Dimensionare contravaintuiri Sistemul de contravatuiri este sub forma de "x,, dispus pe doua niveluri pentru Materiale folosite pentru sistemul de contravantuiri *Otel S355 fyd 355 E 210000 !#1 525 m 110 ε 0$1# %ontravantuirile vor avea clasa de sectiune 1& conform '100&1(200! 'anou Sectiune ) t i + -./ mm/ mm/ cm/ 1 33113 13 13 #0 5!1 35$ 2 3#20$1 13 13 #0 5!1 35$ 3 25315 105 15 25 #$2 10$2 # 1!052 $5 13 25 #15 12!51 Sistemul de contravatuiri trebuie vericat si la incarcari in exploatare din vant de e 4n pr incipiu si st emul de co ntravatu ir i se dimensi ona a la intinde re si se ver i ca l a com la incarcari de exploatare 6 021 110 'anou Sectiune +7 Φ χ 8ericare -./ -./ stabilitate 1 ##53! 913x#0 1225 135!0515 32050 o- 2 #21 913x#0 1225 135!0515 32050 o- 3 2$!3 915x25 1#25 1!## 0#0! 13#!! o- # 21$# 913x25 1!5! 2023# 031# 0!#2 o- Calculul coefcientilor pentru curba de interactiune la tevi circulare comprimate #23 1!0 a avea un:;iul dia:onalei de α < 30= >!0= / ispunand astfel contravantuirile se obtine un un:;i de ? #5= .(mm 2 .(mm 2 + E l f @ A0 . Ed cm 2 / Φ13x#0 Φ13x#0 Φ15x25 Φ13x25 @ A1 . Ed . Bd 1500(f yd !000(f yd
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Dimensionare contravaintuiri Sistemul de contravatuiri este
sub forma de "x,, dispus pe doua niveluri pentru
Materiale folosite pentru sistemul de contravantuiri
*Otel S355
fyd 355
E 210000
%ontravantuirile vor avea clasa de sectiune 1& conform '100&1(200!
'anou Sectiune ) t i
+ -./ mm/ mm/ cm/
1 33113 13 13 #0 5!1 35$
2 3#20$1 13 13 #0 5!1 35$
3 25315 105 15 25 #$2 10$2
# 1!052 $5 13 25 #15 12!51
Sistemul de contravatuiri trebuie vericat si la incarcari in exploatare din vant de e
4n principiu sistemul de contravatuiri se dimensionaa la intindere si se verica la com
la incarcari de exploatare
-./ -./ stabilitate
1 ##53! 913x#0 1225 135! 0515 32050 o-
2 #21 913x#0 1225 135! 0515 32050 o-
3 2$!3 915x25 1#25 1!## 0#0! 13#!! o-
# 21$# 913x25 1!5! 2023# 031# 0!#2 o-
Calculul coefcientilor pentru curba de interactiune
la tevi circulare comprimate
1!0
a avea un:;iul dia:onalei de α < 30= >!0= / ispunand astfel contravantuirile se
obtine un un:;i de ? #5=
.(mm2
.(mm2
+ E
'anou (t d e c χ CS %'
1 #$25 1 1! 031 0515 #$5$ !$11
2 #$25 1 1! 031 0515 #$5$ !$11
3 !3! 1 $0 03!! 0#0! ##5 !32!
# 55! 1 3!$ 03 031# #!$# !5
' a n o u l 1
c
1500(fy #23 0# 1500(fy #23
!000(fy 1!0 02 !000(fy 1!0
8aloare #$25 0.391 8aloare #$25
d
!000(fy 1!0 # !000(fy 1!0
8aloare #$3 9.716 8aloare #$25
' a n o u l 1
CS
C
!000(fy 1!0 2 !000(fy 1!0
8aloare #$25 4.858 8aloare #$25
%' %
8aloare #$3 6.811 8aloare #$25
c
0.391 8aloare !3! 0.366
CS
4.858 8aloare !3! 4.495
6.811 8aloare !3! 6.326
c
8aloare 55! 0.379
CS
Gacem aceasta vericare doarece in caul in care se intampla ceva cu contrava
necontravantuite sa e capabile sa preia ceva din incarcarea seismica25H
%onsideram una din directiile actiunii seismice ,luam foartele taietoare de la b
necontravantuite si vericam sa preia cel putin 25H din actiunea seismica
aca nu se realieaa vericarea realiam o combinatie cu seism in care ampli
cand cadrele necontravantuite preiau cel putin 25H din actiunea seismica
Story 'oint Coad GI Story 'oint
)SE 1 %5 A)I 1#0# )SE 2
)SE # %5 A)I 1#0# )SE 3
)SE 5 %5 A)I 135!5$ )SE !
)SE $ %5 A)I 135!5 )SE
)SE 21 %5 A)I 11#2$# )SE
)SE 2# %5 A)I 11#2$# )SE 10
)SE 25 %5 A)I 1005$3 )SE 11
)SE 2$ %5 A)I 1005$3 )SE 12
9820.47 )SE 13
$20#-. )SE 1!
20#$$ -. )SE 1$
11$!#5-. )SE 20
p 17.26 )SE 23
)SE 1 %! A)I 1#!153 )SE 5
)SE 2 %! A)I 1#105 )SE !
)SE 3 %! A)I 13$5 )SE
)SE # %! A)I 135! )SE $
)SE 2! %! A)I 11#15 )SE 10
)SE 2 %! A)I 10#5! )SE 11
)SE 2$ %! A)I 101!5 )SE 12
10003.7 )SE 13
G cc
G cnc
G b
10003#-. )SE 1!
1$3#$ -. )SE 1$
11$#322-. )SE 20
'rocentul preluat de cadrele necontravantuiteJ )SE 21
p 15.53 )SE 22
!erifcare cadre cu noduri f'e$cadre cu noduri deplas
8om determina deplasarea la varful structurii odata cu contravantuiri si odata
aca deplasarea este preluata in proportie de $0 H de contravantuiri &cadre cu noduri
cadre cu noduri deplasabile
Gacem acest lucru pentru a determina un:imile de LambaM necesare in calcul
al stalpilor structurii multietaMate
60.92 62.50
!erifcare la deplasari laterale a structurii
1. (tarea limita de serviciu %()(&
a irectia lon:itudinala I
Story Load X Y Z DriftX
SFOBK$ SI 5 105 2! 00013 13
SFOBK SI 20!25 21 25 0002102 2102
SFOBK! SI 0 135 222 000221# 221#
SFOBK5 SI #5 0 1$5 000211 211
SFOBK# SI 0 135 1#$ 0001$# 1$#
SFOBK3 SI 225 21 111 0001#5 1#5
SFOBK2 SI 0 5 # 0001#2 1#2
SFOBK1 SI 35 21 3 0000$ 0$
b irectia transversala K
SFOBK$ SK 20!25 5 2! 0001$31 1$31
SFOBK SK 20!25 5 25 00021 21
SFOBK! SK 20!25 135 222 00022!! 22!!
SFOBK5 SK 20!25 135 1$5 000211 211
δ contrav
δ contrav
δ cadre
δ cadre
4n concluie am obtinut ca avem cadre cu noduri deplasabile si se va tine
DriftX (0/ 00
)
SFOBK# SK 20!25 135 1#$ 0001$51 1$51
SFOBK3 SK 20!25 5 111 0001!01 1!01
SFOBK2 SK 35 1125 # 0001#2 1#2
SFOBK1 SK 0 5 3 0000$0$ 0$0$
Directia longitudinala X
SFOBK 0!00"0 0!% & 0!00&0 0!00' ade
SFOBK! 0!00"& 0!% & 0!00&&$ 0!00' ade
SFOBK5 0!00"#" 0!% & 0!00&$& 0!00' ade
SFOBK# 0!00"#'& 0!% & 0!00$%# 0!00' ade
SFOBK3 0!00"&*% 0!% & 0!00** 0!00' ade
SFOBK2 0!00"&0 0!% & 0!00'& 0!00' ade
SFOBK1 0!000#*' 0!% & 0!00"+0 0!00' ade
Directia tran,er,ala Y
SFOBK 0!00"#0 0!% & 0!00&$& 0!00' ade
SFOBK! 0!00++ 0!% & 0!00&%$ 0!00' ade
SFOBK5 0!00"*" 0!% & 0!00&$' 0!00' ade
SFOBK# 0!00"'%" 0!% & 0!00$#0 0!00' ade
SFOBK3 0!00"+0" 0!% & 0!00$0 0!00' ade
SFOBK2 0!00"&* 0!% & 0!00'+ 0!00' ade
SFOBK1 0!000'0' 0!% & 0!00"+ 0!00' ade
2. (tarea limita ultima %()*&
SFOBK 0!00"0 " & 0!00'&0' 0!0% ade
SFOBK! 0!00"& " & 0!00''%+ 0!0% ade
SFOBK5 0!00"#" " & 0!00'+'& 0!0% ade
SFOBK# 0!00"#'& " & 0!00#"$+ 0!0% ade
SFOBK3 0!00"&*% " & 0!00%*' 0!0% ade
SFOBK2 0!00"&0 " & 0!00%+' 0!0% ade
SFOBK1 0!000#*' " & 0!00$"* 0!0% ade
Directia tran,er,ala Y
SFOBK 0!00"#0 " & 0!00'+' 0!0% ade
SFOBK! 0!00++ " & 0!00*0+& 0!0% ade
SFOBK5 0!00"*" " & 0!00'#+& 0!0% ade
SFOBK# 0!00"'%" " & 0!00#&0& 0!0% ade
SFOBK3 0!00"+0" " & 0!00+&0& 0!0% ade
SFOBK2 0!00"&* " & 0!00%#"+ 0!0% ade
SFOBK1 0!000'0' " & 0!00$$ 0!0% ade
d r
15!
rat SFOBK2 0002$# 2$# $
rat SFOBK3 0002 2 $
rat SFOBK# 00035 35!$ $
rat SFOBK5 000#3# #3#2 $
rat SFOBK! 000##3 ##2$ $
rat SFOBK 000#20 #20# $
rat SFOBK$ 0003## 3## $
rat SFOBK1 0001!2 1!1! $
rat SFOBK2 0002$! 2$5$ $
rat SFOBK3 000320 3202 $
rat SFOBK# 00030 302 $
rat SFOBK5 000#3$ #3$2 $
rat SFOBK! 000#53 #532 $
rat SFOBK 000#3# #3#0 $
rat SFOBK$ 0003!!2 3!!2 $
0$5! s
100 s
rat 103! 000312 312 25
rat 0005!$ 5!$0 25
rat 0005$ 5$0 25
rat 00013! 13! 25
rat 000$!$# $!$# 25
rat 000$#0$ $#0$ 25
rat 000!#$ !#$ 25
rat 00051! 51! 25
rat 000!#0# !#0# 25
rat 000#0# #0# 25
rat 000$!# $!# 25
rat 000$!$ $!$0 25
rat 00032# 32# 25
d ra
SL. c
rift admisibil
1!1!
2$5$
3202
302
SI $5 5 105 2! 00013
SI # 0 21 2! 0000052
SI 52 20!25 21 25 0002102
SI 1 0 0 25 0000013
SI 3 0 135 222 000221#
SI # 0 21 222 0000023
SI 25 #5 0 1$5 000211
SI # 0 21 1$5 000005!
SI 3 0 135 1#$ 0001$#
SI # 0 21 1#$ 00000#
SI 1! 225 21 111 0001#5
SI # 0 21 111 00000#
SI 2 0 5 # 0001#2
SI 1 0 0 # 00000$#
SI 2# 35 21 3 0000$
SI 2$ #5 21 3 000002
Coad 'oint I K N riftI riftK
SK 1 0 0 2! 000013
SK 5$ 20!25 5 2! 0001$31
SK 25 #5 0 25 00000$!
SK 5$ 20!25 5 25 00021
SK 2$ #5 21 222 00000
SK 51 20!25 135 222 00022!!
SK 2# 35 21 1$5 00000#1
SK 51 20!25 135 1$5 000211
SK 2$ #5 21 1#$ 0000125
SK 25 #5 0 # 000010#
SK 11$ 35 1125 # 0001#2
SK # 0 21 3 0000055
SK 2 0 5 3 0000$0$
)umina /rinii
.ivel Stalp Cumina
mm/ :rinda !00m
3 2PE!00 !00 5#0
# 2PE!00 !00 5#0
5 2PE)!00 50 5#1
! 2PE)!00 50 5#1
2PE)550 5#0 5#!
$ 2PE)550 5#0 5#!
(tarea de e+orturi
2 11!0 115 2!1! 3$1#2
3 1!13 1213 25 3$11#
# 21!1 1205 210$3 331$
5 202$3 11 1!01 2$!$
! 2#325 12033 1!01 2$3#
2!! 11!# 1!5$1 2$5#5
$ #0#3 131#3 1!5$1 22#
(ectiuni propuse
# PE) #50 ##0 300 21
.(mm2
! PE) #00 30 300 1
PE) #00 30 300 1
$ PE) #00 30 300 1
!erifcare clasa de sectiune
mm/
5 PE) #00 1##5 o- o-
! PE) #00 1##5 o- o-
PE) #00 1##5 o- o-
$ PE) #00 1##5 o- o-
!erifcarea ductilitatii locale
# PE) #50 #1$300 !53! !555
5 PE) #00 33!50 5530 5213#
! PE) #00 33!50 5530 5213#
PE) #00 33!50 5530 5213#
$ PE) #00 33!50 5530 5213#
.ivel Sectiune
2 PE) 500 002! 0502 035!
3 PE) 500 0035 0501 03$1
# PE) #50 0052 050 0##!
5 PE) #00 005# 051$ 050
! PE) #00 00!5 051 0501
PE) #00 00# 051! 0##
$ PE) #00 010 053 0##!
c(t f D 10ε c(t
R D 2ε
.ivel
-.m/ -./ -./
2 150 11!0 2!1! #00
3 1$$1 1!13 25 551
# 1#$! 21!1 210$3 $2
5 12!! 202$3 1!01 10#1$
! 13!5 2#325 1!01 12#5
1!$! 2!! 1!5$1 1#2!2
$ 101 #0#3 1!5$1 202$
b)vericare de rezistenta in reazem
Exista posibilitatea ca marind :rinile, datorita cresterii fortei taietoare asoci
acesteia, sa nu mai e indeplinita conditia de limitare a fortei taietoare efective
asociata mecanismului de plasticare
e asemenea marirea :rinilor se impune pentru a reduce lun:imea de La
4n ona de reaem vericarea o voi face cu sectiunea slabita
.ivel
-./ -.m/ -./
2 11! 31$2 3$1#2 00
3 1!13 3#1!1 3$11# 102
# 21!1 32#30 331$ 12$#0
5 202$3 23!3 2$!$ 1#511
! 2#325 2$32 2$3# 1#51
2!! 25$$# 2$5#5 13#1#
$ #0#3 253 22# 1#1!#
A Ed
camp . Ed
8 Ed
camp
.(mm2/
marirea :rinilor este urmata de o nevericare a conditiei privind forta taietoare
plastifcare cu pana la 35, prin decuparea talpilor :rinii 4n acest fel scade
. Ed
(tarea de e+orturi
2 1502! 25 3350# #2
3 !3!0 22 3313 #2#$5
# 1#53! 2#1 2!3 3!1$0
5 !# 2!0 21332 3052
! 10205 2!0 21332 3052
10551 225 2113 303!2
$ 230#$ 103!# 2113 31501
(ectiuni propuse
# PE) #50 ##0 300 21
5 PE) #00 30 300 1
! PE) #00 30 300 1
PE) #00 30 300 1
$ PE) #00 30 300 1
!erifcare clasa de sectiune
mm/
5 PE) #00 1##5 o- o-
! PE) #00 1##5 o- o-
. Ed
R D 2ε
!erifcarea ductilitatii locale
# PE) #50 #1$300 !53! !555
5 PE) #00 33!50 5530 5213#
! PE) #00 33!50 5530 5213#
PE) #00 33!50 5530 5213#
$ PE) #00 33!50 5530 5213#
.ivel Sectiune
3 PE) 500 001# 055 0#$#
# PE) #50 0035 0553 05$0
5 PE) #00 0020 0553 0!2
! PE) #00 002 0553 0!30
PE) #00 002$ 05#$ 0#
$ PE) #00 00!2 05! 0##1
!erifcari de reistenta
.ivel
-.m/ -./ -./
2 2$!0$ 1502! 2$$! 0
3 3523$ !3! 2$51 1052
. pl,Bd
5 2! !# 1$20 1301
! 20# 10205 1$20 12$3#
202# 10551 1$103 $02
$ 1#3 230#$ 1$103 $10
b)vericare de rezistenta in reazem
Exista posibilitatea ca marind :rinile, datorita cresterii fortei taietoare asoci
acesteia, sa nu mai e indeplinita conditia de limitare a fortei taietoare efective
asociata mecanismului de plasticare
e asemenea marirea :rinilor se impune pentru a reduce lun:imea de La
4n ona de reaem vericarea o voi face cu sectiunea slabita
.ivel
-./ -.m/ -./
1 3035 2021 #12 110
2 1502! 3$5 3$0!1 13$!5
3 !3! #335# 3$11 15233
# 1#53! #2210 32351 1$!5
5 !# 3!20! 2530 1$01
! 10205 3!3! 2530 200$2
10551 2$!5 232$ 1!010
$ 230#$ 25##1 2$#! 15235
b) Cadre contravantuite centric
marirea :rinilor este urmata de o nevericare a conditiei privind forta taietoare
plastifcare cu pana la 35, prin decuparea talpilor :rinii 4n acest fel scade
. Ed
# 2PE!00 !00 !0
.(mm2
; stalp
2 #325 ## 2!1! 35!1!
3 212! #103 25 300$0
# 351!$ #2 210$3 30510
5 22! #0$5 1!01 20$!
! 1530 3# 1!01 2!05
305 #33 1!5$1 205#
$ 25$ 1053! 1!5$1 211
(ectiuni propuse
# PE) #50 ##0 300 21
5 PE) #00 30 300 1
! PE) #00 30 300 1
PE) #00 30 300 1
$ PE) #00 30 300 1
!erifcare clasa de sectiune
1 PE) 500 1## o- o-
2 PE) 500 1## o- o-
3 PE) 500 1## o- o-
# PE) #50 1##25 o- o-
5 PE) #00 1##5 o- o-
! PE) #00 1##5 o- o-
PE) #00 1##5 o- o-
$ PE) #00 1##5 o- o-
. Ed
R D 2ε
.ivel
-.m/ -./ -./
3 1#0 212! 25 5!
# 1102 351!$ 210$3 551
5 112 22! 1!01 !$#1
! $ 153 1!01 5!#0
50!$ 305 1!5$1 #233
$ 1125 25$ 1!5$1 !$0
b)vericare de rezistenta in reazem
.ivel
-./ -.m/ -./
2 #325 23$$ 35!1! 1033
3 212! 1$!3 300$0 !03
# 351!$ 2##2 30510 1053
5 22! 15!1 20$! $51
! 153 20#2 2!05 10#5!
305 $## 205# 5$$
$ 25$ 131 211 $00$
A Ed
camp . Ed
8 Ed
1#$! 32#30
1!$! 25$$#
115 1$ 20#5 30511
A Ed
-.m/
$!22
$!22
$!22
Ed (8
Ed (A
3! 130#$ o- o- o-
3! 133 o- o- o-
313 13$1 o- o- o-
!0 1#! o- o- o-
!#0 15301 o- o- o-
!#0 1!$# o- o- o-
!#2# 1$0$ o- o- o-
!#2# 2302 o- o- o-
iata mecanismului de plasticare la extremitatile
la 05 din cea plastic capabila 4n consecinta daca
baM a stalpilor
10!$ 203# o- o- o-
103$ 2100 o- o- o-
1030 21#$2 o- o- o-
10$3 22# o- o- o-
1111$ 2#112 o- o- o-
11132 2#1! o- o- o-
1105$ 233$# o- o- o-
11515 2##!2 o- o- o-
ec;
V2W3U2 D11 f yd
U D05 f yd
se va recur:e la slabirea sectiunii in ona de
momentul incovoietor capabil si implicit forta taietoare
ec;
V2W3U2 D11 f yd
U D05 f yd
2$!0$ 3$5
3523$ #335#
32$#0 #2210
115 1$ 20#5 30511
11 15 221$#! 2#55##
11 15 221$#! 2#55##
11 15 221$#! 2#55##
11 15 221$#! 2#55##
A Ed
$10# 1!!$ o- o- o-
$10# 1!2 o- o- o-
$02 1#$1 o- o- o-
A pl,Bd
Ed (8
Ed (A
V2W3U2 D11 f yd
U D05 f yd
0$ 135 o- o- o-
0$ 1#$ o- o- o-
013 15!0 o- o- o-
013 1#!05 o- o- o-
iata mecanismului de plasticare la extremitatile
la 05 din cea plastic capabila 4n consecinta daca
baM a stalpilor
1015 231!! o- o- o-
10!#5 231! o- o- o-
10!02 2#!$0 o- o- o-
10!!5 25#55 o- o- o-
10!!5 25!# o- o- o-
105$ 2#3#2 o- o- o-
1102$ 2##33 o- o- o-
se va recur:e la slabirea sectiunii in ona de
momentul incovoietor capabil si implicit forta taietoare
ec;
V2W3U2 D11 f yd
U D05 f yd
1#0 1$!3
1102 2##2
112 15!1
115 1$ 20#5 30511
11 15 221$#! 2#55##
11 15 221$#! 2#55##
11 15 221$#! 2#55##
11 15 221$#! 2#55##
A Ed
3! 1!!!! o- o- o-
3! 1#321 o- o- o-
313 1322 o- o- o-
!0 133!5 o- o- o-
!#0 1312 o- o- o-
!#0 125#! o- o- o-
!#2# 110# o- o- o-
!#2# 130## o- o- o-
U 8ericare 8ericare 8ericare
$#$ 201! o- o- o-
$#! 1!211 o- o- o-
203$5 o- o- o-
$053 1!3#2 o- o- o-
1010 203# o- o- o-
$11$ 152## o- o- o-
10505 1$$0 o- o- o-
ec;
V2W3U2 D11 f yd
U D05 f yd
ec;
V2W3U2 D11 f yd
U D05 f yd
.ivel
1 5 11 22$51 3#!50 1!2! 2!#
2 11! 115 22$51 3#$2! 150 31$2
3 1!13 1213 22!$5 3#$22 1$$1 3#1!1
# 21!1 1205 1$3$! 30#$1 1#$! 32#30
5 202$3 11 1#5## 2!5#1 12!! 23!3
! 2#325 12033 1#5## 2!5 13!5 2$32
2!! 11!# 1##3 2!#03 1!$! 25$$#
$ #0#3 131#3 1##3 25$2 101 253
(ectiuni decupate
1 PE) 500 #0 255 23 12 105$
2 PE) 500 #0 255 23 12 105$
3 PE) 500 #0 255 23 12 105$
# PE) #50 ##0 255 21 115 152$
. Ed
5 PE) #00 30 255 1 11 135!2
! PE) #00 30 255 1 11 135!2
PE) #00 30 255 1 11 135!2
$ PE) #00 30 255 1 11 135!2
!erifcare clasa de sectiune
1 PE) 500 1215 o- o-
2 PE) 500 1215 o- o-
3 PE) 500 1215 o- o-
# PE) #50 1215 o- o-
5 PE) #00 122 o- o-
! PE) #00 122 o- o-
PE) #00 122 o- o-
$ PE) #00 122 o- o-
!erifcarea ductilitatii locale
# PE) #50 352#5 !53! 5!0 !3#30
5 PE) #00 31$0 5530 #503! 502#$
! PE) #00 31$0 5530 #503! 502#$
PE) #00 31$0 5530 #503! 502#$
$ PE) #00 31$0 5530 #503! 502#$
.ivel Sectiune Cimitare Cimitare
1 PE) 500 0020 0#5! 035 o- o-
2 PE) 500 0030 0#5$ 0#0 o- o-
3 PE) 500 00#0 0#5$ 0#3! o- o-
# PE) #50 00!0 0#!! 0511 o- o-
5 PE) #00 00!# 0# 05$# o- o-
! PE) #00 00! 0#$0 05! o- o-
PE) #00 00$ 0# 0515 o- o-
$ PE) #00 012$ 0#$ 0512 o- o-
c(t f D 10ε c(t
R D 2ε
.ivel
-./ -./ -./ -./ -.m/ -.m/
1 3035 131#3 2$$! #12 21015 2021
2 1502! 25 2$$! 3$0!1 2$!0$ 3$5
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Materiale folosite pentru sistemul de contravantuiri
*Otel S355
fyd 355
E 210000
%ontravantuirile vor avea clasa de sectiune 1& conform '100&1(200!
'anou Sectiune ) t i
+ -./ mm/ mm/ cm/
1 33113 13 13 #0 5!1 35$
2 3#20$1 13 13 #0 5!1 35$
3 25315 105 15 25 #$2 10$2
# 1!052 $5 13 25 #15 12!51
Sistemul de contravatuiri trebuie vericat si la incarcari in exploatare din vant de e
4n principiu sistemul de contravatuiri se dimensionaa la intindere si se verica la com
la incarcari de exploatare
-./ -./ stabilitate
1 ##53! 913x#0 1225 135! 0515 32050 o-
2 #21 913x#0 1225 135! 0515 32050 o-
3 2$!3 915x25 1#25 1!## 0#0! 13#!! o-
# 21$# 913x25 1!5! 2023# 031# 0!#2 o-
Calculul coefcientilor pentru curba de interactiune
la tevi circulare comprimate
1!0
a avea un:;iul dia:onalei de α < 30= >!0= / ispunand astfel contravantuirile se
obtine un un:;i de ? #5=
.(mm2
.(mm2
+ E
'anou (t d e c χ CS %'
1 #$25 1 1! 031 0515 #$5$ !$11
2 #$25 1 1! 031 0515 #$5$ !$11
3 !3! 1 $0 03!! 0#0! ##5 !32!
# 55! 1 3!$ 03 031# #!$# !5
' a n o u l 1
c
1500(fy #23 0# 1500(fy #23
!000(fy 1!0 02 !000(fy 1!0
8aloare #$25 0.391 8aloare #$25
d
!000(fy 1!0 # !000(fy 1!0
8aloare #$3 9.716 8aloare #$25
' a n o u l 1
CS
C
!000(fy 1!0 2 !000(fy 1!0
8aloare #$25 4.858 8aloare #$25
%' %
8aloare #$3 6.811 8aloare #$25
c
0.391 8aloare !3! 0.366
CS
4.858 8aloare !3! 4.495
6.811 8aloare !3! 6.326
c
8aloare 55! 0.379
CS
Gacem aceasta vericare doarece in caul in care se intampla ceva cu contrava
necontravantuite sa e capabile sa preia ceva din incarcarea seismica25H
%onsideram una din directiile actiunii seismice ,luam foartele taietoare de la b
necontravantuite si vericam sa preia cel putin 25H din actiunea seismica
aca nu se realieaa vericarea realiam o combinatie cu seism in care ampli
cand cadrele necontravantuite preiau cel putin 25H din actiunea seismica
Story 'oint Coad GI Story 'oint
)SE 1 %5 A)I 1#0# )SE 2
)SE # %5 A)I 1#0# )SE 3
)SE 5 %5 A)I 135!5$ )SE !
)SE $ %5 A)I 135!5 )SE
)SE 21 %5 A)I 11#2$# )SE
)SE 2# %5 A)I 11#2$# )SE 10
)SE 25 %5 A)I 1005$3 )SE 11
)SE 2$ %5 A)I 1005$3 )SE 12
9820.47 )SE 13
$20#-. )SE 1!
20#$$ -. )SE 1$
11$!#5-. )SE 20
p 17.26 )SE 23
)SE 1 %! A)I 1#!153 )SE 5
)SE 2 %! A)I 1#105 )SE !
)SE 3 %! A)I 13$5 )SE
)SE # %! A)I 135! )SE $
)SE 2! %! A)I 11#15 )SE 10
)SE 2 %! A)I 10#5! )SE 11
)SE 2$ %! A)I 101!5 )SE 12
10003.7 )SE 13
G cc
G cnc
G b
10003#-. )SE 1!
1$3#$ -. )SE 1$
11$#322-. )SE 20
'rocentul preluat de cadrele necontravantuiteJ )SE 21
p 15.53 )SE 22
!erifcare cadre cu noduri f'e$cadre cu noduri deplas
8om determina deplasarea la varful structurii odata cu contravantuiri si odata
aca deplasarea este preluata in proportie de $0 H de contravantuiri &cadre cu noduri
cadre cu noduri deplasabile
Gacem acest lucru pentru a determina un:imile de LambaM necesare in calcul
al stalpilor structurii multietaMate
60.92 62.50
!erifcare la deplasari laterale a structurii
1. (tarea limita de serviciu %()(&
a irectia lon:itudinala I
Story Load X Y Z DriftX
SFOBK$ SI 5 105 2! 00013 13
SFOBK SI 20!25 21 25 0002102 2102
SFOBK! SI 0 135 222 000221# 221#
SFOBK5 SI #5 0 1$5 000211 211
SFOBK# SI 0 135 1#$ 0001$# 1$#
SFOBK3 SI 225 21 111 0001#5 1#5
SFOBK2 SI 0 5 # 0001#2 1#2
SFOBK1 SI 35 21 3 0000$ 0$
b irectia transversala K
SFOBK$ SK 20!25 5 2! 0001$31 1$31
SFOBK SK 20!25 5 25 00021 21
SFOBK! SK 20!25 135 222 00022!! 22!!
SFOBK5 SK 20!25 135 1$5 000211 211
δ contrav
δ contrav
δ cadre
δ cadre
4n concluie am obtinut ca avem cadre cu noduri deplasabile si se va tine
DriftX (0/ 00
)
SFOBK# SK 20!25 135 1#$ 0001$51 1$51
SFOBK3 SK 20!25 5 111 0001!01 1!01
SFOBK2 SK 35 1125 # 0001#2 1#2
SFOBK1 SK 0 5 3 0000$0$ 0$0$
Directia longitudinala X
SFOBK 0!00"0 0!% & 0!00&0 0!00' ade
SFOBK! 0!00"& 0!% & 0!00&&$ 0!00' ade
SFOBK5 0!00"#" 0!% & 0!00&$& 0!00' ade
SFOBK# 0!00"#'& 0!% & 0!00$%# 0!00' ade
SFOBK3 0!00"&*% 0!% & 0!00** 0!00' ade
SFOBK2 0!00"&0 0!% & 0!00'& 0!00' ade
SFOBK1 0!000#*' 0!% & 0!00"+0 0!00' ade
Directia tran,er,ala Y
SFOBK 0!00"#0 0!% & 0!00&$& 0!00' ade
SFOBK! 0!00++ 0!% & 0!00&%$ 0!00' ade
SFOBK5 0!00"*" 0!% & 0!00&$' 0!00' ade
SFOBK# 0!00"'%" 0!% & 0!00$#0 0!00' ade
SFOBK3 0!00"+0" 0!% & 0!00$0 0!00' ade
SFOBK2 0!00"&* 0!% & 0!00'+ 0!00' ade
SFOBK1 0!000'0' 0!% & 0!00"+ 0!00' ade
2. (tarea limita ultima %()*&
SFOBK 0!00"0 " & 0!00'&0' 0!0% ade
SFOBK! 0!00"& " & 0!00''%+ 0!0% ade
SFOBK5 0!00"#" " & 0!00'+'& 0!0% ade
SFOBK# 0!00"#'& " & 0!00#"$+ 0!0% ade
SFOBK3 0!00"&*% " & 0!00%*' 0!0% ade
SFOBK2 0!00"&0 " & 0!00%+' 0!0% ade
SFOBK1 0!000#*' " & 0!00$"* 0!0% ade
Directia tran,er,ala Y
SFOBK 0!00"#0 " & 0!00'+' 0!0% ade
SFOBK! 0!00++ " & 0!00*0+& 0!0% ade
SFOBK5 0!00"*" " & 0!00'#+& 0!0% ade
SFOBK# 0!00"'%" " & 0!00#&0& 0!0% ade
SFOBK3 0!00"+0" " & 0!00+&0& 0!0% ade
SFOBK2 0!00"&* " & 0!00%#"+ 0!0% ade
SFOBK1 0!000'0' " & 0!00$$ 0!0% ade
d r
15!
rat SFOBK2 0002$# 2$# $
rat SFOBK3 0002 2 $
rat SFOBK# 00035 35!$ $
rat SFOBK5 000#3# #3#2 $
rat SFOBK! 000##3 ##2$ $
rat SFOBK 000#20 #20# $
rat SFOBK$ 0003## 3## $
rat SFOBK1 0001!2 1!1! $
rat SFOBK2 0002$! 2$5$ $
rat SFOBK3 000320 3202 $
rat SFOBK# 00030 302 $
rat SFOBK5 000#3$ #3$2 $
rat SFOBK! 000#53 #532 $
rat SFOBK 000#3# #3#0 $
rat SFOBK$ 0003!!2 3!!2 $
0$5! s
100 s
rat 103! 000312 312 25
rat 0005!$ 5!$0 25
rat 0005$ 5$0 25
rat 00013! 13! 25
rat 000$!$# $!$# 25
rat 000$#0$ $#0$ 25
rat 000!#$ !#$ 25
rat 00051! 51! 25
rat 000!#0# !#0# 25
rat 000#0# #0# 25
rat 000$!# $!# 25
rat 000$!$ $!$0 25
rat 00032# 32# 25
d ra
SL. c
rift admisibil
1!1!
2$5$
3202
302
SI $5 5 105 2! 00013
SI # 0 21 2! 0000052
SI 52 20!25 21 25 0002102
SI 1 0 0 25 0000013
SI 3 0 135 222 000221#
SI # 0 21 222 0000023
SI 25 #5 0 1$5 000211
SI # 0 21 1$5 000005!
SI 3 0 135 1#$ 0001$#
SI # 0 21 1#$ 00000#
SI 1! 225 21 111 0001#5
SI # 0 21 111 00000#
SI 2 0 5 # 0001#2
SI 1 0 0 # 00000$#
SI 2# 35 21 3 0000$
SI 2$ #5 21 3 000002
Coad 'oint I K N riftI riftK
SK 1 0 0 2! 000013
SK 5$ 20!25 5 2! 0001$31
SK 25 #5 0 25 00000$!
SK 5$ 20!25 5 25 00021
SK 2$ #5 21 222 00000
SK 51 20!25 135 222 00022!!
SK 2# 35 21 1$5 00000#1
SK 51 20!25 135 1$5 000211
SK 2$ #5 21 1#$ 0000125
SK 25 #5 0 # 000010#
SK 11$ 35 1125 # 0001#2
SK # 0 21 3 0000055
SK 2 0 5 3 0000$0$
)umina /rinii
.ivel Stalp Cumina
mm/ :rinda !00m
3 2PE!00 !00 5#0
# 2PE!00 !00 5#0
5 2PE)!00 50 5#1
! 2PE)!00 50 5#1
2PE)550 5#0 5#!
$ 2PE)550 5#0 5#!
(tarea de e+orturi
2 11!0 115 2!1! 3$1#2
3 1!13 1213 25 3$11#
# 21!1 1205 210$3 331$
5 202$3 11 1!01 2$!$
! 2#325 12033 1!01 2$3#
2!! 11!# 1!5$1 2$5#5
$ #0#3 131#3 1!5$1 22#
(ectiuni propuse
# PE) #50 ##0 300 21
.(mm2
! PE) #00 30 300 1
PE) #00 30 300 1
$ PE) #00 30 300 1
!erifcare clasa de sectiune
mm/
5 PE) #00 1##5 o- o-
! PE) #00 1##5 o- o-
PE) #00 1##5 o- o-
$ PE) #00 1##5 o- o-
!erifcarea ductilitatii locale
# PE) #50 #1$300 !53! !555
5 PE) #00 33!50 5530 5213#
! PE) #00 33!50 5530 5213#
PE) #00 33!50 5530 5213#
$ PE) #00 33!50 5530 5213#
.ivel Sectiune
2 PE) 500 002! 0502 035!
3 PE) 500 0035 0501 03$1
# PE) #50 0052 050 0##!
5 PE) #00 005# 051$ 050
! PE) #00 00!5 051 0501
PE) #00 00# 051! 0##
$ PE) #00 010 053 0##!
c(t f D 10ε c(t
R D 2ε
.ivel
-.m/ -./ -./
2 150 11!0 2!1! #00
3 1$$1 1!13 25 551
# 1#$! 21!1 210$3 $2
5 12!! 202$3 1!01 10#1$
! 13!5 2#325 1!01 12#5
1!$! 2!! 1!5$1 1#2!2
$ 101 #0#3 1!5$1 202$
b)vericare de rezistenta in reazem
Exista posibilitatea ca marind :rinile, datorita cresterii fortei taietoare asoci
acesteia, sa nu mai e indeplinita conditia de limitare a fortei taietoare efective
asociata mecanismului de plasticare
e asemenea marirea :rinilor se impune pentru a reduce lun:imea de La
4n ona de reaem vericarea o voi face cu sectiunea slabita
.ivel
-./ -.m/ -./
2 11! 31$2 3$1#2 00
3 1!13 3#1!1 3$11# 102
# 21!1 32#30 331$ 12$#0
5 202$3 23!3 2$!$ 1#511
! 2#325 2$32 2$3# 1#51
2!! 25$$# 2$5#5 13#1#
$ #0#3 253 22# 1#1!#
A Ed
camp . Ed
8 Ed
camp
.(mm2/
marirea :rinilor este urmata de o nevericare a conditiei privind forta taietoare
plastifcare cu pana la 35, prin decuparea talpilor :rinii 4n acest fel scade
. Ed
(tarea de e+orturi
2 1502! 25 3350# #2
3 !3!0 22 3313 #2#$5
# 1#53! 2#1 2!3 3!1$0
5 !# 2!0 21332 3052
! 10205 2!0 21332 3052
10551 225 2113 303!2
$ 230#$ 103!# 2113 31501
(ectiuni propuse
# PE) #50 ##0 300 21
5 PE) #00 30 300 1
! PE) #00 30 300 1
PE) #00 30 300 1
$ PE) #00 30 300 1
!erifcare clasa de sectiune
mm/
5 PE) #00 1##5 o- o-
! PE) #00 1##5 o- o-
. Ed
R D 2ε
!erifcarea ductilitatii locale
# PE) #50 #1$300 !53! !555
5 PE) #00 33!50 5530 5213#
! PE) #00 33!50 5530 5213#
PE) #00 33!50 5530 5213#
$ PE) #00 33!50 5530 5213#
.ivel Sectiune
3 PE) 500 001# 055 0#$#
# PE) #50 0035 0553 05$0
5 PE) #00 0020 0553 0!2
! PE) #00 002 0553 0!30
PE) #00 002$ 05#$ 0#
$ PE) #00 00!2 05! 0##1
!erifcari de reistenta
.ivel
-.m/ -./ -./
2 2$!0$ 1502! 2$$! 0
3 3523$ !3! 2$51 1052
. pl,Bd
5 2! !# 1$20 1301
! 20# 10205 1$20 12$3#
202# 10551 1$103 $02
$ 1#3 230#$ 1$103 $10
b)vericare de rezistenta in reazem
Exista posibilitatea ca marind :rinile, datorita cresterii fortei taietoare asoci
acesteia, sa nu mai e indeplinita conditia de limitare a fortei taietoare efective
asociata mecanismului de plasticare
e asemenea marirea :rinilor se impune pentru a reduce lun:imea de La
4n ona de reaem vericarea o voi face cu sectiunea slabita
.ivel
-./ -.m/ -./
1 3035 2021 #12 110
2 1502! 3$5 3$0!1 13$!5
3 !3! #335# 3$11 15233
# 1#53! #2210 32351 1$!5
5 !# 3!20! 2530 1$01
! 10205 3!3! 2530 200$2
10551 2$!5 232$ 1!010
$ 230#$ 25##1 2$#! 15235
b) Cadre contravantuite centric
marirea :rinilor este urmata de o nevericare a conditiei privind forta taietoare
plastifcare cu pana la 35, prin decuparea talpilor :rinii 4n acest fel scade
. Ed
# 2PE!00 !00 !0
.(mm2
; stalp
2 #325 ## 2!1! 35!1!
3 212! #103 25 300$0
# 351!$ #2 210$3 30510
5 22! #0$5 1!01 20$!
! 1530 3# 1!01 2!05
305 #33 1!5$1 205#
$ 25$ 1053! 1!5$1 211
(ectiuni propuse
# PE) #50 ##0 300 21
5 PE) #00 30 300 1
! PE) #00 30 300 1
PE) #00 30 300 1
$ PE) #00 30 300 1
!erifcare clasa de sectiune
1 PE) 500 1## o- o-
2 PE) 500 1## o- o-
3 PE) 500 1## o- o-
# PE) #50 1##25 o- o-
5 PE) #00 1##5 o- o-
! PE) #00 1##5 o- o-
PE) #00 1##5 o- o-
$ PE) #00 1##5 o- o-
. Ed
R D 2ε
.ivel
-.m/ -./ -./
3 1#0 212! 25 5!
# 1102 351!$ 210$3 551
5 112 22! 1!01 !$#1
! $ 153 1!01 5!#0
50!$ 305 1!5$1 #233
$ 1125 25$ 1!5$1 !$0
b)vericare de rezistenta in reazem
.ivel
-./ -.m/ -./
2 #325 23$$ 35!1! 1033
3 212! 1$!3 300$0 !03
# 351!$ 2##2 30510 1053
5 22! 15!1 20$! $51
! 153 20#2 2!05 10#5!
305 $## 205# 5$$
$ 25$ 131 211 $00$
A Ed
camp . Ed
8 Ed
1#$! 32#30
1!$! 25$$#
115 1$ 20#5 30511
A Ed
-.m/
$!22
$!22
$!22
Ed (8
Ed (A
3! 130#$ o- o- o-
3! 133 o- o- o-
313 13$1 o- o- o-
!0 1#! o- o- o-
!#0 15301 o- o- o-
!#0 1!$# o- o- o-
!#2# 1$0$ o- o- o-
!#2# 2302 o- o- o-
iata mecanismului de plasticare la extremitatile
la 05 din cea plastic capabila 4n consecinta daca
baM a stalpilor
10!$ 203# o- o- o-
103$ 2100 o- o- o-
1030 21#$2 o- o- o-
10$3 22# o- o- o-
1111$ 2#112 o- o- o-
11132 2#1! o- o- o-
1105$ 233$# o- o- o-
11515 2##!2 o- o- o-
ec;
V2W3U2 D11 f yd
U D05 f yd
se va recur:e la slabirea sectiunii in ona de
momentul incovoietor capabil si implicit forta taietoare
ec;
V2W3U2 D11 f yd
U D05 f yd
2$!0$ 3$5
3523$ #335#
32$#0 #2210
115 1$ 20#5 30511
11 15 221$#! 2#55##
11 15 221$#! 2#55##
11 15 221$#! 2#55##
11 15 221$#! 2#55##
A Ed
$10# 1!!$ o- o- o-
$10# 1!2 o- o- o-
$02 1#$1 o- o- o-
A pl,Bd
Ed (8
Ed (A
V2W3U2 D11 f yd
U D05 f yd
0$ 135 o- o- o-
0$ 1#$ o- o- o-
013 15!0 o- o- o-
013 1#!05 o- o- o-
iata mecanismului de plasticare la extremitatile
la 05 din cea plastic capabila 4n consecinta daca
baM a stalpilor
1015 231!! o- o- o-
10!#5 231! o- o- o-
10!02 2#!$0 o- o- o-
10!!5 25#55 o- o- o-
10!!5 25!# o- o- o-
105$ 2#3#2 o- o- o-
1102$ 2##33 o- o- o-
se va recur:e la slabirea sectiunii in ona de
momentul incovoietor capabil si implicit forta taietoare
ec;
V2W3U2 D11 f yd
U D05 f yd
1#0 1$!3
1102 2##2
112 15!1
115 1$ 20#5 30511
11 15 221$#! 2#55##
11 15 221$#! 2#55##
11 15 221$#! 2#55##
11 15 221$#! 2#55##
A Ed
3! 1!!!! o- o- o-
3! 1#321 o- o- o-
313 1322 o- o- o-
!0 133!5 o- o- o-
!#0 1312 o- o- o-
!#0 125#! o- o- o-
!#2# 110# o- o- o-
!#2# 130## o- o- o-
U 8ericare 8ericare 8ericare
$#$ 201! o- o- o-
$#! 1!211 o- o- o-
203$5 o- o- o-
$053 1!3#2 o- o- o-
1010 203# o- o- o-
$11$ 152## o- o- o-
10505 1$$0 o- o- o-
ec;
V2W3U2 D11 f yd
U D05 f yd
ec;
V2W3U2 D11 f yd
U D05 f yd
.ivel
1 5 11 22$51 3#!50 1!2! 2!#
2 11! 115 22$51 3#$2! 150 31$2
3 1!13 1213 22!$5 3#$22 1$$1 3#1!1
# 21!1 1205 1$3$! 30#$1 1#$! 32#30
5 202$3 11 1#5## 2!5#1 12!! 23!3
! 2#325 12033 1#5## 2!5 13!5 2$32
2!! 11!# 1##3 2!#03 1!$! 25$$#
$ #0#3 131#3 1##3 25$2 101 253
(ectiuni decupate
1 PE) 500 #0 255 23 12 105$
2 PE) 500 #0 255 23 12 105$
3 PE) 500 #0 255 23 12 105$
# PE) #50 ##0 255 21 115 152$
. Ed
5 PE) #00 30 255 1 11 135!2
! PE) #00 30 255 1 11 135!2
PE) #00 30 255 1 11 135!2
$ PE) #00 30 255 1 11 135!2
!erifcare clasa de sectiune
1 PE) 500 1215 o- o-
2 PE) 500 1215 o- o-
3 PE) 500 1215 o- o-
# PE) #50 1215 o- o-
5 PE) #00 122 o- o-
! PE) #00 122 o- o-
PE) #00 122 o- o-
$ PE) #00 122 o- o-
!erifcarea ductilitatii locale
# PE) #50 352#5 !53! 5!0 !3#30
5 PE) #00 31$0 5530 #503! 502#$
! PE) #00 31$0 5530 #503! 502#$
PE) #00 31$0 5530 #503! 502#$
$ PE) #00 31$0 5530 #503! 502#$
.ivel Sectiune Cimitare Cimitare
1 PE) 500 0020 0#5! 035 o- o-
2 PE) 500 0030 0#5$ 0#0 o- o-
3 PE) 500 00#0 0#5$ 0#3! o- o-
# PE) #50 00!0 0#!! 0511 o- o-
5 PE) #00 00!# 0# 05$# o- o-
! PE) #00 00! 0#$0 05! o- o-
PE) #00 00$ 0# 0515 o- o-
$ PE) #00 012$ 0#$ 0512 o- o-
c(t f D 10ε c(t
R D 2ε
.ivel
-./ -./ -./ -./ -.m/ -.m/
1 3035 131#3 2$$! #12 21015 2021
2 1502! 25 2$$! 3$0!1 2$!0$ 3$5
3 !3! 22 2$51 3$11 3523$ #335#
# 1#53! 2#1 23110 32351 32$#0 #2210
5 !# 2! 1$20 2530 2! 3!20!
! 10205 2! 1$20 2530 20# 3!3!
10551 225 1$103 232$ 202# 2$!5
$ 230#$ 103!# 1$103 2$#! 1#3 25##1
(ectiuni decupate
1 PE) 500 #0 250 23 12 1!$2$
2 PE) 500 #0 250 23 12 1!$2$
3 PE) 500 #0 250 23 12 1!$2$
# PE) #50 ##0 250 21 115 150
5 PE) #00 30 250 1 11 1332
! PE) #00 30 250 1 11 1332
PE) #00 30 250 1 11 1332
$ PE) #00 30 250 1 11 1332
!erifcare clasa de sectiune
1 PE) 500 11 o- o-
2 PE) 500 11 o- o-
3 PE) 500 11 o- o-
# PE) #50 1125 o- o-
5 PE) #00 115 o- o-
! PE) #00 115 o- o-
. Ed
R D 2ε
!erifcarea ductilitatii locale
.ivel Sectiune
-./ -./ -.m/ -.m/
1 PE) 500 35#5$ !03# !$5$! 001
2 PE) 500 35#5$ !03# !$5$! 001
3 PE) 500 35#5$ !03# !$5$! 001
# PE) #50 35#310 !53! 5522 !23!
5 PE) #00 31#2#2 5530 ##2#$ ##20
! PE) #00 31#2#2 5530 ##2#$ ##20
PE) #00 31#2#2 5530 ##2#$ ##20
$ PE) #00 31#2#2 5530 ##2#$ ##20
.ivel Sectiune Cimitare Cimitare
1 PE) 500 00$ 0#! 03 o- o-
2 PE) 500 003$ 0#1 0#2 o- o-
3 PE) 500 001! 0# 05!3 o- o-
# PE) #50 00#1 0#5 0!! o- o-
5 PE) #00 002# 0# 033 o- o-
! PE) #00 0032 0# 03! o- o-
PE) #00 003# 0## 05$0 o- o-
$ PE) #00 003 0## 0515 o- o-
. pl,Bd
T el T
1$$2$ 2102
1$$2$ 2102
1$$2$ 2102
1$$2$ 2102
4'E 500 500 200
4'E 500 500 200
4'E #00 #00 1$0
4'E #00 #00 1$0
4'E #00 #00 1$0
1 11 15 2311 25!2
1 11 15 2311 25!2
1 11 15 2311 25!2
1! 102 1155 12$ 21#
1! 102 1155 12$ 21#
1#! # $$2 1500 102
1#! # $$2 1500 102
1#! # $$2 1500 102
135 $! $##! 115! 130
135 $! $##! 115! 130
135 $! $##! 115! 130
1!2! SFOBK1 # QB4.N4 A)I 11
11 SFOBK1 # QB4.N4 A)I 1#$$
SFOBK1 # QB4.N4 A)I 1$5
SFOBK1 # QB4.N4 A)I 1$5
SFOBK1 # QB4.N4 A)I 23##
SFOBK1 # QB4.N4 A)I 2$13
SFOBK1 # QB4.N4 A)I 32$1
SFOBK1 # QB4.N4 A)I 35
SFOBK1 # QB4.N4 A)I 35
SFOBK1 # QB4.N4 A)I #21
SFOBK1 # QB4.N4 A)I !013
SFOBK1 # QB4.N4 A4. 1#$$
SFOBK1 # QB4.N4 A4. #21
SFOBK1 # QB4.N4 A4. !013
A reaem
SFOBK1 ! QB4.N4 A)I 1#$$
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SFOBK1 10 QB4.N4 A)I 0325
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SFOBK1 10 QB4.N4 A4. #21
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