Section 2.3 – Differentiation Rules 1 Section 2.3 Differentiation Rules The Product Rule If f and g are differentiable at x , then so is the product fg . Moreover, ( )( ) ( ) ( ) ( ) ( ) fg ' x f x g' x gx f' x = + This rule can be extended to the product of more functions: ( ) uvw ' u' vw uv' w uvw' = + + Example 1: Find the derivative of ( ) ( ) 3 hx x cos x = . Example 2: If ( ) 2 3 5 y x x x = + , find dy . dx
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Section 2.3 – Differentiation Rules 1
Section 2.3 Differentiation Rules
The Product Rule
If f and g are differentiable at x , then so is the product fg . Moreover,
( ) ( ) ( ) ( ) ( ) ( )fg ' x f x g' x g x f ' x= +
This rule can be extended to the product of more functions:
( )uvw ' u' vw uv' w uvw'= + +
Example 1: Find the derivative of ( ) ( )3h x x cos x= .
Example 2: If ( )23 5y x x x= + , find dy .dx
Section 2.3 – Differentiation Rules 2
The Quotient Rule
If f and g are differentiable at x and ( ) 0g x ≠ , then the quotient f / g is differentiable at
x and
( ) ( ) ( ) ( ) ( )( ) 2
' g x f ' x f x g' xf xg g x
− =
Example 3: Find the derivative of ( ) 22
5xf x
x=
+.
Determine the value(s) of x for when the tangent line is horizontal to f.
Section 2.3 – Differentiation Rules 3
Example 4: Find the derivative of ( )4 2tan xf xx
=+
.
Try this one: Find the slope of the tangent line to the curve ( )2
5x xf xx+
=+
at 1x = . Then find
its equation. What is the normal equation?
Section 2.3 – Differentiation Rules 4
What if we wanted the derivative of something like, 7( ) (5 1)f x x= + . Well, to be able to use the rules we’ve learned so far, we’d have to expand the expression. This would be too much work. We have a rule for finding derivatives involving functions of these type.
The Chain Rule
If g is differentiable at x and f is differentiable at ( )g x , then the composition f g is
differentiable at x . Moreover,
( ) ( ) ( )( ) ( )f g ' x f ' g x g' x= ⋅ .
This rule is one of the most important rules of differentiation. It helps us with many complicated functions.
Example 5: Find the derivative of ( ) ( )103 1h x x x= + + .
Example 6: Find the derivative of ( ) ( )25 1f x cos x= + .
Try this one: For 3
1( )g xx x
=−
, find 2x
dydx =
.
Section 2.3 – Differentiation Rules 5
Example 7: Find the derivative of ( ) ( )3 5f x sin x= .
Try this one: Find the derivative of ( ) ( )2 3 22f x cos x x= − + .
Example 8: Let ( )f x x= and ( ) 4 7g x x= + . If ( ) ( )( )h x f g x= , find '( )h x .
Try these: Find the derivative of ( ) 4 46 8f x x x= + .
Section 2.3 – Differentiation Rules 6
Example 9: Find the derivative of 4 62( ) cos 103
f x x x x = −
Example 10: Find the derivative of ( ) ( )( )310 40
4
xg x
x
+=
−.
Try this one:
Find the derivative of ( ) ( )1 323/
f x x x x= − + .
Section 2.3 – Differentiation Rules 7
The Chain Rule in Leibniz Notation
Let y be a function in terms of u and u be a function in terms of x. As a result, y may be expressed as a function in terms of x. How do we differentiate y with respect to x? Expressing y as a function in terms of x and then differentiating it is an option, but we are looking for a better way.
This is what the chain rule says with Leibniz’s double- d notation:
( )( ) ( )( ) ( )d f u x f ' u x u' xdx
= ⋅ or ( ) ( )d duf u f ' udx dx
= ⋅ .
If ( )y f u= , then ( )dy duf ' udx dx
= ⋅ and since ( ) dyf ' udu
= , the chain rule can be written as:
dy dy dudx du dx
= ⋅ . That is, the derivative of y with respect to x is the product of the derivative of
y with respect to u and the derivative of u with respect to x .
This formula can be extended to more variables; each new variable adds a new link to the chain.
For the composition of 3 functions, ( )( )( ) ( )( )( ) ( )( ) ( )d f u v x f ' u v x u' v x v' xdx
= ⋅ ⋅
can be written as: dy dy du dvdx du dv dx
= ⋅ ⋅ .
Example 11: If 2 5y u u= + and 26u x= , evaluate 1x
dydx =
.
Section 2.3 – Differentiation Rules 8
Example 12: The following information is given about two functions f and g .