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DISPLACEMENT DISPLACEMENT MEDTHOD OF ANALYSIS: MEDTHOD OF ANALYSIS: MOMENT DISTRIBUTION MOMENT DISTRIBUTION Member Member Stiffness Stiffness Factor Factor ( ( K  K  ) ) Distribution Distribution Factor Factor (DF) (DF) Carry Carry- Over Over Factor Factor Distribution Distribution of of Couple Couple at at Node Node Moment Moment Distribution Distribution for for Beams Beams General General Beams Beams Symmetric Symmetric Beams Beams Moment Moment Distribution Distribution for for Frames Frames: No : No Sidesway Sidesway Moment Moment Distribution Distribution for for Frames Frames: Sidesway Sidesway
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The Moment Distribution Method

Oct 11, 2015

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The Moment Distribution Method
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  • DISPLACEMENT DISPLACEMENT MEDTHOD OF ANALYSIS: MEDTHOD OF ANALYSIS: MOMENT DISTRIBUTIONMOMENT DISTRIBUTIONMemberMember StiffnessStiffness FactorFactor ((KK))DistributionDistribution FactorFactor (DF)(DF)CarryCarry--OverOver FactorFactorDistributionDistribution of of CoupleCouple at at NodeNodeMoment Moment DistributionDistribution forfor BeamsBeamsGeneral General BeamsBeamsSymmetricSymmetric BeamsBeamsMoment Moment DistributionDistribution forfor FramesFrames: No : No SideswaySideswayMoment Moment DistributionDistribution forfor FramesFrames: : SideswaySidesway

  • General General PrinciplesPrinciples andand DefinitionsDefinitionsThus the Moment Distribution Method (also known as the Cross MetThus the Moment Distribution Method (also known as the Cross Method) hod)

    became the preferred calculation technique for reinforced concrebecame the preferred calculation technique for reinforced concrete te structures. structures.

    The description of the moment distribution method by Hardy CrossThe description of the moment distribution method by Hardy Cross is a little is a little masterpiece. He wrote: "Moment Distribution. The method of momenmasterpiece. He wrote: "Moment Distribution. The method of moment t distribution is this:distribution is this:

    Imagine all joints in the structure held so that they cannot roImagine all joints in the structure held so that they cannot rotate and tate and compute the moments at the ends of the members for this conditiocompute the moments at the ends of the members for this condition;n;

    at each joint distribute the unbalanced fixedat each joint distribute the unbalanced fixed--end moment among the end moment among the connecting members in proportion to the constant for each memberconnecting members in proportion to the constant for each memberdefined as "stiffness";defined as "stiffness";

    multiply the moment distributed to each member at a joint by themultiply the moment distributed to each member at a joint by the carrycarry--over factor at the end of the member and set this product at theover factor at the end of the member and set this product at the other other end of the member; end of the member;

    distribute these moments just "carried over"; distribute these moments just "carried over"; repeat the process until the moments to be carried over are smalrepeat the process until the moments to be carried over are small l

    enough to be neglected; andenough to be neglected; and add all moments add all moments -- fixedfixed--end moments, distributed moments, moments end moments, distributed moments, moments

    carried over carried over -- at each end of each member to obtain the true moment at at each end of each member to obtain the true moment at the end." [Cross 1949:2] the end." [Cross 1949:2]

  • 1. Restrain all possible displacements.

    2. Calculate Distribution Factors:

    The distribution factor DFi of a member connected to any joint J is

    where S is the rotational stiffness , and is given by

  • 3. Determine carry-over factors

    The carry-over factor to a fixed end is always 0.5, otherwise it is 0.0.

    4. Calculate Fixed End Moments. (Table 3.1).

    These could be due to in-span loads, temperature variation and/or relative displacement between the ends of a member.

    5. Do distribution cycles for all joints simultaneously

    Each cycle consists of two steps:1. Distribution of out of balance moments Mo,2.Calculation of the carry over moment at the far end of each member.

    The procedure is stopped when, at all joints, the out of balance moment is a negligible value. In this case, the joints should be balanced and no carry-overmoments are calculated.

  • 6. Calculate the final moment at either end of each member.

    This is the sum of all moments (including FEM) computed during thedistribution cycles.

  • ExampleExample

  • StiffnessStiffness--FactorFactor ModificationModification

  • Example

  • SymmetricSymmetric BeamBeam andand LoadingLoading

  • SymmetricSymmetric BeamBeam withwithAntisymmetricAntisymmetric LoadingLoading

  • Moment Moment DistributionDistribution forfor framesframes::No No sideswaysidesway

  • Moment Moment DistributionDistribution forfor framesframes: : sideswaysidesway