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Chapter 25 Waves and Particles Midterm 4 UTC 1.132
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Chapter 25

Feb 25, 2016

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Chapter 25. Waves and Particles Midterm 4 UTC 1.132   . Wave Phenomena. Interference Diffraction Reflection. Wave Description. – wavelength: distance between crests (meters) T – period: the time between crests passing fixed location (seconds) - PowerPoint PPT Presentation
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Page 1: Chapter  25

Chapter 25

Waves and ParticlesMidterm 4 UTC 1.132  

Page 2: Chapter  25

Wave Phenomena

• Interference• Diffraction• Reflection

Page 3: Chapter  25

l – wavelength: distance between crests (meters)T – period: the time between crests passing fixed location (seconds)v – speed: the distance one crest moves in a second (m/s)f – frequency: the number of crests passing fixed location in one second (1/s or Hz) – angular frequency: 2f: (rad/s)

Tv l

Tf 1

fv l

Wave Description

Page 4: Chapter  25

E E0 cos t E0 cos2T

t

Wave: Variation in Time

Page 5: Chapter  25

xExEE

l

l 2cos2cos 00

Wave: Variation in Space

Page 6: Chapter  25

xEE

l2cos0

t

TEE 2cos0

xt

TEE

l 22cos0

‘-’ sign: the point on wave moves to the right

Wave: Variation in Time and Space

Page 7: Chapter  25

xt

TEE

l 22cos0

But E @ t=0 and x =0, may not equal E0

l xt

TEE 22cos0

phase shift, =0…2

Two waves are ‘out of phase’

Wave: Phase Shift

tEt

TEE cos2cos 00

(Shown for x=0)

Page 8: Chapter  25

In many cases we are interested only in E at certain location:can ignore dependence on x:

tEt

TEE cos2cos 00

Using angular frequency makes equation more compact

Wave: Angular Frequency

t

y(x,t) Asin(kx t)

2T

k 2l

Page 9: Chapter  25

tEE cos0

E0 is a parameter called amplitude (positive). Time dependenceis in cosine function

Often we detect ‘intensity’, or energy flux ~ E2. For example: Vision – we don’t see individual oscillations

Intensity I (W/m2):20EI

Works also for other waves,such as sound or water waves.

Wave: Amplitude and Intensity

Page 10: Chapter  25

Superposition principle: The net electric field at any location isvector sum of the electric fields contributed by all sources.

Can particle model explain the pattern?

Laser: source of radiation which has the same frequency (monochromatic) and phase (coherent) across the beam.

Two slits are sources of two waves with the same phase and frequency.

Interference

Page 11: Chapter  25

Two emitters:

E1

E2

Fields in crossing point

tEE

tEE

coscos

02

01

Superposition: tEEEE cos2 021

Amplitude increases twice: constructive interference

Interference: Constructive

Page 12: Chapter  25

Two emitters:

E1

E2

tEEEE cos2 021

What about the intensity (energy flux)?

Energy flux increases 4 times while two emitters produce onlytwice more energy

There must be an area in space where intensity is smaller than thatproduced by one emitter

Interference: Energy

Page 13: Chapter  25

E1

E2

ttEEEE coscos021

tEEtEE

coscos

02

01

tcos

0

Two waves are 1800 out of phase: destructive interference

Interference: Destructive

Page 14: Chapter  25

Superposition principle: The net electric field at any location isthe vector sum of the electric fields contributed by all sources.

Interference

tEE

tEE

coscos

02

01

tEEEE cos2 021

Amplitude increases twice

Constructive: Energy flux increases 4 times while two emitters produce only twice more energy

ttEEEE coscos021

tEEtEE

coscos

02

01

Two waves are 1800 out of phase

Constructive: Destructive:

Page 15: Chapter  25

Intensity at each location depends on phase shift between twowaves, energy flux is redistributed.

Maxima with twice the amplitude occur when phase shift between two waves is 0, 2, 4, 6 …(Or path difference is 0, l, 2 l…)

Minima with zero amplitude occur when phase shift between two waves is , 3, 5 …(Or path difference is 0, l/2, 3l/2…)

Can we observe complete destructive interference if 1 2 ?

Interference

Page 16: Chapter  25

Predicting Pattern For Two SourcesPoint C on screen is very far from sourcesC

normal

Need to know phase difference

Very far: angle ACB is very small

Path AC and BC are equal

Path difference: )sin(dl

If l = 0, l, 2l, 3l, 4l … - maximumIf l = l/2, 3l/2, 5l/2 … - minimum

Page 17: Chapter  25

Predicting Pattern For Two SourcesC

normal

Path difference: )sin(dl

If l = 0, l, 2l, 3l, 4l … - maximumIf l = l/2, 3l/2, 5l/2 … - minimum

What if d < l ?

complete constructive interferenceonly at =00, 1800

What if d < l/2 ?

no complete destructive interference anywhere

Note: largest l for =/2

Page 18: Chapter  25

d = 4.5 l

Why is intensity maximum at =0 and 1800 ?

Why is intensity zero at =90 and -900 ?

What is the phase difference at Max3?

Intensity versus AnglePath difference: )sin(dl

If l = 0, l, 2l, 3l, 4l … - maximumIf l = l/2, 3l/2, 5l/2 … - minimum

Page 19: Chapter  25

Path difference: )sin(dl

If l = 0, l, 2l, 3l, 4l … - maximumIf l = l/2, 3l/2, 5l/2 … - minimum

d = l/3.5

Two sources are l/3.5 apart. What will be the intensity pattern?

Intensity versus Angle

Page 20: Chapter  25

Path difference:

If l = 0, l, 2l, 3l, 4l … - maximumIf l = l/2, 3l/2, 5l/2 … - minimum

)sin(dl

L=2 m, d=0.5 mm, x=2.4 mmWhat is the wavelength of this laser?

)sin(l ddl )sin(

Lx

)tan(

Small angle limit: sin() tan()

Lx

d

lnm m 600106 7

Lxdl

Two-Slit Interference

Page 21: Chapter  25

Using interference effect we can measure distances with submicronprecision

laser

Detector

Application: Interferometry

Page 22: Chapter  25

Coherent beam of X-rays can be used to reveal the structure of a crystal.Why X-rays?

- they can penetrate deep into matter- the wavelength is comparable to interatomic distance

Diffraction = multi-source interference

Multi-Source Interference: X-ray Diffraction

Page 23: Chapter  25

Diffraction = multi-source interference

lattice

X-ray

Electrons in atoms will oscillate causing secondary radiation.Secondary radiation from atoms will interfere.Picture is complex: we have 3-D grid of sources

We will consider only simple cases

Multi-Source Interference

Page 24: Chapter  25

Acceleratedelectrons

Copper

X-rays

Electrons knock out innerelectrons in Cu. When theseelectrons fall back X-rayis emitted.(Medical equipment)

Synchrotron radiation: Electrons circle around accelerator.Constant acceleration leads to radiation

Generating X-Rays

Page 25: Chapter  25

Simple crystal: 3D cubic grid

first layer

Simple case: ‘reflection’ incident angle = reflected anglephase shift = 0

X-Ray: Constructive Interference

Page 26: Chapter  25

Reflection from the second layer will not necessarily be in phase

Path difference:

sin2dl

Each layer re-radiates. The total intensity of reflected beam depends on phase difference between waves ‘reflected’ from different layers

Condition for intense X-ray reflection:

where n is an integer l nd sin2

X-Ray: Constructive Interference

Page 27: Chapter  25

crystalturn crystal

x-ray diffracted

l nd sin2

May need to observe several maxima to find n and deduce d

Simple X-Ray Experiment

Page 28: Chapter  25

X-ray of Tungsten

Page 29: Chapter  25

Suppose you have a source of X-rays which has a continuum spectrum of wavelengths.How can one make it monochromatic?

crystal

incident broadband X-ray

reflected single-wavelength X-ray

l nd sin2

Using Crystal as Monochromator

Page 30: Chapter  25

Powder contains crystals in all possible orientations

polycrystalline LiF

Note: Incident angle doesn't have to be equal to scattering angle.Crystal may have more than one kind of atoms.Crystal may have many ‘lattices’ with different d

X-Ray of Powdered Crystals

Page 31: Chapter  25

(Myoglobin) 1960, Perutz & Kendrew

X-Ray of Complex Crystals