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Assignment 1 Thermodyanmics

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    ASSIGNMENT 1 THERMODYANMICS

    COURSE : CHEMICAL ENGINEERING

    NAME : SHILENGE T.P

    STUDENT NO : 212046710

    PATNER : LEKHULENI N.P

    DUE DATE : 20/03/13

    SUBMITTING TO : PROFFESOR KOLESNIKOV

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    APPARATUS USED TO PERFORM THESE EXPERIMENT

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    TITLE PAGE

    EXPERIMENT PROOVING THE FIRST LAW OFTHERMODYNAMICS

    1.ABSTRACT

    2. INTRODUCTION

    3.THEORY BASED ON THE CHAPTER4.OBJECTIVE OF THE EXPERIMENT

    5. APPARATUS AND PROCEDURE

    6. SAFETY PRECAUTIONS

    7.ACKNOWLEDGEMENTS

    8.CONCLUSION

    9. RECOMMENDATIONS

    10. REFERENCES

    11. NOMENTLATURE

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    ABSTRACT

    A hairdryer , digital anenometer, thermocouple, and multimeter can beused to demonstrate the first law of thermodynamics. A hairdryer which

    is cheaper makes an excellent example of an open thermodynamic

    system, and can be used as an effective piece of lab equipment.

    Heat , work and mass all cross boundary. From the first law of

    thermodynamics , the energy into the system has to equal the energy

    out for the steady state. From the conservation of mass, which states

    that mass can neither be created nor destroyed meaning the mass going

    in to the system should equal to the mass going out of the system

    The experiment requires one to consider all of the energy terms

    associated with the hairdryer.

    The energy going in includes the electric , work the total enthalpy of theincoming air, kinetic energy of the incoming air. Energy out includes the

    total enthalpy of the outgoing air , and any heat transfer from the case to

    the ambient. Potential energy differences between the inlet and the

    outlet are also considered. By accounting for all of the energy terms one

    should begin to recognise what is most significant and what could be

    neglected

    The first law of thermodynamic can be prooven in a form of any energy

    in nature.

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    INTRODUCTION

    A common hairdryer makes an example of an open thermodynamic

    system. The figure below shows the energy terms that are involved in a

    first law analysis. For a steady state condition the total energy in must

    equal the total energy out. Attempt to measure all of these energy terms

    and then compare the energy in with the energy out to show that the

    hairdryer obeys the first law of thermodynamics. A hairdryer uses three

    different forms of energies to work, electrical energy, heat energy andmechanical energy, electricity is used to generate forms of energy in the

    hairdryer.

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    THEORETICAL BACKGROUND

    The first law of thermodynamics also known as the conservation of

    energy principle which stated that energy can neither be created nor

    destroyed but it can only be converted from one form to the other

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    If we are interested in how heat transfer is converted into doing work,

    then the conservation of energy principle is important. The first law of

    thermodynamics applies the conservation of energy principle to systems

    where heat transfer and doing work are the methods of transferring

    energy into and out of the system. The first law of thermodynamics

    states that the change in internal energy of a system equals the net heat

    transferinto the system minus the net work done bythe system. In

    equation form, the first law of thermodynamics is

    U=QW.

    Here U is the change in internal energyU of the system. Q is the

    net heat transferred into the systemthat is, Q is the sum of all heat

    transfer into and out of the system. W is thenet work done by the

    systemthat is, W is the sum of all work done on or by the system. We

    use the following sign conventions: if Q is positive, then there is a net

    heat transfer into the system; if W is positive, then there is net work done

    by the system. So positive Q adds energy to the system and positive W

    takes energy from the system. Thus U=QW Note also that if more

    heat transfer into the system occurs than work done, the difference is

    stored as internal energy. Heat engines are a good example of this

    heat transfer into them takes place so that they can do work. We will

    now examine Q , W and U further.

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    The first law of thermodynamics is actually the law of conservation of

    energy stated in a form most useful in thermodynamics. The first law

    gives the relationship between heat transfer, work done, and the change

    in internal energy of a system.

    Heat Q and WorkW

    Heat transfer (Q) and doing work (W) are the two everyday means of

    bringing energy into or taking energy out of a system. The processes are

    quite different. Heat transfer, a less organized process, is driven by

    temperature differences. Work, a quite organized process, involves a

    macroscopic force exerted through a distance. Nevertheless, heat and

    Figure 2: The first law of thermodynamics is the

    conservation-of-energy principle stated for a system where

    heat and work are the methods of transferring energy for a

    system in thermal equilibrium. Q represents the net heat

    transfer

    it is the sum of all heat transfers into and out of the

    system. Q is positive for net heat transferinto the system. W

    is the total work done on and by the system. W is positive

    when more work is done bythe system than on it. The

    change in the internal energy of the system, U, is related to

    heat and work by the first law of thermodynamics, U=QW

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    work can produce identical results.For example, both can cause a

    temperature increase. Heat transfer into a system, such as when the

    Sun warms the air in a bicycle tire, can increase its temperature, and so

    can work done on the system, as when the bicyclist pumps air into the

    tire. Once the temperature increase has occurred, it is impossible to tell

    whether it was caused by heat transfer or by doing work. This

    uncertainty is an important point. Heat transfer and work are both energy

    in transitneither is stored as such in a system. However, both can

    change the internal energy( U)of a system. Internal energy is a form of

    energy completely different from either heat or work.

    Internal Energy U

    We can think about the internal energy of a system in two different but

    consistent ways. The first is the atomic and molecular view, which

    examines the system on the atomic and molecular scale. The internal

    energy(U)of a system is the sum of the kinetic and potential energies of

    its atoms and molecules. Recall that kinetic plus potential energy is

    called mechanical energy. Thus internal energy is the sum of atomic and

    molecular mechanical energy. Because it is impossible to keep track of

    all individual atoms and molecules, we must deal with averages and

    distributions. A second way to view the internal energy of a system is in

    terms of its macroscopic characteristics, which are very similar to atomicand molecular average values.

    Macroscopically, we define the change in internal energy U to be that

    given by the first law of thermodynamics:

    U=QW.

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    Many detailed experiments have verified that U=QW, where U is

    the change in total kinetic and potential energy of all atoms andmolecules in a system. It has also been determined experimentally that

    the internal energy U of a system depends only on the state of the

    system and not how it reached that state. More specifically, U is found to

    be a function of a few macroscopic quantities (pressure, volume, and

    temperature, for example), independent of past history such as whether

    there has been heat transfer or work done. This independence means

    that if we know the state of a system, we can calculate changes in its

    internal energy U from a few macroscopic variables.

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    OBJECTIVES OF THE EXPERIMENT

    1.To proove the first law of thermodynamics, to give students a basic

    understand of the fundamental laws of thermodynamics and the ability to

    use them in solving a range of simple engineering problems

    2. To illustrate the relationship of the different energies found when the

    hairdryer is operating

    3.To transform energy in one form to another.

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    APPARATUS AND PROCEDURE

    Hair dryer with 2 speed and 3 heat settings (max power 2000 W)

    Stand for mounting hair dryer

    Custom made holder for five thermocouples with thermocouples

    Digital anenometer (measures air velocity, 0-30 m/s)

    Two digital multimeters for measuring voltage and current

    Any device for reading the thermocouples

    Infrared thermometers temperature range -50 C to 300C

    Dial calipers to measure the area

    SAFETY PRECAUTIONS

    During the experiment, the hairdryer should be well insulated to

    avoid shocks caused by electric current

    PROCEDURE

    Setup a hairdryer and mount it on the holder to hold and balancethe hairdryer from moving

    Measure the ambient temperature and the barometric pressure

    using the thermocouples and barometer

    Turn on the hairdryer and allow it to reach a steady condition

    Record the voltage and current to the hairdryer

    Measure and record the temperature

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    in each of the 17 regions of the hairdryer using the thermocouples

    holding feature

    Measure and record the differential speed the hairdryer driven by

    the turbine inside the hairdryer

    Measure and record the temperature of the nozzle

    Turn off the hairdryer and measure and record all the necessary

    physical dimensions

    Inside diameter is to be measured using the dial caliper

    Measure the velocity of the moving turbine inside the hairdryer,

    using anenometer

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    TEST PROCEDURE

    Before the experiment is perfomed the required data should be

    measured, which includes:

    Ambient temperature

    Inside diameter of the outlet

    Any measurements needed to determine the inlet area

    Electrical work in: Voltage and current

    Mass flow rate and enthalpy out: The outlet is divided into 17

    equal area regions (figure5). Within each of these regions the

    outlet temperature

    The reason for dividing the outlet into regions is because the

    temperatures and velocities have large variations across the outlet

    due to the

    locations of the internal components. This method gives much better

    results than using

    an average value across the cross-sections

    Heat out: Surface temperature of the nozzle and length and

    diameter of the heated area.

    figure5

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    CALCULATIONS REGARDING THE EXPERIMENT

    The basic first law of thermodynamics for the hairdryer can be written as

    (

    )

    equation 1

    Electric Work In:

    W=

    .equation 2

    The above equation is used since the hairdryer has power(2000W)

    and the mass flow rate can be calculated in order to get the work in

    joules per kilogram.

    The area of the nozzle is given by:

    A=

    ..equation 3

    The diameter of the nozzle of the hairdryer is to be measured using

    the dial caliper making it easier to calculate the area using equation

    3.

    Heat Transfer:

    Q = hA(TsT)equation 4

    h is the convection coefficient. This number is given as 5 w/m2- 0C. The

    area can be calculated using equation 3.The surface temperature is

    measured using an digital thermometer. The temperature varies across

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    the surface, a judgment can be made about what to use as an average

    temperature. No effort is made to break the nozzle surface into regions

    of different temperatures, mainly because the heat loss through the

    nozzle is quite low and the extra effort would not be worth the extra time

    it would take.

    Specific enthalpy in:

    .equation 5

    Cp is the specific heat of the incoming air, given to the students as 1.004

    KJ/kg-0C. The temperature T is the absolute temperature of the

    incoming air (room temperature) in K.

    Specific Enthalpy Out:

    is calculated using equation 5, but the temperature used is thetemperature for each data region in the outlet.

    Air Density:

    = .equation 6

    In this equation Pb is the barometric pressure in inches of mercury and T

    is the temperature of the air in the data region measured in 0C. Theother constants are conversion factors so the units of density are kg/m3.

    The constants are correction factors for inconsistent units.

    Mass Flow Rate Out:

    equation 7

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    In this equation is the density of the exiting air as determined byequation 6, V is the velocity measured using the digital anemometer,

    and A is the area of the region of interest. The exit is divided into 17

    equal regions, so A becomes the total exit area divided by 17.

    Velocity In:

    The velocity in is to measured between zero and 30 because the inlet

    area is much larger than the exit, so the velocity will be very low. From

    this information the inlet velocity can be calculated from equation 8.

    equation 8

    Where is the density of the room air , is the inlet velocity, and Ainis the total inlet area. The velocity is assumed to be constant across the

    inlet area. The students are required to take any necessary

    measurements to determine the total inlet area.

    Potential Energy:

    The vertical distance between the centre of the inlet and the centre of

    the outlet is measured. This elevation change is used to calculate the

    potential energy change.

    Miscellaneous Information:

    Many of the equations above contain correction factors for unit

    conversion. As mentioned, these factors are not provided for more

    advanced classes. However, some of the measurements still contain

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    inconsistent units, such as the measurements for the heated area of the

    nozzle, the nozzle diameter, and the measurements for the inlet area.

    The students must recognize inconsistent units throughout the

    calculations and make conversions as needed.

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    CONCLUSION

    The above experiment shows the demonstration of the first law of

    thermodynamics at a very low cost for equipment. Most of the

    instrumentation is available in any typical lab. The hairdryer cost is

    negligible, and the two custom holding fixtures are very simple to

    make. The hairdryer uses three different forms of energy tom work,

    heat energy and mechanical energy, electricity is used to generate

    forms of energy in the hairdryer.

    Energy can be converted in different forms but it cannot be createdor destroyed , proven by the first law of thermodynamics.

    RECOMMENDATIONS

    Bigger equipments such as turbines are recommended to do the

    above experiment, and will give better results since the inside

    diameter and the temperatures can be measured accurately because

    it is wide open on the nozzle.

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    ACKNOWLEDGEMENTS

    We would like to thank professor Kolesnikov for providing us with the

    start up equipments and futher thanks to my patner NkhensaniLekhuleni who worked with me on this assignment.

    REFERENCES

    R. Edwards, A Simple Hair Dryer Experiment to Demonstrate the

    First Law of Thermodynamics,

    Proceedings of the American Society for Engineering EducationAnnual Conference & Exposition, 2005.

    [6] M.J. Prince, R. M. Felder, Inductive Teaching and Learning

    Methods: Definitions, Comparisons, and

    Research Bases, Journal of Engineering Education, 2006.

    L.C. McDermott, Oerstead Medal Lecture 2001: Physics

    Education Research The Key to Student

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    Learning, American Journal of Physics 69, 1127-1137, 2001.

    D.E. Kanter, H.D. Smith, A. McKenna, C. Rieger, R.A.

    Linsenmeier, Inquiry-based Laboratory

    Instruction Throws Out the Cookbookand Improves Learning,

    Proceedings of the American Society for

    Engineering Education Annual Conference & Exposition, 2003.

    L.C. McDermott, et.al., Physics by Inquiry, John Wiley & Sons,

    1996.

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    NOMENCLATURE

    = mass flow rate of the incoming air(

    mass flow rate of the outgoing air(

    specific enthalpy of the incoming air

    specific enthalpy of the outgoing air

    g= acceleration due to gravity(

    D=diameter of the nozzle(m)

    = density of the air((

    A= Area of the nozzle ()