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TUYỂN TẬP CÁC ĐỀ THI THỬ ĐẠI HỌC TRÊN BÁO TOÁN HỌC TUỔI TRẺ

May 30, 2018

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  • 8/14/2019 TUYN TP CC THI TH I HC TRN BO TON HC TUI TR

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    Tuyn tp cc thi thi hc, cao ng trn tp chTon hc v Tui trqua cc nm

    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    TRNG TRUNG HC PH THNG TH X CAO LNH--------------

    TP TH LP CHUYN TON NIN KHA 2006 2009

    Nguyn c Tun -

    TUYN TP CC THI TH

    I HC , CAO NGTRN TP CH

    QUA CQUA CQUA CQUA CCCCC NNNNMMMM

    ---- Thng 03-2009 ----

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    B GIO DC V O TOTP CH TON HC V TUI TR

    NM2003

    THI THI HC, CAO NG S 1Mn thi: TON

    Thi gian lm bi: 180 phtCu I: (2 im)

    Cho hm s: .424 mxmxxy ++=

    1. Kho st v v th hm s khi .0=m 2. Tm cc gi tr ca m th hm s c ba im cc tr sao cho tam gic c nh l ba im cctr nhn gc ta lm trng tm.

    Cu II: (2 im)1. Gii cc phng trnh :

    ( ) ( )( )xx xxxx = 2002loglogloglog 20022002

    2. Tm tt c cc gi tr ca a tp xc nh ca hm s ( )xa

    xaxf

    +=

    2

    2cha tp gi tr ca hm

    s ( ) .242 12 ++=

    axxxg

    Cu III: (2 im)1. Gii phng trnh :

    ( )xxxx 141488 sincos64sincos +=+ 2. Hai ng cao 11 ,BBAA ca tam gic nhn ABC ct nhau ti H. Gi R l bn knh ng trnngoi tip tam gic ABC.Chng minh rng din tch tam gic 11BHA bng CBACR cos.cos.cos.2sin.

    2 .

    Cu IV: (2 im)1. Cho t din OABCc: 0180 AOB BOC+ = gi l OD ng phn gic trong ca gc AOB

    Hy tnh gc

    BOD .2. Trong khng gian vi h ta cc vung gc Oxyz cho hai ng thng :

    ( )2 1 0

    1 0

    x y

    x y z

    + + =

    + = ( )

    3 3 0'

    2 1 0

    x y z

    x y

    + + =

    + =

    a. Chng minh rng hai ng thng ( ) v ( )' ct nhau.

    b. Vit phng trnh chnh tc ca cp ng thng phn gic ca cc gc to bi ( ) v ( )' .

    Cu V: (2 im)

    1. Tnh tch phn :( )

    24

    4 2

    4

    sin

    cos tan 2 tan 5

    xdxI

    x x x

    = +

    2. Trong hp ng 2n vin bi c n vin bi ging ht nhau v n vin bi xanh i mt khc nhauHi c bao nhiu cch khc nhau ly n vin bi t hp .

    ------------------ HT -------------------

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    P S HOC HNG DN GIIS 1-2003:

    Cu I:

    1. Cc bn t gii.2. p dng n l Vi-t bc ba. p s: : 6.m =

    Cu II:

    1.p s: 1001.x =

    2.p s:3 17

    .8

    a+

    >

    Cu III:

    1. Phng trnh v nghim. p dng BT Cauchy.

    2. Cc bn t gii.

    Cu IV:

    1.p s: 090 .BOD =

    2.

    a. Chng minh h c nghim duy nht.

    b. Dng vectn v.

    p s:

    1 32 2 ;

    1 1 2 2 3 5

    14 30 14 30 14 301 32 2 .

    1 1 2 2 3 5

    14 30 14 30 14 30

    x zy

    x zy

    +

    = =

    + + +

    +

    = =

    Cu V:

    1.t tant x= . p s: 32 ln 2 .8

    I =

    2.p s:0

    2 .n

    k n

    n

    k

    C=

    =

    ------------------ HT -------------------

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    P S HOC HNG DN GIIS 2-2003:

    Cu I:

    1. Cc bn t gii.2. Lp bng bin thin.

    p s: 3a .

    Cu II:

    1. p dng BT B.C.S. p s:1

    2x y= =

    2.p s:1

    2.

    Cu III:

    1.t2 1 1

    .3 10

    xt t

    x

    + =

    p s:

    1 2; .

    3 4 5 4x

    =

    2. Cc bn t gii.

    Cu IV:

    1.p s:

    25

    .24V a h=

    2. p s:6 6

    .2 2 2 2

    m

    < y th 2y=f(x)>f(y)=2x . V l . Tng t=> x = y .

    p s :1 5

    1;2

    x x

    = = .

    Cu III:

    1.p n : ( )2 3

    : 2 1 1

    x y zd

    + = = .

    2.p s : C(2 ;1 ;2).

    Cu IV:

    1. ( )( )1

    2

    0

    4 3 1 I x dx=

    t2

    1 sin , ;

    2 23

    x t t

    =

    . Khi ( )0

    3

    21 cos 2

    3

    I t dt

    = + .

    p s :2 1

    23 3I

    = +

    2. Cc bn t gii .

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    Cu V:

    1.t ( ) ( )5 4log 3 3 1 log 3 1x x t+ + = + =

    Ta c ( )3 1 4

    3 2 5 33 3 1 5

    x t

    t tx t

    + = + = + + =

    T (3) ta c1 2

    3. 15 5

    t t

    + =

    . V tri nghch bin .

    p s :x=1.

    2. p s :3

    2

    3

    3.cot 12

    hV

    =

    .

    ------------------ HT -------------------

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    B GIO DC V O TOTP CH TON HC V TUI TR

    NM2008

    THI THI HC, CAO NG S 1Mn thi: TON

    Thi gian lm bi: 180 phtCu I: (2 im)

    Cho h th:

    2 2 1( ) 1

    x x mCm x

    + + = .

    1. Kho st v v th hm sng vi m = 1.2. Tm m (Cm)c cc im cc i, im cc tiu v gc ta O lp thnh tam gic vung ti O

    Cu II: (2 im)1. Gii phng trnh:

    sin(3 ) sin 2 .sin( ).4 4

    x x x

    = +

    2. Gii h phng trnh:

    2 2 2

    3 3 3

    .log 3 log log

    .log 12 log log

    x y y x

    x x y y

    + = +

    + = + .Cu III: (2 im)

    1. Tnh cc tch phn sau:

    2

    31 . 1

    dxI

    x x=

    + ;

    2

    40

    sin2

    1 cos

    x J dx

    x

    =+

    .

    2. Cho bn imA(5;1;3),B(1;6;2) , C(5;0;4) ,D(4;0;6). Chng minh rng hai ng thngAB vCD cho nhau. Tnh khong cch giaAB v CD v vit phng trnh ng vung gc chung cachng.

    Cu IV: (2 im)

    1. Gii phng trnh:32( 2)( 4 4 2 2) 3 1 x x x x + = .2. Cho a, b l cc s thc dng. Chng minh rng :

    2 2

    2 3

    (1 )(1 )2 .

    ( 1)(1 )

    a b b

    a a b

    + +

    + +

    Cu V.A: (2 im) ( Dnh cho THPT khng phn ban)1. Cho n l s nguyn dng vi n 2. Chng minh rng:

    2 1 2 2 2 3 2 21 . 2 . 3 . ... . ( 1).2n nn n n nC C C n C n n

    + + + + = + 2. Cho tam gicABC. Xt tp hp gm nm ng thng song song viAB; su ng thng songsong viBCv by ng thng song song vi CA. Hi cc ng thng ny to ra bao nhiu hnh

    bnh hnh, bao nhiu hnh thang?Cu V.B: (2 im) ( Dnh cho THPT phn ban)

    Cho ng thng () c phng trnh 2 2 0x y + = v elip (E) c phng trnh2 2

    18 4

    x y+ = . Gi

    sng thng () ct (E) ti hai imB v C.1. Tm im A thuc elip (E) tam gicABCcn ti A.2. Tm im A thuc elip (E) din tch tam gicABCt gi tr ln nht.

    ------------------ HT -------------------

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    P S HOC HNG DN GIIS 1-2008:

    Cu I:1. Cc bn t gii.2. (Cm) c im cc i M v im cc tiu N khi v ch khi m > - 2.

    S dng iu kin ,0. =ONOM ta tm c5

    7=m .

    Cu II.

    1. p s:24

    kx = .

    2. p s: ( ) .2log2;2log;3

    4

    3

    4

    =yx

    Cu III.

    1. p s:

    +=

    2

    223ln

    3

    1I ;

    4

    =J .

    2. p s:103

    23693=IJ

    Phng trnh ng vung gc chung:144

    103

    476

    1221103

    586

    ==

    zy

    x

    .

    Cu IV:1. p s:x = 32. Cc bn t chng minh.

    Cu V.A:1. Cc bn t chng minh.2. p s: S hnh bnh hnh l: 675 ( hnh ). S hnh thang l: 1575 (hnh).

    Cu V.B:

    1. p s:

    +

    +

    25

    3921;

    5

    392,

    25

    3921;

    5

    39221 AA

    2. p s: ( )2;2 A

    ------------------ HT -------------------

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    B GIO DC V O TOTP CH TON HC V TUI TR

    NM2008

    THI THI HC, CAO NG S 2Mn thi: TON

    Thi gian lm bi: 180 phtCu I: (2 im)

    Cho hm s: 4 2 2( ) : 2( ) 5 5Cm y x m x m m= + + + 1. Kho st s bin thin v v th (C1) ca hm s khi m = 1.2. Vi nhng gi tr no ca m th th (Cm) c im cc i v im cc tiu, ng thi cc imcc i v im cc tiu lp thnh mt tam gic u.

    Cu II: (2 im)

    1. Gii phng trnh:1

    (1 cos )(1 cos 2 )(1 cos3 ) .2

    x x x+ + + =

    2. Gii h phng trnh:2

    1 2

    1 2

    2log ( 2 2) log ( 2 1) 6

    log ( 5) log ( 4) 1

    x y

    x y

    xy x y x x

    y x

    +

    +

    + + + + =

    + + =

    Cu III: (2 im)

    1. Tnh tch phn:

    11 3 3

    41

    3

    ( ).

    x x I dx

    x

    =

    2. Cho cc s thc dng a, b, c tha mn ab + bc + cd= abc. Chng minh rng:4 4 4 4 4 4

    3 3 3 3 3 31.

    ( ) ( ) ( )

    a b b c c a

    ab a b bc b c ca c a

    + + ++ +

    + + +

    Cu IV: (2 im)Trong khng gian vi h ta Descartes Oxyz, cho mt phng (P) c phng trnh

    2 1 0 x y z+ + = v ng thng (d) c phng trnh

    2 2 0

    2 2 0

    x y

    y z

    =

    + + = .1. Tm to giao imA ca (d) v (P). Tnh so gc to bi (d) v (P).2. Vit phong trnh ng thng () i quaA, () nm trong mt phng (P) sao cho gc to bi haing thng () v (d) bng 450.

    Cu V.A: (2 im) ( Dnh cho THPT khng phn ban)1. Vit phng trnh ng trn i qua hai imA(2;5) ,B(4;1) v tip xc vi ng thng cphng trnh 3 9 0.x y + = 2. Vi n l s nguyn dng, chng minh h thc sau:

    1 2 2 2 22( ) 2( ) ... ( )

    2

    n n

    n n n n

    nC C n C C + + + =

    Cu V.B: (2 im) ( Dnh cho THPT phn ban)

    1.Gii phng trnh: 84 221 1

    log ( 3) log ( 1) log 4 .2 4

    x x x+ + =

    2.Cho hnh chp t gic u S.ABCD c cnh y bng a, chiu cao cng bng a. GiE, K ln ltl trung im ca cc cnhAD vBC. Tnh bn knh ca mt cu ngoi tip hnh chp S.EBK.

    ------------------ HT -------------------

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    P S HOC HNG DN GIIS 2-2008:

    Cu I.1. Cc bn t gii.2.

    k

    (Cm) c ba

    im c

    c tr

    l

    m

    < 2. Ccim c

    c tr

    ca (C

    m

    ) l( ) ( ) ( ).1;2,1;2,55;0 2 mmCmmBmmA + p s: 3 32 =m .

    Cu II.

    1. p s:

    23

    2;

    24mxkx +=+= .

    2. p s: ( ) ( )1;2; =yx .

    Cu III.

    1. p s: 6=

    I 2. Cc bn t gii.

    Cu IV.1. p s: ( )1;0;1 A . Gc ( ) 030)(, =Pd .

    2. p s: Hai ng thng tho mn l: ( )335

    1

    3132

    1:1

    +=

    +=

    +

    zzx;

    ( )335

    1

    3132

    1:2

    +

    +=

    =

    zyx

    Cu V.A:

    1. p s:2 2

    1

    2 22

    ( ) : ( 1) ( 2) 10( ) : ( 17) ( 10) 250C x y

    C x y + =

    + =.

    2. Cc bn t chng minh.

    Cu V.B:

    1. p s:3

    3 2 3

    x

    x

    =

    = +.

    2. p s:8

    29aR =

    ------------------ HT -------------------

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    B GIO DC V O TOTP CH TON HC V TUI TR

    NM2008

    THI THI HC, CAO NG S 3Mn thi: TON

    Thi gian lm bi: 180 pht

    Cu I: (2 im)

    Cho hm s

    2

    ( ) : 1

    x

    C y x

    = 1. Kho st v v th (C) ca hm s.2. Tm cc gi tr ca tham sang thng (d) :y = a(x 3) ct th (C) ti hai im phnbit trong c t nht mt giao im c honh ln hn 1.

    Cu II: (2 im)1. Gii phng trnh: 5 3 22sin 2sin .cos cos 2 sin 0 x x x x x+ + =

    2. Gii h bt phng trnh:3 2

    4 3 2

    3 9 10 0

    5 5 5 4 0

    x x x

    x x x x

    + +

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    P S HOC HNG DN GIIS 3-2008:

    Cu I.1. Cc bn t gii.2. p s: 0a .

    Cu II.

    1. p s:

    kx

    kx

    +=

    +=

    4

    22 .

    2. p s: 14

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    B GIO DC V O TOTP CH TON HC V TUI TR

    NM2008

    THI THI HC, CAO NG S 4Mn thi: TON

    Thi gian lm bi: 180 phtCu I: (2 im)

    Cho hm s: ( )3 22 1 y x x m x m= + (1).

    1. Kho st s bin thin v v th ca hm s khi m = 1.2. Trong trng hp hm s (1) ng bin trong tp s thc R, tm m din tch hnh phng giihn bi th ca hm s (1) v hai trc Ox, Oy c din tch bng 1.

    Cu II: (2 im)1. Gii phng trnh nghim thc: 1 tan . tan 2 cos 3 . x x x =

    2. Tm tt c cc gi tr ca tham sk phng trnh ( )1 4 2 1 2 x x xk k+ + = c nghim.

    Cu III: (2 im)1. Trong mt phng vi h ta Oxy cho elip (E): 2 24 4.x y+ = Qua im M(1;2) k hai ngthng ln lt tip xc vi (E) ti A v B. Lp phng trnh ng thng i qua hai im A v B.

    2. Cho tam gic ABC tha mn: ( )5

    cos 2 3 cos 2 cos 2 0.2

    A B C + + + =

    Tnh ln ba gc ca tam gic .

    Cu IV: (2 im)

    1. Tnh tch phn sau:2

    2 sin

    0

    2cos cos .2

    xx I x x e dx

    = +

    2. Cho ba s thc dngx, y, z tha mn iu kin: 2 1. xy xz+ =

    Tm gi tr nh nht ca biu thc:3 4 5

    . yz zx xy

    S x y z

    = + +

    Cu V.A: (2 im) ( Dnh cho THPT khng phn ban)1. Trong khng gian vi h trc ta Oxyz cho hai ng thng:

    ( )12 4 0

    :3 0

    x yd

    z

    + =

    = ( )2

    0:

    1 0

    y zd

    x

    + =

    =

    Lp phng trnh mt cu c bn knh nh nht tip xc vi c hai ng thng trn.2. C tt c bao nhiu s t nhin chn c 4 ch s, sao cho trong mi sng sau ln hn ch sng lin trc n?

    Cu V.B: (2 im) ( Dnh cho THPT phn ban)1. Cho hnh chp t gic S.ABCD. y ABCD l hnh vung cnh bng a, SA vung gc vi mtphng (ABCD) v SA = a. Tnh din tch ca thit din to bi hnh chp vi mt phng qua Avung gc vi cnh SC.2. Gii bt phng trnh: 2 1log 3 log 2xx .

    ------------------ HT -------------------

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    P S HOC HNG DN GIIS 4-2008:

    Cu I:1. Cc bn tgii.

    2. p s: 316

    =m .

    Cu II:

    1. Hng dn:

    =

    =

    1cos

    03cos

    x

    x.

    2. p s:2

    10

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    B GIO DC V O TOTP CH TON HC V TUI TR

    NM2009

    THI THI HC, CAO NG S 1Mn thi: TON

    Thi gian lm bi: 180 phtCu I: (2 im)

    1. Kho st v v th ca hm s:

    2

    ( ).1

    x

    y Cx

    = 2. Chng minh rng vi mi gi tr thc ca m, ng thng y x m= + (d) lun ct th (C) tihai im phn bit A, B. Tm gi tr nh nht ca di on thng AB.

    Cu II: (2 im)

    1. Gii phng trnh2

    2 13 .2 6x

    x x = .

    2. Gii phng trnh tan tan s in3 sin s in26 3

    x x x x x

    + = +

    .

    Cu III: (1 im)Tnh th tch hnh chp S.ABCbit , , , 60 ,oSA a SB b SC c ASB= = = = 90 , 120 .o o BSC CSA= =

    Cu IV: (1 im)

    Tnh tch phn( )

    2

    30

    sin .

    sin 3.cos

    x dxI

    x x

    =

    + .

    Cu V: (1 im)

    Tm gi tr nh nht ca biu thc 2 2 22 2 2log 1 log 1 log 4P x y z= + + + + + trong l cc s

    dng , , x y z tha mn iu kin 8.xyz =

    PHN DNH RING CHO CHNG TRNHCHUN.

    Cu VIa: (2 im)1. Trong mt phng vi h trc ta vung gc Oxy, cho hai ng thng c phng trnh

    11 0( ); x y d + + = 22 1 0( ). x y d = Lp phng trnh ng thng i qua im (1; 1)M ct 1( )d ,

    2( )d tng ng ti A, B sao cho 2 0 MA MB+ =

    .

    2. Trong khng gian vi h trc ta vung gc Oxyz, cho mt phng (P) c phng trnh2 2 1 0 x y z+ + = v hai im (1: 7 : 1)A , (4;2;0)B . Lp phng trnh ng thng (d) l hnh

    chiu vung gc ca ng thng AB trn mt phng (P).

    Cu VIIa: (1 im)K hiu 1x , 2x l hai nghim phc ca phng trnh bc hai

    22 2 1 0x x + = . Tnh gic tr cc s

    phc21

    1

    x,

    22

    1.

    x

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    PHN DNH RING CHO CHNG TRNH NNG CAO.

    Cu VIb: (2 im)1. Trong mt phng vi h trc ta vung gc Oxy, cho hyperbol (H) c phng trnh

    2 2

    19 4

    x y

    = . Gi s (d) l mt tip tuyn thay i v F l mt tring hai tiu im ca (H), k FMvung gc vi (d). Chng minh rng M lun nm trn mt ng trn cnh, vit phng trnhng trn .2. Trong khng gian vi h truc tc vung gc Oxyz, cho ba im (1;0;0)A , (0;2;0)B , (0;0;3)C .Tm ta trc tm ca tam gic ABC.

    Cu VIIb: (1 im)Ngi ta s dng 5 cun sch Ton, 6 cun sch L, 7 cun sch Ha (cc cun sch cng loiging nhau) lm gii thng cho 9 hc sinh, mi hc sinh c hai cun sch khc loi. Trong s9 hc sinh trn c 2 bn Ngc v Tho. Tm xc sut hai bn Ngc v Tho c gii thng gingnhau.

    ------------------ HT -------------------

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    P S HOC HNG DN GIIS 1-2009:

    Cu I:1. Cc bn t gii.

    2. p s: min 2 2AB = 2m = .

    Cu II:

    1. Phng trnh c 3 nghim: p s:3

    1

    1 1 8log 6

    4

    x

    x

    = +

    =

    .

    2. Phng trnh c 3 h nghim: p s:22

    23

    x k

    x k

    x k

    =

    =

    = +

    .

    Cu III:

    p s: Th tch l2

    12V abc= .

    Cu IV:

    p s:3

    6I= .

    Cu V:

    p s: min 5 2 2P x y z= = = = .

    Cu VI.a:1. p s:ng thng:x=1.

    2. Phng trnh ng thng:3 2

    4 3 1

    x y z = =

    .

    Cu VII.a:p s: Cc gi tr: (-2i; 2i).

    Cu VI.b:Cc bn t gii.

    Cu VII.b:Cc bn t gii.

    ------------------ HT -------------------

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    B GIO DC V O TOTP CH TON HC V TUI TR

    NM2009

    THI THI HC, CAO NG S 2Mn thi: TON

    Thi gian lm bi: 180 phtCu I: (2 im)

    Cho hm s )(1

    42Cx

    x

    y +

    = .1. Kho st s bin v v th hm s(C).2. Tm trn th (C) hai im i xng nhau qua ng thng MN bit M (-3;0) v N (-1;-1).

    Cu II: (2 im)

    1. Gii phng trnh: .2

    7

    4

    3cos4cos

    2

    12coscos4 4 =+

    xxxx

    2. Gii phng trnh: 1232.3 ++= xx xx .

    Cu III: (1 im)

    Tnh tch phn:

    +

    +=

    2

    0 cos1

    sin1

    dxex

    xI

    x .

    Cu IV: (1 im)Cho hnh chp tam gic u S.ABC di cnh bn bng 1. Cc mt bn hp vi mt phng y mtgc . Tnh th tch hnh cu ni tip hnh chp S.ABC.

    Cu V: (1 im)Trong khng gian vi h ta vung gc Oxyz cho ng thng l c phng trnh:

    )(

    24

    2

    32

    Rt

    tz

    ty

    tx

    +=

    =

    +=

    v hai im A(1;2;-1), B(7;-2;3).

    Tm trn ng thng l nhng im sao cho tng khong cch t n A v B l nh nht.

    PHN DNH RING CHO CHNG TRNHCHUN.

    Cu VIa: (2 im)1. Nm on thngc di 1 cm, 3 cm, 5 cm, 7 cm, 9cm. ly ngu nhin ba on thng trong nmon thng trn. Tm xc sut ba ton thng ly ra lp thnh mt tam gic.

    2. Gii h phng trnh:

    =

    +=

    5

    8

    yx

    yyxyxx

    .

    Cu VIIa: (1 im)

    Tm gi tr nh nht ca hm s:)sincos2(sin

    cos2

    xxx

    xy

    = , vi .

    30

    < x

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    PHN DNH RING CHO CHNG TRNH NNG CAO.

    Cu VIb: (2 im)

    1. Tm cc gi tr cax trong khai trin khai nh thc Newton:n

    xx

    + 5 3log)2()310log( 22 bit rng

    s hng th su ca khai trin bng 21 v 231 2 nnn CCC =+ .

    2. Cho

    +=

    3

    2sin

    3

    2cos3

    i . Tm cc s phc sao cho =3 .

    Cu VIIb: (1 im)Gi a, b, c l di ba cnh ca mt tam gic c chu vi bng 2. Chng minh rng:

    2227

    52 222

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    P S HOC HNG DN GIIS 2-2009:

    Cu I:1. Cc bn t gii.2.p s: (0; 4); (2; 0)A B .

    Cu II:1. p s: 8kx = .2. Phng trnh c 2 nghim: p s: 1;1 == xx .

    Cu III:

    p s: 2

    eI = .

    Cu IV:

    p s:

    3

    2

    sin tan

    tan 4(1 sin )V

    = + + .

    Cu V:p s: (2;0;4)M .

    Cu VI.a:

    1. p s:35

    3

    C.

    2. p s: )2;3();2;3();( =yx .

    Cu VII.a:

    p s: 13tan2

    32min =

    += y .

    Cu VI.b:1. p s:x=2.

    2.

    p s:

    +

    =

    +

    =

    +

    =

    9

    8sin

    9

    8cos3

    9

    2

    sin9

    2

    cos3

    9

    4sin

    9

    4cos3

    33

    3

    2

    31

    i

    i

    i

    .

    Cu VII.b:Cc bn t gii.

    ------------------ HT -------------------

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    B GIO DC V O TOTP CH TON HC V TUI TR

    NM2009

    THI THI HC, CAO NG S 3Mn thi: TON

    Thi gian lm bi: 180 pht

    Cu I: (2 im)

    Cho hm s )1(1

    )12( 2

    = x

    mxmy .

    1. Kho st s bin v v th (C) ca hm s (1) ng vi m = -1.2. Tm m th ca hm s (1) tip xc vi ng thng y =x.

    Cu II: (2 im)

    1. Gii phng trnh: 09

    log))9((log 22 =+

    ++x

    xxx .

    2. Gii h phng trnh:

    =+

    =+

    ++

    yxyx

    yx

    xyyx

    2

    22 12

    .

    Cu III: (1 im)

    1. Tm gii hn:3 22

    2

    0 1

    )1ln(lim

    2

    xe

    xL

    xx +

    +=

    .

    2. Tnh tch phn: +

    =2

    03)cos(sin

    sin

    dxxx

    xdxI .

    Cu IV: (1 im)

    Cho hnh chp ct tam gic u ngoi tip mt hnh cu bn knh rcho trc. Tnh th tch hnhchp ct, bit rng cnh y ln gp i cnh y nh.

    Cu V: (1 im)

    Cho phng trnh: mxxx

    x+=

    12

    12

    13 2( vi m l tham s).

    Tm m phng trnh cho c nghim duy nht.

    PHN DNH RING CHO CHNG TRNHCHUN.

    Cu VIa: (2 im)1. Trong khng gian vi h ta Oxyz cho mt phng P c phng trnh:x+y+z+3=0; ng thng

    dc phng trnh:12

    2

    1

    1 zyx=

    =

    +v cc im A(3;1;1); B(7;3;9); C(2;2;2).

    a. Vit phng trnh mt phng (Q) cha dv song song vi mt phng (P).

    b. Tm ta ca im M thuc (P) sao cho MCMBMA 32 ++ nh nht.

    2. Cho ng trn (C): 012622 =++ yxyx . Vit phng trnh ng thng di qua M(0;2) vct (C) theo mt dy cung c di l 4.

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    Cu VIIa: (1 im)Chng minh rng vi mi s t nhin n ( vi n>2), ta c: )1(22 )1()2( > nnn nnn .

    PHN DNH RING CHO CHNG TRNH NNG CAO.

    Cu VIb: (2 im)1. Trong khng gian h ta Oxyz cho mt phng ( ) c phng trnh: 3x+2y-z+4=0 v hai imA(4;0;0) v B(0;4;0). Gi I l trung im ca on thng AB. Tm ta giao im ca ng thngAB vi mt phng () v xc nh ta im K sao cho KI vung gc vi mt phng (), ngthi K cch u gc ta O av2 mt phng ( ).

    2. Cho elip (E) c phng trnh 125100

    22

    =+yx

    . Tm cc im M thuc (E) nhn hai tiu im ca elip

    (E) di mt gc 1200.

    Cu VIIb: (1 im)

    Chng minh rng vi mi s t nhin n ( vi n>2), ta c: )1ln()1ln(ln2

    +> nnn .

    ------------------ HT -------------------

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    Tp th lp 12T THPT Th x Cao Lnh Nin kho 2006-2009 GVCN: Thy Nguynnh Huy

    P S HOC HNG DN GIIS 3-2009:

    Cu I:1. Cc bn t gii.2. p s: { }1\Rm .

    Cu II:1. p s: 10=x .2. H phng trnh c 2 nghim: p s: )3;2();0;1();( =yx .

    Cu III:

    1. p s:3

    7L

    = .

    2. p s:1

    2I = .

    Cu IV:Cc bn t gii.

    Cu V:p s: Rm .

    Cu VI.a:1.a. p s: 01 =++ zyx .

    b. p s:

    9

    2;

    9

    20;

    9

    5M .

    2. p s: 22;22

    1+=+= xyxy .

    Cu VII.a:Cc bn t gii.

    Cu VI.b:

    1. p s: Giao im: )0;16;12( ;

    4

    3;

    2

    1;

    4

    1K .

    2. p s:

    3150;

    33101M ;

    3150;

    33102M ;

    3150;

    33103M v

    3150;

    33104M .

    Cu VII.b:Cc bn t gii.

    ------------------ HT -------------------

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    Thc hin:

    Tp th Lp 12T

    Trng THPT Th x Cao LnhNin kha: 2006 -2009

    Gio vin ch nhim:

    Thy Nguyn nh Huy

    1. Tuyn tp cc nm 2003:Tp tht4. Chu trch nhim chnh: L Ngc c

    2. Tuyn tp cc nm 2004:Tp tht5. Chu trch nhim chnh: Phm Ngc Trng

    3. Tuyn tp cc nm 2005:Tp tht6. Chu trch nhim chnh: L Thanh Sang

    4. Tuyn tp cc nm 2006:Tp tht3. Chu trch nhim chnh: Trnh Hong Anh

    5. Tuyn tp cc nm 2007:Tp tht2. Chu trch nhim chnh: Nguyn Hong Vit Khnh

    6. Tuyn tp cc nm 2008:Tp tht1. Chu trch nhim chnh: Nguyn Hng Hong

    7. Tuyn tp cc nm 2009:Tp tht3. Chu trch nhim chnh: Nguyn c Tun

    Nguyn c Tun