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P a g e 1 | 15

Previous Years Exam Papers of Rajasthan State

(CIVIL ENGINEERING)

CHAPTER-WISE, DETAILED & ERROR FREE SOLUTIONS

For

B. CHAND PUBLICATION

RAJASTHAN JUNIOR ENGINEER

EXAMINATION 2020

PWD, PHED, WRD, RSAMB, DLB, Panchayati Raj and others


P a g e 2 | 15

B. Chand Publication

Engineers Pride- Most advanced and Honest Institute for UPSC IAS, UPSC IES,GATE,GATE,SSC-JE, RRB-JE, State(AEn/JEn),PSUs etc.-By IITian (B.Tech/ IIT Guwahati),Ex. Assistant Commandant, IES(Indian Railways)-B.CHAND, Class Room/Office Address-C-225, Ganesh Marg, C-Block, Mahesh Nagar (200 Meter from Riddhi Siddhi Tiraha), Gopal Pura Mode (between Gandhi Nagar Railway Station and Durga Pura Railway Station), Jaipur, Rajasthan, 9660807149, 7014320833, 8078607812, [email protected] , www.engineerspride.org , www.engineeringpride.com -

1st Edition: March 2020

2nd Edition: April 2020

MRP: 500/- Only

Disclaimer - all care has been taken while designing this book but still there might be some

error and for more clarity students may refer to video solutions of this book available on

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RAJASTHAN JUNIOR ENGINEER EXAMINATION 2020

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reproduced, stored in or introduced into a retrieval system, or transmitted in any form or by any

means (electronic, mechanical, photo-copying, recording or otherwise), without the prior written

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P a g e 3 | 15

Content (Paper-wise)

S.No. Name of Examination (Chronological Order) No. of MCQs

1.0 ACF 2011 200

2.0 Lecturer 2011 100

3.0 VP-ITI 2012 100

4.0 RPSC-AE 2013 100

5.0 WRD-JE(Degree) 2013 80+40

6.0 WRD-JE(Diploma) 2013 80+40

7.0 GWD-AE 2014 100

8.0 Lecturer 2014 100

9.0 WRD-JE(Degree) 2016 80+40

10.0 WRD-JE(Degree) 2016/TSP 80+40

11.0 WRD-JE(Diploma)2016 80+40

12.0 WRD-JE(Diploma)2016/TSP 80+40

13.0 PHED-JE(Degree) 2016 60+40

14.0 PHED-JE(Diploma) 2016 60+40

15.0 RPSC-AE 2018 100

Total 1720


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Index | Subject-wise

S. No. Subject Page No.

1. Strength of Materials (SOM) 5

2. Theory of Structures (TOS) 35

3. Building Materials & Concrete Technology 45

4. Construction Technology 80

5. Reinforced Cement Concrete & Prestresses Concrete (RCC &

PSC)

87

6. Design of Steel Structures (DSS) 112

7. Project Management (PM) 128

8. Tendering System (TS) 134

9. Geotechnical Engineering (GT) 136

10. Environmental Engineering (EE) 172

11. Fluid Mechanics (FM) 197

12. Hydraulic Machines (HM) 219

13. Open Channel Flow (OCF) 222

14. Survey Technology (ST) 225

15. Highway Engineering (HE) 252

16. Hydrology (HDD) 267

17. Irrigation Engineering (IRR) 279

18. Geology 292

19. Bridges 294

20. CAD 303

21. Rajasthan History, Art and Culture 310


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22. Rajasthan Geography 322

23. Rajasthan Economy 340

24. Rajasthan Polity 460

25. Other minor topics of Rajasthan GK 380

26. India GK 385

27. Current Affairs 396


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aka Mechanics of Solids (MOS) or Solid Mechanics

S. NO. CHAPTER Page No.

1 CH 01 Simple stress, simple strain,

properties or materials and Elastic

Constants

7

2 SFD and BMD

3 CG and MOI

4 Deflection

5 Transformation of Stresses

6 Bending Stress

7 Shear Stress

8 Torsion

9 Springs

10 Columns

11 Pressure vessels

12 Combined stress

Strength of Materials (SOM)


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CH 01 Simple stress, simple strain,

properties or materials and Elastic

Constants

1. If a material has identical elastic properties in all directions it is said to be....

(1) Homogenous

(2) Isotropic

(3) Elastic

(4) Orthotropic

ACF-(Rajasthan)-2011, Lecturer

Rajasthan l Diploma l collage-2011 &

PHED-JE 2016 (Diploma)

Sol. (2) A property of a material is the response of a material to external stimuli.

Consider any point inside the bulk of a material. At that point, we apply a stimulus (or a load) in a direction. We get a certain response and that is what we call property of the material in that direction.

However, if we apply similar stimuli at all possible directions at that one point and get different results every time, we call that material anisotropic.

Now, if we get similar results by applying similar stimuli in all possible directions at that point, we call the material Isotropic. It is an idealized concept and no such material exists.

If we get similar results by applying similar stimuli in only 3 mutually perpendicular directions at that point alone, we call the material orthotropic.

It is important to mention that we decide anisotropy/isotropy at a certain point inside the bulk of the material only. At some other point, same stimuli may produce different results.

So, a material can be orthotropic at some point, anisotropic at another & isotropic at other. It is not a bulk concept.

But this phenomenon will make our calculations almost impossible. So, we employ the concept of homogeneity while studying our systems. A material is called homogeneous if it exhibits similar results (properties) in a single direction only but at every point throughout the bulk of the material.

The material easiest to analyse is the one which is both isotropic & homogeneous because its each and every point behaves similarly to external stimuli from all directions. On the other hand, anisotropic material calculations require advanced matrix calculations and Finite Element analysis-based software like Ansys, Abacus etc.

2. If a composite bar of steel and copper is heated, the copper bar will be under.......

(1) Tension

(2) Compression

(3) Shear

(4) Torsion

ACF-(Rajasthan)-2011 & Lecturer Rajasthan l Diploma l collage-2011

Sol. (2) A composite bar may be defined as a bar made up of two or more materials joined together in such a manner that both


P a g e 8 | 15

are extended or contracted as a single unit.

Since coefficient of thermal expansion of copper is more than that of steel hence copper bar will expend more but as both the bars are connected rigidly with each other so their final length will be same. This results compression in copper bar and tension in steel bar.

Thermal expansion is the tendency of matter to change its shape, area, and volume in response to a change in temperature.

Material

Fractional expansion

per degree C x10^-6

Fractional expansion

per degree F x10^-6

Glass, ordinary

9 5

Glass, Pyrex 4 2.2

Quartz, fused

0.59 0.33

Aluminium 24 13

Brass 19 11

Copper 17 9.4

Iron 12 6.7

Steel 13 7.2

Platinum 9 5

Tungsten 4.3 2.4

Gold 14 7.8

Silver 18 10

3. Poisson's ratio is involving.......

(1) Elastic Modulli

(2) Stresses

(3) Strains

(4) None of these

ACF-(Rajasthan)-2011

Sol. (3) Poisson's ratio is given by

Lateral strain

Longitudinal strain

= −

Hence, strains are involved in

Poisson's ratio

4. The necessary condition for equilibrium of body is

(1) ∑H =0

(2) ∑V =0

(3) ∑M =0

(4) All of the above

ACF-(Rajasthan)-2011

Sol. (4)

2D

3D

https://en.wikipedia.org/wiki/Shapehttps://en.wikipedia.org/wiki/Areahttps://en.wikipedia.org/wiki/Volume


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5. Every material obeys the Hook’s law within its

(1) Elastic limit

(2) Plastic limit

(3) Limit of proportionality

(4) None of the above

ACF-(Rajasthan)-2011, Lecturer Rajasthan l Diploma l collage-2011 & Lecturer l Rajasthan l Diploma l collage-2014

Sol. (3)

Every material obeys the Hooke's Law

within limit of proportionality.

Up to limit of proportionality, axial stress is

propositional to longitudinal strain

according to Hooke's law.

Mathematically,

σ ∝ Longitudinal

σ= E Longitudinal

where, E= Young's modulus

6. For an isotropic, homogeneous and elastic material obeying Hooke's law, number of independent elastic constant is

(1) 2 (2) 3

(3) 9 (4) 1

Lecturer l Rajasthan l Diploma l collage-2011

Sol. (1) For an isotropic, homogeneous and

elastic material obeying Hooke's law, the

Number of elastic constants is 2.

Number of independent elastic constants

in case of orthotropic material are 9.

Number of independent constants for in

anisotropic material are 21.

7. The property by virtue of which a material deformed under the load is enabling to return to its original dimension when load is removed.

(1) Plasticity (2) Ductility

(3) Elasticity (4) Malleability


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Lecturer l Rajasthan l Diploma l collage-2011 and VP-ITI-(Rajasthan)-2012

Sol. (3) The property by virtue of which a

material deformed under the load is

enabling to return to its original dimension

when load is removed is called Elasticity.

Malleability is the ability of materials to deform easily under compressive stress. This can be often characterized as materials ability to form thin sheets by hammering or rolling.

On the other hand, Ductility is the ability of materials to deform easily under tensile stress. This can be often characterized as materials ability to be drawn into wires. It is also used to describe the extent to which the material can be plastically deformed.

In case you do not know the difference between compressive and tensile stress, compressive stress is generated by the force acting towards the centre, while the tensile stress is generated by the force acting away from the material. In layman's term, compressive force makes the material smaller and the tensile force stretches the material.

8. Modulus of rigidity is defined as the ratio of

(1) Longitudinal stress to longitudinal strain

(2) shear stress to shear strain

(3) Stress to strain

(4) Stress to volumetric strain

RPSC-AEN-2013

Sol. (2) According Hooke's low, shear stress

is proportional to shear strain up to

proportional limit.

mathematically,

shear stress (𝜏) ∝ shear strain (𝛾)

G =

G=

where, G = Modulus of rigidity or shear

modulus.

Note: Line equation,

y=mx

where, m= slope of the line

Similarly, G =

G= slope of shear stress– shear strain curve

up to propositional limit.

9. The relation between modulus of elasticity E, bulk modulus K, Poisson's ratio 1/m is.

(1)E = 3K (1 - 2/m)

(2)E = 2K (1 - 3/m)

(3)K = 3E (1 - 2/m)

(4)K = 2E (1 - 3/m)

RPSC-AEN-2013

Sol. (1) Take 𝝁 =𝟏

𝒎

• The relationship between Young’s modulus (E), rigidity modulus (G) and Poisson’s ratio (µ) is expressed as:


P a g e 11 | 15

• The relationship between Young’s modulus (E), bulk modulus (K) and Poisson’s ratio (µ) is expressed as:

• Young’s modulus can be expressed in terms of bulk modulus (K) and rigidity modulus (G) as:

• Poisson’s ratio can be expressed in terms of bulk modulus (K) and rigidity modulus (G) as:

10. The maximum value of Poisson's ratio for an elastic material is

(1) 0.25 (2) 0.5

(3) 0.75 (4) 0.1


Sol. (2) Typical Poisson's Ratios for some common materials are indicated below.

Material Poisson's Ratio

- μ -

Upper limit 0.5

Aluminium 0.334

Aluminium, 6061-T6 0.35


- μ -

Aluminium, 2024-T4 0.32

Beryllium Copper 0.285

Brass, 70-30 0.331

Brass, cast 0.357

Bronze 0.34

Clay 0.41

Concrete 0.1 - 0.2

Copper 0.355

Cork 0

Glass, Soda 0.22

Glass, Float 0.2 - 0.27

Granite 0.2 - 0.3

Ice 0.33

Inconel 0.27 - 0.38

Iron, Cast - gray 0.211

Iron, Cast 0.22 - 0.30

Iron, Ductile 0.26 - 0.31

Iron, Malleable 0.271


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- μ -

Lead 0.431

Limestone 0.2 - 0.3

Magnesium 0.35

Magnesium Alloy 0.281

Marble 0.2 - 0.3

Molybdenum 0.307

Monel metal 0.315

Nickel Silver 0.322

Nickel Steel 0.291

Polystyrene 0.34

Phosphor Bronze 0.359

Rubber 0.48 - ~0.5

Sand 0.29

Sandy loam 0.31

Sandy clay 0.37

Stainless Steel 18-8 0.305

Steel, cast 0.265

Steel, Cold-rolled 0.287


- μ -

Steel, high carbon 0.295

Steel, mild 0.303

Titanium (99.0 Ti) 0.32

Wrought iron 0.278

Z-nickel 0.36

Zinc 0.331

Note

I. In general, range of poisson’s ratio is

-1 to 0.5 but for most of the civil

engineering materials this range is 0.0

to 0.5

II. Polymer foam has got value of

poisson’s ratio as -1

11. A metal bar of length 100 mm is inserted between two rigid supports and its temperature is increased by 100 C. If the coefficient of thermal expansion is 8 x 10-6 per 0C and the young's modulus is 1.5 x 105 MPa, the stress in the bar is

(1) Zero (2) 12 MPa

(3) 24 MPa (4)2400 MPa


Sol. (2) Given: Length (𝑙) = 100 mm

t (change in temperature) = 10°C

∝ = 8 × 10-6 per °C


P a g e 13 | 15

E = 1.5 × 105 MPa

we know that,

stress in the bar (𝜎) = ∝ tE

= 8 ×10-6 × 10 × 1.5 × 105

= 12 MPa

Note that strain in this bar will be

zero as it is inserted between rigid

supports.

12. The stress below which a material does not fractures under large number of reversals of stress is called: -

(1) Creep

(2) Ultimate strength

(3) Endurance limit

(4) Residual stress

[RPSC-AEN-GWD-2014]

Sol. (3)

The stress below which a material

does not fractures under large

number of reversals of stress is called

endurance limit. Endurance limit is

also known as Fatigue limit.

Creep is a property by virtue of

which a material undergoes

additional deformation (over and

above elastic deformation) with

passes of time under sustained

loading within elastic limit.

13. The greatest amount of strain energy per unit volume that a material can absorb up to its elastic limit is: -

(1) Toughness Index

(2) Proof resilience

(3) Resilience

(4) Potential energy

VP-ITI-(Rajasthan)-2012

Sol. (*)

I. Strain energy absorbed by the

material up to elastic limit is called

resilience.

II. Strain energy absorbed per unit

volume by the material up to elastic

limit is called modulus of

resilience.

III. Maximum strain energy that can be

absorbed by the spring up to the

elastic limit without creating a

permanent distortion is called

proof resilience.

Note that for this question no answer is

correct but still proof resilience (2) can

be marked as nearest correct

Stress

Endurance

limit For ferrous metals

Number of cycles of loading which

cause fatigue failure


P a g e 14 | 15

14. The value of Poisson's ration of the materials lie between: -

(1) 1 and 2 (2) 0 and 1/2

(3) 0 and 1 (4) 2 and 3

VP-ITI-(Rajasthan)-2012

Sol. (2)

For more information kindly refer to the solution of Q.10

15. Simple stress means

(1) Direct tensile stress

(2) Direct compressive stress

(3) Shear stress

(4) Only one type of stress


Sol. (4) Simple stress means only one type

of stress. Note that for this question all

options are correct but option (4) is best.

16. The relationship between modulus

of elasticity (E) and Bulk Modulus (K)

and Poisson’s ratio m is

(1) E=3k(1-2m) (2) E=3k(1+2m)

(3) E=3k(1-m) (4) E=3k(1+m)

PHED-JE 2016 (Diploma)

Sol. (1) E=3k(1-2m), for more information

refer the solution of Q.9 and don’t get

confused with the notation of poission’s

ratio.

17. A rubber bar of length 1.5m and

200mm diameter is stretched along

its length by 20mm with a force of 15

kN. As a result, its diameter is

reduced by 2mm. The poisons' ratio

of the bar material will be:

(1) 5 (2) 1

(3) 0.75 (4) 0.5

WRD-JE-DIPLOMA-TSP-2016

Sol. (3)

Poison’s ratio,laterral strain

longitudinal strain = −

( )2 / 20020 /1500

−= −

0.75 =

18. A structure is subjected to different

sets of loads, and then sum of

deflections under each set of loads

acting separately is equal to total

deflection of the structure due to

different sets loads provided loads

are within:

(1) Elastic limits including buckling

(2) Proportional limits without

buckling

(3) Elastic limit

(4) Limit State

WRD-JE-DIPLOMA-TSP-2016


P a g e 15 | 15

Sol. (2) The statement given in this

question is talking about principle of

superposition. This principle is applicable

when Hooke’s law is valid, and

deformations are very small. Hooke’s law is

valid within proportional limit hence

answer is (2)

19. The phenomenon of decreased

resistance of material due to

reversal of stress is called-

(1) Creep (2) Fatigue

(3) Resilience (4) Plasticity

AE-RAJASTHAN-2018

Sol. (2) In materials science, fatigue is the

weakening of a material caused by cyclic

loading(reversal of stress) that results in

progressive and localized structural

damage and the growth of cracks.

20. What shall be the ratio of modulus

of elasticity to shear modulus of a

material having poison's ratio of 0.5

(1) 3 (2) 1.5

(3) 1 (4) 0.5

WRD-JE-DIPLOMA-2016

Sol. (1)

G=𝐸

2(1+𝜇)

𝐸

𝐺= 2(1 + 𝜇)

= 2(1 + .5)

= 3
https://en.wikipedia.org/wiki/Materials_science

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