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Unit 1-3 Unit 1-3 Review Review 1
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Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Dec 18, 2015

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Page 1: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Unit 1-3 Unit 1-3 ReviewReview

11

Page 2: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Mass = 4 kg, acceleration = 5m/sMass = 4 kg, acceleration = 5m/s2 2 → →

Find the weight - FFind the weight - Fgg (N) (N)

22

Ft = 50N

Page 3: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Mass = 4 kg, acceleration = 5 m/sMass = 4 kg, acceleration = 5 m/s22

FFgg = 40 N = 40 N

What is the normal Force?What is the normal Force?

33

Ft = 50N

Page 4: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Mass = 4 kg, acceleration = 5 m/sMass = 4 kg, acceleration = 5 m/s22

FFgg = 40 N = 40 N

What is the net Force?What is the net Force?

44

Ft = 50N

Page 5: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Mass = 4 kg, acceleration = 5 m/sMass = 4 kg, acceleration = 5 m/s22

FFgg = 40 N, F = 40 N, Fnetnet = 20 N = 20 N

What is the frictional Force?What is the frictional Force?

55

Ft = 50N

Page 6: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Mass = 4 kg, acceleration = 5 m/sMass = 4 kg, acceleration = 5 m/s22

FFgg = 40 N, F = 40 N, Fnetnet = 20 N, F = 20 N, Fff = 30N = 30N

What is µ?What is µ?

66

Ft = 50N

Page 7: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

22ndnd and 3 and 3rdrd Law LawCannon and CannonballCannon and Cannonball

F = FF = F

MMa = ma = mAA77

Page 8: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Velocity is to speed as Velocity is to speed as displacement is to displacement is to

(A) acceleration (A) acceleration (B) momentum(B) momentum(C) time (C) time (D) distance(D) distance

Page 9: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

99

Convert 50.1 km to m Convert 50.1 km to m

Page 10: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

1010

An airplane travels at an average speed An airplane travels at an average speed of 400 mile/hour. How many hours will of 400 mile/hour. How many hours will

it take the plane to fly 1200 miles?it take the plane to fly 1200 miles?

Page 11: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

1111

A car accelerates from a position of A car accelerates from a position of rest to 50 m/s in 20 seconds. rest to 50 m/s in 20 seconds.

Determine the rate of acceleration in Determine the rate of acceleration in m/sm/s22

Page 12: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

1212

A car accelerates from a position of A car accelerates from a position of rest to 50 m/s in 20 seconds. rest to 50 m/s in 20 seconds.

Determine the rate of acceleration in Determine the rate of acceleration in 2.5 m/s2.5 m/s2 2

Calculate the speed (m/s) of the car Calculate the speed (m/s) of the car at the end of the first 6 seconds.at the end of the first 6 seconds.

Page 13: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

The diagram shows a resultant vector, The diagram shows a resultant vector, R. Which diagram best represents R. Which diagram best represents a pair of component vectors, A and B, that a pair of component vectors, A and B, that would combine to form resultant vector R?would combine to form resultant vector R?

Page 14: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A person is standing on a bathroom scale A person is standing on a bathroom scale in an elevator car. If the scale reads a in an elevator car. If the scale reads a value greater than the weight of the value greater than the weight of the person at rest, the elevator car could be person at rest, the elevator car could be movingmoving(A) downward at constant speed(A) downward at constant speed(B) upward at constant speed(B) upward at constant speed(C) downward at increasing speed(C) downward at increasing speed(D) upward at increasing speed(D) upward at increasing speed

Page 15: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

The diagram represents the path of an object The diagram represents the path of an object after it was thrown. What happens to the after it was thrown. What happens to the object’s acceleration as itobject’s acceleration as ittravels from travels from A A to to BB? ? (A) It decreases.(A) It decreases.(B) It increases.(B) It increases.(C) It remains the same.(C) It remains the same.

Page 16: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A 0.2-kg red ball is thrown horizontally at a A 0.2-kg red ball is thrown horizontally at a speed of 4 m/s from a height of 3 meters. A 0.4-speed of 4 m/s from a height of 3 meters. A 0.4-kgkg green ball is thrown horizontally from the green ball is thrown horizontally from the same height at a speed of 8 m/s. Compared to same height at a speed of 8 m/s. Compared to the time it takes the red ball to reach the ground, the time it takes the red ball to reach the ground, the time it takes the green ball to reach the the time it takes the green ball to reach the ground isground is

(A) one-half as great (A) one-half as great (B) the same(B) the same(C) twice as great (C) twice as great (D) four times as great(D) four times as great

Page 17: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

The acceleration due to gravity on the surface The acceleration due to gravity on the surface of planet of planet X X is 19.6 m/sis 19.6 m/s22. If an object on the . If an object on the surface of this planet weighs 980 Newtons, the surface of this planet weighs 980 Newtons, the mass of the object in kilograms ismass of the object in kilograms is

Page 18: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

The acceleration due to gravity on the surface The acceleration due to gravity on the surface of planet of planet X X is 19.6 m/sis 19.6 m/s22. How far will an . How far will an object fall in 3 seconds?object fall in 3 seconds?

Page 19: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A basketball player jumped straight up to grab A basketball player jumped straight up to grab a rebound. If she was in the air for 0.80 a rebound. If she was in the air for 0.80 second, how long did it take to reach the top of second, how long did it take to reach the top of her jump?her jump?

Page 20: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A basketball player jumped straight up to grab A basketball player jumped straight up to grab a rebound. If she was in the air for 0.80 a rebound. If she was in the air for 0.80 second, how high did she jump?second, how high did she jump?

Page 21: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

The force required to start an object sliding across a The force required to start an object sliding across a uniform horizontal surface is larger than the force uniform horizontal surface is larger than the force required to keep the object sliding at a constant required to keep the object sliding at a constant velocity. The magnitudes of the required forces are velocity. The magnitudes of the required forces are different in these situations because the force of different in these situations because the force of kinetic frictionkinetic friction(A) is greater than the force of static friction(A) is greater than the force of static friction(B) is less than the force of static friction(B) is less than the force of static friction(C) increases as the speed of the object relative to (C) increases as the speed of the object relative to the surface increasesthe surface increases(D) decreases as the speed of the object relative to (D) decreases as the speed of the object relative to the surface increasesthe surface increases

Page 22: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A man is pushing a baby stroller. Compared to A man is pushing a baby stroller. Compared to the magnitude of the force exerted on the the magnitude of the force exerted on the stroller by the man, the magnitude of the force stroller by the man, the magnitude of the force exerted on the man by the stroller isexerted on the man by the stroller is

(A) zero(A) zero(B) smaller, but greater than zero(B) smaller, but greater than zero(C) larger(C) larger(D) the same(D) the same

Page 23: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A constant unbalanced force is applied to an A constant unbalanced force is applied to an object for a period of time. Which graph best object for a period of time. Which graph best represents the acceleration of the object as a represents the acceleration of the object as a function of elapsed time?function of elapsed time?

Page 24: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

The diameter of a United States penny is The diameter of a United States penny is closest toclosest to

(A) 100 m (A) 100 m (B) 10(B) 10–1–1 m m (C) 10(C) 10–2–2 m m(D) 10(D) 10–3–3 m m

Page 25: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

During a 5.0-second interval, an object’s During a 5.0-second interval, an object’s velocity changes from 25 meters per velocity changes from 25 meters per second east to 15 meters per second east. second east to 15 meters per second east.

Determine the magnitude of the object’s Determine the magnitude of the object’s acceleration in m/sacceleration in m/s22..

Page 26: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A projectile has an initial horizontal velocity of 15 meters per second and an

initial vertical velocity of 25 m/s.

Determine the projectile’s horizontal displacement (in m) if the total time of

flight is 5.0 seconds.

Page 27: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A projectile has an initial horizontal velocity of 15 meters per second and an

initial vertical velocity of 25 m/s.

Determine the maximum height of the projectile (in m) if the total time of flight

is 5.0 seconds.

Page 28: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A net force of 25 Newtons is applied horizontally to a 10-kilogram block resting on a table. What is the magnitude of the acceleration of the block?

(A) 0.0 m/s2 (B) 0.40 m/s2

(C) 0.26 m/s2 (D) 2.5 m/s2

Page 29: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

The speed of a car is increased uniformly from 20 meters per second to 30 meters per second in 4.0 seconds. The magnitude of the car’s average acceleration in this 4.0-second interval is(A) 0.40 m/s2 (B) 10 m/s2

(C) 2.5 m/s2 (D) 13 m/s2

Page 30: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A box is at rest on an inclined plane. Which vector best represents the direction of the normal force acting on the box?(A) A (B) B (C) C (D) D

Page 31: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

If the magnitude of the gravitational force of Earth on the Moon is F, the magnitude of the gravitational force of the Moon on Earth is

(A) smaller than F (B) larger than F (C) equal to F

Page 32: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Which term represents a scalar quantity?

(A) distance(B) force (C) displacement(D) weight

Page 33: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

An apple weighing 1 Newton on the surface of Earth has a mass of approximately

(A) 1×10–1 kg(B) 1×100 kg(C) 1×101 kg (D) 1×102 kg

Page 34: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

In which situation is the net force on the object equal to zero (mechanical equilibrium)?

(A) a satellite moving at constant speed around Earth in a circular orbit(B) an automobile braking to a stop (C) a bicycle moving at constant speed on a straight, level road (D) a pitched baseball being hit by a bat

Page 35: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A 10.0-kilogram mass are held at rest on a frictionless 30.0° incline by force F. What is the approximate magnitude of force F?

(A) 9.81 N(B) 85.0 N (C) 49.1 N(D) 98.1 N

Page 36: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

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The graph shows the velocity of a race car moving along a straight line as a function of time. What is the magnitude of the displacement of the car from t = 2.0 seconds to t = 4.0 seconds?

(A) 20 m(B) 40 m(C) 60 m(D) 80 m

Page 37: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Which vector diagram represents the greatest magnitude of displacement for an object?

Page 38: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A child is flying a kite, K. A student at point B, located 100. meters away from point A (directly underneath the kite), measures the angle of elevation of the kite from the ground as 30°. Determine the height, AK, in meters of the kite.

Page 39: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A child is flying a kite, K. A student at point B, located 100. meters away from point A (directly underneath the kite), measures the angle of elevation of the kite from the ground as 30°. A small lead sphere is dropped from the kite. Calculate the amount of time required for the sphere to fall to the ground.

Page 40: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A car traveling on a straight road at 15.0 m/s accelerates uniformly to a speed of 21.0 m/s in 12.0 seconds. What is the acceleration in m/s2?

Page 41: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A golf ball is hit with an initial velocity of 15 m/s at an angle of 35 degrees above the horizontal. What is the vertical component of the golf ball’s initial velocity in m/s?

Page 42: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

A golf ball is hit with an initial velocity of 15 meters per second at an angle of 35 degrees above the horizontal. What is the horizontal component of the golf ball’s initial velocity?

Page 43: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Goofy the clown is working in Lost Goofy the clown is working in Lost Wages & wants to jump off the top of Wages & wants to jump off the top of the Bellagio which is 155-m tall and the Bellagio which is 155-m tall and land in the pool which is 21-m away land in the pool which is 21-m away from the base of the hotel. from the base of the hotel.

How many seconds will Goofy be How many seconds will Goofy be falling? falling?

Page 44: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

Goofy the clown is working in Lost Wages Goofy the clown is working in Lost Wages & wants to jump off the top of the Bellagio & wants to jump off the top of the Bellagio which is 155-m tall and land in the pool which is 155-m tall and land in the pool which is 21-m away from the base of the which is 21-m away from the base of the hotel.hotel.

t = 5.6 st = 5.6 s

How fast will Goofy need to run (m/s) so How fast will Goofy need to run (m/s) so he does not hit the concrete between the he does not hit the concrete between the hotel and the pool? hotel and the pool?

Page 45: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

4545

•For his next stunt, Goofy wants to For his next stunt, Goofy wants to be shot out of a cannon and land in a be shot out of a cannon and land in a barrel of water. Goofy will leave the barrel of water. Goofy will leave the cannon at 100 m/s at an angle of 45cannon at 100 m/s at an angle of 45oo..

What is Goofy’s vertical velocity as What is Goofy’s vertical velocity as he leaves the cannon?he leaves the cannon?

Page 46: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

4646

For his next stunt, Goofy wants to be For his next stunt, Goofy wants to be shot out of a cannon and land in a shot out of a cannon and land in a barrel of water. Goofy will leave the barrel of water. Goofy will leave the cannon at 100 m/s at an angle of 45cannon at 100 m/s at an angle of 45oo..

vvvv = 70.7 m/s = 70.7 m/s

How many seconds will it take How many seconds will it take Goofy’s to reach his maximum Goofy’s to reach his maximum

height?height?

Page 47: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

4747

For his next stunt, Goofy wants to be For his next stunt, Goofy wants to be shot out of a cannon and land in a shot out of a cannon and land in a barrel of water. Goofy will leave the barrel of water. Goofy will leave the cannon at 100 m/s at an angle of 45cannon at 100 m/s at an angle of 45oo..

vvvv = 70.7 m/s, t = 7.1 s = 70.7 m/s, t = 7.1 s

What is the minimum height for the What is the minimum height for the tent so Goofy does not scrape the tent so Goofy does not scrape the top?top?

Page 48: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

4848

For his next stunt, Goofy wants to be For his next stunt, Goofy wants to be shot out of a cannon and land in a shot out of a cannon and land in a barrel of water. Goofy will leave the barrel of water. Goofy will leave the cannon at 100 m/s at an angle of 45cannon at 100 m/s at an angle of 45oo..

vvvv = 70.7 m/s, t = 7.1 s, y = 250 m = 70.7 m/s, t = 7.1 s, y = 250 m

What is Goofy’s horizontal velocity What is Goofy’s horizontal velocity (m/s) as he leaves the cannon?(m/s) as he leaves the cannon?

Page 49: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

4949

For his next stunt, Goofy wants to be For his next stunt, Goofy wants to be shot out of a cannon and land in a shot out of a cannon and land in a barrel of water. Goofy will leave the barrel of water. Goofy will leave the cannon at 100 m/s at an angle of 45cannon at 100 m/s at an angle of 45oo..

vvvv = 70.7 m/s, t = 7.1 s, y = 250 m = 70.7 m/s, t = 7.1 s, y = 250 m

vvHH = 70.7 m/s = 70.7 m/s

How far from the cannon does the How far from the cannon does the barrel of water need to be placed?barrel of water need to be placed?

Page 50: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5050

In a plane that goes 310 m/s the pilot In a plane that goes 310 m/s the pilot wants to fly directly north when the wants to fly directly north when the wind is blowing at 155 m/s from the wind is blowing at 155 m/s from the east. east.

(a) In what direction must he head the (a) In what direction must he head the plane?plane?

Page 51: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5151

In a plane that goes 310 m/s the pilot In a plane that goes 310 m/s the pilot wants to fly directly north when the wants to fly directly north when the wind is blowing at 155 m/s from the wind is blowing at 155 m/s from the east. east.

(a) In what direction must he head the (a) In what direction must he head the plane?plane?

Angle = 30 degreesAngle = 30 degrees

(b) How fast will the plane be going (b) How fast will the plane be going north?north?

Page 52: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5252

An airplane descending to the runway An airplane descending to the runway at 250 m/s is going at an angle of 22at 250 m/s is going at an angle of 22oo with the horizontal. Find with the horizontal. Find

(a) Its horizontal velocity (m/s)(a) Its horizontal velocity (m/s)

Page 53: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5353

An airplane descending to the runway An airplane descending to the runway at 250 m/s is going at an angle of 22at 250 m/s is going at an angle of 22oo with the horizontal. Find with the horizontal. Find

(a) Its horizontal velocity(a) Its horizontal velocity

vvhh = 232 m/s = 232 m/s

(b) Its vertical velocity(b) Its vertical velocity

..

Page 54: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5454

A rock is thrown horizontally at 25 m/s A rock is thrown horizontally at 25 m/s from a roof that is 75 m high. How from a roof that is 75 m high. How many seconds does it take to hit the many seconds does it take to hit the ground? ground?

Page 55: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5555

A rock is thrown horizontally at 25 m/s A rock is thrown horizontally at 25 m/s from a roof that is 75 m high. How long from a roof that is 75 m high. How long does it take to hit the ground? does it take to hit the ground?

t = 3.9 st = 3.9 s

How far does the rock go horizontally How far does the rock go horizontally before hitting the ground? before hitting the ground?

Page 56: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5656

A football punter kicks a ball at 40 m/s at an A football punter kicks a ball at 40 m/s at an angle of 50angle of 50oo..(a) What is the ball’s initial vertical velocity?(a) What is the ball’s initial vertical velocity?

Page 57: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5757

A football punter kicks a ball at 40 m/s at an A football punter kicks a ball at 40 m/s at an angle of 50angle of 50oo..(a)(a)What is the ball’s initial vertical velocity?What is the ball’s initial vertical velocity?VvVv = 30.6 m/s = 30.6 m/s(b) What is the ball’s initial horizontal velocity? (b) What is the ball’s initial horizontal velocity?

Page 58: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5858

A football punter kicks a ball at 40 m/s at an A football punter kicks a ball at 40 m/s at an angle of 50angle of 50oo..(a)(a)What is the ball’s initial vertical velocity?What is the ball’s initial vertical velocity?VvVv = 30.6 m/s = 30.6 m/s(b)(b)What is the ball’s initial horizontal velocity? What is the ball’s initial horizontal velocity? VhVh = 25.7 m/s = 25.7 m/s(c) How long until it reaches the top of its flight? (c) How long until it reaches the top of its flight?

Page 59: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

5959

A football punter kicks a ball at 40 m/s at an A football punter kicks a ball at 40 m/s at an angle of 50angle of 50oo..(a)(a)What is the ball’s initial vertical velocity?What is the ball’s initial vertical velocity?VvVv = 30.6 m/s = 30.6 m/s(b)(b)What is the ball’s initial horizontal velocity? What is the ball’s initial horizontal velocity? VhVh = 25.7 m/s = 25.7 m/s(c) How long until it reaches the top of its flight? (c) How long until it reaches the top of its flight? t = 3.1 st = 3.1 s(d) How high does it go? (d) How high does it go?

Page 60: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

6060

A football punter kicks a ball at 40 m/s at an A football punter kicks a ball at 40 m/s at an angle of 50angle of 50oo..(a)(a)What is the ball’s initial vertical velocity?What is the ball’s initial vertical velocity?VvVv = 30.6 m/s = 30.6 m/s(b)(b)What is the ball’s initial horizontal velocity? What is the ball’s initial horizontal velocity? VhVh = 25.7 m/s = 25.7 m/s(c) How long until it reaches the top of its flight? (c) How long until it reaches the top of its flight? t = 3.1 st = 3.1 s(d) How high does it go? (d) How high does it go? y = 47my = 47m(e) How long until it hits the ground? (e) How long until it hits the ground?

Page 61: Unit 1-3 Review 1. Mass = 4 kg, acceleration = 5m/s 2 → Find the weight - F g (N) 2 F t = 50N.

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A football punter kicks a ball at 40 m/s at an A football punter kicks a ball at 40 m/s at an angle of 50angle of 50oo..(a)(a)What is the ball’s initial vertical velocity?What is the ball’s initial vertical velocity?VvVv = 30.6 m/s = 30.6 m/s(b)(b)What is the ball’s initial horizontal velocity? What is the ball’s initial horizontal velocity? VhVh = 25.7 m/s = 25.7 m/s(c) How long until it reaches the top of its flight? (c) How long until it reaches the top of its flight? t = 3.1 st = 3.1 s(d) How high does it go? (d) How high does it go? y = 47my = 47m(e) How long until it hits the ground? (e) How long until it hits the ground? t = 6.1 st = 6.1 s(f) What is the total distance that it travels?(f) What is the total distance that it travels?