Top Banner
The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is drainage basin area. (Hack, 1957)
25

The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Dec 26, 2015

Download

Documents

Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Page 1: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

The Power Function

Studies of stream length and drainage basins determined an empirical relationship :

L = 1.4 A0.6

where L is stream length and A is drainage basin

area. (Hack, 1957)

Page 2: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

The Power Function

In our lab exercise on sinking forams, you derived the equation for Stokes settling velocity,

Vstokes

= (g/18 d2

Stokes derived this equation from consideration of the driving forces and resisting forces for sinking foraminifera.

Page 3: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

The Power Function

Both the empirically defined Hack equation and the analytically derived Law for Stokes velocity are examples of power functions.

A power function is written in general form by

y = axb .

Page 4: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

The Power Function

In the case of Hack's Law,

y = Lx = Ab = 0.6(a = 1.4)

L = 1.4 A0.6

y = axb

Page 5: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

The Power Function

In the case of Stokes velocity,

y = Vstokes

x = db = 2(a = g/18)

y = axb

Vstokes

= (g/18 d2

Page 6: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

The Power Function

y = axb

What is interesting about this equation is what happens when you apply logarithms.

How would you do it ?

log y = log a + b*log x

Does this equation remind you of anything ?

Page 7: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Logarithm of a Power Function

log y = log a + b*log x

This may be similar to the equation for a straight line where y = b + m*x

b = 3m = 1

y = 3 + 1*x y = 3 + x

What kind of scale would we need to plot the logarithmic equation to simulate a linear equation ?

(at the x intercept when x = 0, y = 3)

Page 8: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Logarithm of a Power Function

log y = log a + b*log x

If a and x are a set of measurements and y is a column of results

and we take the log of each of these numbers

Then plot these log values on normal graph paper...

We see a straight line.

With b as the slope.

The x intercept (log x = 0)

occurs at log ax

y

Page 9: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Logarithm of a Power Function

log y = log a + b*log x

If we plot x against y on log-log paper,

We also see a straight line

Again, b is the slope

The line crosses x = 1

Where y = a

x

y

Page 10: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions in Geology

Log - log plots are common in geology

As a result, power functions often arise in geology

C = CoF(D-1)

As crystals settle out of a magmaelement concentrations, C, in theremaining liquid change accordingto this equation.

Where Co is initial concentration, F is the fraction of liquid remaining, and D is the distribution coefficient.

Linear plot of

C = CoF(D-1)

Page 11: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions in Geology

Log - log plots are common in geology

As a result, power functions often arise in geology

C = CoF(D-1) log-log plot

log C = log Co + (D-1) log F

Page 12: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions in Geology

Stream length (y) and drainage-basin area (x) are measuredand listed in the table above.

The logs of each measurement are listed in column 4 and 5

If we plot columns 4 and 5 and try to “fit” a line to the data

Constant = 0.148761, and slope is 0.53687

Page 13: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions in Geology

Constant = 0.148761, and slope is 0.53687

How can we write this in a linear style equation with logs ?

log y = 0.148761 + 0.53687 log x

Page 14: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions in Geology

log y = 0.148761 + 0.53687 log x

Plot columns x and y (squares)

Test theory, but plotting the line for the log eqn above.

Pretty good fit!

Page 15: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions in Geology

log y = 0.148761 + 0.53687 log x

Remember that if we take the “antilog” of both sides

We get y = 100.148761 x0.53687

Simplifying, y = 1.41 x0.54

Page 16: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions on a Linear Scale

y = 1.41 x0.54

Data in a power function plotted on a linear-linear scale

The curve continues to increase

But it increases at an ever decreasing slope

Page 17: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions on a Linear Scale

y = 1.41 x0.54

To understand the “slopes” of a function, take it's derivative

dy = 0.76 x-0.46

dx The exponent, b is < 1 (negative)

This says the slope will decrease, as x progresses

riserun

=

Page 18: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions on a Linear Scale

Taking the derivative in general

dy = (a) xb-1

dx If the exponent, b is > 1 (positive)

Then the slope will increase, as x progresses

What if b = 1 ? Then what ?

Page 19: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions on a Linear Scale

y = 1.41 x0.54

To Summarize: For y = axb-1

Plots will be convex- upward if b < 1 (negative exp) Plots will be convex -downward if b > 1 (positive exp) Plots will be a straight line if b = 1.

Page 20: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions and Exponential Functions

It is easy to confuse power fns with exponential fns

We've already looked at exponential functions

But we have not studied power functions until today.

y = xb y = bx

Exponential functions produce a straight line when plotted on a linear-log scale.

Where as power functions produce a straight line when plotted on a log-log scale

Page 21: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Power Functions and Exponential Functions

y = xb

In a power function, for every increase in x by some factor y increases by some other factor

In an exponential function, for every increase in x by some factor y may increase by an order of magnitude

(assuming b is a whole number) This is where the concept of a half-life comes from.

y = bx

Page 22: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Studies of stream length and drainage basins determined an empirical relationship :

L = 1.4 A0.54

where L is stream length and A is drainage basin

area. (Hack, 1957)

Back to Drainage Basins and Hack's Law

The exponential “b” value here has been debated.

Page 23: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

L = 1.4 A0.6

Back to Drainage Basins and Hack's Law

Some say that if b > 0.5

Then the length/area relationship implies that large basins are more elongated.

Page 24: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

L = 1.4 A0.54

Shape of Drainage Basins

Understanding length/area ratio

If A = wL

Then, L = 1.4 (wL)0.54

Simplifying.... w/L = 0.53L-0.15

w

L

Notice that the exponent is negative.

How will w/L change as you go downstream (increasing L) ?

Page 25: The Power Function Studies of stream length and drainage basins determined an empirical relationship : L = 1.4 A 0.6 where L is stream length and A is.

Shape of Drainage Basins

Put L on one side: w/L = 0.53L-0.15

w = 0.53 L0.85

Will a plot of L versus w be convex up or down ?

w

L