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There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only of right triangles…
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There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

Mar 31, 2015

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Edith Twining
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Page 1: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle.

Unfortunately, the world does not consist only of right triangles…

Page 2: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

As a matter of fact, right triangles end up being more of a rarity than commonplace.

Page 3: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

There are many situations where angles other than 90O are present.

Page 4: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

Does that mean when we come across a situation that can only be modeled with a non-right triangle that we abandon our pursuit?….

Page 5: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.
Page 6: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

No Way!!!!There exists two Laws of

Trigonometry that allow one to solve problems that involve non-right Triangles:

Page 7: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

RememberA capital letter represents an

angle in a triangle, and a small letter represents a side of a

triangle

A

a

Page 8: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.
Page 9: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

A BO

C

b

c

a

If b,c and O are all known, then O is called a “Contained Angle”

(the blue line also forms a “c”, [kind of] which is how I remember to use the “c”osine law in this case..)

Page 10: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

A BO

C

b

c

a

The Cosine Law can be used to find the length of the opposite side to O

In this case, the length of side a

Page 11: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

In General:

a2 = b2 + c2 – 2bcCosOo

A BO

C

b

c

a

Page 12: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

For Example: Find a

A50o

C

8m

10m

a

B

Page 13: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

a2 = 82 + 102 – 2(8)(10)Cos50o

A50o

C

8m

10m

a

a2 = 61.15m a = 7.8 m

B

a2 = b2 + c2 – 2(b)(c)CosAo

You should be able to load this into your calculator directly from left to right…if not, see me

Page 14: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.
Page 15: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

The Sine Law

If the triangle being solved does not consists of a right triangle (3PTRs) or a contained angle (Cosine Law), then another tool must be used.

Page 16: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

If a corresponding angle and side are known, they form an

“opposing pair”

A

C

Bc

b a

O1 O2

Page 17: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

The Sine Law can be used to determine an unknown side or angle given an “opposing pair”

A

C

Bc

b a

O1 O2

Page 18: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

The Sine Law

b SinA = SinB

a c = SinC

A

C

Bc

ba

Page 19: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

Find the length of a

a

A

C

c

2473o

57o

N

We can not use the Cosine Law because there is not a contained angle…

We must therefore look for an opposite pair. Hmmm…..

A-HA!!!(it’s all good)

Page 20: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

Find the length of a

a

A

C

c

24

57o

N

aSin73o

= 24Sin57o

a = 27.4

73o

Again, this can be put directly into your calculator. See me for help.

Page 21: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

Pg 2901a,c,d,e4a,c,e5a,c68,10,12,14Pg 2951(11 unco, stop

here)

Page 22: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

The Ambiguous Case

Page 23: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

Find A

11

9

48oA

11

SinA =9

Sin48o

A = 65.3o

Does that make sense?

No Way!!!

Page 24: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

Side 9 can also be drawn as:

119

48o

A

Could A be 65o in this

case?

Page 25: There is no doubt that the 3 PTRs are extremely useful when solving problems modeled on a right triangle. Unfortunately, the world does not consist only.

This type of discrepancy is called the “Ambiguous Case”

Be sure to check the diagram to see which answer fits:

O, or 180o - O