Top Banner
Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)
22

Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Jan 01, 2016

Download

Documents

oprah-patterson

Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment). Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment) My PowerPoint lecture notes available on-line www.physics.umanitoba.ca/~ens/16.102lectures.html - PowerPoint PPT Presentation
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Page 1: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Werner Ens

518 Allen

Office Hours: Monday 2 - 6 pm(or by appointment)

Page 2: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Werner Ens

518 Allen

Office Hours: Monday 2 - 6 pm(or by appointment)

My PowerPoint lecture notes available on-line

www.physics.umanitoba.ca/~ens/16.102lectures.html

(Complete lecture notes prepared last year by Professor Birchall are available at the course web site)

Page 3: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz1. Which arrows correctly represent

acceleration?

(a) (b) (c) (d) (e)

Page 4: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz2. Which is the trajectory after the line is cut?

(a)

(b)

(c)

(d)

Page 5: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz3. What happens to an astronaut if his tether to

an orbiting space station is cut?

(a) Stays with space station

(b) Falls behind in orbit

(c) Falls to earth

(d) Lost in space (moves away)

(e) Remains stationary with respect to the sun

Page 6: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz4. What happens if an astronaut releases a ball

while standing on the moon?

(a) It falls to the ground (moon)

(b) It rises

(c) It stays where it is released

(d) Moves horizontally (moon’s horizon)

Page 7: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz solutions1. Which arrows correctly represent

acceleration?

(a) (b) (c) (d) (e)

Page 8: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz solutions2. Which is the trajectory after the line is cut?

(a)

(b)

(c)

(d)

Page 9: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz solutions3. What happens to an astronaut if his tether to

an orbiting space station is cut?

(a) Stays with space station

(b) Falls behind in orbit

(c) Falls to earth

(d) Lost in space (moves away)

(e) Remains stationary with respect to the sun

Page 10: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz solutions4. What happens if an astronaut releases a ball

while standing on the moon?

(a) It stays where it is

(b) It rises

(c) It falls to the ground (moon)

(d) Moves horizontally (moon’s horizon)

Page 11: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Quiz solutions

1 d, 2 b, 3 a, 4 c

Page 12: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Chapter 1

Introduction

Mathematical Concepts

Page 13: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

1) Representation of physical quantities

• Arithmetic is abstract: 10 - 5 = 5• A physical quantity (distance) requires

comparison to a standard: L = 10 is meaningless

m

10 m

• A physical quantity is an algebraic product of a number and a unit: L = 10 m

Page 14: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

2) Units combine algebraically; Dimensional Analysis

d3 = d1 + d2

d1 = 5m;

d2 = 8m

d3 = 5m + 8m

= (5 + 8)m

=13m

Page 15: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

2) Units combine algebraically; Dimensional Analysis

A = l • w

l = 8m

w = 4m

A = 8m• 4m = 32m2

V = lwh ≠ 32h

V = 32m2h

If h = 2m, then V = 64m3

Page 16: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Example: Vector Addition• Jogger runs 145 m 20.0º East of North

– Displacement vector A

• Then 105 m 35.0º South of East– Displacement vector B

• Find resultant displacement C=A+B

A =145 m; θA =70º

θA

20º

x (E)

y (N) rA

35º rB

rC

θC

θB

B =105 m; θB =360º−35º

→ 325º or −35º

Find C and θC

Step 0: Draw a picture & organize data

Page 17: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Example: Vector Addition

A =145 m; θA =70ºθA20º

x (E)

y (N) rA

• Step 1: Convert to component representation

Ax =AcosθA =(145m)cos70º=49.6m

Ax

Ay

Ay =AsinθA =(145m) sin70º=136m

Page 18: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Example: Vector Addition

x (E)

y (N) 35º rB

θB

B =105 m; θB =360º−35º

→ 325º or −35º

• Step 1: Convert to component representation

Ax =AcosθA =(145m)cos70º=49.6mAy =AsinθA =(145m) sin70º=136m

By

Bx

By =BsinθB =(105m) sin(-35º) =−60.2mBx =BcosθB =(105m) cos(-35º) =86.0m

Page 19: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Example: Vector Addition• Step 2: Sum components

Ax =49.6mAy =136m

By =−60.2mBx =86.0mθA

20º

x (E)

y (N) rA

35º rB

rC

θC

θB

Cx =Ax + Bx =135.6m

Cy =Ay + By =76.0m

Page 20: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Example: Vector Addition• Step 3: Convert result to geometric representation

(magnitude, direction)

Ax =49.6mAy =136m

By =−60.2mBx =86.0m

x (E)

y (N)

rC

θC

Cx =135.6m

Cy =76.0m

C = Cx2 +Cy

2 =155m

Cx

Cy

tanθc =Cy

Cx

=.560 → θC = 29.2º (North of East)

Page 21: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Example: Vector Addition• Step 3: Convert to geometric representation (magnitude, direction)

x (E)

y (N)

rC

θC

Cx =135.6m

Cy =−76.0m

C = Cx2 +Cy

2 =155m

Cx

Cy

tanθc =Cy

Cx

=−.560 → θC = −29.2º

Page 22: Werner Ens 518 Allen Office Hours: Monday 2 - 6 pm (or by appointment)

Example: Vector Addition• Step 3: Convert to geometric representation (magnitude, direction)

x (E)

y (N)

rC

θC Cx =−135.6m

Cy =−76.0m

C = Cx2 +Cy

2 =155m

Cx

Cy

tanθc =Cy

Cx

=.560 → θC = 29.2º?

→ θC = 29.2º +180º = 209.2º