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Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4
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Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Jan 13, 2016

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Page 1: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

• Chapter 4

Page 2: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Goals for Chapter 4

• To understand force – either directly or as the net force of multiple components.

• To study and apply Newton’s First Law.

• To study and apply the concept of mass and acceleration as components of Newton’s Second Law.

• To differentiate between mass and weight.

• To study and apply Newton’s Third Law.

• To open a new presentation of problem data in a free body diagram.

Page 3: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Dynamics, a new frontier

• Stated previously, the onset of physics separates into two distinct parts:

– statics and

– dynamics.

• So, if something is going to be dynamic, what causes it to be so?

– A force is the cause, it is either

• pushing or

• pulling.

Page 4: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Types of Force Illustrated I – Figure 4.1

Page 5: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Types of Force II – Figure 4.2

• Single or net

– Contact force

– Normal force

– Frictional force

– Tension

– Weight

Page 6: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

A force may be resolved into components – Figure 4.4

•Fx = F CosΘ

•Fy = F SinΘ

Page 7: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Components and Resultants II – Figure 4.6

• An example of component resolution.

Page 8: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 9: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 10: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 11: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

R = F1 + F2 + F3 + ……..= Σ F, (resultant, and vector sum, of forces)

Rx = Σ Fx , Ry = Σ Fy

(components of vector sum of forces)

Once we have the components Rx and Ry, we can find the magnitude and direction of the vector R.

Page 12: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

HOMEWORK

3; 5; 12; 13; 17; 18; 20; 22; 26; 28;

30; 31; 33; 35; 36; 37; 38

Page 13: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Newton’s First Law – Figure 4.7

•“Objects at rest tend to stay at rest and objects in motion tend to stay in motion in a straight line unless it is forced to change that state by forces acting on it”

Page 14: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 15: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

R = F1 + F2 = 0• Zero resultant force is equal to no force at all.• When an object is acted on by no forces or by several forces whose vector sum (resultant) is zero, we say that the object is in equilibrium, R = Σ F = 0 (equilibrium under zero resultant force) Each component of R must be zero, so Σ Fx = 0, Σ Fy = 0. (object in equilibrium)

Page 16: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

We determine effect with the net force. – Figure 4.8

Page 17: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 18: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 19: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 20: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 21: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Mass and Newton’s Second Law II – Figure 4.12

•Let’s examine some situations with more than one mass.

Page 22: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

INERTIA

Page 23: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Newton’s Second Law of Motion (Vector Form)

The vector sum (resultant) of all the forces acting on an object equals the object’s mass times its acceleration :

ΣF = ma

The acceleration a has the same direction as the resultant force ΣF.

Page 24: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Newton’s Second Law of Motion (Components Form)

For an object moving in a plane, each component of the total force equals the mass times the corresponding component of acceleration:

ΣFx = max ΣFx = max

Page 25: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Definition of the newton

One newton is the amount of force that gives an acceleration of 1 meter per second squared to an object with a mass of 1 kilogram. That is,

1 N = (1 kg) ( 1 m/s2)

Page 26: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 27: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 28: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

ON THE MOON

Page 29: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Measurement of mass – Figure 4.20

•Since gravity is constant, we can compare forces to measure unknown masses.

Page 30: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Forces are the origin of motion

Forces Acceleration a=F/m

Velocityv= v0 + at

Positionx = x0 + v0t + ½ at2

Page 31: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Forces and free body diagrams

• we account for the forces and draw a free body diagram.

•In this case, the net force is unbalanced.

•This is a good example of forces in dynamics.

Page 32: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Newton’s Third Law

Page 33: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Newton’s Third Law

•“For every action there is an equal and opposite reaction.”

•Rifle recoil is a wonderful example.

Page 34: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

For two interacting objects A and B, the formal statement of Newton’s third law is

FA on B = -FB on A

Newton’s own statement, translated from the latin of the Principia, isTo every action there is always opposed an equal reaction; or, the mutual actions of two objects upon each other are always equal, and directed to contrary parts.

Newton’s Third Law

Page 35: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Free-Body Diagram

Page 36: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Page 37: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Use free body diagrams in any situation – Figure 4.24

•Find the object of the focus of your study and collect all forces acting upon it

Page 38: Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Chapter 4.

Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley

Homework

• 3, 9, 14, 20, 21, 23, 30, 34, 41, 52