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902555 2 SUPERVISOR’S USE ONLY 90255M © Mana Tohu Mātauranga o Aotearoa 2011. Pūmau te mana. Kia kaua rawa he wāhi o tēnei tuhinga e tāruatia ki te kore te whakaaetanga a te Mana Tohu Mātauranga o Aotearoa. Ahupūngao, Kaupae 2, 2011 90255 Te whakaatu māramatanga o te pūhanga manawa 2.00 i te ahiahi Rāapa 16 Whiringa-ā-rangi 2011 Whiwhinga: Ono Tirohia mehemea e ōrite ana te Tau Ākonga ā-Motu kei tō pepa whakauru ki te tau kei runga ake nei. Me whakautu e koe ngā pātai KATOA kei roto i te pukapuka nei. Tirohia mēnā kei a koe te Puka Rauemi L2–PHYSMR. Ki roto i ō whakautu, whakamahi māramahia ngā tātainga ā-tau, ngā kupu, ngā hoahoa hoki/ rānei e hiahiatia ana. Me hoatu te wae tika o te Pūnaha Waeine o te Ao (SI) ki ngā whakautu ā-tau. Ki te hiahia koe ki ētahi atu wāhi hei tuhituhi i tō whakautu, whakamahia ngā wāhanga wātea kei muri i te pukapuka nei. Tirohia mehemea kei roto i tēnei pukapuka ngā whārangi 2–19 e raupapa tika ana, ā, kāore hoki he whārangi wātea. HOATU TE PUKAPUKA NEI KI TE KAIWHAKAHAERE HEI TE MUTUNGA O TE WHAKAMĀTAUTAU. MĀ TE KAIMĀKA ANAKE Paearu Paetae Paetae Paetae Kaiaka Paetae Kairangi Te tāutu, te whakaahua rānei i ētahi āhuatanga o ngā tītohunga ā-rongo, ngā ariā, ngā mātāpono rānei. Te whakaahua, te whakamārama rānei e ai ki ngā tītohunga ā-rongo, ngā ariā, ngā mātāpono, ngā hononga hoki / rānei. Te homai whakamārama poto, e whakaatu mai ana i te matatau ki ngā tītohunga ā-rongo, ngā ariā, ngā mātāpono, ngā hononga hoki / rānei. Te whakaoti rapanga takitahi. Te whakaoti rapanga. Te whakaoti rapanga takimaha. Whakakaotanga o te tairanga mahinga See back cover for an English translation of this cover
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Page 1: Ahupūngao, Kaupae 2, 2011 - NZQA

902555

2SUPERVISOR’S USE ONLY

9 0 2 5 5 M

© Mana Tohu Mātauranga o Aotearoa 2011. Pūmau te mana.Kia kaua rawa he wāhi o tēnei tuhinga e tāruatia ki te kore te whakaaetanga a te Mana Tohu Mātauranga o Aotearoa.

Ahupūngao, Kaupae 2, 201190255 Te whakaatu māramatanga o te pūhanga manawa

2.00 i te ahiahi Rāapa 16 Whiringa-ā-rangi 2011 Whiwhinga: Ono

Tirohia mehemea e ōrite ana te Tau Ākonga ā-Motu kei tō pepa whakauru ki te tau kei runga ake nei.

Me whakautu e koe ngā pātai KATOA kei roto i te pukapuka nei.

Tirohia mēnā kei a koe te Puka Rauemi L2–PHYSMR.

Ki roto i ō whakautu, whakamahi māramahia ngā tātainga ā-tau, ngā kupu, ngā hoahoa hoki/ rānei e hiahiatia ana.

Me hoatu te wae tika o te Pūnaha Waeine o te Ao (SI) ki ngā whakautu ā-tau.

Ki te hiahia koe ki ētahi atu wāhi hei tuhituhi i tō whakautu, whakamahia ngā wāhanga wātea kei muri i te pukapuka nei.

Tirohia mehemea kei roto i tēnei pukapuka ngā whārangi 2–19 e raupapa tika ana, ā, kāore hoki he whārangi wātea.

HOATU TE PUKAPUKA NEI KI TE KAIWHAKAHAERE HEI TE MUTUNGA O TE WHAKAMĀTAUTAU.

MĀ TE KAIMĀKA ANAKE Paearu Paetae

Paetae Paetae Kaiaka Paetae KairangiTe tāutu, te whakaahua rānei i ētahi āhuatanga o ngā tītohunga ā-rongo, ngā ariā, ngā mātāpono rānei.

Te whakaahua, te whakamārama rānei e ai ki ngā tītohunga ā-rongo, ngā ariā, ngā mātāpono, ngā hononga hoki / rānei.

Te homai whakamārama poto, e whakaatu mai ana i te matatau ki ngā tītohunga ā-rongo, ngā ariā, ngā mātāpono, ngā hononga hoki / rānei.

Te whakaoti rapanga takitahi. Te whakaoti rapanga. Te whakaoti rapanga takimaha.

Whakakaotanga o te tairanga mahinga

See back cover for an English translation of this cover

Page 2: Ahupūngao, Kaupae 2, 2011 - NZQA

Kia 60 meneti hei whakautu i ngā pātai o tēnei pukapuka.

Kua hoatu ngā ture katoa i runga i te Puka Rauemi L2-PHYSMR motu kē.

PĀTAI TUATAHI: TE EKENGA PAHIKARA

(a) HekaiekepahikaraaJacquie.Itētahiatakatīmataiateekemaiitepūwāhiwhakatū,ā,kawhakatereite1.2ms–2mōte14hēkonatehaere.

Whakaatuhiakotōnaterewhakamutungaimuriite14hēkonakote16.8ms–1.

(b) Kaahuwhakaterāwhitiiaitētahitereaumouote16.8ms–1,ā,kahurikimauī(kaahukiteRaki),kāre e rerekē tana tere.

Tāiatētahihoahoa perekawhakamahikitetātaiitehuringa o tana tere(terahimeteahunga).

Raki

Tonga

Hauāuru Rāwhiti

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MĀ TE KAIMĀKA

ANAKE

Page 3: Ahupūngao, Kaupae 2, 2011 - NZQA

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You are advised to spend 60 minutes answering the questions in this booklet.

All formulae are provided on the separate Resource Sheet L2-PHYSR.

QUESTION ONE: THE BIKE RIDE

(a) Jacquieisabikerider.Onemorningshestartsridingfromrestand acceleratesat1.2ms–2for14seconds.

Showthatherfinalvelocityafter14secondsis16.8ms–1.

(b) SheheadsEastataconstantspeedof16.8ms–1,thenturnsleft(headsNorth),without changing speed.

Drawavector diagramanduseitcalculatethechange in her velocity (sizeanddirection).

N

S

W E

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(c) KaheriaJacquieitanapahikaramārungaitētahipotikawhakawhitiitētahiawae65mtewhānui.Kawhakawhititonuatutepoti(↑)iteawa,meteterengaote6.8ms–1irungaitewai.Nāteiaotewai(→)katautepoti15mkiraroatuiteawa.

Tātaihiatetereotepotiehāngaianakitetahataha(arā,tepapa).

Kataeatetīmataitōwhakautumātetāingāhoahoaperewhaitapangamōngātawhitimengāterenga.

(d) KātahikahaereaJacquiemātetahiaraporowhitahuapaemeteterengaaumou.

Whakaahuahiaheahaiatērāehoatuanaitetōpana e hiahiatia anakiahaereporowhitatonute pahikara.

Kōrerotiateahunga o tēnei tōpana.

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(c) Jacquietakesherbikeonaboatacrossariver65mwide.Theboatheadsstraightacross(↑)theriver,withaspeedof6.8ms–1relativetothewater.Thecurrent(→)causestheboattoland15mdownstream.

Calculatethespeedoftheboatrelativetothebank(ground).

Youmaybeginyouranswerbydrawinglabelledvectordiagramsfordistancesandspeeds.

(d) Jacquiethenridesalongahorizontalcircularpathatconstantspeed.

Describewhatitisthatprovidestheforce neededtokeepthebikegoinginacircle.

State the direction of this force.

Page 6: Ahupūngao, Kaupae 2, 2011 - NZQA

PĀTAI TUARUA: TE ARAWHATA

EekepahikaraanaaJacquiemātētahiarawhataaumouetautokohiaanaingāpitoerua,pērāhokiitehoahoakeiraro.

5.0 m

25.0 m

A B

(a) E25.0mteroaotearawhata.KotepapatipuoJacquiemetanapahikarako72kg.Kotepapatipuotepiritiko760kg.

Tātaihiatetōpana tautoko (FA)etukunaanaetepito A, metetōpana tautoko (FB)etukunaanaetepito Botearawhatainae5.0maJacquiemaiitepitoA.

(b) Whakapuakinaōwhakautukitewāhanga(a)kitemahatikaongāmatitāpua.

Homaihepūtakemōtōkōwhiringaongāmatitāpuakirotoiōwhakautukitewāhanga(a).

(c) ItewāeekepahikaraanaaJacquieitetere16.8ms–1,katukiiakitētahipōropoiwhanaetakaporeanakiaiaitetereote8.0ms–1.Kapanawhakawahoatutepōropoiwhanakiteahungahāngaimeteterengaote5.0ms–1.

16.8 m s–1

8.0 m s–1 5.0 m s–1

i mua i te tutukinga i muri i te tutukinga

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Page 7: Ahupūngao, Kaupae 2, 2011 - NZQA

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QUESTION TWO: THE BRIDGE

Jacquiecyclesalongauniformbridgethatissupportedatbothends,asshowninthediagram.

5.0 m

25.0 m

A B

(a) Thelengthofthebridgeis25.0m.ThemassofJacquieandherbikeis72kg.Themassofthebridgeis760kg.

Calculate the support force (FA)providedbyend A andthe support force (FB) providedby end BofthebridgewhenJacquieis5.0mfromendA.

(b) Expressyouranswerstopart(a)tothecorrectnumberofsignificantfigures.

Giveareasonforyourchoiceofsignificantfiguresinyouranswerstopart(a).

(c) WhileJacquieiscyclingataspeedof16.8ms–1,shecollideswithasoccerballthatisrollingtowardsherataspeedof8.0ms–1.Thesoccerballbouncesoffintheoppositedirectionwithaspeedof5.0ms–1.

16.8 m s–1

8.0 m s–1 5.0 m s–1

before collision after collision

Page 8: Ahupūngao, Kaupae 2, 2011 - NZQA

TātaihiatetereoJacquie(terahimeteahunga)whaimuriitetutukinga.

Mewaihoekoengāpāngaotewaku.

KotepapatipuoJacquiemetanapahikara=72.0kg.

Kotepapatipuotepōropoiwhana=0.430kg.

(d) Whakamāramahiaheahatetikangaotetutukinga tāwariwarimetetutukinga rorohakore.

Tukingatāwariwari:

Tukingarorohakore:

Whakaahuahiameriroiakoeteahakiawhakataumēnāhetutukingatāwariwari,rorohakorerāneitetutukingaiwaenganuiitepahikarametepōropoiwhana.

Kāorehetikangawhakaotitātainga.

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Page 9: Ahupūngao, Kaupae 2, 2011 - NZQA

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CalculateJacquie’svelocity(sizeanddirection)afterthecollision.

Youmayignoreanyeffectsoffriction.

MassofJacquieandherbike=72.0kg

Massofsoccerball=0.430kg.

(d) Explainwhatismeantbyanelastic collision andan inelastic collision.

Elasticcollision:

Inelasticcollision:

Describewhatyouwouldneedtodoinordertodeterminewhetherthiscollisionbetweenthebikeandthesoccerballis elasticorinelastic.

Youarenotrequiredtocarryoutanycalculations.

Page 10: Ahupūngao, Kaupae 2, 2011 - NZQA

(e) WhakamāramatiateāhuaewhakamauruaitetōpanaotepōrokiaJacquiemetanapahikarakiteroaotewāitepānga,Ā,whakamāramatiatewhaipāngaotetōpanaotepōrokiaJacquiemetanapahikarakitetōpanaotepāngaoJacquiemetanapahikarakitepōro.

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Page 11: Ahupūngao, Kaupae 2, 2011 - NZQA

(e) ExplainhowtheforceexertedbytheballonJacquieandherbikeisdependentonthedurationofthetimeonimpact,ANDexplainhowtheforceexertedbytheballonJacquieandherbikeisrelatedtotheforceexertedbyJacquieandherbikeontheball.

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Page 12: Ahupūngao, Kaupae 2, 2011 - NZQA

PĀTAI TUATORU: PŪNGAO ME TE NEKEHANGA TĪTERE

EpanatetungāneoJacquie,aErnie,itētahimīhinitapahiotaotametetōpanaote26Nmetekokiote34°kitepapa,pēneiitēneiiraronei.

www.treehugger.com/push-mower-jjh01.jpg

(a) Whakamāramakatoatiaheahaikoreaitekatoaotetōpana26NekarawhiuaanaeErnieewhakamahiakiapanaitemīhinitapahiotaotawhakatehuapaeitepapa.

(b) TātaihiatekahaehuaanaitāErniemahiinawhakatereiaitanamīhinitapahiotaotakite 4.0mirotoite3.0hēkona.

Homaingāwaeinetikamōtōwhakautu.

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He tapu tēnei rauemi. E kore taea te tuku atu.

Aata tirohia ki ngā kupu kei raro iho i te pouaka nei.

Page 13: Ahupūngao, Kaupae 2, 2011 - NZQA

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QUESTION THREE: ENERGY AND PROJECTILE MOTION

Jacquie’sbrotherErnieispushingalawnmowerwithaforceof26Natanangleof34°totheground,asshownbelow.

www.treehugger.com/push-mower-jjh01.jpg

(a) Explainfullywhynotallofthe26NforceexertedbyErnieisusedtopushthelawnmowerhorizontallyalongtheground.

(b) CalculatethepowerproducedbyErniewhenheacceleratesthemowerthroughadistanceof4.0min3.0seconds.

Givethecorrectunitsforyouranswer.

For copyright reasons, this resource cannot be reproduced

here.

Page 14: Ahupūngao, Kaupae 2, 2011 - NZQA

(c) KawhanatetamaaErnie,aJacob,itētahipōrokiaErnieirotoitemāra.1.75mtetāroaroaoErnie.KawhanaaJacobitepōrometetere24ms–1itekoki36°kitepapa.E35mtanatawhitiatuotetūmaioErnie.

36°

35 m

1.75 m

Jacob

24 m s–1

Ernie

KĀORE i āwhatatia te

hoahoa

KapātepōrokiaErnie,kahiparāneiirungaakeitōnamāhunga?

Iōtātainga,tīmatamātewhakaatukotewāhangahuapaeoteteretīmataotepōroko 19.4ms–1.

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Page 15: Ahupūngao, Kaupae 2, 2011 - NZQA

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(c) Ernie’ssonJacobkicksaballtowardsErnieinthegarden.Ernieis1.75mtall.Jacobkickstheballwithavelocityof24ms–1atanangleof36°totheground.Jacobisstanding35mawayfromErnie.

36°

35 m

1.75 m

Jacob

24 m s–1

Ernie

Diagram is NOT to scale

WilltheballhitErnieorgooverhishead?

Inyourcalculations,startbyshowingthatthehorizontalcomponentoftheinitialvelocityoftheballis19.4ms–1.

Page 16: Ahupūngao, Kaupae 2, 2011 - NZQA

Kahangawharetukutukutepūngāwerewereirotoitemāra,ā,kamautētahipepe.Katorowhakararotewharetukutukumāte0.065minamautepepee0.003kgtepapatipukiroto.

Keirarokotētahikauwhatamōtetōpanametetotorohokiotewharetukutuku.

tōpana (N)

totoro (m)

(d) WhakamāramahiaheahaikoreaietaeatewhakamahiitetureW=Fdheitātaiitepūngaomoekūtorotoroepuritiaanaitewharetukutukuinamautepepekiroto.

Mewhakaurukirotoitōwhakamāramatētahikōreromōngāmeamewhakamahiheitātaiitēneipūngao.

(e) Tātaihiatepūngaomoekūtorotoroepuritiaanaitewharetukutukuinamautepepeirotoitewharetukutuku.

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Page 17: Ahupūngao, Kaupae 2, 2011 - NZQA

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Aspiderspinsawebinthegardenandamothgetscaughtintheweb.Thewebstretchesdownwardsby0.065mwhenthemothofmass0.003kgiscaughtinit.

Agraphforforceagainstextensionforthespider’swebisshownbelow.

force (N)

extension (m)

(d) ExplainwhytheformulaW=Fdcannotbeusedtocalculatetheelasticpotentialenergystoredinthewebwhenthemothgetscaughtinit.

Yourexplanationshouldincludeastatementofwhatshouldbeusedtocalculatethisenergy.

(e) Calculatetheelasticpotentialenergystoredinthewebwhenthemothiscaughtintheweb.

Page 18: Ahupūngao, Kaupae 2, 2011 - NZQA

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MĀ TE KAIMĀKA

ANAKETAU PĀTAI

He wāhi anō mēnā e hiahiatia ana.Tuhia te (ngā) tau pātai mēnā e hāngai ana.

Page 19: Ahupūngao, Kaupae 2, 2011 - NZQA

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Physics 90255, 2011

ASSESSOR’S USE ONLY

QUESTION NUMBER

Extra space if required.Write the question number(s) if applicable.

Page 20: Ahupūngao, Kaupae 2, 2011 - NZQA

© New Zealand Qualifications Authority, 2011. All rights reserved.No part of this publication may be reproduced by any means without the prior permission of the New Zealand Qualifications Authority.

Level 2 Physics, 201190255 Demonstrate understanding of mechanics

2.00 pm Wednesday 16 November 2011 Credits: Six

Check that the National Student Number (NSN) on your admission slip is the same as the number at the top of this page.

You should attempt ALL the questions in this booklet.

Make sure that you have Resource Sheet L2–PHYSMR.

In your answers use clear numerical working, words and / or diagrams as required.

Numerical answers should be given with an appropriate SI unit.

If you need more room for any answer, use the extra space provided at the back of this booklet.

Check that this booklet has pages 2 – 19 in the correct order and that none of these pages is blank.

YOU MUST HAND THIS BOOKLET TO THE SUPERVISOR AT THE END OF THE EXAMINATION.

ASSESSOR’S USE ONLY Achievement Criteria

Achievement Achievement with Merit Achievement with ExcellenceIdentify or describe aspects of phenomena, concepts or princi-ples.

Give descriptions or explanations in terms of phenomena, con-cepts, principles and / or relation-ships.

Give concise explanations that show clear understanding in terms of phenomena, concepts, principles and / or relationships.

Solve straightforward problems. Solve problems. Solve complex problems.

Overall level of performance

90

25

5M

English translation of the wording on the front cover