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TMAT 103 Chapter 3 Right-Triangle Trigonometry
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TMAT 103

Jan 02, 2016

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TMAT 103. Chapter 3 Right-Triangle Trigonometry. TMAT 103. § 3.1 The Trigonometric Ratios. § 3.1 – The Trigonometric Ratios. Angle Initial side Terminal side Vertex. § 3.1 – The Trigonometric Ratios. Measurement Degrees Minutes Seconds. § 3.1 – The Trigonometric Ratios. - PowerPoint PPT Presentation
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Page 1: TMAT 103

TMAT 103

Chapter 3

Right-Triangle Trigonometry

Page 2: TMAT 103

TMAT 103

§3.1

The Trigonometric Ratios

Page 3: TMAT 103

§3.1 – The Trigonometric Ratios

• Angle– Initial side– Terminal side– Vertex

Page 4: TMAT 103

§3.1 – The Trigonometric Ratios

• Measurement– Degrees– Minutes– Seconds

Page 5: TMAT 103

§3.1 – The Trigonometric Ratios

•Measurement Tools - Protractor

Page 6: TMAT 103

§3.1 – The Trigonometric Ratios

• Types of angles– Obtuse

• Greater than 90°

– Acute• Less than 90°

– Right• Exactly 90°

Page 7: TMAT 103

§3.1 – The Trigonometric Ratios

• Converting minutes and seconds to degrees– 1’ = 1/60°– 1’’ = 1/3600°– To convert x° y’ z’’ to degrees:

°

x° y’ z’’ =

– Ex: Convert 33° 14’ 52’’ to degrees

360060

zyx

Page 8: TMAT 103

§3.1 – The Trigonometric Ratios

• Converting degrees to minutes, and seconds– Reverse the procedure on the previous slide– To convert x.y to minutes and seconds:

• x is the degrees

• Multiply y by 60– The integer part is the minutes

– Multiply the fractional part by 60 – the new integer part is the seconds

– Ex: Convert 33.71 to degrees, minutes, and seconds

Page 9: TMAT 103

§3.1 – The Trigonometric Ratios

• Pythagorean Theorem (Right triangles)c2 = a2 + b2

Page 10: TMAT 103

§3.1 – The Trigonometric Ratios

• Ex: Find c in the diagram below

Page 11: TMAT 103

§3.1 – The Trigonometric Ratios

• Ex: Find a in the diagram below

Page 12: TMAT 103

§3.1 – The Trigonometric Ratios• Trigonometric ratios

– Relationship between an acute angle of a right triangle and the lengths of its sides

• sin A = side opposite A hypotenuse

• cos A = side adjacent to A hypotenuse

• tan A = side opposite A side adjacent to A

• cot A = side adjacent to A side opposite A

• sec A = hypotenuse side adjacent to A

• csc A = hypotenuse side opposite A

Page 13: TMAT 103

§3.1 – The Trigonometric Ratios

• Ex: Find the 6 trigonometric ratios for A

Page 14: TMAT 103

§3.1 – The Trigonometric Ratios

• Similar triangles– Corresponding angles are equal– Consider sin A in the picture below

• Does it matter if ABC is used, or ADE?

Page 15: TMAT 103

§3.1 – The Trigonometric Ratios

• Examples– Show that cot A = cos A by using the ratios

sin A

– Given that sin A = .8387, and cos A = .5446, compute the remaining 4 trigonometric ratios for A. Round to 4 significant figures.

Page 16: TMAT 103

TMAT 103

§3.2

Values of the Trigonometric Ratios

Page 17: TMAT 103

§3.2 – Values of the Trigonometric Ratios

• Trigonometric ratios of the 60° and 30° angles.

Page 18: TMAT 103

§3.2 – Values of the Trigonometric Ratios

• Trigonometric ratios of the 45° angle.

Page 19: TMAT 103

§3.2 – Values of the Trigonometric Ratios

• Trigonometric ratios of the other angles.– Use a calculator

• Examples:– Find sin 65.25°– Find cot 22° 3’ 44’’– Find if cos = 0.5402

Page 20: TMAT 103

TMAT 103

§3.3

Solving Right Triangles

Page 21: TMAT 103

§3.3 – Solving Right Triangles

• Solving a triangle – Finding unknown values of sides or angles

• Tools needed to solve triangles– Pythagorean theorem– Complementary angles add to 90°– Trigonometric ratios

Page 22: TMAT 103

§3.3 – Solving Right Triangles

• Ex: Find angle A to the nearest hundredth of a degree.

Page 23: TMAT 103

§3.3 – Solving Right Triangles

• Ex: Completely solve the given triangle.

Page 24: TMAT 103

TMAT 103

§3.4

Applications of the Right Triangle

Page 25: TMAT 103

§3.4 – Applications of the Right Triangle

• A pilot is piloting a helicopter in the wilderness at 1200 feet about the ground searching for a downed plane. As the pilot spots it, she measures its angle of depression as 53°. She also spots a road whose angle of depression is 15°. Find the distance of the downed plane to the road.

Page 26: TMAT 103

§3.4 – Applications of the Right Triangle

• The pathway for a mineshaft is described as follows: The first shaft extends north and down at an angle of 3.5° for 225 feet to a vertical shaft which is 125 feet long. A third shaft then extends north and down at an angle of 6.8° for 175 feet. What is the total depth below ground level at the end of the third shaft? Also, what is the net horizontal distance from the ground opening to the end of the third shaft?