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Precalculus
Trigonometry III
By Dr. Dalia M. Gil, Ph.D.
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Topics
Periodic Functions.
Basic Identities.
Pythagorean Identities.
Sum and Difference Identities.
Confunction Identities.
Double Identities.
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Periodic Function
A function fis said to be periodic if thereexists a positive constant psuch that
f(s + p)= f(s)
for all sin the domain of f. The smallest
such positive number pis called theperiod of a function.
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Periodic Function f(s + p)= f(s)
sin (s + 2)= sin s and cos (s + 2)= cos s
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Basic Identities
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The equation of a unit circle in the xy-plane is x2 + y2 = 1
x = cos s and y = sin s
Pythagorean Identities
x2 + y2 = 1
(cos s)2 + (sin s)2 = 1
cos2 s + sin2 s = 1
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From sin2 s + cos2 s = 1, we can find otheridentities
Dividing both sidesby sin2 s
Pythagorean Identities
sin2 s + cos2 s = 1
sin2 s / sin2 s + cos2 s / sin2 s = 1 / sin2 s
1 + cot2 s = csc2 s Simplifying
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From sin2 s + cos2 s = 1, we can find otheridentities
Dividing both sidesby cos2 s
Pythagorean Identities
sin2 s + cos2 s = 1
sin2 s / cos2 s + cos2 s / cos2 s = 1 / cos2 s
tan2 s + 1 = sec2 s Simplifying
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Pythagorean Identities
sin2 s + cos2 s = 1
tan2 s + 1 = sec2 s
1 + cot2 s = csc2 s
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cos x (tan x sec x)
Example: multiply and simplify:
Simplifying Trigonometric Expressions
= cos x tan x cos x sec x
= cos x (sin x / cos x) cos x (1 / cos x)
= sin x 1
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sin2 x cos2 x + cos4 x
Example: multiply and simplify:
Simplifying Trigonometric Expressions
= cos2 x (sin2 x + cos2 x)
= cos2 x sin2 x + cos2 x = 1
Common factor
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cot (- ) / csc (- )
Example: multiply and simplify:
Simplifying Trigonometric Expressions
= [cos(- ) / (sin(- ) ] / [1 / sin(- )]
= cos (- ) = cos
= [cos(- ) / (sin(- ) ] . [sin(- )]
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[2 sin2 t + sin t 3] / [1 cos2 t sin t]
Example: multiply and simplify:
Simplifying Trigonometric Expressions
sin2 x + cos2 x = 1,or sin2 x = 1 - cos2 x
= [2 sin2
t + sin t 3] / [sin2
t sin
t ]
= (2 sin t + 3)(sin t 1) / sin t (sin t 1) ]
= (2 sin t + 3) / sin t
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Example: Multiply and simplify:
Simplifying Trigonometric Expressions
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Example: Rationalize the denominator:
Simplifying Trigonometric Expressions
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Example: Express (9 + x2) as atrigonometric function of without usingradicals by letting x = 3 tan .
Assume 0 < < /2.
Then find sin and cos
Simplifying Trigonometric Expressions
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Some important identities involving sumsor difference of two numbers or angles.
These numbers are identifies with theletters u and v.
Now we start for the identity cosine.
Sum and Difference Identities
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Lets consider a realnumber u in theinterval [/2, ] and areal number v in theinterval [0, /2].
These determine the
points A and B on theunit circle.
Sum and Difference Identities
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The arc length sis
u v, and 0 s.
The coordinates of Aare (cos u, sin u),and the coordinate of
Bare (cos v, sin v).
Sum and Difference Identities
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Using the formula ofdistance AB:
Sum and Difference Identities
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Rotate the circle sothat point B is at (1,0).
Although thecoordinates of point Aare now (cos s, sin s),the distance AB has
not changed:
Sum and Difference Identities
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Simplifying:
Sum and Difference Identities
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Now we have two expressions for AB
Sum and Difference Identities
Equating the both expressions for AB
Solving this expressions we obtain sum anddifference identities
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sin (u + v) = sin u cos v + cos u sin v. sin (u - v) = sin u cos v - cos u sin v.
cos (u + v) = cos u cos v - sin u sin v. cos (u - v) = cos u cos v + sin u sin v.
tan (u + v) = (tan u + tan v) / (1 - tan u tan v)
tan (u - v) = (tan u - tan v) / (1 + tan u tan v)
Sum and Difference Identities
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Express as a difference of two numberswhose sine and cosine values are known:
Example: Find cos(5/12) exactly
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Find cos(5/12) exactly: Using cos (u - v) = cos u cos v + sin u sin v
Example: Sum and Difference Identities
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Express 105 as the sum of two measures:
105 = 45 + 60
sin 105 = sin (45 + 60)= sin 45 . sin 60 + cos 45 . cos 60
= 2/2 . + 2/2 . 3/2
= (2 + 6) / 4
sin 105 0.9659 and (2 + 6) / 4 0.9659
Example: Find sin 105 exactly
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Rewrite 15 as 45 - 30 and use the identityfor the tangent of a difference:
tan 15 = tan(45 - 30)= (tan 45 - tan 30) / (1 + tan 45 tan 30)
= ( 1 - 3/2) / (1 + 1 . 3/3)
= (3 - 3) / (3 + 3)
Example: Find tan 15 exactly
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Confunction Identities
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Prove the identity sin( + /2) = cos
sin(
+
/2) = sin
cos
/2 + cos
sin
/2
= sin . 0 + cos . 1
= cos
Example: Confunction Identities
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Other Confunction Identities
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Other Confunction Identities
Prove the identity sin( + /2) = cos
sin(
+
/2) = sin
cos
/2 + cos
sin
/2
= sin . 0 + cos . 1
= cos
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Find an identity for:
tan (x + /2)
= sin (x + /2) / cos (x + /2)
= cos x / - sin x
= - cot x
Other Confunction Identities
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Find an identity for:
sec (x 90)
= 1 / (cos (x 90)
= 1 / sin x
= csc x
Other Confunction Identities
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Double Identities
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To find these identities we will use the sumformulas to develop sin 2x
sin (u + v) = sin u cos v + cos u sin v.
Substitute x for both u and v
sin (x + x) = sin 2x
= sin x cos x + cos x sin x= 2 sin x cos x
Double-Angle Identities
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To find these identities we will use the sumformulas to develop cos 2x
cos (u + v) = cos u cos v - sin u sin v.
Substitute x for both u and v
cos (x + x) = cos 2x
= cos x cos x - sin x sin x= cos2 x sin2 x
Double-Angle Identities
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To find these identities we will use the sumformulas to develop tan 2x
tan (u + v) = (tan u + tan v) / (1 - tan u tan v).
Substitute x for both u and v
tan (x + x) = tan 2x
= (tan x + tan x) / (1 - tan x tan x).
= 2tan x / (1 tan2 x).
Double-Angle Identities
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Double-Angle Identities
Given tan = -3/4 and is in the quadrant II.Find each of the following
a) sin 2
b) cos 2c) tan 2d) The quadrant in which 2 lies.
sin = 3/5 and cos = -4/5
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Double-Angle Identities
a) sin 2= 2 sin cos = 2 . 3 / 5 . (-4 / 5) = -24 / 25
b) cos 2= cos2 - sin2= (-4 / 5)
2
(3/5)2
= 16 / 25 9 / 25
= 7 / 25
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Double-Angle Identities
c) tan 2= 2 tan / (1 tan2)= 2 (- 3 / 4 ) / ( 1 (- 3 / 4 )2
= (- 3 / 2) / (1 9/16)= - 24 / 7
d) sin 2
is negative and cos 2
is positive, so2 is in quadrant IV.
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Other Identities
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Half-Angle Identities
These identities are found taking squareroots and replacing x by x/2 .
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Example: Half-Angle Identities
Find tan(/8) exactly.
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References
Precalculus Graphs & Models. by M. L.
Bittinger et al. Addison Wesley Prentice1996 (pp 321 458 ).