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Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able to join us
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Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Jan 02, 2016

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Page 1: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Welcome to the Webinar“Live” Review for Test 1 (MAC

1105)

We will start promptly at 8:00 pm

Everyone will be placed on mute

I am happy that you are able to join us

Page 2: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

NoteThe following slides present sample problems similar to the test content, including the worked-out solutions.

These are a few problems and do not include all the competencies tested on Test 1.

To be prepared for the test, you must review the material from all the assigned Chapters 1 and 2 sections and follow the Study Guide posted on Blackboard!

Page 3: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Find the x-and-y-intercepts of the graph of -3x + ¾ y = 18  

To find the x-intercept, set y = 0

-3x + ¾ (0) = 18

-3x = 18

x = -6 or (-6, 0)If asked for ordered pair form, write your answer in the form (x, y). If

not asked for ordered pair form, then just write the values as specified on the question.

To find the y-intercept, set x = 0

-3(0) + ¾ y = 18

¾ y = 18

(4/3)(¾) y = 18(4/3)

y = 24 or (0, 24)

Page 4: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Slopes of Lines

12

12

xxyy

runrise

xy

m

Page 5: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Choose the graph that matches y = ⅕ x – 5

a. b.

c. d.

 

Page 6: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Graphing y = ⅕ x – 5 using the slope-intercept method

First, identify the y-intercept and the slope:(Remember y = mx + b, where m is slope and b is y-intercept)

y-intercept is -5 or (0, -5)

slope is ⅕

Now, plot the y-intercept and from there, apply “rise over run”

 

Page 7: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Choose the graph that matches y = ⅕ x – 5

a. b.

c. d.

y-intercept is (0, -5). So, eliminate a and d.slope is 1/5. So, rise 1, run 5. Answer is b

 

Page 8: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

What can we say about the slopes of the following lines?

a.l4 is negative

b.l1 , l2 are positive c.l3 is undefined

d.l3 is zero

Answer: d

Page 9: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Write the slope-intercept form of the equation for the line passing through the points (-7, 6) and (1, -3).

First, find slope:

Use the point-slope formula (with any of the given points), and simplify to slope-intercept form:

y – y1 = m(x – x1)

y – (-3) = -(9/8)(x – 1)

y + 3 = -(9/8)(x – 1)

y = -(9/8)x + (9/8) – 3

  y = -(9/8)x + (9/8) – (24/8)

y = -(9/8)x – 15/8

89

89

)7(163

xy

m

Page 10: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Parallel lines have negative reciprocal slopes.

a. True

b. False

Your time to work! Poll Question

Page 11: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Parallel lines have negative reciprocal slopes.

a. True

b. False

Answer: False

Parallel lines have equal slopes.

Perpendicular lines have negative reciprocal slopes.

Page 12: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

True or False:

The equation of the line that passes through the point (1, 4)

and is perpendicular to y = -2x + 6 is y = -½ x + 9/2.

Slopes are -2 and - ½, which are not negative reciprocals of each other!

Answer: False

Page 13: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Find the point-slope form of the equation of the line through the point(-2, 3) parallel to the line 6x + 3y – 9 = 0.

?

First, change to slope-intercept form by isolating the y:

3y = -6x + 9

y = -2x + 3Now, find a line with slope m = -2 and passing through (-2, 3).

y – y1 = m(x – x1)

y – 3 = -2[x – (-2)]

y – 3 = -2(x + 2)

You have to stop here! (asked for point-slope form)

Page 14: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

The line whose equation is y = -6 has slope m =

a. -6

b. -1/6

c. 0

d. 6

e. Undefined 

Your time to work!Poll Question

Page 15: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

The line whose equation is y = -6 has slope m =

a. -6

b. -1/6

c. 0

d. 6

e. Undefined

Vertical Line: x =

Horizontal Line: y =

Answer: cy = -6 is a horizontal line, therefore, m = 0

Page 16: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

True or False: The following table represents a function.

 

Function: For each input, there exists only one unique output

Answer: True

Different inputs can share the same output, like (-3, 0) and (12, 0)

p -5 -3 6 7 12

q -1 0 7 -2 0

Page 17: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

True or False: The following graph represents a function.

Passes Vertical Line Test?Yes.

Answer: True

Page 18: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

For the following graph,

a.Find C(150) b. Find x if C(x) = 10

a.C(150) means given the input of 150, find the output. Therefore, C(150) = 20

b.If C(x) = 10, we are looking for x values where the output is10.Therefore, x = 50; 300

Page 19: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

For the following function,a.Find domain and range b.Find increasing and decreasing intervals

a.Domain (Input): 0 x 300 or [0, 300] Range (Output): 5 y 25 or [5, 25]

b.Increasing: (0, 200) Decreasing: (200, 300)

Page 20: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Find the domain and range of the function f(x) = Domain: Possible values of the input.Range: Possible values of the output.

Domain: or

2x – 6 0 2x 6 x 3 or [3, infinity)

Range: y 0 or [0, infinity)

62 x

positive zero

Page 21: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

If p is the function ‘f’ of q, then:

a. p = f(q)

b. the point (q, p) is on the graph of f

c. f(0) = p is the vertical intercept of f for some p value

d. f(q) = 0 is the horizontal intercept for some q value(s)

e. the domain of f are all the possible values of q

f.the range of f are all output values p

g.all of the above

h. none of the above 

Your time to work!Poll Question

Answer using the Questions Box

Page 22: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

If p is the function ‘f’ of q, then:

a. p = f(q)

b. the point (q, p) is on the graph of f

c. f(0) = p is the vertical intercept of f for some p value

d. f(q) = 0 is the horizontal intercept for some q value(s)

e. the domain of f are all the possible values of q

f.the range of f are all output values p

g.all of the above

h. none of the above 

Answer: g

Page 23: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Dance Rooms Here charges $65 per hour and a $350 deposit.

a. Find a linear function that models this situation. Use C for cost and h for hours.b. Find and interpret the slope and the vertical intercept.c. If the total cost was $740, how many hours was the dance room used?d. Find and interpret C(4.5)

a. Cost = deposit fee plus rate per hour for each hour of use C(h) = 350 + 65h Note: This problem involves variables C and h. Using other variables not stated onthe problem would be marked incorrect. Example, C(x) = 350 + 65x.Make sure to use the variables as specified on each of the test questions!

b. Slope = 65. The cost increases at a rate of $65 per hour. The vertical intercept is 350 and it denotes the initial fee.

Page 24: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

c. If the total cost was $740, how many hours was the dance room used?d. Find and interpret C(4.5)

c. We know C(h) = 350 + 65h 350 + 65h = 740 Solving for h we have

350 – 350 + 65h = 740 – 350

65h = 390 65h = 390 65 65 h = 6 hours d. C(h) = 350 + 65h C(4.5) = 350 + 65(4.5) = 350 + 292.5 = 642.5 If the dance room is used for 4.5 hours, the cost is $642.50

Page 25: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

A test has 26 questions worth 100 points. The test consists of multiple choice questions worth 2 points each and free response questions worth 6 points each. How many multiple choice questions are on the test?

First, establish a system of equations. Let x = multiple choice questions and y = free response questions

Number of questions: x + y = 26Question value: 2x + 6y = 100

Multiply the first equation by -2, to help us eliminate the x-terms: (-2)(x + y) = (26)(-2)So, we have

-2x – 2y = -52 2x + 6y = 100 4y = 48

y = 12Back-substitute y = 12 into one of the original equations to find x. x + (12) = 26x = 14 multiple choice questions

Page 26: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

If f(x) = -x3 + 3x – 5, find f(-2)

f(-2) = -(-2)3 + 3(-2) – 5

= -(-8) – 6 – 5

= 8 – 6 – 5

= -3

So, f(-2) = -3; that is, when the input is -2, the output is -3.

Page 27: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

If f(x) = x2 + 2x + h, find f(x + h)

f(x + h) = (x + h)2 + 2(x + h) + h

Note: (x + h)2 = (x + h) (x + h) = x² + 2xh + h² Therefore,

f(x + h) = (x + h)2 + 2(x + h) + h

= x² + 2xh + h² + 2x + 2h + h = x² + 2xh + h² + 2x + 3h

Page 28: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Professor Vivaldi asked the students to evaluate f(x + h) given the function f(x) = 3x2 + 6.

Brenda’s answer: 3x2 + 3h2 + 6

Miranda’s answer: 3x2 + 6xh + 3h2 + 6

T.J.’s answer: 6x2h2 + 6xh + 6

Who is correct?

a. Brenda

b. Miranda

c. T.J.

d. Neither Your time to work!

Answer using the Questions Box

Page 29: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Professor Vivaldi asked the students to evaluate f(x + h) given the function f(x) = 3x2 + 6.

b. Miranda’s answer: 3x2 + 6xh + 3h2 + 6

f(x + h) = 3(x + h)2 + 6

= 3(x2 + 2xh + h2) + 6

= 3x2 + 6xh + 3h2 + 6

Page 30: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

A group of friends can spend no more than $50 for popcorn and sodas at a concert. A small bag of popcorn costs $6 and a medium soda is $5. Let x represent popcorn and y represent a soda. Which of the following describes this scenario?

a.5x + 6y 50

b.6x + 5y 50

c.5x + 6y 50

d.6x + 5y 50

x: popcorn, $6 each 6x y: soda, $5 each 5y

We can eliminate a and c.

“No more than $50” implies 50 dollars or less

Answer is b.

Page 31: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

NOTE: It is important that you follow the instructions on the test.

For example, if asked for interval notation, write your answer using interval notation. If you are not asked for interval notation, then just write the values as specified on the question.

If asked for ordered pair form, write your answer in the form (x, y). If not asked for ordered pair form, then just write the values as specified on the question.

So, read and follow instructions!

Page 32: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

This "live" review session has covered

content addressed on test 1, but you

need to review chapters 1-2 and

complete all the problems assigned on

the study guide, so that you are well-

prepared for the test.

Page 33: Welcome to the Webinar “Live” Review for Test 1 (MAC 1105) We will start promptly at 8:00 pm Everyone will be placed on mute I am happy that you are able.

Do well!

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