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WELCOME TO LESSON 9 PYTHAGOREAN THEOREM Prepared for : Class IX Subject : Geometry Class Teacher : M A Monzoor Book used : Text Book, Web Page Date : 01/03/2011 Pithagor as Next Home Previo us
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Welcome to lesson 9 Pythagorean T heorem

Dec 30, 2015

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Prepared for : Class IX Subject : Geometry Class Teacher: M A Monzoor Book used : Text Book, Web Page Date : 01/03/2011. Pithagoras. Welcome to lesson 9 Pythagorean T heorem. Home. Previous. Next. End. Requirements: - Textbook (VIII & IX-X) - PowerPoint PPT Presentation
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Page 1: Welcome  to lesson 9 Pythagorean  T heorem

WELCOME TO LESSON 9

PYTHAGOREAN THEOREM

Prepared for : Class IX

Subject : Geometry

Class Teacher : M A Monzoor

Book used : Text Book, Web Page

Date : 01/03/2011

Pithagoras

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Page 2: Welcome  to lesson 9 Pythagorean  T heorem

Requirements:- Textbook (VIII & IX-X)- Webpage- Computer Set

Pithagoras Theorem

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Aims and Objectives

At the end of the theorem the students will be able to learn about

- The area of a square- The right angled triangle- Solving new problems

square

triangle

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1 1 1 1 1 1 1 1 1 1 1 1

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9 16

25

AB 2 = AC2 + BC2

A C

A B

CB

3 2 + 42 = 52

বৃ�হত্তম বৃর্গ�টি অপর দু টি বৃর্গের্গ�র সমষ্টির

। সম�ন

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Page 5: Welcome  to lesson 9 Pythagorean  T heorem

C

A

F

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K

B

EK

আমিম যমিদু বৃর্গ�গুর্গে��র্গে� মিনর্গে��ক্তভা�র্গেবৃ ।স�জা�র্গে� প�মির

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Page 6: Welcome  to lesson 9 Pythagorean  T heorem

আমিম প্রমি�টি বৃর্গের্গ�রবৃমিহ: অ�র্গে র বৃ�হু

বৃ�দু মিদুই ��হর্গে� আমর� মি� প�ই?

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সমকো��নী� ত্রিভু�কো�র অত্রি�ভু�কো�র উপর অত্রি�� বর্গ�কো�কোর ক্ষে�ফল অপর দু�ই

ব�হুর উপর অত্রি�� বর্গ�কো�কোর ক্ষে�ফকোলর ।সমষ্টির সম�নী

প#থা�র্গের্গ�র�র্গেসর উপপ�দু&

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Pithagoras

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স�ধা�রণ ত্রিনীব�চনী: মকোনী �ত্রির, ABC এ�টি সমর্গে��ণী# মি)ভা*জা

এবৃ� ∠C = এ� সমকো��ণএখা�র্গেন, AB । অমি�ভা*জা প্রম�ণী �রর্গে� হর্গেবৃ

যেয, AB এর উপর অমি-� বৃর্গ�র্গে.) = AC এর উপর উমি-� বৃর্গ�র্গে.) + BC এর উপর অমি-�

। বৃর্গ�র্গে.)”অথা�� AB2 = AC2 + BC2.

C

BA

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অ�নী: AB, AC এবৃ� BC এর

উপর যথা�ক্রর্গেম ABED, ACGF এবৃ�BCHK

।অ-ন �মির

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উক্ত সর�র্গেরখা� AB এবৃ� DE যথা�ক্রর্গেম M এবৃ� L । মিবৃন্দু র্গে� যে1দু �র্গের C, D এবৃ� B, F যেয�র্গ

। �মির

A B

C

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LD E

C মিবৃন্দু মিদুর্গে2 AD অথাবৃ�BE এর

সম�ন্তর�� �র্গেরCL । অ-ন �মির

H

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প্রম�ণী:∠BAD = CAF ∠[ প্রর্গে�&র্গে� এ� সমর্গে��ণী]

উভা2 প�র্গে ∠BAC যেয�র্গ �র্গের প�ই ∠BAD + BAC = CAF + ∠ ∠

BAC.∠ ∴ ∠CAD = BAF.∠

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এখান ΔCAD এবৃ�ΔBAF এর মর্গে4& CA =

AF, AD = AB এবৃ�অন্ত�ভা*ক্ত ∠CAD = অন্ত�ভা*ক্ত∠BAF,

∴ ΔCAD ≅ ΔBAF.

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[If in two triangles each of two sides of one is equal to the corresponding side of the other respectively and the included angle of those sides of one is equal to that of the other, then the triangles are congruent.] Thm-7

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যেযর্গেহ�* ∠ACB এবৃ� ∠ACG

প্রর্গে�&র্গে� এ�সমর্গে��ণী

∴ BCG এ�ই সর�র্গেরখা�2

।অবৃমি5�[If the sum of two adjacent angles is equal to two right angles, then their twoexterior sides lie in the same straight line.]

A B

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Microsoft Office Word Document

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এখান যেযর্গেহ�* মি)ভা*জার্গে.) CAD এবৃ� আ2�র্গে.) ADLM এ�ই ভা6 মিম AD

এবৃ� AD ও CL, এ�ই সম�ন্তর�র্গে� । যেরখা�য র্গর্গে�র মর্গে4& অবৃমি5�

ADLM = 2 (Δ যে.) CAD) ...................... (1)

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Theorem-2

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অনরূপভা�র্গেবৃ আমর� প্রম�ণী �রর্গে� প�মির যেয, ACGF = 2 (Δ region BAF) ..............(2)

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∴ আ2�র্গে9� ADLM = বৃর্গ�র্গে.) ACGF……….…(3)

C

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A B

C

D E

K

H

এ�ইভা�র্গেবৃ C, E এবৃ� A, K, যেয�র্গ

�র্গের প্রম�ণী �র� য�2 যেয,

L

M

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আ2�র্গে.) BELM = বৃর্গ�র্গে.) BCHK ………....(4)

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Adding (3) and (4) it is obtained,

C

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LD

M B

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Square region ABED = Square region ACGF + Square region BCHK.

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��হর্গে�আমর� বৃ�র্গে� প�মির যেয, AB এর উপর অমি-� বৃর্গ�র্গে.র্গে)র যে.র্গে)ফ� = t AC এর উপর অমি-� বৃর্গ�র্গে.র্গে)র যে.র্গে)ফ� + BC এর উপর অমি-� বৃর্গ�র্গে.র্গে)র যে.র্গে)ফ�

AB2 = AC2 + BC2 [proved]

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Alternative proofs of the theorem:1.Proof using similar triangles2.Proof by rearrangement3.Algebraic proofs4.Proof by using differences.

eql triangle

rearrangement

algebaic

differentials

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Page 23: Welcome  to lesson 9 Pythagorean  T heorem

Have you any questions?

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Quiz:How many equal triangles can you get from the square whose one side is 28 metres?

Ans

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Home work1. Mr. Nur Hossain went 40 metres north from a

starting point of his house and then went 60 metres west of that point. Then he returned to his starting pint making the shortest distant. How long did Mr. Nur Hossain walked?

2. One side of a rectangle is half of the adjacent side of the same rectangle. If the shorter side of the rectangle is ----- metre then what will be the surrounding of the rectangle? What will be the area of that rectangle?

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Page 26: Welcome  to lesson 9 Pythagorean  T heorem

That’s all for today, dear students.

Thanks a lot.

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