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Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles
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Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Jan 02, 2016

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Page 1: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Unit 8 – Right Triangle TrigTrigonometric Ratios

in Right Triangles

Page 2: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Trigonometric Ratios are based on the Concept of Similar Triangles!

Page 3: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

All 45º- 45º- 90º Triangles are Similar!

45 º

2

2

22

45 º

1

1

2

45 º

1

2

1

2

1

Page 4: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

All 30º- 60º- 90º Triangles are Similar!

1

60º

30º

½

23

32

60º

30º

2

4

2

60º

30º

1

3

Page 5: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

hypotenuse

leg

leg

a

b

c

Trigonometric functions -- the ratios of sides of a right triangle.

Similar Triangles Always Have the Same Trig Ratio Answers!

SINECOSINE

TANGENT

They are abbreviated using their first 3 letters

c

a

hypotenuse

oppositesin

oppositec

b

hypotenuse

adjacentcos

adjacent

b

a

adjacent

oppositetan

Page 6: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

This method only applies if you have a right triangle and is only for the acute angles (angles less than 90°) in the triangle.

3

45

Oh, I'm

acute!

So am I!

Page 7: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

a

b

c

Here is a mnemonic to help you memorize the ratios.

SOHCAHTOA

c

b

hypotenuse

oppositesin

adjacentcos

hypotenuse

a

c opposite

tanadjacent

b

a

opposite

adjacent

SOHCAHTOA

Page 8: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

It is important to note WHICH angle you are talking about when you find the value of the trig function.

a

bc

Let's try finding some trig functions with some numbers.

3

45

sin = Use a mnemonic and figure out which sides of the triangle you need for sine.

h

o5

3

opposite

hypotenuse

tan =

a

o3

4

opposite

adjacent

Use a mnemonic and figure out which sides of the triangle you need for tangent.

Page 9: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

a

bc

How do the trig answers for and

relate to each other?

3

45opposite

hypotenuse

opposite

adjacent

Page 10: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Find the sine, the cosine, and the tangent of angle A.

Give a fraction and decimal answer (round to 4 places).

hyp

oppA sin

8.10

9 8333.

hyp

adjA cos

8.10

6 5556.

adj

oppA tan

6

9 5.1

9

6

10.8

A

Now, figure out your ratios.

Page 11: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

1.9 cm

7.7 cm

14º

1.9

7.7Tangent 14º

0.25

The Tangent of an angle is the ratio of the opposite side of a triangle to its adjacent side.

oppositeadjacent

hypotenuse

Page 12: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

3.2 cm

7.2 cm24º

3.2

7.2

Tangent 24º

0.45

Tangent A =

opposite

adjacent

Page 13: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

As an acute angle of a triangle approaches 90º, its tangent

becomes infinitely large

Tan 89.9º = 573

Tan 89.99º = 5,730

Tangent A =

opposite

adjacent

etc.

very large

very small

Page 14: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Since the sine and cosine functions alwayshave the hypotenuse as the denominator,

and since the hypotenuse is the longest side,these two functions will always be less than 1.

Sine A =

opposite

hypotenuse

Cosine A =

adjacent

hypotenuse

ASine 89º = .9998

Sine 89.9º = .999998

Page 15: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

3.2 cm7.9 cm

24º

9.7

2.3

Sin 24º

0.41

Sin α = hypotenuse

opposite

Page 16: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

5.5 cm

7.9 cm

46º

9.7

5.5

Cos 46º

0.70

Cosine β = hypotenuse

adjacent

Page 17: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Ex. Solve for a missing value using a trig function.

5520 m

x

20

55tanx

m 6.28x

x55tan20tan 20 55 )

Now, figure out which trig ratio you have and set up the problem.

Page 18: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Ex: 2 Find the missing side. Round to the nearest tenth.

72

80 ft

x

x

8072tan

ft 26x

8072tan x

72tan

80x

tan 80 72 = ( ) )

Now, figure out which trig ratio you have and set up the problem.

Page 19: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Ex: 3 Find the missing side. Round to the nearest tenth.

24

283 mx 283

24sinx

m 1.115x

x24sin283

Now, figure out which trig ratio you have and set up the problem.

Page 20: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Ex: 4 Find the missing side. Round to the nearest tenth.

4020 ft x

2040cos

x

ft 3.15x

x40cos20

Page 21: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Finding an angle.(Figuring out which ratio to use and getting

to use the 2nd button and one of the trig buttons.)

Page 22: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Ex. 1: Find . Round to four decimal places.

9

17.2

Make sure you are in degree mode (not radians).

9

2.17tan

2nd tan 17.2 9

3789.62

)

Now, figure out which trig ratio you have and set up the problem.

Page 23: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Ex. 2: Find . Round to three decimal places.

23

7

Make sure you are in degree mode (not radians).

23

7cos

2nd cos 7 23

281.72

)

Page 24: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Ex. 3: Find . Round to three decimal places.

400

200

Make sure you are in degree mode (not radians).

400

200sin

2nd sin 200 400

30)

Page 25: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

When we are trying to find a sidewe use sin, cos, or tan.

When we are trying to find an

angle we use sin-1, cos-1, or tan-1.

Page 26: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

A plane takes off from an airport an an angle of 18º and a speed of 240 mph. Continuing at this speed and angle,

what is the altitude of the plane after 1 minute?

18º

x

After 60 sec., at 240 mph, the plane has traveled 4 miles

4

Page 27: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

18º

x4

opposite

hypotenuse

SohCahToa

Sine A =

opposite

hypotenuse Sine 18 =

x

4

0.3090 =

x

4

x = 1.236 milesor

6,526 feet

1

Soh

Page 28: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

An explorer is standing 14.3 miles from the base of Mount Everest below its highest peak. His angle of

elevation to the peak is 21º. What is the number of feet from the base of Mount Everest to its peak?

21º14.3

x

Tan 21 =

x

14.30.3839 =

x

14.3

x = 5.49 miles = 29,000 feet

1

Page 29: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

A swimmer sees the top of a lighthouse on the edge of shore at an 18º angle. The lighthouse is

150 feet high. What is the number of feet from theswimmer to the shore?

18º

150

Tan 18 =

x

150

x

0.3249 =

150

x

0.3249x = 150

0.3249 0.3249

X = 461.7 ft1

Page 30: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

A dragon sits atop a castle 60 feet high. An archer stands 120 feet from the point on the ground directly

below the dragon. At what angle does the archer need to aim his arrow to slay the dragon?

x

60

120

Tan x =

60

120Tan x = 0.5

Tan-1(0.5) = 26.6º

Page 31: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Solving a Problem withthe Tangent Ratio

60º

53 ft

h = ?

We know the angle and the We know the angle and the side adjacent to 60º. We want to side adjacent to 60º. We want to know the opposite side. Use theknow the opposite side. Use thetangent ratio:tangent ratio:

ft 92353

531

3

5360tan

h

h

h

adj

opp

1

23

Why?

Page 32: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

A surveyor is standing 50 feet from the base of a large tree. The surveyor measures the angle of elevation to the top of the tree as 71.5°. How tall is the tree?

50

71.5°

?

tan 71.5°

tan 71.5° 50

y

y = 50 (tan 71.5°)

y = 50 (2.98868)

149.4y ft

Ex.

Opp

Hyp

Page 33: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

A person is 200 yards from a river. Rather than walk directly to the river, the person walks along a straight path to the river’s edge at a 60° angle. How far must the person walk to reach the river’s edge?

200

x

Ex. 5

60°

cos 60°

x (cos 60°) = 200

x

X = 400 yards

Page 34: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Trigonometric Functions on a Rectangular Coordinate System

x

y

Pick a point on theterminal ray and drop a perpendicular to the x-axis.

ry

x

The adjacent side is xThe opposite side is yThe hypotenuse is labeled rThis is called a REFERENCE TRIANGLE.

y

x

x

yx

r

r

x

y

r

r

y

cottan

seccos

cscsin

Page 35: Unit 8 – Right Triangle Trig Trigonometric Ratios in Right Triangles.

Trigonometric Ratios may be found by:

45 º

1

1

2Using ratios of special trianglesUsing ratios of special triangles

145tan2

145cos

2

145sin

For angles other than 45º, 30º, 60º you will need to use a For angles other than 45º, 30º, 60º you will need to use a calculator. (Set it in Degree Mode for now.)calculator. (Set it in Degree Mode for now.)