Nama: Rolina Z Tambunan NIM: No. 1 Komposisi Susu: Rumus-rumus: Air : 87.50% Protein : 3.70% Lemak : 3.70% Laktosa : 4.60% Abu : 0.50% T=283 K, Diperoleh: Pers. 3-9 Kw : 0.588042 Kp : 0.190486 Kf : 0.153078 Kc : 0.214841 Ka : 0.343319 Pers. 12-18 w : 997.8357 p : 1324.719 f : 921.4143 c : 1595.995 a : 2420.994 Pers. 10 X vw : 0.008769 X vp : 0.000279 X vf : 0.000402 X vc : 0.000288 X va : 0.000021 Choi dan okos (Pers.2): k= 0.005340 W/m oC No. 2 T 2 = 43 o C , T 1 = 45 o C, x2 = 4 mm, x1 = 2mm Gradien suhu T/ x=(T 2-T1)/(x2-x1) =(43-45)/(4-2)*1000 = -1000.00 Pers (23) : T = - (-1000)(x1-x)+T 1 k w = 0.57109 + 0.0017625T-6.7306x10 -6 T 2 ....................... 3) k p = 0.1788 + 0.0011958 T – 2.7178 x 10 -6 T 2 ................... 5) k f = 0.1807 – 0.0027604 T – 1.7749 x 10 -7 T 2 .................. 6) k c = 0.2014 + 0.0013874 T – 4.3312 x 10 -6 T 2 ................... 7) k a = 0.3296 + 0.001401 T – 2.9069 x 10 -6 T 2 ...................... 9) Satuan untuk nilai k = W/m o K. w = air murni, ic = es, p = protein, f = fat/lemak, c = karbohidrat, fi = fiber, a = abu Densitas komponen dihitung dengna rumus : w = 998.18 + 0.0031439T – 0.0037574 T 2 ........ 12) p = 1329.9 – 0.51814 T ................................... 14) f = 925.59 – 0.41757 T .................................. 15) c = 1599.1 – 0.31046 T .................................. 16) a = 2423.8 – 0.28063 T .................................. 18) X vi ditentukan dari fraksi massa (X i ), densitas komponen ( i ) dan densitas komposit ( ) Choi dan okos (1987) : k = (k i X vi ) ........................ 2) k i = konduktivitas panas komponen murni X vi = fraksi volume dari tiap komponen murni ............23)