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Chapter 8: Factoring
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Chapter 8: Factoring

Jan 18, 2016

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Chapter 8: Factoring. Fill in the titles on the foldable. 8.1 Prime factoring and factor a monomial (top). Prime # = factors only include 1 and itself Composite # = more than two factors. Ex: Prime factor 90. Prime numbers: 1, 3, 5, 7, 11, 13, 17, 23, 29, 31, 37 …. 90. 2. 45. 3. 15. - PowerPoint PPT Presentation
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Page 1: Chapter 8: Factoring

Chapter 8: Factoring

Page 2: Chapter 8: Factoring

Chapter 8 : FactoringPrime Factoring & Factor a monomial 8.1

Greatest Common Factor (GCF) 8.1

Factor Using Distributive Property 8.2

Factory by Grouping 8.2

Zero Product Property 8.2

Factoring Trinomials – x2 + bx + c 8.3

Factoring Trinomials – ax2 + bx + c 8.4

Factoring Differences of Squares 8.5

Factoring Perfect Squares 8.6

Square Root Property 8.6

Rational Expressions 11.2

Fill in the titles on the foldable

Page 3: Chapter 8: Factoring

8.1 Prime factoring and factor a monomial (top)

Prime # = factors only include 1 and itself Composite # = more than two factors

Ex: Prime factor 90 Prime numbers:

1, 3, 5, 7, 11, 13, 17, 23, 29, 31, 37 ….

90

2 45

3 15

3 5

2 x 3 x 3 x 5 =

2 x 32 x 5

Page 4: Chapter 8: Factoring

8.1 Prime factoring and factor a monomial (bottom)

Factor a monomial = list all factors separately (no exponents)

Ex: 38rs2t Ex: -66pq2

2 19

38

2 x 19 x r x s x s x t

-66

-1 66

2 33

3 11

-1 x 2 x 3 x 11 x p x q x q

Page 5: Chapter 8: Factoring

8.1 Greatest Common Factor (top)

GCF = the largest factor that is in all the given monomials

1. factor all monomials 2. circle all common factors 3. Multiply all the circled factors

Page 6: Chapter 8: Factoring

8.1 Greatest Common Factor (bottom)

Ex: 84 & 70 Ex: 36x2y & 54xy2z

84

2 42

2 21

3 7

2 x 2 x 3 x 7

70

2 35

5 7

2 x 5 x 7

2 x 7= 14

36

2 18

2 9

3 3

2 x 2 x 3 x 3 x x x x x y

54

2 27

3 9

3 3

2 x 3 x 3 x 3 x x x y x y x z

2 x 3 x 3 x x x y= 18xy

Page 7: Chapter 8: Factoring

8.2 Factor Using Distributive Property (top)

Find the GCF of the monomials Write each term as a product of the GCF and

the remaining factors Simplify the remaining factors

Page 8: Chapter 8: Factoring

8.2 Factor Using Distributive Property (bottom)

Ex: 12a2 + 16a Ex: 3p2q – 9pq2 + 36pq

12

2 6

2 3

16

2 8

2 4

2 2

2 x 2 x 3 x a x a

2 x 2 x 2 x 2 x a= 2 x 2 x a =4a

4a(3a) + 4a(4) =

4a(3a + 4)

-9

-1 9

x 3 x p x p x q

36

2 18

2 9

3 3

-1 x 3 x 3 x p x q x q2 x 2 x 3 x 3 x p x q

3 x p x q = 3pq

3pq(p) + 3pq(-3q) + 3pq(12) =

3pq(p - 3q + 12)

3 3

Page 9: Chapter 8: Factoring

8.2 Factor by Grouping (top)

Group the terms (first two and last two) Find the GCF of each group Write each group as a product of the GCF

and the remaining factors Combine the GCFs in a group and write the

other group as the second factor

Page 10: Chapter 8: Factoring

8.2 Factor by Grouping (bottom)

Ex: 4ab + 8b + 3a + 6

(4ab + 8b)(+ 3a + 6)

4

2 28

2 4

2 2

2 x 2 x a x b

2 x 2 x 2 x b=4b

4b(a + 2)

3 x a

6

2 3

2 x 3 = 3

+3 (a + 2)

(4b + 3)(a + 2)

Ex: 3p – 2p2 – 18p + 27

(3p – 2p2 )( – 18p + 27)

3 x p

2 x p x p= p

-18

2 9

3 3

-1 x 2 x 3 x 3 x p

-1 1827

3 9

3 3

3 x 3 x 3 = 9

p(3 – 2p) + 9(-2p + 3)

(p + 9)(-2p + 3)

Page 11: Chapter 8: Factoring

8.2 Zero Product Property (top)

Roots = the solutions to the equation

When an equation is factored and equal to zero:Set each factor equal to zero and solve for the variable

Page 12: Chapter 8: Factoring

8.2 Zero Product Property (bottom)

Ex: (d – 5)(3d + 4) = 0

d – 5 = 0 3d + 4 = 0 + 5 + 5

d = 5

- 4 - 4

3d = -4/3 /3

d = -4/3

Roots are d = 5 and -4/3

Ex: 7f2 – 35f = 0

7 x f x f-35

-1 35

5 7

-1 x 5 x 7 x f= 7f

7f(f) + 7f(-5)

7f(f – 5) = 0

7f = 0 f – 5 = 0

/7 /7f = 0

+ 5 + 5f = 5

Roots are f = 0 and 5

Page 13: Chapter 8: Factoring

8.3 Factoring Trinomials – x2 + bx + c (top)

Get everything on one side (equal to zero) Split into two groups ( )( ) = 0 Factor the first part x2 (x )(x ) = 0 Find all the factors of the third part (part c) Fill in the factors of c that will add or subtract to

make the second part (bx) Foil to check your answer

Use Zero Product Property to solve if needed

Page 14: Chapter 8: Factoring

8.3 Factoring Trinomials – x2 + bx + c (bottom)

Ex: x2 + 6x + 8

(x )(x ) 8

1, 8

2, 4(x + 2)(x + 4)

FOIL

x2 + 2x + 4x + 8

x2 + 6x + 8

Ex: r2 – 2r - 24

(r )(r ) 24

1, 24

2, 12

3, 8

4, 6

(r + 4)(r - 6)

FOIL

r2 – 6r + 4r - 24

r2 - 2x - 24

Ex: s2 – 11s + 28 = 0

(s )(s ) 28

1, 28

2, 14

4, 7

(s- 4)(s - 7) = 0

FOIL

s2 – 7s – 4s + 28

s2 – 11s + 28

s – 4 = 0 s – 7 = 0 +4 +4 +7 +7

s = 4 s = 7

s = 4 and 7

Page 15: Chapter 8: Factoring

8.4 Factoring Trinomials – ax2 + bx + c (top)

Get everything on one side (equal to zero) Put the first part in each set of parentheses Find product of the first and last parts Find the factors of the product Fill in the pair of factors that adds or subtracts to the

second part Remove the GCF from one set of parentheses Write what is left of the that group as one factor and then

the other group as the other factor

if you can’t factor = prime(use the zero product property to solve if needed)

Page 16: Chapter 8: Factoring

8.4 Factoring Trinomials – ax2 + bx + c (bottom)

Ex: 5x2 + 13x + 6 Ex: 10y2 - 35y + 30 = 05 x 6 = 30

1, 30

2, 15

3, 10

5, 6

(5x + 10)(5x + 3)

(x + 2)(5x + 3)

5(2y2 - 7y + 6) = 0

Hint: find the gcf to pull it out and make the numbers smaller if possible

2 x 6 = 12

1, 12

2, 6

3, 4

2 x y x y

2 x 2 = 2

= 5

5(y - 2)(2y - 3) = 0

y – 2 = 0 2y – 3 = 0

Solve for y.

y = 2 and 1.5

(5x )(5x )

5x: x 5 10: 2 5

(5x + 10) 5(x + 2)

5(2y )(2y )=05(2y - 4)(2y - 3)=0

(2y - 4) 2(y - 2)

Page 17: Chapter 8: Factoring

8.5 Factoring Differences of Squares (top)

Factor each term Write one set of parentheses with the factors adding and

one with the factors subtracting Foil to check your answer

Ex: n2 - 25 Ex: 9x3 – 4x

n x n 5 x 5

(n + 5)(n - 5)

Hint: find the gcf to pull it out and make the numbers smaller if possible

x(9x2 – 4)

x[ 3x x 3x 2 x 2]

x(3x + 2)(3x - 2)

Page 18: Chapter 8: Factoring

8.5 Factoring Differences of Squares (bottom)

Ex: 5x3 + 15x2 – 5x - 15 Ex: 121a = 49a3

5[x3 + 3x2 – x – 3]

5[ (x3 + 3x2)( – x – 3)]

3 x x x xx x x x x = x2

5[ x2(x + 3)

-1 x x

-1 x 3 = -1

- 1(x + 3)]

5[(x2 – 1)(x + 3)]5[(x x x 1 x 1)(x + 3)]

5(x + 1)(x - 1)(x + 3)

-121a -121a

0 = 49a3 – 121a0 = a(49a2 – 121)

0 = a(7a x 7a 11 x 11)

0 = a(7a + 11)(7a - 11)

a = 0 7a + 11 = 0 7a - 11 = 0 -11 -11 +11 +117a = -11 7a = 11/7 /7 /7 /7

a= -11/7 a = 11/7

a = -11/7, 0, and 11/7

Page 19: Chapter 8: Factoring

8.6 Factoring Perfect Squares (top)

Perfect Square Trinomial: Is the first term a perfect square? Is the last term a perfect square? Does the second term = 2 x the product of the

roots of the first and last terms?

If any of these answers is no- it is not a perfect square trinomial

Page 20: Chapter 8: Factoring

8.6 Factoring Perfect Squares (bottom)

Ex: (x – 7)2 Ex: (a – 4)2

x2 – 14x + 49 a2 – 8a + 16

Ex: 9y2 – 12y + 4

1. 9y2 = 3y x 3y yes

2. 4 = 2 x 2 yes

3. 2(3y x 2) = 2(6y) = 12y yes

(3y – 2)2

Page 21: Chapter 8: Factoring

8.7 Square Root Property

7)8( 2 y

78 y

78 y

Ex: (y – 8)2 = 7 Ex: (b – 7)2 = 36

78 y+8 +8 +8 +8

78y 78 y

36)7( 2 b

67 b

b – 7 = 6 b – 7 = -6+7 +7 +7 +7

b = 13 b = 1

Page 22: Chapter 8: Factoring

11.2 Rational Expressions(top)

Page 23: Chapter 8: Factoring

11.2 Rational Expressions(bottom)