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Turing’s Bombes
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Turing’s Bombes

Mar 17, 2016

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Kevin Henry

Turing’s Bombes. Solve Enigma using known plaintext. Depending on German patterns, e.g. weather reports Sometimes setup by seeding/farming Depended on Engima characteristics: No letter enciphered to itself Self-inverse of cipher. Procedure (by hand). Find a crib – piece of known plaintext - PowerPoint PPT Presentation
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Page 1: Turing’s Bombes

Turing’s Bombes

Page 2: Turing’s Bombes

Solve Enigma using known plaintext

• Depending on German patterns, e.g. weather reports

• Sometimes setup by seeding/farming

• Depended on Engima characteristics:– No letter enciphered to itself– Self-inverse of cipher

Page 3: Turing’s Bombes

Procedure (by hand)• Find a crib – piece of known plaintext• Find its alignment

– No letter matches reduces possibilities– All possible alignments may need to be tested

• Test an alignment by working through possible plugboard settings for every rotor setting– Inconsistency eliminates this rotor setting– Consistent plugboard setting makes this rotor

setting a likely candidate – test it on the rest of the message

Page 4: Turing’s Bombes

Example

URUXI CHDII FOEQA DIIYD RYHMN NQOVWUNIV ERSIT YHALL

UNIV ERSIT YHALL

OEQADIIYD RYHMN

UNIVERSITYHALL

ENIGMA

Page 5: Turing’s Bombes

OEQADIIYD RYHMN

UNIVERSITYHALL

PLUGBOARD

ROTORSsetting 1setting 2setting 3

… PLUGBOARD

Need to check for all possible rotor positions at setting 1

Page 6: Turing’s Bombes

Checking one rotor settingOEQADIIYD RYHMN

UNIVERSITYHALL

ABCDEFGHIJKLM NOPQRSTUVWXYZJNPXFEZVRAQUS 1 BWCKIMYLHODTG

BAONURQJZHPTS 2 DCKGFMLEYXWVI

VGIMPYBWCZURD 3 TXESLQNKAHOFJ

FSWUGAEQPVTRO 4 YMIHLBKDJCZNX

UILXONWVBRQCT 5 FESKJPMAHGDZYTZWXPGFONQRVS 6 IHEJKMAYLCDUB

HNUXKSYARQEML 7 BPOJIFVCTZDGW

MENVBZLQSYWGA 8 CRXHOIUTDKPJF

OVRUGHEFYMNZJ 9 KAXSCQWDBTPIL

QEGYBKCVMOFTI 10 ZJXASRLWHUPDN

OWPFGDEVTNSXQ 11 JACMYKIZHBLRU

IFRYJBNZAEWOP 12 GLMVCUXSQKTDH

YSEMCWXPZRNQD 13 KUHLJBVOTFGAI

LMVJUNWZRDPAB 14 FTKYIXOECGSQH

Assume I-A

and continue

1 V-Q, M-Y, R-T, S-H,

3 8 6 7

2 I-R, L-Y, K-Y

10 10 11

3 N-I, G-I, W-I

6 8 8

Page 7: Turing’s Bombes

Menu is a summary of relationships

U

N E

I

TDLM

O

R Q

YHAV S

1

13 14 2 5 9

36

4 12 11

10 78

Page 8: Turing’s Bombes

Checking a rotor setting

• All possible plugboard connections for a letter are generated – means this setting cannot work

• All plugboard connections generated are consistent – means this is a likely rotor setting

• All but one plugboard setting are generated – means the other is likely correct

Page 9: Turing’s Bombes

How to mechanize this?• Need an enigma for each link indicated• Enigmas should be set the given number of

steps apart – if the link is X, then it should be X-1 steps ahead of link 1.

• Double-ended, so they can be chained together.

• Need to arrange feedback into the system

Page 10: Turing’s Bombes

How to mechanize this?• Each letter has 26 wires, one for each possible

plugboard setting• One wire is selected for one letter (say I-A as in

our example)• Current goes through that wire into the enigma

set at position 8 (and the one at position 3)• All the outputs of 8 are linked to Y, but only one

(M-Y) is activated.• This is attached to the M-Y wire feeding into

enigma set at position 10. All its 26 outputs go to R. Output I-R is selected.

• The I inputs now go into R at positions 3 and 8 and the process continues

Page 11: Turing’s Bombes

How to mechanize this?

• Turing had the idea of this mechanism• Welchman added the observation that the

links are all two-way– If M-Y is selected, then Y-M should also be

selected.– He devised a wiring that made connections so

the circuits reflected this – the “diagonal board”

Page 12: Turing’s Bombes

What it looked like

Page 13: Turing’s Bombes

What it looked like

Page 14: Turing’s Bombes

SchematicRed = top drum, Green = middle drum, Blue = bottom drum

Page 15: Turing’s Bombes

One set of drums = One Enigma

• Set of three rotors and reflector• Left wires are 26 letters in• Right wire are 26 letters out• These wires are used to connect

according to the menu

Page 16: Turing’s Bombes

Simplified example with 8 lettersa,b,c,d,e,f,g,h

123456789BEACHHEADEDBGEAHDB

Page 17: Turing’s Bombes

Simplified example with 8 letters

Page 18: Turing’s Bombes

Simplified example with 8 letters

Page 19: Turing’s Bombes

Simplified example with 8 letters

Turing’s Version

Page 20: Turing’s Bombes

Simplified example with 8 letters

Page 21: Turing’s Bombes

Circuits carry out trace electricallyProcess

• Set voltage to one wire for selected letter– For example E-A

• Register includes all wires for a selected letter– For example all E wires

• For a given position of the rotors, let circuit build

Page 22: Turing’s Bombes

Circuits carry out trace electricallyThree outcomes

• Circuits cascade until all E wires are connected to voltage – indicates rotor setting does not work

• Circuits cascade until all but one E wire are connected – indicates the rotor setting works for the unselected wire

• Circuits are consistent, only one E wire (and only one for any other letter) is live – indicates rotor setting is likely solution

Page 23: Turing’s Bombes

Bombe rotates through rotor settings

• When all wires in E register are on, continue to next setting

• When one or more wires are not on, stop– Could be one of the situations that indicates a

possible rotor setting– The setting must be checked for consistency– If consistent, then check to see if decode

results

Page 24: Turing’s Bombes

Bombe capacity• One row of Bombe has 12 pseudo-enigmas

connected (means max of 12 links)• Each of three rows is set to a different rotor

order• Top rotors move at 120 rpm

– This means 26 * 120 rotor positions per minute!– 5 2/3 minutes to check all 17,576 positions for

the given rotor order• Motion stops as described

– rotor position needs to be recorded and checked, then bombe is restarted

Page 25: Turing’s Bombes

Bombe• Once one message is broken for an

enigma group (army, naval, etc), then all messages can be decoded for that day

• At midnight, a new day-key would take effect and the process would start again