Warm–up #9. Solve by Factoring 2 #s that mult to 56 –15 & add to –8 –7 set each factor = 0 Common factor first Make = 0!!!

Warm–up #91. Solve by Factoring

2. Solve by Completing the Square

Solve by Factoring1.

x(2x(x – 4) – 7(x – 4)) = 0

x(2x – 7)(x – 4) = 0

x = 0 2x – 7 = 0 x – 4 = 0

{0, 4, }

2 #s that mult to56

–15 & add to

–8 –7

set each factor = 0

Common factor first

Make = 0!!!

=

Solve by Completing the Square

2.

2 2 2

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Homework LogWed

10/14

Lesson 2 – 4

Learning Objective: To solve quadratic forms

Hw: #210 Pg. 128 #12, 24, 36, 37 – 51 odd, WS # 8 – 10

10/14/15 Lesson 2 – 4 Quadratic Form Day 2

Advanced Math/Trig

Learning Objective

To solve quadratic equations in quadratic form

Solve by Factoring1.

4u(u – 1) – 9(u – 1) = 0

(4u – 9)(u – 1) = 0

Make = 0 first

It has quadratic form

Let 2 #s that mult to3

6

–13& add to

–4 –9

Solve by Factoring1. (4u – 9)(u – 1) = 0

(2x – 3)(2x + 3)(x + 1)(x – 1) = 0

2x – 3 = 0 2x + 3 = 0 x + 1 = 0 x – 1 = 0

Now replace u with

4 Answers!!

Highest Power is 4!!

Solve by Factoring2.

u(u + 8) – 1(u + 8) = 0

(u – 1)(u + 8) = 0

Let

2 #s that mult to–8

7& add to

8 –1

Solve by Factoring2. (u – 1)(u + 8) = 0

1

Now replace u with

Solve by completing the square!

Diff & Sum of Cubes!

1 11

Solve by Factoring2.

x – 1 =

x = x = 6 Answers!!

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Solve by Factoring3.

2u(u + 3) + 1(u + 3) = 0

(2u + 1)(u + 3) = 0

Let

2 #s that mult to6

7& add to

6 1

Solve by Factoring3. (2u + 1)(u + 3) = 0

2 = –x 1 = –3x

Now replace u with

2 Answers!!

Solve by Factoring4.

u(u – 7) + 9(u – 7) = 0

(u – 7)(u + 9) = 0

Let

2 #s that mult to–63

2& add to

–7 9

Solve by Factoring4. (u – 7)(u + 9) = 0

((x – 4) – 7)((x – 4) + 9) = 0

(x – 11)(x + 5) = 0

x – 11 = 0 x + 5 = 0

{– 5, 11}

Now replace u with

2 Answers!!

Highest Power is 2!!

Solve by Factoring5.

(u – 4) (u + 4) = 0

(

(x – 2)(x + 2)() = 0

Let

Diff of Squares

Replace u with

x =

Solve by Factoring6.

2u(2u + 7) + 5(2u + 7) = 0

(2u + 7)(2u + 5) = 0

Let

2 #s that mult to14

0

24& add to

14

10

Solve by Factoring6. (2u + 7)(2u + 5) = 0

(2(3x – 2) + 7)(2(3x – 2) + 5) = 0

(6x – 4 + 7)(6x – 4 + 5) = 0

(6x + 3)(6x + 1) = 0

6x + 3 = 0 6x + 1 = 0

Replace u with

Solve by Factoring7.

3(5u(4u – 9) – 1(4u – 9) = 0

3(4u – 9)(5u – 1) = 0

Make = 0 first

Factor out GCF!

Let

2 #s that mult to180

–49& add to

–45 –4

Solve by Factoring7. 3(4u – 9)(5u – 1) = 0

3(2x – 3)(2x + 3)(5) = 0

2x – 3 = 0 2x + 3 = 0 5

Now replace u with

5

=

=

x =

Ticket Out the Door

Solve

Homework

#210 Pg. 128 #12, 24, 36, 37 – 51 odd, WS # 8 – 10