LÔÙP 10 A 2 TRƯỜNG THPT LÊ TRUNG ĐÌNH
LP 10 A2 TRNG THPT L TRUNG NH
KiM TRA BI C Cho cc nguyn t X, Y, Z c s hiu nguyn t ln lt l 12, 19, 20.a/ Xc nh v tr ca cc nguyn t trn trong bng tun honb/ Cng thc oxit, hiroxit ca chng c dng nh th no?c/ Sp xp X, Y, Z theo th t tnh kim loi tng; sp xp cc hiroxit theo th t tnh baz tngX 1s22s22p63s2 Y 1s22s22p63s23p64s1 Z 1s22s22p63s23p64s2 Chu k 3 nhm IIA Chu k 4 nhm IA Chu k 4 nhm IIA a/ b/ Cng thc oxit: XO, Y2O, ZOCng thc hiroxit: X(OH)2, YOH, Z(OH)2 c/ Tnh kim loi tng theo th t: X < Z < YTnh baz ca cc hiroxit tng theo th t: X(OH)2 < Z(OH)2 < YOHp n012345k.Loi gimk.Loi tng
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NBit v tr ca mt nguyn t trong bng tun hon c th suy ra cu to nguyn t ca nguyn t khng?
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NVD1: Nguyn t A c s th t l 19 thuc chu k 4, nhm IA. Hy cho bit c im cu to nguyn t ca nguyn t A?STT=Z=P=E = 19- Nguyn t A c 19 proton 19 electronS lp e = STT chu k - C 4 lp electronchu k 4 c 4 lp eS e lp ngoi cng = STT nhm ANhm IA c 1 e lp ngoi cng - C 1 electron lp ngoi cng
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NVD2: Nguyn t B c cu hnh electron nguyn t l: 1s22s22p63s23p4 Hy xc nh v tr ca B trong bng tun honC 6 e lp ngoi cng, l nguyn t p thuc nhm VIA- A chim th 16 - Thuc chu k 3c 3 lp e thuc chu k 3STT=Z =E = 16 - Thuc nhm VIA
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NV tr ca mt nguyn t trong bng tun hon ()S th t ca nguyn tS th t ca chu kS th t ca nhm A Cu to nguyn t .-S proton, s electronS lp electronS electron lp ngoi cngEm c nhn xt g v mi quan h gia v tr ca nguyn t trong bng tun hon v cu to nguyn t ca nguyn t ?Bit v tr ca mt nguyn t trong bng tun hon, c th suy ra cu to nguyn t ca nguyn t v ngc liBTAD
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NII- QUAN H GiA V TR V TNH CHT CA NGUYN TVD: Nguyn t A th 16, chu k 3, nhm VIA. BTHA l kim loi hay phi kim?
- Nhm VIA C 6 electron lp ngoi cng- Chu k 3 A l phi kim A l phi kim (lu hunh)
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NII- QUAN H GiA V TR V TNH CHT CA NGUYN TVD: Nguyn t A th 16, chu k 3, nhm VIA. BTHCng thc oxit cao nht ca A c dng nh th no?
- Nhm VIA Ha tr cao nht trong hp cht vi oxi l 6 Cng thc oxit cao nht: SO3 A l phi kim (lu hunh) Cng thc oxit cao nht: SO3
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NII- QUAN H GiA V TR V TNH CHT CA NGUYN TVD: Nguyn t A th 16, chu k 3, nhm VIA. BTHSO3 thuc loi oxit g?
- Nhm VIA Ha tr cao nht trong hp cht vi oxi l 6 Cng thc oxit cao nht: SO3 A l phi kim (lu hunh) Cng thc oxit cao nht: SO3 SO3 l oxi axit, H2SO4 l axit mnh
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NII- QUAN H GiA V TR V TNH CHT CA NGUYN TVD: Nguyn t A th 16, chu k 3, nhm VIA. BTHCng thc hp cht kh vi hiro ca A c dng nh th no?
- Nhm VIA Ha tr vi hiro l 2 Cng thc hp cht kh vi hiro: H2S A l phi kim (lu hunh) Cng thc oxit cao nht: SO3 Cng thc hp cht kh vi hiro: H2SSO3 l oxit axit, H2SO4 l axit mnh
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NII- QUAN H GiA V TR V TNH CHT CA NGUYN TEm c nhn xt g v mi quan h gia v tr v tnh cht ca nguyn t?Bit v tr ca mt nguyn t trong bng tun hon, c th suy ra tnh cht ha hc c bn ca n.VD: Nguyn t A th 16, chu k 3, nhm VIA. A l phi kim (lu hunh) Cng thc oxit cao nht: SO3 Cng thc hp cht kh vi hiro: H2SSO3 l oxit axit, H2SO4 l axit mnhBTAD
Bi 10: NGHA CA BNG TUN HON CC NGUYN T HA HCI- QUAN H GiA V TR CA NGUYN T V CU TO NGUYN T CA NII- QUAN H GiA V TR V TNH CHT CA NGUYN TIII- SO SNH TNH CHT HA HC CA MT NGUYN T VI CC NGUYN T LN CNDa trn c s no so snh tnh cht ca mt nguyn t vi cc nguyn t ln cn?Da vo quy lut bin i tnh cht ca mt nguyn t trong bng tun hon c th so snh tnh cht ha hc ca mt nguyn t vi cc nguyn t ln cnBTAD
BI TP TR LI NHANHB cu hi 1B cu hi 4B cu hi 2B cu hi 35BT1BT2BT3BT4
Cu 1: Nguyn t X thuc chu k 3 nhm VA. Cng thc hp cht kh vi hiro c dng nh th no?p n:XH3 012345B cu hi 1
Cu 2: Trong 1 chu k, theo chiu tng ca in tch ht nhn, tnh phi kim ca cc nguyn t ................, ng thi tnh kim loi ca chng .............. T trong du ... ln lt l:p n:mnh dn , yu dn 012345yu dn mnh dnB cu hi 1
Cu 1: Phn lp electron ngoi cng ca nguyn t nguyn t X l 3p2. X thuc nhm no trong bng tun hon?p n:IVA012345B cu hi 2
Cu 2: Nguyn t X thuc nhm IIA. Cng thc oxit cao nht ca X c dng nh th no?p n:XO012345B cu hi 2
p n:yu dn, mnh dn012345Cu 1: Trong 1 nhm A, theo chiu tng ca in tch ht nhn, tnh phi kim ca cc nguyn t ............., ng thi tnh kim loi ca chng .................. T trong du ... ln lt l:mnh dn yu dnB cu hi 3
p n: 26, chu k 4, nhm VIIIB012345Cu 2: Nguyn t ca nguyn t Y c cu hnh electron l 1s22s22p63s23p63d64s2. Xc nh v tr ca Y (, chu k, nhm) trong bng tun hon . B cu hi 3
p n:M(OH)2 012345Cu 3: Nguyn t ca nguyn t M c 12 electron lp v. Cng thc hiroxit ca M c dng nh th no?B cu hi 3
p n:A thuc nhm IIIA, Y thuc nhm VIA. 012345Cu 1: X v Y l 2 nguyn t nhm A. Nguyn t X c cng thc oxit cao nht l A2O3, Y to vi hiro hp cht c dng H2Y. X, Y thuc nhm no trong bng tun hon? B cu hi 4
p n:Hiroxit ca X c tnh baz mnh hn 012345Cu 2: X v Y l 2 nguyn t thuc cng chu k 3, X nhm IIA, Y nhm VA. Hiroxit ca nguyn t no c tnh baz mnh hnB cu hi 4
p n:1s22s1 012345Cu 3: Nguyn t M chu k 2 nhm IA. Hy cho bit cu hnh electron nguyn t ca MB cu hi 4
Cu hnh electron nguyn t ca nguyn t X l 1s22s22p63s23p1. Xc nh v tr ca X trong bng tun honC 13 electron chim s 13C 3 lp electron chu k 3C 3 electron ha tr, l nguyn t p nhm IIIAX nm s 13, chu k 3, nhm IIIABTH
Nguyn t Y s 20, chu k 4, nhm IIA. Hy cho bit nhng tnh cht ha hc c bn ca YC 2 electron lp ngoi cng Y l kim loi (Ca)Cng thc oxit cao nht: YOCng thc hiroxit c dng Y(OH)2, c tnh bazBTHD nhng 2 elctrron: Y Y2+ + 2e
Hy sp xp cc nguyn t sau theo th t tnh kim loi tng dn:Mg. Al, K, CaBTHAl < Mg < Ca < KChiu tng tnh kim loi
Bi tp 1:Phn mc nng lng cao nht ca nguyn t nguyn t A l 3p4 . Trong phn ng ha hc, A s c khuynh hng A. nhng 2 electronB. nhn 2 electronC. nhn 4 electronD. nhng 4 electron
A! ng ri
! Sai mt ri
Bi tp 2:Nguyn t X, cation Y2+, anion Z- u c cu hnh electron l 1s22s22p6. a/ Kt lun no sau y ng? A. X l kim loi, Y l kh him, Z l phi kimC. X l kh him, Y l kim loi, Z l phi kimB. X l kh him, Y l phi kim, Z l kim loiD. X l phi kim, Y l kim loi, Z l kh him
Bi tp 2:Nguyn t X, cation Y2+, anion Z- u c cu hnh electron l 1s22s22p6. b/ S electron trong nguyn t ca cc nguyn t X, Y, Z ln lt l: A. 18, 20, 17C. 10, 12, 9B. 18, 16, 19D. 10, 8, 11
A! ng ri
! Sai mt ri
A! ng ri
! Sai mt ri
Bi tp 3:Nguyn t X to vi hiro hp cht c dng XH4. Oxit cao nht ca n cha 53,3% oxi v khi lng. X l: A. CB. SiC. SD. N
A! ng ri
! Sai mt ri
Bi tp 4:Nguyn t A thuc chu k 2 nhm IIIA, B thuc chu k 3 nhm IIIA, C thuc chu k 3 nhm IIA, D thuc chu k 4 nhm IIA.Tnh kim loi ca cc nguyn t gim theo th t: A. D > C > B > AB. A > B > C > DC. A > D > B > CD. B > C > D > A
A! ng ri
! Sai mt ri
Chuc cac em hoc sinh hoc gioi va thanh cong !Xin chan thanh cam n cac thay co giao a ve d gi !
BTH012345