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Application of Integral Done by : Fatma Al-nuaimi Kashaf Bakali Parisa Yazdjerdi Heba Hammud Nadine Bleibel
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Page 1: The graph: Similarly, parisa yazdjerdi.

Application of Integral

Done by :

Fatma Al-nuaimi

Kashaf Bakali

Parisa Yazdjerdi

Heba Hammud

Nadine Bleibel

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Definition of Area by Integral

by : Fatma Al-nuaimi(201004421)

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Finding areas by integration.

Using Riemann sum.

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Use Riemann sum to find the value of:

The graph:

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Step 1:

We can determine the value by subdividing the region into rectangle:

When the number of rectangles n

The area of rectangle is A=L*W

Width=W= 1/n

Length= 1+(1/n)i

So,

i

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Step 3: Performing some algebraic manipulation:

i

i

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Step 4:

Taking the limit to calculate the area:

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Area under the curveBy: Kashaf Bakali

(201105803)

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Find the Area enclosed by the parabola and above the x-axis.

As the area to be calculated should be above x-axis so, .

We first find the points of intersection by solving both equations simultaneously. i.e.

So,

Hence, the intersection points are; .

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Now, we sketch the graph.

The graph tells us the limit.

In this case, we have to find area from -1 till 3.

So, dx

)

=

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Similarly,

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Find the area bounded between and

Firstly, we would find the intersection points by solving both given equations simultaneously. i.e.

We get the intersections points as,

We sketch the graph.

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Now we have, . We use the formula, In this case,

and. Hence,

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Area between two curveBy: Parisa Yazdjerdi

(201005599)

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Areas between two curves

Process of finding area between two curves consist of 3 main steps :

1. finding intersection of the curves ( put two equation in an equality)

2. Drawing the graph to distinguish intervals and exact areas

3. Using integral formula

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Area between two curves

Example : find area between f(x) = Sin x , g(x) = Cos x , x = 0 and x = π/2 .

First step : find intersections

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Area between tow curves

Second step : Drawing the Graph

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Area between two curves

Third step : Using formula to find area

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Area between two curves

parisa yazdjerdi

22222

4

)]2

1

2

1()10[()]10()

2

1

2

1[(

]sincos[]cos[sin

]cos[sin]sin[cos

so,

cosx -sinx|=cosx-sinx| so, 0>cosx -sinx

and

sinx-cosx|=sinx-cosx|so, 0 >sinx-cosx therefore24

cossin4

0;sincos

2

4

40

2

4

4

0

xxxx

dxxxdxxxA

xxxandxxx

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Volume of SolidBy : Hebba Hammud

(201003247)

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Volume of Solids

For any Solid(S),we cut it into pieces and approximate each piece by a cylinder. This is called : cross-sectional area.

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Definition of Volume

)(

)()(lim1

abAAdx

dxxAxxiAv

b

a

b

a

n

in

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Exercises(about the x-axis)

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Find the volume v resulting from the revolution of the region bounded by:y=√x , from x=0 to x=1 about the x-axis.

2)0

2

1(

2

)(

10

2

1

0

1

0

2

x

xdx

dxxv

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Find the volume v resulting from the revolution of the region bounded by:y=√(a2-x2 ) from x=-a to x=a and the x-axis about the

x-axis.

3

4]

3

2[2

]0)3

[(2

)3

(2

)(2

)(

)(

33

32

0

32

0

22

22

222

aa

aaa

xxa

dxxa

dxxa

dxxav

a

a

a

a

a

a

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Exercises (about the y-axis)

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Find the volume of the solid of revolution generated by rotating the curve y = x3 between y = 0 and y = 4 about the y-axis.

We first must express x in terms of y, so that we can apply the formula.

If y = x3 then x = y1/3

The formula requires x2, so x2 = y2/3

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Find the volume generated by the areas bounded by the Given curves if they are revolved about the y-

axis: y2 = x, y = 4 and x = 0 [revolved about the y-axis]

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VolumeBy: Nadine Bleibel

(201104593)

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Basics of a Cylinder

Nadine Bleibel

A cylinder is a simple solid which is boundedby a plane region B1- which is called the base.A cylinder also has a congruent region B2 in a Parallel plane.

The formula for volume for a circular cylinder isV=(Pi)r^2(h)

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EXAMPLE 1 (example 2 p 356)

Nadine Bleibel2

)02

1(

2

)(

10

2

1

0

1

0

2

x

xdx

dxxv

Find the Volume of the solid obtained by rotatingAbout the x-axis the region under the curvey= √x from 0 to 1.

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EXAMPLE 2 (example 3 p357)

Nadine Bleibel

EXAMPLE: Find the volume of the solid obtaining by rotating about the y-axis the region bounded by y = x3, y = 8, and x = 0.

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