Top Banner
Math 251: Quiz 3 September 18, 2018 Name: / 25 There are 25 points possible on this quiz. No aids (book, calculator, etc.) are permitted. Show all work for full credit. 1. [5 points] Evaluate the limit. Show work and use proper limit notation for full credit. lim x!-5 x + 5 x 2 + 7x + 10 2. [5 points] Evaluate the limit. Show work and use proper limit notation for full credit. lim x!0 2 - p 4 + h h 3. [4 points] a. Why is the following not a true statement?: 2x 2 - 3x x = 2x - 3 b. Explain why the following equation is correct: lim x!0 2x 2 - 3x x = lim x!0 2x - 3 UAF Calculus I 1 v-1 = I. m its + s Cxts ) ( XII = times . s ¥-2 = = km K-oFh)(ztT peso h = I in 4-14+471-50 h - - tho - ha = Inigo - I =-D The expression on the right - hand side is defined at * = o , but the expression an the left-hand side is not . The expressions inside the lands are the sane except at one pout ( x = o ) ad " limits don't care about are point !
2

tho =-D · 2020-05-04 · Math 251: Quiz 3 September 18, 2018 Name: / 25 There are 25 points possible on this quiz. No aids (book, calculator, etc.) are permitted. Show all work for

May 27, 2020

Download

Documents

dariahiddleston
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Page 1: tho =-D · 2020-05-04 · Math 251: Quiz 3 September 18, 2018 Name: / 25 There are 25 points possible on this quiz. No aids (book, calculator, etc.) are permitted. Show all work for

Math 251: Quiz 3 September 18, 2018

Name: / 25

There are 25 points possible on this quiz. No aids (book, calculator, etc.) are permitted. Show all

work for full credit.

1. [5 points] Evaluate the limit. Show work and use proper limit notation for full credit.

limx!�5

x+5

x2 +7x+10

2. [5 points] Evaluate the limit. Show work and use proper limit notation for full credit.

limx!0

2�p

4+hh

3. [4 points]

a. Why is the following not a true statement?:

2x2 �3xx

= 2x�3

b. Explain why the following equation is correct:

limx!0

2x2 �3xx

= limx!0

2x�3

UAF Calculus I 1 v-1

= I. m its+ → - s Cxts )( XII

=

times. s ¥-2

=

= km K-oFh)(ztTpeso h

= I in4-14+471-50h

-

- tho -

ha = Inigo - I =-D

The expression onthe right - hand side is defined

at *= o,but the expression an the left-hand side is not

.

The expressions inside the landsare the sane except at one pout

( x = o ) ad"

limits don't care about are

point !

Page 2: tho =-D · 2020-05-04 · Math 251: Quiz 3 September 18, 2018 Name: / 25 There are 25 points possible on this quiz. No aids (book, calculator, etc.) are permitted. Show all work for

Math 251: Quiz 3 September 18, 2018

4. [6 points] Consider the function

f (x) =

(2x+1 x < 0

�1+ x x � 0

a. On the axes below, sketch a graph of f (x).

x

f (x)

�4 �2 2 4

�2

2

b. Evaluate the limit, or explain why it does not exist:

limx!0

f (x)

c. Is f continuous at x = 0? Explain using the definition of continuity.

5. [5 points] Use the Intermediate Value Theorem to justify the claim that there exists a number x on

the interval (0,1) satisfying ex �6x = 0.

UAF Calculus I 2 v-1

¥lim fix ) = - I since the left - and right -

Not hard limits are different,

Iim ffx )= I the limit figofCx ) does+ → o

-

not exist.

The function is not continuous at te O.

We

would need Iim fk ) = flo ) = - I. But the limit does

to not exist .

Let f Cx) -- ex - Gx . Notice f (o ) =/ so

,but

f Cl ) = 2.7 - GL O. Since f k ) is continuous

on [ o , I ] the IV T implies for some x in ( o , D,

f- ( x ) = O.