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n mn hc cng ngh ch to my Page 1
I HC BCH KHOA H NI Cng ha x hi ch ngha Vit Nam
VIN C KH c lp- t do- hnh phc
B MN CNG NGH CH TO MY
NHIM V:
THIT K N MN HC CNG NGH CH TO MY
H v tn: Nguyn Quyt lp: CTM1-K53
I/ u thit k:
Thit k quy trnh cng ngh ch to chi tit dng: TRC
II/ Cc s liu ban u:
Sn lng hng nm: 10000 chi tit
iu kin sn xut: my cng c truyn thng
III/ Ni dung cc phn thuyt minh v tnh ton:
1. Phn tch chc nng lm vic ca chi tit
2. Phn tch tnh cng ngh trong kt cu ca chi tit
3. Xc nh dng sn xut
4. Chn phng php ch to phi
5. Lp th t cc nguyn cng (v s g t,k hiu,nh v,kp
cht,chn my,chn dao,k hiu chiu chuyn ng ca dao v chi tit)
6. Tnh lng d cho mt b mt(mt trn ngoi,trong hoc mt
phng)V tra lng d cho cc b mt cn li
7. Tnh ch ct cho 1 nguyn cng(cho nguyn cng cn thit k
g) v tra ch ct cho cc nguyn cng cn li
8. Tnh thi gian gia cng c bn cho tt c cc nguyn cng.
9. Tnh v thit k 1 g( s g t,lc kp,thit k cc c cu ca
g,tnh sai s chun,sai s kp cht,sai s mn,sai s iu chnh,sai s
ch
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n mn hc cng ngh ch to my Page 2
to cho php,t yu cu k thut ca g,lp bng k khai cc chi tit
g, thit k g gia cng t kch thc,tp thuyt minh phi c bn gc
nhim v thit k v bn v chi tit)
IV/ Phn bn v:
1. Chi tit lng phi: 1 bn (kh A0 hay A1)
2. S nguyn cng: 1 bn ( kh A0)
3. g: 1 bn ( kh giy A0 hay A1)
H ni ngy 30 thng 8 nm 2011
Ngi nhn: ging vin hng dn:
(h tn v ch k) (h tn v ch k)
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n mn hc cng ngh ch to my Page 3
Li ni u
Mn hc cng ngh ch to my ng vai tr quan trng trong
chng trnh o to k s v cn b k thut v thit k v ch to cc loi
my, cc thit b phc v cc ngnh cng nghip, nng nghip, giao thng
vn ti ...
n mn hc cng ngh ch to my k 9 l mt trong cc n c
tm quan trng nht i vi mt sinh vin khoa c kh. n gip cho sinh
vin hiu nhng kin thc hc khng nhng mn cng ngh ch to my
m cc mn khc nh: my cng c, dng c ct... n cn gip cho
sinh vin c hiu dn v thit k v tnh ton mt qui trnh cng ngh ch
to mt chi tit c th.
c s gip v hng dn tn tnh ca thy Trng Honh Sn
trong b mn cng ngh ch to my n nay n mn hc ca em
hon thnh. Tuy nhin vic thit k n khng trnh khi sai st em rt
mong c s ch bo ca cc thy v s ch bo ca cc bn.
Em xin chn thnh cm n thy Trng Honh Sn gip em
hon thnh cng vic c giao.
H Ni, ngy 06/8/2011
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I.Phn tch chc nng lm vic ca chi tit:
*Chi tit tit c thit k l chi tit Trc Qut Trn:
Vi sn lng 10.000 chic/ nm iu kin sn xut truyn thng
- Vt liu ch to trc l thp C45.
- chi tit chu ti trng v mment xon kh ln
- Nhng kch thc quan trng l nhng b mt lp ghp, i hi chnh
xc cao v hnh dng hnh hc v v tr tng quan.Nhng b mt ny i
hi pha m bo bng b mt, ng tm, vung gc cc b mt
cn thit trc lm vic c lu di, trnh gy mi mn cho cc b
mt.
-kch thc on trc c ng knh 17dng lp ln nh hng ln nht ti cht lng
chi tit,cc b mt khc t nh hng ti cht lng ca
chi tit
* Cc yu cu k thut ca chi tit l:
- Mt tr A cn c gia cng vi chnh xc, bng b mt cao
lp vi chi tit khc.
- ng tm gia mt lp ghp A v 17 l 0,02mm. - vung gc gia cc ng tm
phi chnh xc, nm trong khong 0,1
/100mm bn knh.
II. Phn tch tnh cng ngh trong kt cu ca chi tit:
- Trc c ng knh gim dn v hai pha cc b mt ca trc c kh nng
gia cng c bng cc dao thng thng c th tin dao thng sut
- ng knh trc nh nht c th m vn m bo chc nng lm vic
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- L/D
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Trong :
Q1: khi lng ca chi tit
V: th tch ca chi tit
: khi lng ring ca vt liu
Th tch ca chi tit (tnh gn ng):
V=L.d2/4=11.73.142.22/4= 0.0445(dm3)
Vi thp = 7.852 Kg/dm3
Ta c: Q=0.04457.852=0.350(Kg)
Da vo gi tr tnh toan cua N v Q1 tra bangr 2.6 ta xc nh dc
dng
sn xut ca sn phm l lot ln
IV.Chn phng php ch to phi
Dng sn xut l lot ln, chi tit l trc bc c chnh ng knh khng
ln nn ta dng phi cn nng, tit din trn cho chnh xc thng v
cao, gim ng k c lng d gia cng, gp phn gim gi thnh sn
phm.
V.Th t nguyn cng
5.1 Thit k s b nguyn cng
* Nguyn cng 1: gia cng to chun
Kha mt u v khoan hai l tm: tin hnh trong mt nguyn cng, ng
thi thc hin phay mt u v hai khoan l tm c hai pha trn ma
chuyn dung
*Nguyn cng 2: tin th v tin tinh mt ngoi ca trc
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G trc trn hai mi tm ca my tin ren vt vn nng, tin th v tinh
trong mt ln g t tin th mt ngoi,tin tinh on trc c ng knh
17 dng lp ln *Nguyn cng 3: ln nhm on trc c ng knh 19 dng l Stato
*Nguyn cng 4: Khoan, doa l 6 trn my khoan ng *Nguyn cng 5: Khoan l
8 trn my khoan ng *Nguyn cng 6: Khoan cc l 6,8 trn my khoan ng
*Nguyn cng 7: nhit luyn chi tit t cng yu cu
*Nguyn cng 8: mi th, mi tinh on trc c ng knh 17 dng lp ln.Mi
phng mt phn trn trc tai v tr cn gia cng l trn trc trn
my mi chuyn dung
*Nguyn cng9: kim tra ng tm ca on trc lp ln
5.2 Thit k nguyn cng
*Nguyn cng 1:kha mt u v khoan l tm
-nh v v kep cht: dy l nguyn cng u tin nn chun gia cng l
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chun th,l mt tr ngoi ca phi.Chi tit gia cng c nh v v kp
cht trn khi V t nh tm
-Chn my:chon may chuyn dng 6902M2 cng sut ng c N = 3kW(tra bng
9-31s tay CNCTM tp 3)
-chn dao : dao phay mt u bng thp gi P18 c kch thc D = 50mm,L
=36mm, d = 22mm, s rng 10 (tra bng 4-92 s tay CNCTM tp 1)
Mi khoan tm chuyn dng P18
*Nguyn cng 2: tin th, tin tinh, mt ngoi ca trc
-nh v v kp cht:nh v bng 2 l tm, g trn hai mi tm.dng tc
kp truyn chuyn ng quay cho trc.lc kp theo phng dc trc
-Chon my: my tin ren vt vn nng 1K62
-Chn dao: dao tin ngoi thn thng gn mnh hp kim cng
Kch thc H = 16mm; B = 10mm; L =100mm ; = 45 dao tin rnh thn cong
gn mnh thp gi P18
Kch thc H = 16mm; B = 10mm; L =100mm
(tra bng 4-5 v 4-8 s tay CNCTM tp 1)
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*Nguyn cng 3:ln nhm on trc 19
-nh v v kp cht:nh v bng 2 l tm, g trn hai mi tm.dng tc
kp truyn chuyn ng quay cho trc.lc kp theo phng dc trc
-Chn my :my mai trn ngoi 3A130
-Dng c ln nhm : S dng con ln tr
*Nguyn cng 4: khoan doa l 6
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-nh v v kp cht: dnh v bng 2 khi V ngn khng ch 4 bc t do,vai
trc t ln than khi V khng ch 1 bc t do
-Chn my: my khoan ng 2A125 c dng knh mi khoan c bn
trung bnh ln nht l 25.Cng sut ca my N = 2.8kW(tra bng 9-1b s tay
CNCTM tp 3)
-Chon dao:- mi khoan rut g bng thp gi ui cn,loi ngn c ng
knh d =5.8mm c cc kch thc: chiu di L =138mm,chiu di lm vic l
=57mm, mi doa lin khi chui tr P18 c kch thc D = 2 16mm, L =
49170mm, l =11 52mm(tra bng 4-42 ; 4-47s tay CNCTM tp 1)
*Nguyn cng 5: khoan l 8 -nh v v kp cht: dnh v bng 2 khi V ngn
khng ch 4 bc t do,vai
trc t ln than khi V khng ch 1 bc t do
-Chn my: my khoan ng 2A125 c dng knh mi khoan c bn
trung bnh ln nht l 25.Cng sut ca my N = 2.8kW(tra bng 9-1b s tay
CNCTM tp 3)
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-Chon dao :- mi khoan rut g bng thp gi ui cn,loi ngn c ng
d =8mm c cc kch thc: chiu di L=156mm,chiu di lm vic l= 75mm
*Nguyn cng 6:khoan l 8, khoan l 12 -nh v v kp cht: dnh v bng 2
khi V ngn khng ch 4 bc t do,u
trc t ln phin t khng ch 1 bc t do lc kp theo phng vung gc
vi trc.
-Chn my: my khoan ng 2H125 c dng knh mi khoan c bn
trung bnh ln nht l 25.Cng sut ca my N = 2.8kW (tra bng 9-1b s
tay CNCTM tp 3)
-Chon dao :- mi khoan rut g bng thp gi ui cn,loi ngn c ng
knh d =12mm c cc kch thc: chiu di L =182mm,chiu di lm vic l
= 101mm v d = 8mm c cc kch thc: chiu di L =156mm,chiu di lm
vic l = 75mm (tra bng 4.42 s tay CNCTM tp 1)
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*Nguyn cng 7: nhit luyn v sa li l tm
*Nguyn cng 8:mi 2 mt tr ngoi 17 nh v v kp cht:nh v bng 2 l tm, g
trn hai mi tm.dng tc kp
truyn chuyn ng quay cho trc.lc kp theo phng dc trc
-Chn my :my mi trn ngoi 3A110B,my c cng sut la N = 2,2 kW
-Chon :chn loi profin thng co kich thc D =325mm H = 1 40 mm,d =
1 68mm(tra s bng 4-170tay CNCTM tp 1)
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*Nguyn cng 9 :kim tra
VI.Tnh ton lng d gia cng
V chi tit gia cng dc g trn 2 mi tm nn sai s g t theo phng
hng knh trong trng hp ny gd=0.
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Lng d gia cng ti thiu c tnh theo cng thc:
2Zmin=2(RZ i-1+Tai-1+i-1) Sai lch v v tr khng gian ca phi c xc
nh nh sau:
= (c2+ lt2 )1/2
c: lch tm l Ta c: c =k.L k: cong n v trn 1mm chiu di. L: chiu di
mt gia cng L= 61mm
Tra bng 3.7 HDTK ACN CTM k= 0.15m c= 0.1561=9.15m lt: cong tm
lt=( ph2/4 + 0.252)1/2 ph tra bng 3.53 S tay CNCTM tp 1 ta c
c=1.1mm 0.25_ sai s do iu chnh my khi khoan l tm
lt=( 1.12/4 + 0.252)1/2 = 0.604 = 604m Do sai lch v v tr khng
gian ca phi l: = (6042 + 9.152)1/2 604m Sai lch khng gian cn li sau
tin th
1 = 0.06 ph = 0.06 604 = 37m Sai lch khng gian cn li sau tin
tinh
2 = 0.04 ph = 0.04 604 = 25m Sai lch khng gian cn li sau tin
th
3 = 0.02 ph = 0.02 604 = 12m
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Gi tr Ta , Rz ca bc cng ngh tra theo bng 3.5 HDTKDACNCTM
Dung sai ca mi bc cng ngh tra bng 3.91 S tay CNCTM tp 1
Ta c :
Lng d ti thiu sau khi tin th :
2Zmin1 =2(150 + 150 + 604) = 2 904m
Lng d ti thiu sau khi tin tinh
2Zmin2 =2(50 + 50 + 37) = 2 137m
Lng d ti thiu sau khi mi th :
2Zmin3 =2(30 + 30 + 25) = 2 85m
Lng d ti thiu sau khi mi tinh :
2Zmin4 =2(10 + 20 + 12) = 2 42m
Kch thc tnh ton cc chi tit :
Mi th : dt3 = 17.001 + 2 0.042 = 17.085 mm
Tin tinh : dt2 = 17.084 + 2 0.085 = 17.225 mm
Tin th : dt1 = 17.225 + 2 0.137 = 17.592 mm 17.6 mm Phi : dph =
17.592 + 2 0.904 = 19.337 mm 19.4 mm Kch thc gii hn ln nht :
Mi tinh : dmax4 = 17.001 + 0.013 = 17.014 mm
Mi th : dmax3 = 17,085 +0.085 = 17.137 mm
Tin tinh: dmax2 = 17.225 + 0.130 = 17.355 mm
Tin th : dmax1 = 17.8 + 0.210 = 18.01 mm
Phi : dmaxph = 19.4 + 1.1 = 20.5 mm
Lng d gii hn :
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Zghimax : lng d gii hn ln nht
Zghimim : lng d gii hn nh nht
Ta c :
Mi tinh : 2Z4max = 17.137 17.014 =123m
Mi th : 2Z3max= 17.385 17.137 =248m
Tin tinh : 2Z2max = 18.01 17.385 =625m
Tin th : 2Z1max= 20.05 18.01 =2490m
Mi tinh : 2Z4min = 17.085 17.001 =84m
Mi th : 2Z3min = 17.225 17.085 =170m
Tin tinh : 2Z2min = 17.60 17.255 = 345m
Tin th : 2Z1min = 19.4 17.6 =1800m
Lng d tng cng ln nht:
Z0max = Zmax = 123 + 248 + 624 +2490 =3486 m Lng d tng cng nh
nht:
Z0min = Zmin = 84 + 170+ 345 +1800 =2399 m Lng d danh ngha :
Z0dn = Z0min +700 1 =3098m
700_ gii hn di ca phi
1_ gii hn di cua chi tit
Kch thc danh ngha ca ng knh :
d0dn= 17.001 + 3.098 =20.099 mm 20.1mm
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Kim tra chnh xc ca tnh ton th hin :
Z0max Z0min =ph ct Tht vy:
3486 2399 =1100 13 =1087
Lng d gia cng cc kch thc gii hn trung gian ca mt trc
Bc
cng ngh
Cc thnh phn ca
lng d (m)
Lng
d tnh
ton
Zmin
(m)
Kch
thc
tnh
ton dti
(mm)
Dung
sai (mm)
Kch thc gii
hn (mm)
Lng d
gii hn
(m)
Rza
Ta a
b
dmin dmax Zbmin Zbmax
Phi 150 150 604 0 - 20,5 1,1 19,4 20,5 - -
Tin th 50 50 37 0 2904 17,8 0,21 17,8 18,01 1800 2490 Tin tinh
30 30 25 0 2137 17,225 0,13 17,225 17,355 345 625 Mi th 10 20 12 0
285 17,085 0,085 17,085 17,137 170 248 Mi tinh 5 15 - 0 242 17,001
0,013 17,001 17,014 84 123 Tng cng
2399 3486
*Tra lng d cho cc b mt cn li:
-kha mt u: 3mm
-Doa l 6: 0,1mm -khoan l 12: 2mm
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VII.Xc inh ch ct
7.1 tnh ch ct cho nguyn cng thit k g
a. khoan l 8 bng mi khoan rut g thp gi, D = 8 mm *Chiu su ct ,
t= 4 mm
*Lng chy dao S
Theo bng 5-25 ( STCNCTM) tp 2 ta c :
Lng chay dao th Ssb = 0.150.2 (mm/vng)
Chn Ssb = 0.2 mm/vng
S = Ssbkhc = 0.2 (0.910.751) = 0.135mm/vng
Chn S = 0.15mm/vng
* Tnh tc ct khi khoan l :
. Vt= ymv
qv
STKDC
+ H s Cv v cc s m dng cho khoan cho bng 5-28 STCNCTM1 , ta
c:
+ H s Cv=7 q=0.4 y=0.7 m=0.2
+ H s iu chnh chung cho tc ct tnh n cc i kin thc t :
Kv=Kmv.Kuv.Klv
+ Kmv : h s ph thuc vo vt liu gia cng (bng 5-145-4)
Kmv=
vn
b
750=
9.0
610750
= 0.83
+ Kuv: h s ph thuc vo vt liu dng c ct (bng 5-6
STCNCTM1)Kuv=1
+ Klv: h s ph thuc vo chiu su khoan (bng 5-31 STCNCTM1)
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Klv= 1
Tui bn trung bnh ca mi khoan T=25(pht) (bng 5-30 STCNCTM1)
Vt = 1183.015.02587
7.02.0
4.0
=26.49(m/pht)
S vng quay trc chnh l :
nt=
D
Vt.
.1000
=814.349.261000
=1054.54(vng/pht)
+Chn theo my nm = 1120 (vng/pht) , cp tc 10 . Do
Vt = 100011208
= 28.15 (m/pht)
* Tnh lc chiu trc Po (N) v m men xon M (Nm).
- Cng thc tnh l Po v m men xon M khi khoan l l .
. pyq
M kSDCx = 10 ; pyq
p kSDC = 10
-Tr s Cm ;Cp v cc s m c tra trong bng 5-32 .
CM = 0.0345 , q=2 , y=0.8 (h s cho m men )
CP = 68 , q=1 , y = 0.7
kP : H s tnh n cc yu t gia cng thc t
kP= kmP= 75.075.0
750610
=0.81
Mx= 100.034582 0.150.8 0.81 = 3.92 (N.m)
Po = 106880.15 0.70.81 = 1167.74( N )
- Cng thc tnh cng sut ct :
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Ne = 9750.nM x = 3.921060/9750 = 0.43 kW
- So snh vi cng thc my :
Nc Ne - Ngha l : 0.047 kW 2.2 0.8 = 1.76 kW
- Vy my 2H125 cng sut gia cng l 8 b. khoan l 6 bng mi khoan rut
g thp gi, D =5.8 mm *Chiu su ct , t= 2.9 mm
*Lng chy dao S
Theo bng 5-25 ( STCNCTM) tp 2 ta c :
Lng chay dao th Ssb = 0.10.15 (mm/vng)
Chn Ssb = 0.15 mm/vng
S = Ssbkhc = 0.15 (0.910.751) = 0.1mm/vng
Chn S = 0.1mm/vng
* Tnh tc ct khi khoan l :
. Vt= ymv
qv
STKDC
+ H s Cv v cc s m dng cho khoan cho bng 5-28 STCNCTM1, ta c:
Cv=7 q=0.4 y=0.7 m=0.2
+ H s iu chnh chung cho tc ct tnh n cc i kin thc t :
Kv=Kmv.Kuv.Klv
Kmv : h s ph thuc vo vt liu gia cng (bng 5-145-4)
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Kmv=
vn
b
750=
9.0
610750
= 0.83
Kuv: h s ph thuc vo vt liu dng c ct (bng 5-6 STCNCTM1)
Kuv=1
Klv: h s ph thuc vo chiu su khoan (bng 5-31 STCNCTM1)
Klv= 1
Tui bn trung bnh ca mi khoan T=25(pht) (bng 5-30 STCNCTM1)
Vt = 1183.01.0258.57
7.02.0
4.0
=30.9(m/pht)
S vng quay trc chnh l :
nt=
D
Vt.
.1000
=8.514.39.301000
=1695.8(vng/pht)
- Chn theo my nm = 1500(vng/pht) , cp tc 11 . Do
Vt = 100015008.5
= 27.33 (m/pht)
* Tnh lc chiu trc Po (N) v m men xon M (Nm).
- Cng thc tnh l Po v m men xon M khi khoan l l .
. pyq
M kSDCx = 10 ; p
yqp kSDC = 10
-Tr s Cp ; CMv cc s m c tra trong bng 5-32 .
CM = 0.0345 , q=2 , y=0.8 (h s cho m men )
CP = 68 , q=1 , y = 0.7
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kP : H s tnh n cc yu t gia cng thc t kP= kmP=75.075.0
750610
=0.81
Mx= 100.03455.82 0.10.8 0.81 = 1.49 (N.m)
Po = 10685.80.1 0.70.81 = 637.4( N )
-Cng thc tnh cng sut ct:
Ne = 9750.nM x = 1.491500/9750 = 0.23 kW
- So snh vi cng thc my:
Nc Ne - Ngha l : 0.23 kW 2.2 0.8 = 1.76 kW
- Vy my 2H125 cng sut gia cng l 6 c. Doa l 6 bng , D =6 mm *Chiu
su ct , t= 0.1 mm
*Lng chy dao S
Theo bng 5-27 ( STCNCTM) tp 2 ta c :
Chn S = 0.8mm/vng
* Tnh tc ct khi khoan l :
. Vt= yxmv
qv
StTKDC
. H s Cv v cc s m dng cho khoan cho bng 5-28 STCNCTM1 ,
ta c:
+ H s Cv=10.5 q=0.3 x = 0.2 y=0.65 m=0.4
+ H s iu chnh chung cho tc ct tnh n cc i kin thc t :
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Kv=Kmv.Kuv.Klv
. Kmv : h s ph thuc vo vt liu gia cng (bng 5-145-4)
Kmv=
vn
b
750=
9.0
610750
= 0.83
. Kuv: h s ph thuc vo vt liu dng c ct (bng 5-6
STCNCTM1)Kuv=1
. Klv: h s ph thuc vo chiu su khoan (bng 5-31 STCNCTM1)
. Klv= 1
Tui bn trung bnh ca mi khoan T=25(pht) (bng 5-30 STCNCTM1)
Vt = 1183.08.01.02565.10
65.02.04.0
3.0
=7.54(m/pht)
S vng quay trc chnh l :
nt=
D
Vt.
.1000
=614.354.71000
=400(vng/pht)
- Chn theo my nm = 450(vng/pht) , cp tc 7 . Do
Vt = 10004506
= 8.48 (m/pht)
* Tnh lc chiu trc Po (N) v m men xon M (Nm).
- Cng thc tnh l Po v m men xon M khi doa l l .
. ZDStCx yzx
p
=10021
; p
yqp kSDC = 10
-Tr s CP v cc s m c tra trong bng 5-32 .
CP = 68 , q=1 , y = 0.7
-
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kP : H s tnh n cc yu t gia cng thc t kP= kmP= 75.075.0
750610
=0.81
-Tr s Cp v cc s m c tra trong bng 5-23
Cp = 200 x = 1 y = 0.75
Mx= 2000.1 0.080.75 610 = 0.9 (N.m)
Po = 106860.08 0.70.81 = 564.04( N )
- Cng thc tnh cng sut ct :
Ne = 9750.nM x 0.9450/9750 = 0.042 kW
- So snh vi cng thc my :
Nc Ne - Ngha l : 0.042 kW 2.2 0.8 = 1.76 kW
- Vy my 2H125 cng sut gia cng l 6 7.2 tra ch ct ch nguyn cng cn
li
*Nguyn cng 1
Phay mt u:lng chy dao Sz = 0.05 mm/vng(bng 5-119 S tay
CNCTM tp 2)
Vn tc ct V =54 m/ph
(bng 5-119 S tay CNCTM tp 2)
Tc quay ca trc chnh: n = DV
1000=
2414.3541000
=716 vng/ph
Ly theo my nm =750 vng/ph
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Vn tc ct thc t V = 1000
24750 =57.3 m/ph
Khoan l tm
*Nguyn cng 2:
-Tin th 22 : chiu su ct t = 2mm
Lng chy dao S = 0.3 mm/vng (bng 5-60 S tay CNCTM tp 2)
Vn tc ct Vtb =106 m/pht
Tui bn dng c T = 90 pht (bng 5-66 S tay CNCTM tp 2)
Vc = Vtb hc = 1060.9110.9 =86.8 m/ph
Tc quay ca trc chnh: n = D
V
1000=
2414.38.861000
=1151 vng/ph
Ly theo my nm =1000 vng/ph
Vn tc ct thc t V = 1000
241000 =75.4 vng/ph
Cng sut ct N =1.7 kW (bng 5-68 S tay CNCTM tp 2)
Cng sut ca ng c N = 7.5k W. Vy Nyc
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Tc quay ca trc chnh: n = DV
1000=
2214.38.861000
=1255 vng/ph
Ly theo my nm =1250 vng/ph
Vn tc ct thc t V = 1000
221250 =86.4 vng/ph
Cng sut ct N =1.7 kW (bng 5-68 S tay CNCTM tp 2)
Cng sut ca ng c N = 7.5k W. Vy Nyc
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Tui bn dng c T = 90 pht (bng 5-66 S tay CNCTM tp 2)
Vc = Vtb hc = 1060.9110.9 =86.8 m/ph
Tc quay ca trc chnh: n = D
V
1000=
1914.38.861000
=1454 vng/ph
Ly theo my nm =1500 vng/ph
Vn tc ct thc t V = 1000
191500 =89.5 vng/ph
Cng sut ct N =1.7 kW (bng 5-68 S tay CNCTM tp 2)
Cng sut ca ng c N = 7.5k W. Vy Nyc
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Lng chy dao S = 0.1mm/vng
Tc ct V = 35m/ph
Tc quay ca trc chnh: n = D
V
1000=
19351000
=586vng/ph
Ly theo my nm =600 vng/ph
Vn tc ct thc t V = 1000
19600 =35.8 vng/ph
Cng sut ct N =1.7 kW (bng 5-68 S tay CNCTM tp 2)
Cng sut ca ng c N = 7.5k W. Vy Nyc
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Vn tc ct thc t V =1000
12475 =17.9 m/ph
Cng sut ct N (tra bng 5-88 s tay CNCTM tp 2) N = 0.8 kW
So snh vi cng thc my :
Nc Ne - Ngha l : 0.8 kW 2.2 0.8 = 1.76 kW
-khoan l 8 Chiu su ct t = 4 mm
Lng chy dao S (tra bng 5-87 s tay CNCTM tp 2)
S=0.16mm/vng
Tc ct V (tra bng 5-86 s tay CNCTM tp 2) V =17m/ph
Tc quay trc chnh n = D
V
1000=
8171000
= 676 vng/ph
Ly theo my n = 600 vng/ph
Vn tc ct thc t V =1000
8600 =15 m/ph
Cng sut ct N (tra bng 5-88 s tay CNCTM tp 2) N = 0.8 kW
So snh vi cng thc my :
Nc Ne - Ngha l : 0.8 kW 2.2 0.8 = 1.76 kW Nguyn cng 7 :nhit
luyn
Nguyn cng 8: mi trc 17 *mi th
Tra bng 5-203 s tay CNCTM tp 2
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Lng chy dao ngang S = 3mm/ph
S vng quay ca chi tit nct = 300 vng/ph
*mi tinh
Tra bng 5-204 s tay CNCTM tp 2
Lng chy dao ngang S = 2.33mm/ph
S vng quay ca chi tit nct = 500 vng/ph
VIII. Tnh thi gian gia cng c bn cho tt c cc nguyn cng:
Thi gian gia cng cho cc nguyn cng c tnh nh sau:
Tng = Tcb + Tph + Tphv + Tk
- Tcb l thi gian gia cng c bn c tnh theo s gia cng c th
(bng 5.35.9)
- Tl thi gian ph Tph=10% Tcb
- Tpv l thi gian phc v: Tphv = Tpvkt + Ypvtc
Tpvkt: l thi gian phc v k thut Tpvkt=3% Tcb
Tpvtc: l thi gian phc v t chc Tpvtc=2% Tcb
Tphv =5% Tcb
- Tk l thi gian ngh ca cng nhn Tk=10% Tcb
Vy Tng = Tcb + Tph + Tphv + Tk=125%Tcb
Nguyn cng 1 : Kha mt u v khoan l tm
Khoan l tm: phtnSLL
Tcb 26,01,0.50067
.1
=
+=
+=
mmL
mmggdL
7
65,030cot215,3)25,0(cot
21
=
=+=+=
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Phay mt u: phtnS
LLLTcb 099,05,0.75010522
.21
=
++=
++=
Thi gian ca nguyn cng 1: Tng1 = 1,25(0,26+0,099) =0,449 pht
Nguyn cng 2: Tin th v tin tinh ng knh trc
Tin th 22:
mmLmmL
mmtgtg
tL
1173)31(
32452)25,0(
2
1
=
==
=+=+=
pht
nSLLLTcb 41,03,01000
33117.
21=
++=
++=
Tin th 19:
mmLmmL
mmtgtg
tL
1053)31(
32452)25,0(
2
1
=
==
=+=+=
pht
nSLLLTcb 30,03,01250
33105.
21=
++=
++=
Tin th 16,5:
mmL
mmtgtg
tL
41
32452)25,0(1
=
=+=+=
pht
nSLLTcb 1,005,0.750
341.
1=
+=
++=
Tin bn tinh 17:
-
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mmLmmL
mmtgtg
tL
92)31(
32452)25,0(
2
1
=
==
=+=+=
pht
nSLLLTcb 1,022,0.1500
2392.
21=
++=
++=
Tin tinh 17:
mmLmmL
mmtgtg
tL
92)31(
32452)25,0(
2
1
=
==
=+=+=
pht
nSLLL
Tcb 13,0213,0.15002392
.21
=++
=++
=
Tin sn rnh:
mmLmmL
12)31(2
=
==
pht
nSLL
Tcb 15,031,0.600213
.1
=+
=+
=
Tin vt mp:
mmLmmL
12)31(2
=
==
pht
nSLLTcb 06,021,0.1000
213.
1=
+=
+=
Thi gian ca nguyn cng 2:
Tng2 = 1,25(0,41+0,3+0,1+0,1+0,13+0,15+0,06) =1,563 pht
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Nguyn cng 3:ln nhm
phtnthT
ctcb 11,001,0.450
5,025,1.
25,1 ===
Thi gian ca nguyn cng 3:Tng3 = 1,250,11=0,138
Nguyn ng 4: khoan doa l 6 Khoan:
mmL
mmL
mmgdDL
5,162)31(
7)25,0(cot2
2
1
=
==
=+
=
pht
nSLLL
Tcb 11,015,0.1500275,16
.21
=
++=
++=
Doa
mmLmmL
mmgdDL
5,162)31(
7)25,0(cot2
2
1
=
==
=+
=
pht
nSLLLTcb 08,08,0.400
275,16.
21=
++=
++=
Thi gian ca nguyn cng 4:Tng4 = 1,25(0,11 +0,08) =0,238 pht
Nguyn cng 5: khoan l 8
mmL
mmgdDL
13
10)25,0(cot21
=
=+
=
pht
nSLL
Tcb 14,015,0.11201013
.1
=
+=
+=
Thi gian ca nguyn cng 5:Tng5 = 1,250,14=0,175
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Nguyn cng 6: khoan l 8; 12 L12
mmL
mmgdDL
34
14)25,0(cot21
=
=+
=
pht
nSLL
Tcb 51,02,0.4753414
.1
=
+=
++=
l 8
mmLmmmmL
mmgdDL
243)31(
10)25,0(cot2
2
1
=
==
=+
=
pht
nSLLLTcb 39,016,0.600
31024.
21=
++=
++=
Thi gian ca nguyn cng 6:Tng6 = 1,25(0,51+0,39) =1,125 pht
Nguyn cng 8: mi th v mi tinh
Mi th: Tcb = 0,15ld = 0,15917 =0,023 pht
Mi tinh: Tcb = 0,18ld = 0,18917 =0,028 pht
Thi gian ca nguyn cng 8:Tng8 = 1,25(0,023+0,028) =0,064 pht
Tng thi gian gia cng:
T=0,449+1,563+0,138+0,238+0,175+1,125+0,064 =3,752 pht
IX.thit k g gia cng chi tit
9.1Xc nh kch thc bn my : my khoan ng 2H125
Khong cch t ng tm truicj chnh ti tr : 250mm
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Khong cch ln nht t mt trc chnh ti bn : 700mm
Kch thc b mt lm vic ca bn my : 400450 mmmm
Dch chuyn ln nht ca trc chnh : 170 mm
Lc tin dao : 900 kG
Cng sut ca my : 2.2 kW
9.2 Xc nh phng php nh v
S dng c nh v l 2 khi V ngn khng ch 4 bc t do,vai ca tr t vo
mt bn ca khi V khng ch 1 bc t do,.d tng cn vng cho chi tit
khi gia cng s dng them cht t ph t vo du trc 16.5 9.3 kch th nh
v:
+phin dn +cht t ph
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Khi V
9.4 xc nh phng chiu ca lc ct,lc kp
*lc ct:mi khoan di t trn xung,lc doc P tu tren xung,momen
xoan
theo chieu quay cua mui khoan(nhu hinh ve)
*luc kp: phng ca lc kp vung gc vi trc,hng t trn
xung,im t ca lc gia hai khi V
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9.5 xc nh lc kp
Khi khoan tat hay lc do li ct sinh ra c xu hng lam chi tit
quay
quang trc ca n.do kt cu ca g nn khi khoan l 6 lc P0 c xu hng lm
lt chi ti tit.nn khi tnh lc kp ta phi tnh cho ca 2 trng hp
*Khi khoan,doa l 6 momen xon ln nht khi ta khoan l nn lc kp dc
tnh cho trng hp nguy him nht l khoan l.
n gin ta coi phn lc ti cht t ph bng lc dc trc khi khoan v
lc kp cht gy ra phn lc trn khi V
Ta c:
Mms = R ( N f1 + P0 f2 +Wf3 ) = K MX
N =
2sin
W
Suy ra:
2sin
13
20
ff
fPRMK
Wx
+
=
P0: lc ct theo phng thng ng
R: bn knh ca trc ti im nh v R=16,5mm
f1, f2 , f3: ln lt l h s ma st gia trc v khi V, cht t ph v m k
ly: f1 =0,2 ; f2 = 0,3 ; f3 =0,45
K: h s an ton
K0: h s an tondnh mc.trong mi trng hp K0 =1.5
K1 :H s k dn lng d khng du khi gia cng K1 =1
K2: H s k n cn dao lm tng lc khi ct K2 =1.5
K3: H s k dn v ct khng lien tc lm tng lc ct K3 = 1
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K4: H s k dn ngun sinh lc khng n nh khi kp bng tay K4 = 1.3
K5 :H s k nvij tr ca tay quay co cu kp c thun tin khng K5 =1
K6 :H s k n momen lt phi quay quang dim ta K6 =1
K = K0 K1 K2 K3 K4 K5 K6 =2,925
Thay s vo biu thc ta tnh c W = 99,5 N
9.6 chn c cu kp vad c cu sinh lc
C cu kp phi tha mn cc yu cu:khi kp phi gi ng v tr ca
phi,lc kp to ra phi ,khng lm bin dng chi tit,kt cu nh
gn,thao tc thun li v an ton.Vi cc yu cu dy ta chon c cu kp
bng ren vt n,sinh lc bng tay
9.7Xc nh sai s ch to cho php v yu cu k thut ca g:
*sai s ch to cho php Sai s g nh hng n sai s kch thc gia cng,nhng
phn ln n
nh hng n sai so tng quan v tr gia b mt gia cng v b mt
chun.khi khoan chnh xc ca kch thc v v tr b mt gia cng ph
thuc vo v tr tng quan gia cc chi tit nh v trn g
Sai s g t dc tnh theo cng thc:
222222222 dcmctkcdgkcgd ++++=++=
Trong :
-c :sai s do chun nh v khng trng vi gc kch thc, y
chun nh v l mt ngoi ca trc,gc kch thc l ng tm ca trc
nn s c sai s chun,d thy sai s chun bng dung sai kch thc on
trc 17. Nn c = 30m -kc sai s do lc kp gy ra do
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d thy kc = 0
-m : Sai s mn tnh theo cng thc
m= =0.18 Trong :
: h s ph thuc vo kt cu nh v N : s lng chi tit( 15000 chi
tit)
Ta c: m = 0.1811000 =19 m -dc: sai s sinh ra do qu trnh lp rp v
iu chnh g.Sai s iu
chnh ph thuc vo kh nng iu chnh v dng c iu chnh khi lp
rp.Trong thc t tnh ton ta c th ly dc =5m.
-gd: sai s g t, khi tnh ton g ta ly gi tr sai s g t cho
php [gd] =1/3 vi l dung sai nguyn cng gd =40 m - ct sai s ch to
cho php ca g (cn xc nh khi ch to g)
[ct] c tnh theo cng thc: [ ] ( )22222 cmdckcgdct +++=
Thay s ta tnh c: [ ] ( ) mct 1830195040 2222 =+++=
*yu cu k thut ca g - khng song song gia dng tm ca khi V v mt
phng y g
0,018mm/100mm chiu di. - ng lc tm ca hai khi V0,018mm/100mm bn
knh -Sai s v tr tng quan ca cc chi tit trn g0,1mm/100mm chiu
di
-Cc chi tit nh khi V, bc dn, phin dn u phi gia cng t cp chin
xac cp 7, c ti t cng t 5060 HRC
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-Hnh dng v yu cu k thut ca cc chi tit nh m kep, n kp, bu-
long dai c, vt,cht tr dm bo theo tiu chun quy nh ca nh nc.
-Thn g c kh ng sut d
-Cc cnh ca g khng c cnh sc. Dung sai cc kch thc t do c
chnh xc cp 8
-
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TI LIU THAM KHO
1.Hng dn thit k n cng ngh ch to my
GS.TS. Nguyn c Lc-Lu Vn Khang
Nh xut bn khoa hc k thut-2006
2.S tay cng ngh ch to my tp:1,2,3
Ch bin: GS.TS. Nguyn c Lc
Nh xut bn khoa hc k thut-2003
3.Atlat g
GS. TS. Trn Vn ch
Nh xut bn khoa hc k thut-2006
4. g
GS. TS. Trn Vn ch
Nh xut bn khoa hc k thut-2006
5.Cng ngh ch to my
Ch bin: GS.TS. Trn Vn ch
Nh xut bn khoa hc k thut-2003
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MC LC
Trang
Nhim v thit k 1
Li ni u 3
I.Phn tch chc nng lm vic ca chi tit 4
II. Phn tch tnh cng ngh trong kt cu ca chi tit 4
III. Xc nh dng sn xut 5
IV. Chn phng php ch to phi 6
V/. Lp th t cc nguyn cng 6
VI. Tnh lng d cho mt b m 13
VII. Tnh ch ct cho 1 nguyn cng 18
VIII. Tnh thi gian gia cng c bn cho tt c cc nguyn cng 30
IX. Tnh v thit k g 34
Ti liu tham kho 41