• • • • • • 3 4 · 3 4 . (-2) (-2) (-2) . 2 4 2 4 2 · 2 · 2 · 2 a m th
OpenStax-CNX module: m60215 1
Use Multiplication Properties of
Exponents*
OpenStax
This work is produced by OpenStax-CNX and licensed under the
Creative Commons Attribution License 4.0�
Abstract
By the end of this section, you will be able to:
• Simplify expressions with exponents
• Simplify expressions using the Product Property for Exponents
• Simplify expressions using the Power Property for Exponents
• Simplify expressions using the Product to a Power Property
• Simplify expressions by applying several properties
• Multiply monomials
note: Before you get started, take this readiness quiz.
1.Simplify: 34 ·
34 .
If you missed this problem, review .2.Simplify: (−2) (−2) (−2) .If you missed this problem, review .
1 Simplify Expressions with Exponents
Remember that an exponent indicates repeated multiplication of the same quantity. For example, 24 meansto multiply 2 by itself 4 times, so 24 means 2 · 2 · 2 · 2.
Let's review the vocabulary for expressions with exponents.
note:
This is read a to the mth power.
*Version 1.2: Jan 18, 2017 12:45 pm -0600�http://creativecommons.org/licenses/by/4.0/
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In the expression am, the exponentm tells us how many times we use the basea as a factor.
Before we begin working with variable expressions containing exponents, let's simplify a few expressionsinvolving only numbers.
Example 1
Simplify: a43b71c(56
)2d(0.63)
2.
Solution : Solutiona
43
Multiply three factors of 4. 4 · 4 · 4Simplify. 64
b
71
Multiply one factor of 7. 7
c (56
)2Multiply two factors.
(56
) (56
)Simplify. 25
36
d
(0.63)2
Multiply two factors. (0.63) (0.63)
Simplify. 0.3969
note:
Exercise 2 (Solution on p. 21.)
Simplify: a63b151c(37
)2d(0.43)
2.
note:
Exercise 3 (Solution on p. 21.)
Simplify: a25b211c(25
)3d(0.218)
2.
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Example 2Simplify: a(−5)4b−54.
Solution : Solution
1. a
(−5)4
Multiply four factors of − 5. (−5) (−5) (−5) (−5)Simplify. 625
2. b
−54
Multiply four factors of 5. − (5 · 5 · 5 · 5)Simplify. − 625
note:
Exercise 5 (Solution on p. 21.)
Simplify: a(−3)4b−34.
note:
Exercise 6 (Solution on p. 21.)
Simplify: a(−13)2b−132.
Notice the similarities and di�erences in Example 2a and Example 2b! Why are the answers di�erent? Aswe follow the order of operations in part a the parentheses tell us to raise the (−5) to the 4th power. In partb we raise just the 5 to the 4th power and then take the opposite.
2 Simplify Expressions Using the Product Property for Exponents
You have seen that when you combine like terms by adding and subtracting, you need to have the same basewith the same exponent. But when you multiply and divide, the exponents may be di�erent, and sometimesthe bases may be di�erent, too.
We'll derive the properties of exponents by looking for patterns in several examples.First, we will look at an example that leads to the Product Property.
What does this mean?How many factors altogether?
So, we have
Notice that 5 is the sum of the exponents, 2 and 3.
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Table 1
We write:
x2 · x3
x2+3
x5
(1)
The base stayed the same and we added the exponents. This leads to the Product Property for Expo-nents.
note: If a is a real number, and m and n are counting numbers, then
am · an = am+n (2)
To multiply with like bases, add the exponents.
An example with numbers helps to verify this property.
22 · 23 ?= 22+3
4 · 8 ?= 25
32 = 32X
(3)
Example 3Simplify: y5 · y6.
Solution : Solution
Use the product property, am · an = am+n.
Simplify.
Table 2
note: Exercise 8 (Solution on p. 21.)
Simplify: b9 · b8.
note:
Exercise 9 (Solution on p. 21.)
Simplify: x12 · x4.
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Example 4Simplify: a25 · 29b3 · 34.
Solution : Solution
1. a
Use the product property, am · an = am+n.
Simplify.
Table 3
2. b
Use the product property, am · an = am+n.
Simplify.
Table 4
note: Exercise 11 (Solution on p. 21.)
Simplify: a5 · 55b49 · 49.
note:
Exercise 12 (Solution on p. 21.)
Simplify: a76 · 78b10 · 1010.
Example 5Simplify: aa7 · abx27 · x13.
Solution : Solution
1. a
Rewrite, a = a1.
Use the product property, am · an = am+n.
Simplify.
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Table 5
2. b
Notice, the bases are the same, so add the exponents.
Simplify.
Table 6
note: Exercise 14 (Solution on p. 21.)
Simplify: ap5 · pby14 · y29.
note:
Exercise 15 (Solution on p. 21.)
Simplify: az · z7bb15 · b34.
We can extend the Product Property for Exponents to more than two factors.
Example 6Simplify: d4 · d5 · d2.
Solution : Solution
Add the exponents, since bases are the same.
Simplify.
Table 7
note: Exercise 17 (Solution on p. 21.)
Simplify: x6 · x4 · x8.
note:
Exercise 18 (Solution on p. 21.)
Simplify: b5 · b9 · b5.
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3 Simplify Expressions Using the Power Property for Exponents
Now let's look at an exponential expression that contains a power raised to a power. See if you can discovera general property.
What does this mean?How many factors altogether?
So we have
Notice that 6 is the product of the exponents, 2 and3.
Table 8
We write:
(x2
)3x2·3
x6
(4)
We multiplied the exponents. This leads to the Power Property for Exponents.
note: If a is a real number, and m and n are whole numbers, then
(am)n= am·n (5)
To raise a power to a power, multiply the exponents.
An example with numbers helps to verify this property.
(32)3 ?
= 32·3
(9)3 ?
= 36
729 = 729X
(6)
Example 7
Simplify: a(y5)9b(44)7.
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Solution : Solutiona
Use the power property, (am)n = am·n.
Simplify.
Table 9
b
Use the power property.
Simplify.
Table 10
note: Exercise 20 (Solution on p. 21.)
Simplify: a(b7)5b(54)3.
note:
Exercise 21 (Solution on p. 21.)
Simplify: a(z6)9b(37)7.
4 Simplify Expressions Using the Product to a Power Property
We will now look at an expression containing a product that is raised to a power. Can you �nd this pattern?
(2x)3
What does this mean? 2x · 2x · 2xWe group the like factors together. 2 · 2 · 2 · x · x · xHow many factors of 2 and of x? 23 · x3
Notice that each factor was raised to the power and (2x)3is 23 · x3.
We write: (2x)3
23 · x3
The exponent applies to each of the factors! This leads to the Product to a Power Property forExponents.
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note: If a and b are real numbers and m is a whole number, then
(ab)m
= ambm (7)
To raise a product to a power, raise each factor to that power.
An example with numbers helps to verify this property:
(2 · 3)2 ?= 22 · 32
62?= 4 · 9
36 = 36X
(8)
Example 8Simplify: a(−9d)2b(3mn)
3.
Solution : Solution
1. a
Use Power of a Product Property, (ab)m = ambm.
Simplify.
Table 11
2. b
Use Power of a Product Property, (ab)m = ambm.
Simplify.
Table 12
note: Exercise 23 (Solution on p. 21.)
Simplify: a(−12y)2b(2wx)5.
note:
Exercise 24 (Solution on p. 21.)
Simplify: a(5wx)3b(−3y)3.
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5 Simplify Expressions by Applying Several Properties
We now have three properties for multiplying expressions with exponents. Let's summarize them and thenwe'll do some examples that use more than one of the properties.
note: If a and b are real numbers, and m and n are whole numbers, then
Product Property am · an = am+n
Power Property (am)n
= am·n
Product to a Power (ab)m
= ambm
All exponent properties hold true for any real numbers m and n. Right now, we only use whole numberexponents.
Example 9
Simplify: a(y3)6(
y5)4b(−6x4y5
)2.
Solution : Solution
1. a (y3)6(
y5)4
Use the Power Property. y15 · y20
Add the exponents. y35
2. b (−6x4y5
)2Use the Product to a Power Property. (−6)2
(x4
)2(y5)2
Use the Power Property. (−6)2(x8
) (y10
)Simplify. 36x8y10
note:
Exercise 26 (Solution on p. 21.)
Simplify: a(a4)5(
a7)4b(−2c4d2
)3.
note:
Exercise 27 (Solution on p. 21.)
Simplify: a(−3x6y7
)4b(q4)5(
q3)3.
Example 10
Simplify: a(5m)2 (
3m3)b(3x2y
)4(2xy2
)3.
Solution : Solution
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1. a
(5m)2 (
3m3)
Raise 5m to the second power. 52m2 · 3m3
Simplify. 25m2 · 3m3
Use the Commutative Property. 25 · 3 ·m2 ·m3
Multiply the constants and add the exponents. 75m5
2. b (3x2y
)4(2xy2
)3Use the Product to a Power Property.
(34x8y4
) (23x3y6
)Simplify.
(81x8y4
) (8x3y6
)Use the Commutative Property. 81 · 8 · x8 · x3 · y4 · y6
Multiply the constants and add the exponents. 648x11y10
note:
Exercise 29 (Solution on p. 21.)
Simplify: a(5n)2 (
3n10)b(c4d2
)5(3cd5
)4.
note:
Exercise 30 (Solution on p. 21.)
Simplify: a(a3b2
)6(4ab3
)4b(2x)
3 (5x7
).
6 Multiply Monomials
Since amonomial is an algebraic expression, we can use the properties of exponents to multiply monomials.
Example 11Multiply:
(3x2
) (−4x3
).
Solution : Solution (3x2
) (−4x3
)Use the Commutative Property to rearrange the terms. 3 · (−4) · x2 · x3
Multiply. −12x5
note:
Exercise 32 (Solution on p. 21.)
Multiply:(5y7
) (−7y4
).
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note:
Exercise 33 (Solution on p. 21.)
Multiply:(−6b4
) (−9b5
).
Example 12Multiply:
(56x
3y) (
12xy2).
Solution : Solution (56x
3y) (
12xy2)
Use the Commutative Property to rearrange the terms. 56 · 12 · x
3 · x · y · y2
Multiply. 10x4y3
note:
Exercise 35 (Solution on p. 21.)
Multiply:(25a
4b3) (
15ab3).
note:
Exercise 36 (Solution on p. 21.)
Multiply:(23r
5s) (
12r6s7).
note: Access these online resources for additional instruction and practice with using multiplica-tion properties of exponents:
• Multiplication Properties of Exponents1
7 Key Concepts
� Exponential Notation
� Properties of Exponents
◦ If a, b are real numbers and m,n are whole numbers, then
Product Property am · an = am+n
Power Property (am)n
= am·n
Product to a Power (ab)m
= ambm
1https://openstax.org/l/25MultiPropExp
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8
8.1 Practice Makes Perfect
Simplify Expressions with ExponentsIn the following exercises, simplify each expression with exponents.
Exercise 37
a 35
b 91
c(13
)2d (0.2)
4
Exercise 38 (Solution on p. 21.)
a 104
b 171
c(29
)2d (0.5)
3
Exercise 39
a 26
b 141
c(25
)3d (0.7)
2
Exercise 40 (Solution on p. 22.)
a 83
b 81
c(34
)3d (0.4)
3
Exercise 41
a (−6)4b −64
Exercise 42 (Solution on p. 22.)
a (−2)6b −26
Exercise 43
a −(14
)4b(− 1
4
)4Exercise 44 (Solution on p. 22.)
a −(23
)2b(− 2
3
)2
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Exercise 45
a −0.52b (−0.5)2
Exercise 46 (Solution on p. 22.)
a −0.14b (−0.1)4
Simplify Expressions Using the Product Property for ExponentsIn the following exercises, simplify each expression using the Product Property for Exponents.
Exercise 47d3 · d6
Exercise 48 (Solution on p. 22.)
x4 · x2
Exercise 49n19 · n12
Exercise 50 (Solution on p. 22.)
q27 · q15
Exercise 51a 45 · 49 b 89 · 8
Exercise 52 (Solution on p. 22.)
a 310 · 36 b 5 · 54
Exercise 53a y · y3 b z25 · z8
Exercise 54 (Solution on p. 22.)
a w5 · w b u41 · u53
Exercise 55w · w2 · w3
Exercise 56 (Solution on p. 22.)
y · y3 · y5
Exercise 57a4 · a3 · a9
Exercise 58 (Solution on p. 22.)
c5 · c11 · c2
Exercise 59mx ·m3
Exercise 60 (Solution on p. 22.)
ny · n2
Exercise 61ya · yb
Exercise 62 (Solution on p. 22.)
xp · xq
Simplify Expressions Using the Power Property for ExponentsIn the following exercises, simplify each expression using the Power Property for Exponents.
Exercise 63a(m4
)2b(103
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Exercise 64 (Solution on p. 22.)
a(b2)7
b(38)2
Exercise 65a(y3)x
b (5x)y
Exercise 66 (Solution on p. 22.)
a(x2
)yb (7a)
b
Simplify Expressions Using the Product to a Power PropertyIn the following exercises, simplify each expression using the Product to a Power Property.
Exercise 67a (6a)
2b (3xy)
2
Exercise 68 (Solution on p. 22.)
a (5x)2b (4ab)
2
Exercise 69a (−4m)
3b (5ab)
3
Exercise 70 (Solution on p. 22.)
a (−7n)3 b (3xyz)4
Simplify Expressions by Applying Several PropertiesIn the following exercises, simplify each expression.
Exercise 71
a(y2)4 · (y3)2
b(10a2b
)3Exercise 72 (Solution on p. 22.)
a(w4
)3 · (w5)2
b(2xy4
)5Exercise 73
a(−2r3s2
)4b(m5
)3 · (m9)4
Exercise 74 (Solution on p. 22.)
a(−10q2p4
)3b(n3
)10 · (n5)2
Exercise 75
a (3x)2(5x)
b(5t2
)3(3t)
2
Exercise 76 (Solution on p. 22.)
a (2y)3(6y)
b(10k4
)3(5k6
)2
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Exercise 77
a (5a)2(2a)
3
b(12y
2)3( 2
3y)2
Exercise 78 (Solution on p. 22.)
a (4b)2(3b)
3
b(12j
2)5( 2
5j3)2
Exercise 79
a(25x
2y)3
b(89xy
4)2
Exercise 80 (Solution on p. 22.)
a(2r2
)3(4r)
2
b(3x3
)3(x5
)4Exercise 81
a(m2n
)2(2mn5
)4b(3pq4
)2(6p6q
)2Multiply Monomials
In the following exercises, multiply the monomials.
Exercise 82 (Solution on p. 22.)(6y7
) (−3y4
)Exercise 83(−10x5
) (−3x3
)Exercise 84 (Solution on p. 22.)(−8u6
)(−9u)
Exercise 85(−6c4
)(−12c)
Exercise 86 (Solution on p. 22.)(15f
8) (
20f3)
Exercise 87(14d
5) (
36d2)
Exercise 88 (Solution on p. 23.)(4a3b
) (9a2b6
)Exercise 89(
6m4n3) (
7mn5)
Exercise 90 (Solution on p. 23.)(47rs
2) (
14rs3)
Exercise 91(58x
3y) (
24x5y)
Exercise 92 (Solution on p. 23.)(23x
2y) (
34xy
2)
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Exercise 93(35m
3n2) (
59m
2n3)
Mixed PracticeIn the following exercises, simplify each expression.
Exercise 94 (Solution on p. 23.)(x2
)4 · (x3)2
Exercise 95(y4)3 · (y5)2
Exercise 96 (Solution on p. 23.)(a2)6 · (a3)8
Exercise 97(b7)5 · (b2)6
Exercise 98 (Solution on p. 23.)(2m6
)3Exercise 99(
3y2)4
Exercise 100 (Solution on p. 23.)(10x2y
)3Exercise 101(
2mn4)5
Exercise 102 (Solution on p. 23.)(−2a3b2
)4Exercise 103(−10u2v4
)3Exercise 104 (Solution on p. 23.)(
23x
2y)3
Exercise 105(79pq
4)2
Exercise 106 (Solution on p. 23.)(8a3
)2(2a)
4
Exercise 107(5r2
)3(3r)
2
Exercise 108 (Solution on p. 23.)(10p4
)3(5p6
)2Exercise 109(
4x3)3(
2x5)4
Exercise 110 (Solution on p. 23.)(12x
2y3)4(
4x5y3)2
Exercise 111(13m
3n2)4(
9m8n3)2
Exercise 112 (Solution on p. 23.)(3m2n
)2(2mn5
)4Exercise 113(
2pq4)3(
5p6q)2
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8.2 Everyday Math
Exercise 114 (Solution on p. 23.)
Email Kate emails a �yer to ten of her friends and tells them to forward it to ten of their friends,who forward it to ten of their friends, and so on. The number of people who receive the email onthe second round is 102, on the third round is 103, as shown in the table below. How many peoplewill receive the email on the sixth round? Simplify the expression to show the number of peoplewho receive the email.
Round Number of people
1 10
2 102
3 103
. . . . . .
6 ?
Table 13
Exercise 115Salary Jamal's boss gives him a 3% raise every year on his birthday. This means that each year,Jamal's salary is 1.03 times his last year's salary. If his original salary was $35,000, his salary after1 year was $35, 000 (1.03), after 2 years was $35, 000(1.03)
2, after 3 years was $35, 000(1.03)
3, as
shown in the table below. What will Jamal's salary be after 10 years? Simplify the expression, toshow Jamal's salary in dollars.
Year Salary
1 $35, 000 (1.03)
2 $35, 000(1.03)2
3 $35, 000(1.03)3
. . . . . .
10 ?
Table 14
Exercise 116 (Solution on p. 23.)
Clearance A department store is clearing out merchandise in order to make room for new inven-tory. The plan is to mark down items by 30% each week. This means that each week the cost ofan item is 70% of the previous week's cost. If the original cost of a sofa was $1,000, the cost forthe �rst week would be $1, 000 (0.70) and the cost of the item during the second week would be
$1, 000(0.70)2. Complete the table shown below. What will be the cost of the sofa during the �fth
week? Simplify the expression, to show the cost in dollars.
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Week Cost
1 $1, 000 (0.70)
2 $1, 000(0.70)2
3
. . . . . .
8 ?
Table 15
Exercise 117Depreciation Once a new car is driven away from the dealer, it begins to lose value. Each year,a car loses 10% of its value. This means that each year the value of a car is 90% of the previousyear's value. If a new car was purchased for $20,000, the value at the end of the �rst year would be$20, 000 (0.90) and the value of the car after the end of the second year would be $20, 000(0.90)
2.
Complete the table shown below. What will be the value of the car at the end of the eighth year?Simplify the expression, to show the value in dollars.
Week Cost
1 $20, 000 (0.90)
2 $20, 000(0.90)2
3
4 . . .
5 ?
Table 16
8.3 Writing Exercises
Exercise 118 (Solution on p. 23.)
Use the Product Property for Exponents to explain why x · x = x2.
Exercise 119Explain why −53 = (−5)3 but −54 6= (−5)4.Exercise 120 (Solution on p. 23.)
Jorge thinks(12
)2is 1. What is wrong with his reasoning?
Exercise 121Explain why x3 · x5 is x8, and not x15.
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8.4 Self Check
a After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.
b Af-ter reviewing this checklist, what will you do to become con�dent for all goals?
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Solutions to Exercises in this Module
Solution to Exercise (p. 2)a 216 b15c 9
49d 0.1849Solution to Exercise (p. 2)a32b 21 c 8
125d0.047524Solution to Exercise (p. 3)a 81 b −81Solution to Exercise (p. 3)a 169 b −169Solution to Exercise (p. 4)b17
Solution to Exercise (p. 4)x16
Solution to Exercise (p. 5)a 56 b 418
Solution to Exercise (p. 5)a 714 b 1011
Solution to Exercise (p. 6)a p6 b y43
Solution to Exercise (p. 6)a z8 b b49
Solution to Exercise (p. 6)x18
Solution to Exercise (p. 6)b19
Solution to Exercise (p. 8)a b35 b 512
Solution to Exercise (p. 8)a z54 b 349
Solution to Exercise (p. 9)a 144y2 b 32w5x5
Solution to Exercise (p. 9)a 125w3x3 b −27y3Solution to Exercise (p. 10)a a48 b −8c12d6Solution to Exercise (p. 10)a 81x24y28 b q29
Solution to Exercise (p. 11)a 75n12 b 81c24d30
Solution to Exercise (p. 11)a 256a22b24 b 40x10
Solution to Exercise (p. 11)−35y11Solution to Exercise (p. 12)54b9
Solution to Exercise (p. 12)6a5b6
Solution to Exercise (p. 12)8r11s8
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Solution to Exercise (p. 13)a 10,000 b 17 c 4
81d 0.125Solution to Exercise (p. 13)a 512 b 8 c 2764d 0.064Solution to Exercise (p. 13)a 64 b−64Solution to Exercise (p. 13)a − 4
9b 4
9Solution to Exercise (p. 14)a−0.001b 0.001Solution to Exercise (p. 14)x6
Solution to Exercise (p. 14)q42
Solution to Exercise (p. 14)a 316 b 55
Solution to Exercise (p. 14)a w6 b u94
Solution to Exercise (p. 14)y9
Solution to Exercise (p. 14)c18
Solution to Exercise (p. 14)ny+2
Solution to Exercise (p. 14)xp+q
Solution to Exercise (p. 15)a b14 b 316
Solution to Exercise (p. 15)a x2y b 7ab
Solution to Exercise (p. 15)a 25x2 b 16a2b2
Solution to Exercise (p. 15)a −343n3 b 81x4y4z4
Solution to Exercise (p. 15)a w22 b 32x5y20
Solution to Exercise (p. 15)a −1000q6p12 b n40
Solution to Exercise (p. 15)a 48y4 b 25, 000k24
Solution to Exercise (p. 16)a 432b5 b 1
200j16
Solution to Exercise (p. 16)a 128r8 b 1
200j16
Solution to Exercise (p. 16)−18y11Solution to Exercise (p. 16)72u7
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Solution to Exercise (p. 16)4f11
Solution to Exercise (p. 16)36a5b7
Solution to Exercise (p. 16)8r2s5
Solution to Exercise (p. 16)12x
3y3
Solution to Exercise (p. 17)x14
Solution to Exercise (p. 17)a36
Solution to Exercise (p. 17)8m18
Solution to Exercise (p. 17)1000x6y3
Solution to Exercise (p. 17)16a12b8
Solution to Exercise (p. 17)827x
6y3
Solution to Exercise (p. 17)1024a10
Solution to Exercise (p. 17)25000p24
Solution to Exercise (p. 17)x18y18
Solution to Exercise (p. 17)144m8n22
Solution to Exercise (p. 18)1, 000, 000Solution to Exercise (p. 18)$168.07Solution to Exercise (p. 19)Answers will vary.Solution to Exercise (p. 19)Answers will vary.
http://cnx.org/content/m60215/1.2/