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Extra 1125

Jun 02, 2018

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  • 8/11/2019 Extra 1125

    1/12

    ay +by +cy = g(t), y(0) =y0, y(0) =z0

    a b c

    s y = y (t) Y(s) y y

    Y(s)

    y(0)

    y(0)

    Y(s)

    y(t)

    f(t)

    f(t)

    s

    limA

    A0

    estf(t)

    f(t) L {f(t)} F(s)

    s

    f(t) =e2t

    limA A0 e

    st

    e2t

    limA

    A0

    e(2s)t

    s= 2

    limA

    A0

    e(22)t = limA

    A0

    1 = limA

    t|A0= limA

    A=

    s

    2

    s= 2

    limA

    A0

    e(2s)t = limA

    e(2s)t

    2 s |A0= lim

    Ae(2s)A

    2 s

    e(2s)0

    2 s

    2 s >0 2 s 2

    limA

    e(2s)A

    2 s

    e(2s)0

    2 s

    = 0

    1

    2 s=

    1

    s 2

    e2t

    L {f(t)}= F(s) = 1

    s 2

  • 8/11/2019 Extra 1125

    2/12

    eat

    cos(bt)

    sin(bt)

    t

    tn

    g(t)

    f(t) L {f(t)}

    eat 1sa

    cos(bt) ss2+b2

    sin(bt) bs2+b2

    tn n!sn+1

    n! = n(n 1)(n 2) . . . (2)(1) n 0! 1

    bi s

    b

    tn

    s

    f(t) =t

    limA

    A0

    estt

    u= t

    v = est

    u = 1

    v = 1s

    est

    limA

    1

    stest

    A0

    1

    sest(1)

    = limA

    1

    stest +

    A0

    1

    sest

    = limA

    1

    stest

    1

    s2est

    A0

    = limA

    1

    sAesA

    1

    s2esA +

    1

    s0e0 +

    1

    s2e0

    s

  • 8/11/2019 Extra 1125

    3/12

    f1(t) f2(t) f1(t) +f2(t)

    L {f1(t) +f2(t)}= L {f1(t)} + L {f2(t)}

    c

    c f1(t)

    L {c f1(t)}= c L {f1(t)}

    f(t) = 3e2t + cos(4t) + 5t2

    L3e2t + cos(4t) + 5t2

    =L

    3e2t

    + L {cos(4t)} + L

    5t2

    = 3L

    e2t

    + L {cos(4t)} + 5L

    t2

    = 3 1

    s 2+

    s

    s2 + 42+ 5

    2!

    s(2+1) =

    3

    s 2+

    s

    s2 + 42+

    10

    s(2+1)

    L

    3e2t + cos(4t) + 5t2

    = 3

    s 2+

    s

    s2 + 42+

    10

    s(2+1)

    L {f1(t)f2(t)} =L {f1(t)} L {f2(t)}

    L {eat cos(bt)}= limA

    A0

    esteat cos(bt) = limA

    A0

    e(as)t cos(bt)

    s=a

    u= cos(bt)

    v = e(as)t

    u =b sin(bt) v= e(as)t

    as

    limA

    e(as)t

    a s cos(bt)

    A0

    e(as)t

    a s (b sin(bt))

    = limA

    e(as)t

    a s

    cos(bt) + b

    a s A

    0

    e(as)t(sin(bt)) u = sin(bt) v = e(as)t u =

    b cos(bt) v= e(as)t

    as

    = limA

    e(as)t

    a s cos(bt) +

    b

    a s

    e(as)t

    a s sin(bt)

    A0

    e(as)t

    a s (b cos(bt))

    = limA

    e(as)t

    a s cos(bt) +

    b

    a s

    e(as)t

    a s sin(bt)

    b2

    (a s)2

    A0

    e(as)t(cos(bt))

  • 8/11/2019 Extra 1125

    4/12

    limA A0

    e(as)t

    cos(bt)

    = limAe(as)t

    a s cos(bt) + b

    a s

    e(as)t

    a s sin(bt) b2

    (a s)2 A0

    e(as)t

    (cos(bt))

    b

    2

    (as)2

    A0

    e(as)t(cos(bt))

    limA

    1 +

    b2

    (a s)2

    A0

    e(as)t cos(bt)

    = limA

    e(as)t

    a s cos(bt) +

    b

    a s

    e(as)t

    a s sin(bt)

    limA

    (a s)2 +b2

    (a s)2

    A0

    e(as)t cos(bt)

    = limA

    e(as)t

    a s cos(bt) +

    b

    a s

    e(as)t

    a s sin(bt)

    (a s)2 = (s a)2 (as)2+b2

    (as)2

    limA

    A0

    e(as)t cos(bt) = (s a)2

    (s a)2 +b2 limA

    e

    (as)t

    a s cos(bt) + b

    a se

    (as)t

    a s sin(bt)

    A

    0

    s > a limA

    e(as)A

    as cos(bA) = lim

    A

    b

    as

    e(as)A

    as sin(bA) = 0

    limA

    A0

    e(as)t cos(bt) = (s a)2

    (s a)2 +b2

    e(as)0

    a s cos(0)

    b

    a s

    e(as)0

    a s sin(0)

    = (s a)2

    (s a)2 +b2

    1

    a s

    =

    (s a)2

    (s a)2 +b2

    1

    s a

    =

    (s a)

    (s a)2 +b2

    s > a

    Leat cos(bt) =

    (s a)

    (s a)2 +b2

    L

    eat sin(bt)

    = b

    (s a)2 +b2

    s a bi

    eat cos(bt)

    s a

    L {f(t)} f(t)

    L {f(t)}= 1s2

    L

    e2t

    = 1s2

    t 1s2

    1s2

    e2t L1

    L1

    1s2

    = e2t

    s F(s)

    F(s)

    f(t) L {f(t)}= F(s)

  • 8/11/2019 Extra 1125

    5/12

    L1 {F(s)} = f(t) t L {f(t)} = 1

    s2

    f(t) =e2t L1

    1s2

    =e2t

    F1(s) F2(s) F1(s) +F2(s)

    L1 {F1(s) +F2(s)}= L1 {F1(s)} + L

    1 {F2(s)}

    c c F1(s)

    L1 {c F1(s)}= c L1 {F1(s)}

    F(s) = 1s2

    + 8s2+4

    + 2s2s24s+13 f(t) L {f(t)}= F(s)

    t F(s)

    s 2

    2

    eat a a= 2

    a= 2 F(s) e2t

    s2 + 4 2i s = 2i s= 2i cos(2t) sin(2t)

    s

    s

    s

    8

    sin(2t)

    s2 4s+ 13

    2 3i s2 4s + 13 = (s 2)2 + 32

    s

    a bi (s a)2 +b2

    2s 2

    (s 2)2 + 32

    s

    s 2

    e2t cos(3t) e2t sin(3t)

    L

    e2t

    = 1s2

    1s2

    1

    s 2 =1

    1

    s 2=1L

    e2t

    =L

    e2t

  • 8/11/2019 Extra 1125

    6/12

    e2t

    L1 1

    s 2

    =e2t

    L {sin(2t)} = 2s2+22

    8s2+22

    = 4 2s2+22

    4 = 82

    4 sin(2t)

    L1

    8

    s2 + 4

    = 4 sin(2t)

    L

    e2t cos(3t)

    = s2(s2)2+32

    L

    e2t sin(3t)

    = 3(s2)2+32

    e2t cos(3t)

    e2t sin(3t)

    s

    2s 2

    (s 2)2 + 32 = 2

    s 1

    (s 2)2 + 32

    eat cos(bt) eat sin(bt)

    s

    s a+a

    2 s 1

    (s 2)2 + 32 = 2

    s 2 + 2 1

    (s 2)2 + 32 = 2

    (s 2) + 1

    (s 2)2 + 32

    = 2

    s 2

    (s 2)2 + 32+

    1

    (s 2)2 + 32

    e2t cos(3t)

    e2t sin(3t)

    1

    (s 2)2 + 32 =

    1

    3

    3

    (s 2)2 + 32

    13e

    2t sin(3t)

    2

    s 2

    (s 2)2 + 32 +

    1

    3

    3

    (s 2)2 + 32

    2s2(s2)2+32

    L1 2s 2

    (s 2)2 + 32 = 2e2t cos(3t) +

    1

    3e2t sin(3t)

    t

    F(s) = 1s2

    + 8s2+4

    + 2s2s24s+13

    L1

    1

    s 2+

    8

    s2 + 4+

    2s 2

    s2 4s+ 13

    =e2t + 4 sin(2t) + 2

    e2t cos(3t) +

    1

    3e2t sin(3t)

  • 8/11/2019 Extra 1125

    7/12

    F(s)

    1

    s 2+ 4

    2

    s2 + 22 + 2 s 2

    (s 2)2 + 32 +

    1

    3

    3

    (s 2)2 + 32

    = 1

    s 2+

    8

    s2 + 4+ 2

    s 2

    s2 4s+ 13+

    1

    s2 4s+ 13

    = 1

    s 2+

    8

    s2 + 4+

    2(s 2 + 1)

    s2 4s+ 13

    = 1

    s 2+

    8

    s2 + 4+

    2s 2

    s2 4s+ 13 =F(s)

    f(t)

    f(t) =

    f1(t) a0 t < a1

    f2(t) a1 t < a2

    . . .

    fn(t) an1 t < an

    f1(t) f2(t) . . . fn(t) t a0 an

    f(t) =f1(t) t < a1 f(t) =fn(t) an1 t

    f(t) =

    et t

  • 8/11/2019 Extra 1125

    8/12

    t f(t)

    t = 1

    u1(t) u1(t)

    0

    1

    t= 1

    u1(t)

    t= 1

    et

    sin(t)

    sin(t) et u1(t)

    f(t) =et +u1(t)

    sin(t) et

    +?

    t f(t)

    t= 2

    t2

    sin(t)

    f(t) =et +u1(t)

    sin(t) et

    +u2(t)

    t2 sin(t)

    t < 1 u1(t) = 0 u2(t) = 0 f(t) =et

    f(t) =et + (0)

    sin(t) et

    + (0)

    t2 sin(t)

    =et

    1 t

  • 8/11/2019 Extra 1125

    9/12

    B u

    uc(t)

    f

    ecs limB

    B0

    esuf(u) =ecsL {f(u)}= ecsL {f(t)}= ecsF(s)

    L {f(u)}= L {f(t)} f

    c 0 c c A

    limA

    c0

    estuc(t)f(t c) +

    Ac

    estuc(t)f(t c)

    uc(t) = 0 0 t < c c0

    est(0)f(t c) = 0

    uc(t) = 1 t c

    limA

    A

    c

    est(1)f(t c) = limA

    A

    c

    estf(t c)

    uc(t) 1

    u= t c t= u+c t =

    limA

    Accc

    es(u+c)f(u)

    = limA

    Ac0

    escesuf(u)

    =ecs limA

    Ac0

    esuf(u)

    B= A c A B A

    B

    =ecs limB

    B0

    esuf(u)

    f(u) F(s)

    F(s) = limA

    A0

    estf(t)

    u B u

    t

    B

    A

    uc(t)f(t c) ecsF(s) ecs

    uc(t)f(t c) f

    t

    f(t c) u+c f(u+c c) =f(u)

  • 8/11/2019 Extra 1125

    10/12

    L {f(u)} f(u) L {uc(t)f(t c)}= ecsL {f(u)}

    u4(t)e2t

    c= 4

    f(t c) =f(t 4) =e2t

    t u+c= u+ 4 f(u)

    f(u) =e2(u+4) =e2u+8 =e8e2u

    f(u) =e8e2u

    L

    e8e2u

    =e8L

    e2u

    =e8 1

    s 2

    u4(t)e2t

    L

    u4(t)e2t

    =e4s e8 1s 2

    L {uc(t)}= ecs

    1

    s

    uc(t) =uc(t)e0(tc)

    f(t c) =e0(tc)

    f(u) =e0u

    e0u

    1s0

    = 1s

    uc(t) =

    uc(t)e0(tc)

    L {uc(t)}= L

    uc(t)e0(tc)

    =ecsL

    e0u

    =ecs1

    s

    u2(t)(t 1) u4(t)et

    u2(t)(t 1) c= 2 f(t 2) =t 1

    f(u) = (u+ 2) 1 =u+ 1

    f(u) =u+ 1

    L {u+ 1}= 1

    s2+

    1

    s

    u2(t)(t 1)

    L {u2(t)(t 1)}= L {u2(t)(u+ 1)}= e2s

    1

    s2 +

    1

    s

    u4(t)et =u4(t) (e

    t) c= 4 f(t 4) =et

    f(u) =eu+4 =e4eu

    f(u) =e4eu

    L

    e4eu

    =e4L {eu}= e4 1

    s 1

  • 8/11/2019 Extra 1125

    11/12

    u4(t)(et)

    L

    u4(t)(et

    )

    =L

    u4(t)(e4

    eu

    )

    =e4s

    e4 1

    s 1

    u2(t)(t 1) u4(t)et

    e2s

    1

    s2+

    1

    s

    +e4s

    e4

    1

    s 1

    ecsF(s) L1 {ecsF(s)}

    u= t c L1 {F(s)}= f(u) L1 {ecsF(s)}= uc(t)f(u) =uc(t)f(t c)

    t

    ecsF(s) c

    u

    e2s ss2+32

    c= 2

    u= t 2

    s

    s2+32 u

    t

    s2 + 32 3i

    cos(3u) sin(3u) s cos(3u)

    L1

    e2s s

    s2 + 32

    =u2(t) cos(3u) =u2(t) cos(3(t 2)) =u2(t) cos(3t 6)

    e2s s(s2)2+32

    c= 2 u= t 2

    s

    (s2)2+32 u

    t

    (sa)2+b2 e2u cos(3u)

    e2u sin(3u)

    s 2 3 s s= s 2 + 2

    s 2 + 2

    (s 2)2 + 32 =

    s 2

    (s 2)2 + 32 +

    2

    (s 2)2 + 32

    e2u cos(3u)

    3

    33

    3

    s 2

    (s 2)2 + 32 +

    3

    3

    2

    (s 2)2 + 32

    = s 2

    (s 2)2 + 32+

    2

    3

    3

    (s 2)2 + 32

  • 8/11/2019 Extra 1125

    12/12

    23e

    2u sin(3u)

    e2u cos(3u) + 23

    e2u sin(3u)

    e2s s(s2)2+32

    u2(t)

    e2u cos(3u) + 23e2u sin(3u)

    u= t 2

    L1

    e2s s

    (s 2)2 + 32

    =u2(t)

    e2(t2) cos(3(t 2)) +

    2

    3e2(t2) sin(3(t 2))