Top Banner

of 16

Tín hiệu hệ thống-Lecture 06

Nov 02, 2015

Download

Documents

Kong King

tài liệu khoa điện trường đh Bách khoa tphcm. hcmut
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
  • 7/13/2019 Tn hiu h thng-Lecture 06

    1/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    Lecture-6

    "0"00! T#n $i%u ' $% t$(ng

    Biu din tn hiu bng chui FourierBiu din tn hiu bng chui Fourier

    )i*u +in t#n $i%u -.ng t t#n $i%u tr1 gia3)i*u +in t#n $i%u -.ng t t#n $i%u tr1 gia3

    C$u4i F3urier l56ng gi7C$u4i F3urier l56ng gi7C$u4i F3urier $'m m8 $C$u4i F3urier $'m m8 $7 ng ;a $% t$(ng i t#n $i%u tu?n $3'n7 ng ;a $% t$(ng i t#n $i%u tu?n $3'n

  • 7/13/2019 Tn hiu h thng-Lecture 06

    2/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    )i*u +in t#n $i%u -.ng t t#n $i%u tr1 gia3

    Biu din tn hiu da vo khng gian tn hiu trc giao:

    Tm cntha iu kin nng lng sai s min:

    Sai s:1

    ( ) ( ) ( )N

    n n

    n

    e t f t c x t =

    =

    2

    1

    1 ( ) ( )t

    n nt

    n

    c f t x t dt E

    = Nng lng ca thnh phn sai s min: 2

    1

    N

    e f n n

    n

    E E c E=

    =

    Nng lng ca thnh phn sai s

    0 nu N

    t!p c"s#

    1 1 2 2

    1( ) ( ) ( ) ... ( ) ( )

    N

    N N n n

    nf t c x t c x t c x t c x t

    =+ + + = $

    %hi N & ta c': lu ( )*u +,- .ng / mt nng lng

    1 2

    1

    ( ) ( );n nn

    f t c x t t t t

    =

    = 1hu2i34u5i65

    2

    1

    *1 ( ) ( )t

    n nt

    n

    c f t x t dt E

    = Th7c: 8h9c:

  • 7/13/2019 Tn hiu h thng-Lecture 06

    3/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier l56ng gi7

    Khng gian tn hiu lng gic trc giao:

    0 0 0 0 0 0{1, cos( ), cos(2 ),..., cos( ),....; sin( ), sin(2 ),..., sin( ),...}t t n t t t n t

    0n : gi l hi th9 n 00

    2,

    T

    =

    Biu din f(t) trong khng gian tn hiu lng gic trcgiao:

    0 0 0 1 1 0

    1 1

    ( ) cos( ) sin( );n nn n

    f t a a n t b n t t t t T

    = =

    = + + + 1 0

    1 0

    1

    1 01

    1

    0

    02

    00

    ( )cos( ) 2( )cos( )

    cos ( )

    t T

    t Tt

    n t T t

    t

    f t n t dt

    a f t n t dt Tn t dt

    +

    +

    += = 1 0

    10

    0

    2; ( )sin( )

    t T

    nt

    b f t n t dt T

    +

    = 1 0

    10

    0

    1( )

    t T

    ta f t dt

    T

    +=

    ;it # )

  • 7/13/2019 Tn hiu h thng-Lecture 06

    4/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier l56ng gi7

    Biu din f(t) trong khng gian tn hiu lng gic trcgiao:

    0 0 0 1 1 0

    1 1

    ( ) cos( ) sin( );n nn n

    f t a a n t b n t t t t T

    = =

    = + + + ;it # )

  • 7/13/2019 Tn hiu h thng-Lecture 06

    5/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier l56ng gi7

    Biu din f(t) trong khng gian tn hiu lng gic trcgiao:;> )?: khai t5i@n ABtC,6

    DtEF

    t54ng kh4Gng 0t0 0

    2 / 2T = =

    / 2

    00

    10,504ta e dt

    = =

    / 220

    2 2cos(2 ) 0,504

    1 16tna e nt dt

    n

    = =

    + / 2

    20

    2 8sin(2 ) 0,504

    1 16

    t

    n

    nb e nt dt

    n

    = = +

    ( )21

    2( ) 0.504 1 cos2 4 .s in2nt ; 01 16n

    f t nt n tn

    =

    = + + +

    0 0 0,504C a= =

    2

    20,504

    1 16nC

    n

    = +

    1tan 4n n =

    1

    21

    2( ) 0.504 1 cos(2 tan 4 ) ; 0

    1 16nf t nt n t

    n

    =

    = +

    +

  • 7/13/2019 Tn hiu h thng-Lecture 06

    6/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier l56ng gi7

    nh tu!n hon c"a chu#i $ouri%r lng gic:

    1hu2i 34u5i65 ch4 ABtC chH .ng t54ng kh4Gng tIttIJT0Ng4i kh4Gng tIttIJT0K

    0 0

    1

    ( ) cos( );n nn

    t C C n t for all t

    =

    = + +0( ) ( );t T t for all t = BtC Li@u )iMn ch4 tin hiu tunh4n

    ;!= nu BtC$ tIttIJT0Li@u )iMn ch4 ABtC$ tIttIJT0BtC Li@u)iMn ch4 t>n hiu tun h4n )4 l!p l )?:

  • 7/13/2019 Tn hiu h thng-Lecture 06

    7/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier l56ng gi7

    &hu#i $ouri%r lng gic c"a tn hiu tu!n hon:

    0 0 0

    1 1

    ( ) cos( ) sin( )n nn n

    f t a a n t b n t

    = =

    = + +

    0 0

    1

    ( ) cos( )n nn

    f t C C n t

    =

    = + +

    00

    0

    2( )cos( )n

    Ta f t n t dt

    T

    =

    00

    0

    2( )sin( )n

    Tb f t n t dt

    T=

    00

    0

    1( )

    Ta f t dt

    T=

    0 0C a=

    n n nC a b= +

    1tan nnn

    b

    a

    =

  • 7/13/2019 Tn hiu h thng-Lecture 06

    8/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier l56ng gi7

    ' d :

  • 7/13/2019 Tn hiu h thng-Lecture 06

    9/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier l56ng gi7

    ' d *:

  • 7/13/2019 Tn hiu h thng-Lecture 06

    10/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier l56ng gi7

    +i,u kin t-n t.i chu#i $ouri%r:

    0( )

    Tf t dt<

    TQn t

  • 7/13/2019 Tn hiu h thng-Lecture 06

    11/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier $'m m8 $

    /0 tn hiu h1 12 trc giao:

    { }0 ; 0, 1, 2,....jn te n =

    &hu#i $ouri%r h1 12:

    0

    ( ) jn t

    nn

    f t D e

    ==( )0

    0

    *1( )

    jn t

    nT

    n

    D f t e dtE

    =

    00

    0

    1( )

    jn t

    nT

    D f t e dtT

    =

  • 7/13/2019 Tn hiu h thng-Lecture 06

    12/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier $'m m8 $

    34i li5n h gi6a chu#i $ouri%r h1 12 0h7c 8 chu#i$ouri%r

    lng gic:0cos( )n nC n t + ( )0 0( ) ( )

    2n nj n t j n tnC e e

    + += +

    nD nD

    0 01

    ( ) cos( )n nn

    f t C C n t

    == + +( )0 00

    1

    ( ) jn t jn t

    n n

    n

    f t D D e D e

    =

    = + + 0jn tnn

    D e

    =

    =

    9.ng h1 12 8lng gic l

    tng ;ngth

  • 7/13/2019 Tn hiu h thng-Lecture 06

    13/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier $'m m8 $

    0 0

    2

    2

    n

    n

    jnn

    jnn

    D C

    CD e

    CD e

    =

    =

    =

    1,2,3,...n=

    >h? $ouri%r:

    0 0;D C=

    1

    2n n n

    D D C= =8h\ Li[n ]: Bch@nC

    8h\ pha: BlAC; ;n n n nD D = =

    34i li5n h gi6a chu#i $ouri%r h1 12 0h7c 8 chu#i$ouri%r

    lng gic:

  • 7/13/2019 Tn hiu h thng-Lecture 06

    14/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    C$u4i F3urier $'m m8 $

    +nh lC >arD%val :

    0 0

    1

    ( ) cos( )n nn

    f t C C n t

    == + +

    2 2

    0

    1

    12

    f n

    n

    P C C

    =

    = +

    0( ) jn t

    n

    n

    f t D e

    =

    = 2 2201

    2f n nn n

    P D D D

    = =

    = = +

    1Wng su*t ca t>n hiu tun h4n LXng t\ng cWng su*t ca t*tcG c^c hi

  • 7/13/2019 Tn hiu h thng-Lecture 06

    15/16

    Signal & Systems- Tran Quang Viet FEEE, HCMUT Semester: 02/09!0

    7 ng ;a $% t$(ng i t#n $i%u tu?n $3'n

    00

    0

    2( ) ;

    jn t

    n

    nf t D e T

    == =

    ( )j t j te H j e

    input

    _utput

    0 0

    0( )jn t jn t

    n n

    n n

    D e D H jn e

    = =

    `nput ABtC _utput=BtC

    (EF)

    u!n honc=ng chukG vHi f(t)

    +0 7ng c"a h th4ng EF& vHi tn hiu tu!n hon :

  • 7/13/2019 Tn hiu h thng-Lecture 06

    16/16

    Signal & Systems - Tran Quang Viet FEEE HCMUT Semester: 02/09!0

    7 ng ;a $% t$(ng i t#n $i%u tu?n $3'n

    ' d :

    2

    2

    2

    ( ) (1 4 )

    j nt

    nf t en

    == (3 1) ( ) ( )D y t f t+ =( ) 1/(3 1)

    ( ) 1/(3 1)

    H s s

    H j j

    = += +

    2

    2

    2( )

    (1 4 )( 6 1)

    j nt

    n

    y t en j n

    =

    = +

    2

    r 2 2 2 21 1

    8 1P 2 | |

    (1 4 ) (36 1)ipple n

    n n

    Dn n

    = =

    = = +

    rP 0.025

    ipple= rP 0.05ipple =