.& 0.110.01&&

0.01%2

2

0.&31#

#

0.3%01$

"0.#3&%#2%

&.%031>/

0#

0 0.& 0.213& 0.#3&%#

1 0.%$"2

0 0

0.3$"%

%

:ur'a hubungan P dengan *umlah aakan

1 2 3 4 5 6 7 80

0.1

0.2

0.3

0.4

0.5

0.6

OP% (2min)

Jumlah Ayakan

OP%

:ur'a distribusi komulati

0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.80

0.2

0.4

0.6

0.8

1

1.2

Ku!a "is#i$usi Kmula#i& (2min)

'%OP

1'%OP

* (mm)


5/12

7ari kur'a diatas didapatkan diameter partikel tengah8 dpm adalah 0.#mm

:ur'a distribusi rekuensi

00.10.20.30.40.50.60.70.80.+

1

Ku!a "is#i$usi ,ekuensi (2min)

(*)

P%

7ari kur'a diatas didapatkan diameter partikel ang sering munul8 dp

adalah

,. - M'!%

7engan menggunakan ara perhitungan ang sama pada data selan*utna8

didapatkan data seperti tabel diba9ah.

min

dp

(mm

)

∆

dp

(mm

)

P

(:g)P ,P Pi 1/,P

5uas6pesiik (

m3

Kg¿

1."0.0"0$

$0.1"%$3

%0.1"%$3

%;7/

0#

0.%# 0.1#0.01#2

&

0.03%&

0.3

10.2#&3

0.&3&%%#"

$

%.%&>/

0#


6/12

0."1 0.10.01"2

30.033

0.0%"

1

0.31021

#

0.#$12#%#3

$

%.3&13>/

0#

0.& 0.11 0.01#&&

0.03$"3

0.%21

0.3#%%3

0.##1"%#%$

&.221>/0#

0 0.&0.21%$

1

0.##1"%

&1

0.$1$&

30 0

0.3$&"

3


1 2 3 4 5 6 7 80

0.1

0.2

0.3

0.4

0.5

0.6

OP% (4min)

nama Ayakan

OP%



7/12

0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.80

0.2

0.4

0.6

0.8

1

1.2

Ku!a "is#i$usi Kmula#i&(4min)

'%OP

1'%OP

* (mm)



00.10.20.30.40.50.60.70.80.+

1

Ku!a "is#i$usi ,ekuensi(4min)

(*)

P%

7ari kur'a diatas didapatkan diameter partikel ang sering munul8 dp

adalah

-. M'!%




8/12

& min

dp

(mm)

∆

dp(mm

)

P(:g)

P ,P Pi 1/,P

5uas 6pesiik

( m3

Kg¿

1." 0.0&"%& 0.1"1%11 0.1"1%11 ;7/0#

0."1 0.1 0.01&10.00%&

0.3$$321

0.2$1%%

#0.&00&"%#33 ".%&"3">/0#

0.& 0.11 0.01"320.03%#

10.31"3

0.3$%&

$0.##&%2"101 ".13##>/0#

0 0.& 0.21$$30.##&%2

"1

0.$2%0

#0 0

0.3$$"


1 2 3 4 5 6 7 8

0

0.1

0.2

0.3

0.4

0.5

0.6

OP% (6min)

Jumlah Ayakan

OP%



9/12

0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.80

0.2

0.4

0.6

0.8

1

1.2


'%OP

1'%OP

* (mm)



00.10.20.30.40.50.60.70.80.+

1


(*)

P%

7ari kur'a diatas didapatkan diameter partikel ang sering munul8 dp adalah

/. 0 M'!%




10/12

% min

dp

(mm)

∆

dp(mm

)

P(:g)

P ,P Pi 1/,P

5uas 6pesiik

( m3

Kg¿

1." 0.0&#0.1&%&

0.1&%& ;7/0#

0.%# 0.1# 0.01## 0.03$23"

0.3#% 0.2&1#""

0.&#200%& $.03&>/0#

0."1 0.1 0.01&00.00&0

30.3$#03

0.2$002

#0.&0#$"003 ".%1"2>/0#

0.& 0.11 0.01## 0.03$11 0.3#130.3###

#0.#%"03$ &.3&312>/0#

0 0.& 0.2233$0.#%

"1

0.$2"

%0 0

0.3$#0


1 2 3 4 5 6 7 80

0.1

0.2

0.3

0.4

0.5

0.6

OP% (8min)

Jumlah Ayakan

OP%



11/12

0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.80

0.2

0.4

0.6

0.8

1

1.2


'%OP

1'%OP

* (mm)



00.10.20.30.40.50.60.70.80.+

1


(*)

P%

7ari kur'a diatas didapatkan diameter partikel ang sering munul8 dp adalah

VII. PEMBAHASAN

VIII. KESIMPULAN


12/12

&.

-. DAFTAR PUSTAKA

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