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Week 2. Chemical Kinetics Analysis of Rate Equation

Jun 04, 2018

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  • 8/13/2019 Week 2. Chemical Kinetics Analysis of Rate Equation

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    Reaction Engineering

    Chemical Kinetics /

    Analysis of rate equations

    1

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    Chemical Kinetics - outcomes

    Understand the significance of kinetics

    Aware of concentration dependencies

    Understand the difference elementary / non-elementary reactions

    Calculate the order of reaction

    Aware of temperature dependencies Arrhenius, activation energy

    2

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    The Rate Equation / Stoichiometry

    aA bB cC dD

    dtdN

    Vr AA 1 rate of disappearance of A

    dt

    dN

    Vr CC

    1 rate of appearance of C

    d

    r

    c

    r

    b

    r

    a

    r DCBA

    Relationship

    between rates of

    reaction

    3

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    Concentration / Temp. dependency terms

    .).,( tempconcfr

    ,...)],()][([ BAA CCfTkr

    Reaction rate

    (constant)

    Concentration

    dependent terms

    4

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    Concentration-dependent term

    ,...)],([ BAA CCfkr Almost without exception determined by experimental observation!!!

    Most common expression:

    DBAA CCkCr ....

    Order of reaction: AinorderBinorder

    orderoverall...n

    5

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    Elementary / Non-elementary Reactions

    Elementary reactions

    iff stoichiometric coefficients are the same as theindividual reaction order of each species

    Non-elementary reactions

    stoichiometry does not match the kinetics

    DCBA

    BAA CkCr

    stoichiometric coeff: 1 dcba

    1 a

    BAA CkCr 2 2

    1

    BAA CkCr

    1 b

    A sequence of elementary reactions 6

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    Elementary reactions / Molecularity

    = the number of molecules involved in a reaction

    refers ONLY to elementary reaction!!!

    Elementary reactions

    PX

    PX2

    PYX PX3

    PYX 2

    PZYX

    Rate Law

    XkC

    2

    XkC

    YXCkC3

    XkC

    2

    YXCkC

    ZYX CCkC

    Molecularity Comments

    unimolecular

    bimolecular

    bimolecular

    termolecular

    termolecular

    termolecular

    X decomposes

    X collides with X

    X collides with Y

    X+X+X collide

    X+Y+Y collide

    X+Y+Z collide

    tymoleculariorder

    7

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    Non-elementary reactions

    Overall reaction:

    )(2)(2)()(4 222 gBrgOHgOgHBr kexp

    Sequence of reactionsproposed mechanism:

    )()()( 2 gHOOBrgOgHBr

    )(2)()( gHOBrgHBrgHOOBr

    )()()()( 22 gBrgOHgHBrgHOBr

    )()()()( 22 gBrgOHgHBrgHOBr

    (1)

    (2)

    (3)

    (4)

    k1

    k2

    k3

    k4

    elementary

    reactions(bimolecular)

    (slow)

    (fast)

    (fast)

    (fast)

    kexp=func(k1,k2,k3,k4)

    kexp=k1 8

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    Concentration / Temp. dependency terms

    .).,( tempconcfr

    ,...)],()][([ BAA CCfTkr

    Reaction rate

    (constant)

    Concentration

    dependent terms

    9

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    Rate constant (k)

    ,...)],([ BAA CCfkr

    Dimensions vary with order of reaction (n):

    nionconcentrattime 11 )()(

    Reaction order

    (mol/m3)

    CA

    (mol/m3)

    (mol/m3)

    (mol/m3.s)

    (mol/m3.s)

    (mol/m3.s)

    -rA Rate law

    (mol/m3)/skrA

    AA kCr

    2

    AA kCr

    1/s

    (m3/mol)/s

    zero

    1st

    2nd

    k

    10

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    Temperature dependency

    Activation energy

    RTEekk /0

    Activation energy (E) calculation:

    data for same concentration different temperatures

    TR

    Ekk 1

    lnln 0

    TR

    Ekk

    1

    3.2loglog 0or

    211

    2 11ln

    TTR

    E

    k

    k

    T1,T2

    ln, log

    211

    2 11

    3.2

    log

    TTR

    E

    k

    k

    12

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    Activation energy calculation

    example 1

    First order reaction: CBA

    Data: k (1/s) 0.00043 0.00103 0.0018 0.00355 0.00717T(K) 313 319 323 328 333

    211

    2 11

    3.2log

    TTR

    E

    k

    k

    21

    12

    /1/1

    )/log()3.2(

    TT

    kkRE

    00303.0/1005.0 11 Tk

    00319.0/10005.0 22 Tk

    Hint: for 1)/log(1.0 2112 kkkkmolkJE /12013

    0

    0.5

    1

    1.5

    2

    2.5

    3

    3.5

    4

    0.00295 0.003 0.00305 0.0031 0.00315 0.0032 0.00325

    1/T Vs log k

    Log k

    1/T

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    Activation energy calculation

    example 2

    To obtain pasteurised milk:

    heating at 63C for 30 min

    heating at 74C for 15 s

    KTt 336min30 11

    212

    1

    1

    2 11lnlnTTR

    E

    t

    t

    k

    k

    Reaction rate is inversely

    proportional with reaction time

    KTt 347min25.0sec15 22

    347

    1

    336

    1

    314.825.0

    30ln

    E

    molJE /422000

    Find the activation energy of the process

    14

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    Data on the tenebrionid beetle whose body mass is 3.3 g show that it can

    push a 35-g ball of dung at 6.5 cm/s at 27 C, 13 cm/s at 37 C, and 18 cm/s

    at 40 C. How fast can it push dung at 41.5 C? [B. Heinrich. The Hot-

    Blooded Insects (Cambridge, Mass.: 1993).]

    Activation energy calculation

    example 3

    15

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    The behavior of the beetle can be modeled by the Arrhenius equation.

    The beetle's speed (k) increases exponentially with temperature.

    Arrhenius equation:

    To calculate how fast the beetle can push the ball determine:

    the activation energy (E)

    the Arrhenius coefficient (k0) of the beetle

    Activation energy calculation

    example 3

    RTEekk /0

    16

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    k1 = 6.5 T1 = 300K

    k2=13 T2 =310 K

    k3= 18 T3=313 K

    k4 = ? T4 = 314.5 K

    ln(k) for T=314.5 is equal to ~2.95

    This corresponds to a k4value of 19.1 cm/s.

    Activation energy calculation

    example 3

    Plot ln(k) vs. 1/T

    Predict ln(k) for T=314.5 K

    Rate (cm/s) Temp (K)

    How would you solve the

    problem analytically?17

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    Analysis of rate equations - outcomes

    Be able to use experimental data to get empirical rate equations

    Necessity of a rate equation for design purposes

    Able to analyse different types of reactions

    Expand the analysis to multiple reactions

    Chain reactions and their interpretation & analysis

    18

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    Analysis of rate equations general

    issues

    dt

    dN

    Vr ii

    1The rate equation:

    The form might be suggested by:Theoretical considerations

    Empirical curve-fitting procedure

    The value of equation constants experimental only!

    2 step-procedure:

    Find concentration dependency at Temp=const.

    Find temperature dependency of the rate constants

    19

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    dt

    dN

    Vr ii

    1The rate equation:

    Equipment used for getting the empirical data

    batch reactor container that holds the reactants usually for

    homogeneous reactions

    flow reactor continuous flow in / flow out - usually for

    heterogeneous reactions

    Measurements:

    concentration of a component

    change in physical properties (conductivity, refractive index)

    change in total pressure when V=constant.

    change in volume when P=constant.

    Analysis of rate equations general

    issues (contd.)

    20

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    dt

    dN

    Vr ii

    1The rate equation:

    Procedures for analysing the kinetic data:

    integral method:

    guess a form of rate equation

    integration & mathematical manipulation

    predict the plot of C=f (time) as a straight line

    plot the data and if good fit accept the equation

    differential method:

    find (1/V)(dN/dt) from the data

    test the fit directly (no integration)

    Analysis of rate equations general

    issues (contd.)

    21

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    0

    0

    A

    AAA

    N

    NNX

    Conversion of A:

    Constant volume batch reactor

    conversion

    = the fraction of A

    reacted away

    0000

    0 1/

    /11

    A

    A

    A

    A

    A

    A

    A

    AAA

    C

    C

    VN

    VN

    N

    N

    N

    NNX

    The volume of reaction mixture = constant

    = constant density reaction system dt

    dCr AA

    22

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    A. Integral method- irreversible, unimolecular, first order rxs. -

    sProductA

    A

    A

    A kCdt

    dC

    r

    Test the first-order rate equation form:

    using concentration

    using conversion

    0

    1A

    AA

    CCX

    0A

    AA

    C

    dCdX

    AAAA

    A kCdt

    dXC

    dt

    dCr 0

    0A

    AA

    C

    Ck

    dt

    dX

    )1( AA

    A Xkdt

    dXr

    24

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    A. Integral method- irreversible, unimolecular, first order rxs. -

    tX

    A

    A dtk

    X

    dXA

    00

    1

    Separate & integrate:

    tC

    CA

    A dtkC

    dCA

    A 00

    ktC

    C

    A

    A 0

    ln

    using concentration

    using conversion

    ktXA )1ln(

    AA kC

    dt

    dC

    )1( AA Xkdt

    dX

    25

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    A. Integral method- irreversible, unimolecular, first order rxs. -

    Plot the experimental data & the proposed equation line:

    -ln(CA

    /CA0

    )orl

    n(1-XA

    )

    t

    If the data fit Accept first-order rate equation

    kslope

    26

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    t

    A

    X

    AA

    A dtkCXMX

    dXA

    00

    0 1

    Separate & integrate:

    A

    B

    AB

    AB

    A

    A

    A

    B

    MC

    C

    CC

    CC

    XM

    XM

    X

    Xlnln

    )1(ln

    1

    1ln

    0

    0

    B1. Integral method- irreversible, bimolecular, second order rxs. -

    ktCCktMC ABA )()1( 000

    1MCondition:00 BA

    CC or

    28

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    B2. Integral method- irreversible, bimolecular, second order rxs. -

    sProductA2

    22

    0

    2

    )1( AAAA

    A XkCkCdt

    dCr

    The second-order rate equation form:

    ktX

    X

    CCC A

    A

    AAA 1

    111

    00

    t

    AC

    1

    kslope

    0

    1

    ACerceptint

    t

    kCslope A0

    A

    A

    X

    X

    1

    30

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    B3. Integral method- irreversible, bimolecular, second order rxs. -

    sProductBA 2

    )2)(1(20 AAABAAA XMXkCCkCdtdCr

    The second-order rate equation form:

    kt

    X

    X

    CCC A

    A

    AAA

    2

    1

    111

    00

    ktMCXM

    XM

    CC

    CCA

    A

    A

    AB

    AB )2()1(

    2lnln 0

    0

    0

    2M

    2M31