Introduction Special Relativity General Relativity Applications The Geometry of Relativity Tevian Dray Department of Mathematics Oregon State University http://www.math.oregonstate.edu/ ~ tevian OSU 4/27/15 Tevian Dray The Geometry of Relativity 1/27
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IntroductionSpecial RelativityGeneral Relativity
Applications
The Geometry of Relativity
Tevian Dray
Department of MathematicsOregon State University
http://www.math.oregonstate.edu/~tevian
OSU 4/27/15 Tevian Dray The Geometry of Relativity 1/27
The Geometry of Special RelativityTevian DrayA K Peters/CRC Press 2012ISBN: 978-1-4665-1047-0http://physics.oregonstate.edu/coursewikis/GSR
Differential Forms andthe Geometry of General RelativityTevian DrayA K Peters/CRC Press 2014ISBN: 978-1-4665-1000-5http://physics.oregonstate.edu/coursewikis/GDF
http://physics.oregonstate.edu/coursewikis/GGR
OSU 4/27/15 Tevian Dray The Geometry of Relativity 2/27
OSU 4/27/15 Tevian Dray The Geometry of Relativity 3/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Measurements
Width:θ
1
θ
1
Apparent width > 1
1cos θ
1cos θ
Slope:
y
xφ
y’
x’
y
x
φθ
m 6= m1 +m2
tan(θ + φ) = tan θ+tanφ1−tan θ tanφ = m1+m2
1−m1m2
OSU 4/27/15 Tevian Dray The Geometry of Relativity 4/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Rotations
y
B
θ
θ
A
y’
x’
x
OSU 4/27/15 Tevian Dray The Geometry of Relativity 5/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Trigonometry
ds2 = −c2 dt2 + dx2
.ρ
ββ ρρ( cosh , sinh )
β
ρβ = arclength
4
5
3
β
tanhβ =3
5=⇒ coshβ =
5
4
(coshβ ≥ 1; tanhβ < 1)
OSU 4/27/15 Tevian Dray The Geometry of Relativity 6/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Trigonometry
β
βB
t’
A
x’
t
x
•
β coshρ
β sinhρρ
β
•
OSU 4/27/15 Tevian Dray The Geometry of Relativity 7/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Length Contraction
x’
t’t
x
x’
t’t
x
ℓ ′ = ℓcoshβ
β β
ℓ
ℓ ′
•
ℓ
ℓ ′
•
OSU 4/27/15 Tevian Dray The Geometry of Relativity 8/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Time Dilation
x’
ct’ct
x
OSU 4/27/15 Tevian Dray The Geometry of Relativity 9/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Pole & Barn
A 20 foot pole is moving towards a 10 foot barn fast enough thatthe pole appears to be only 10 feet long. As soon as both ends ofthe pole are in the barn, slam the doors. How can a 20 foot polefit into a 10 foot barn?
-20
-10
0
10
20
-20 -10 10 20 30
-20
-10
0
10
20
-10 10 20 30
barn frame pole frame
OSU 4/27/15 Tevian Dray The Geometry of Relativity 10/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Relativistic Mechanics
A pion of (rest) mass m and (relativistic) momentum p = 34mc
decays into 2 (massless) photons. One photon travels in the samedirection as the original pion, and the other travels in the oppositedirection. Find the energy of each photon. [E1 = mc2, E2 =
14mc2]
0
0
mc2
Β
E
E1
E2
pc
p1c
p2c
p0c
E0
E0
p0c
Β
Β
ΒΒ
p 0c
sinhΒ
p 0c
sinhΒ
E0c
coshΒ
E0c
coshΒ
0
0
mc2
Β
E1
p1 c
E2
p2 c
p0c
E0
E0
p0c
Β
Β
Β
p0 c sinh
Β
p0 c sinh
Β
E0 c cosh
ΒE
0 c coshΒ
OSU 4/27/15 Tevian Dray The Geometry of Relativity 11/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Twin Paradox
One twin travels 24 light-years to star X at speed 2425c; her twin
brother stays home. When the traveling twin gets to star X, sheimmediately turns around, and returns at the same speed. Howlong does each twin think the trip took?
β
•24
25 7
coshβ =25
7
•
7
q
q =7
coshβ=
49
25 49/25
7
24
25
β
Straight path takes longest!
OSU 4/27/15 Tevian Dray The Geometry of Relativity 12/27
IntroductionSpecial RelativityGeneral Relativity
Applications
Circle GeometryHyperbola GeometryApplications
Addition of Velocities
v
c= tanhβ
tanh(α+ β) =tanhα+ tanhβ
1 + tanhα tanhβ=
uc+ v
c
1 + uvc2
Einstein addition formula!
OSU 4/27/15 Tevian Dray The Geometry of Relativity 13/27
IntroductionSpecial RelativityGeneral Relativity
Applications
The MetricDifferential FormsGeodesicsEinstein’s Equation