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Test: Final Exam Semester 1 Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer. Semester 1 Final Term Exam covers Sections 11-18 of Database Design. Section 12 1. One-to-One relationships are transformed into Check Constraints in the tables created at either end of that relationship. True or False? Mark for Review (1) Points True False (*) Correct 2. The Oracle Database can implement a many to many relationship. You simply create two foreign keys between the two tables. True or False? Mark for Review (1) Points True False (*) Incorrect. Refer to Section 12 3. Why would this table name NOT work in an Oracle database? this_year_end+next_year Mark for Review (1) Points Table names must begin with an alphabetic character Too long The Plus sign + is not allowed in object names (*) None of the above Incorrect. Refer to Section 12
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Page 1: Test

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 12

1.  One-to-One relationships are transformed into Check Constraints in the tables created at either end of that relationship. True or False?  Mark for Review(1) Points

True

False (*)

Correct

2.  The Oracle Database can implement a many to many relationship. You simply create two foreign keys between the two tables. True or False?  Mark for Review(1) Points

True

False (*)

Incorrect. Refer to Section 12

3.  Why would this table name NOT work in an Oracle database? this_year_end+next_year  Mark for Review(1) Points

Table names must begin with an alphabetic character

Too long

The Plus sign + is not allowed in object names (*)

None of the above

Incorrect. Refer to Section 12

4.  In a physical data model, an attribute becomes a _____________.  Mark for Review(1) Points

Table

Foreign Key

Page 2: Test

Constraint

Column (*)

Correct

5.  In a physical data model, a relationship is represented as a combination of: (Choose Two)  Mark for Review(1) Points

(Choose all correct answers)

Column

Primary Key or Unique Key (*)

Check Constraint or Unique Key

Foreign Key (*)

Incorrect. Refer to Section 12

6.  Identify all of the incorrect statements that complete this sentence: A primary key is: (Choose three)  Mark for Review(1) Points

(Choose all correct answers)

A single column that uniquely identifies each column in a table (*)

One or more columns in a table that uniquely identifies each row in that table

A set of columns in one table that uniquely identifies each row in another table (*)

Only one column that must be null (*)

Incorrect. Refer to Section 12

7.  The explanation below is a column integrity constraint:A column must contain only values consistent with the defined data format of the column. True or False?Mark for Review(1) Points

True (*)

False

Correct

Page 3: Test

8.  Foreign keys must be null. True or False?  Mark for Review(1) Points

True

False (*)

Correct

9.  The explanation below is a User Defined integrity rule and must therefore be manually coded, the Database cannot enforce this rule automatically:A primary key must be unique, and no part of the primary key can be null. True or False?Mark for Review(1) Points

True

False (*)

Incorrect. Refer to Section 12

10.  When translating an arc relationship to a physical design, you must turn the arc relationships into foreign keys. Assuming you are implementing an Exclusive Design, you must also create two Unique Key Constraints to ensure the Arc is implemented correctly. True or False?  Mark for Review(1) Points

True

False (*)

Incorrect. Refer to Section 12

Page 1 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 12

11.  Which of the following are reasons why you should consider using a Subtype Implementation?  Mark for Review(1) Points

The resulting table will reside in a single database and be used by just ONE user.

Page 4: Test

When the common access paths for the supertypes are different.

Business functionality and business rules, access paths and frequency of access are all very different between subtypes. (*)

Most of the relationships are at the supertype level

Incorrect. Refer to Section 12

Section 13

12.  The _______ clause can be added to a SELECT statement to return a subset of the data.  Mark for Review(1) Points

ANYWHERE

WHICH

WHERE (*)

EVERY

Correct.

13.  What command can be used to create a new row in a table in the database?  Mark for Review(1) Points

CREATE

NEW

ADD

INSERT (*)

Correct.

Section 16

14.  You want to create a list of all albums that have been produced by the company. The list should include the title of the album, the artist’s name, and the date the album was released. The ALBUMS table includes the following columns:ALB_TITLE VARCHAR2(150) NOT NULLALB_ARTIST VARCHAR2(150) NOT NULLALB_DATE DATE NOT NULL

Which statement can you use to retrieve the necessary information?

Page 5: Test

Mark for Review(1) Points

SELECT *FROM albums;(*)

SELECT alb_title, alb_artist, alb_datesFROM album;

SELECT alb_title, alb_artist, alb_datesFROM albums;

SELECT alb_title; alb_artist; alb_dateFROM albums;

Incorrect. See Section 16

15.  In a SELECT clause, what is the result of 2 + 3 * 2?  Mark for Review(1) Points

6

8 (*)

10

13

Correct.

16.  Which SQL keyword specifies that an alias will be substituted for a column name in the output of a SQL query?  Mark for Review(1) Points

AS (*)

OR

AND

SUBSTITUTE

Correct.

17.  When you use the SELECT clause to list one or two columns only from a table and no WHERE clause, which SQL capability is used?  Mark for Review(1) Points

Joining only

Page 6: Test

Selection only

Projection only (*)

Projection and Selection

Incorrect. See Section 16

18.  When listing columns in the SELECT list, what should you use to separate the columns?  Mark for Review(1) Points

Commas (*)

Semicolons

Dashes

Underscores

Correct.

19.  In which clause of a SELECT statement would you specify the name of the table or tables being queried?  Mark for Review(1) Points

The FROM clause (*)

The SELECT clause

The WHERE clause

Any of the above options, you can list tables wherever you want to in a SELECT statement.

Correct.

20.  The SELECT statement retrieves information from the database. In a SELECT statement, you can do all of the following EXCEPT:  Mark for Review(1) Points

Projection

Manipulation (*)

Joining

Selection

Incorrect. See Section 16

Page 7: Test

Page 2 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 16

21.  In a SELECT statement Additions are evaluated before Multiplications. True or False?  Mark for Review(1) Points

True

False (*)

Correct.

22.  You cannot use computers unless you completely understand exactly how they work. True or False?  Mark for Review(1) Points

True

False (*)

Incorrect. See Section 16

Section 17

23.  The STUDENT table contains these columns:STUDENT_ID NUMBER(10) Primary KeyLAST_NAME VARCHAR2(25)FIRST_NAME VARCHAR2(25)MAIN_SUBJECT_ID NUMBER(3)ADVISOR_ID NUMBER(5)

Evaluate this statement:SELECT DISTINCT advisor_id, main_subject_idFROM student;

Which statement is true?Mark for Review(1) Points

Each ADVISOR_ID can be displayed only once.

Page 8: Test

Each MAIN_SUBJECT_ID can be displayed more than once per ADVISOR_ID. (*)

Each combination of ADVISOR_ID and MAIN_SUBJECT_ID can be displayed more than once.

Each MAIN_SUBJECT_ID can be displayed only once per query.

Incorrect. See Section 17

24.  You want to create a report that displays all employees who were hired before January 1, 2000 and whose annual salaries are greater than 50000.The EMPLOYEES table contains these columns:

EMPLOYEE_ID VARCHAR2(5) PRIMARY KEYLAST_NAME VARCHAR2(35)HIREDATE DATEDEPARTMENT_ID NUMBER(4)

The SALARY table contains these columns:

SALARYID VARCHAR2(5) PRIMARY KEYSALARY NUMBER(5, 2)EMPLOYEE_ID VARCHAR2(5) FOREIGN KEY

Which query should you issue?Mark for Review(1) Points

SELECT last_name, hiredate, salaryFROM employees NATURAL JOIN salary USING employee_idWHERE hiredate < 01-jan-00 AND salary > 50000;

SELECT last_name, hiredate, salaryFROM employees JOIN salaryON employee_id = employee_idWHERE hiredate < ’01-jan-00′ AND salary > 50000;

SELECT last_name, hiredate, salaryFROM employees NATURAL JOIN salaryWHERE hiredate < ’01-jan-00′ AND salary > 50000;(*)

SELECT last_name, hiredate, salaryFROM employees (+) salaryWHERE hiredate < ’01-jan-00′ AND salary > 50000;

Incorrect

25.  The EMPLOYEES table includes these columns:EMPLOYEE_ID NUMBER(4) NOT NULL

Page 9: Test

LAST_NAME VARCHAR2(15) NOT NULLFIRST_NAME VARCHAR2(10) NOT NULLHIRE_DATE DATE NOT NULL

You want to produce a report that provides the first names, last names and hire dates of those employees who were hired between March 1, 2000, and August 30, 2000. Which statements can you issue to accomplish this task?Mark for Review(1) Points

SELECT last_name, first_name, hire_dateFROM employeesWHERE hire_date BETWEEN ’01-MAR-00′ AND ’30-AUG-00′;(*)

SELECT last_name, first_name, hire_dateFROM employeesWHERE hire_date BETWEEN ’30-AUG-00′ AND ’01-MAR-00′;

SELECT last_name, first_name, hire_dateFROM employeesGROUP BY hire_date >= ’01-MAR-00′ and hire_date <= ’30- AUG-00′;

SELECT last_name, first_name, hire_dateFROM employeesAND hire_date >= ’01-MAR-00′ and hire_date <= ’30-AUG- 00′;

Correct.

26.  You need to display all the values in the EMAIL column that contains the underscore (_) character as part of that email address. The WHERE clause in your SELECT statement contains the LIKE operator. What must you include in the LIKE operator?  Mark for Review(1) Points

The ESCAPE option (\) and one or more percent signs (%)

The (+) operator

A percent sign (%)

The ESCAPE option (\) (*)

Incorrect. See Section 17

27.  Evaluate this SELECT statement:SELECT *FROM employeesWHERE department_id IN(10, 20, 30)AND salary > 20000;

Page 10: Test

Which values would cause the logical condition to return TRUE?Mark for Review(1) Points

DEPARTMENT_ID = 10 and SALARY = 20000

DEPARTMENT_ID = 20 and SALARY = 20000

DEPARTMENT_ID = null and SALARY = 20001

DEPARTMENT_ID = 10 and SALARY = 20001 (*)

Correct. See Section 17

28.  If the EMPLOYEES table has the following columns, and you want to write a SELECT statement to return the employee last name and department number for employee number 176, which of the following SQL statements should you use?Name Type LengthEMPLOYEE_ID NUMBER 22FIRST_NAME VARCHAR2 20LAST_NAME VARCHAR2 25EMAIL VARCHAR2 25PHONE_NUMBER VARCHAR2 20SALARY NUMBER 22COMMISSION_PCT NUMBER 22MANAGER_ID NUMBER 22DEPARTMENT_ID NUMBER 22

Mark for Review(1) Points

SELECT last_name, department_idFROM employeesWHERE employee_id = 176;(*)

SELECT last_name, department_idFROM employeesWHERE employee_id equals 176;

SELECT first_name, employee_idFROM employeesWHERE employee_id = 176;

SELECT last_name, employee_idFROM employeesWHERE employee_id equals 176;

Correct.

Page 11: Test

29.  Evaluate this SELECT statement:SELECT last_name, first_name, salaryFROM employees;

How will the heading for the SALARY column appear in the display by default in Oracle Application Express?Mark for Review(1) Points

The heading will display with the first character capitalized and centered.

The heading will display with the first character capitalized and left justified.

The heading will display as uppercase and centered. (*)

The heading will display as uppercase and left justified.

Correct.

30.  You need write a SELECT statement that should only return rows that contain 34, 46, or 48 for the DEPARTMENT_ID column. Which operator should you use in the WHERE clause to compare the DEPARTMENT_ID column to this specific list of values?  Mark for Review(1) Points

=

!=

IN (*)

BETWEEN..AND..

Correct.

Page 3 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 17

31.  Which comparison operator searches for a specified character pattern?  Mark for Review(1) Points

IN

Page 12: Test

LIKE (*)

BETWEEN…AND…

IS NULL

Incorrect. See Section 17.

32.  What does the DISTINCT keyword do when it is used in a SELECT clause?  Mark for Review(1) Points

Hides NULL values

Eliminates all unique values and compares values

Eliminates duplicate rows in the result (*)

Eliminates only unique rows in the result

Incorrect. See Section 17

33.  Which symbol represents the not equal to condition?  Mark for Review(1) Points

#

‘+’

!= (*)

~

Correct.

34.  Which of the following elements cannot be included in a WHERE clause?  Mark for Review(1) Points

A column alias (*)

A column name

A comparison condition

A constant

Correct.

Page 13: Test

35.  Where in a SQL statement can you not use arithmetic operators?  Mark for Review(1) Points

SELECT

FROM (*)

WHERE

NONE

Incorrect. See Section 17.

36.  Which clause would you include in a SELECT statement to restrict the data returned to only the employees in department 10?  Mark for Review(1) Points

WHERE (*)

FROM

SELECT

IS

Correct.

Section 18

37.  Which of the following best describes the meaning of the LIKE operator?  Mark for Review(1) Points

Display rows based on a range of values.

To test for values in a list.

Match a character pattern. (*)

To find Null values.

Incorrect. See Section 18

38.  The ORDER BY clause always comes last. True or False?  Mark for Review(1) Points

True (*)

False

Page 14: Test

Correct.

39.  Which of the following is TRUE regarding the logical AND operator?  Mark for Review(1) Points

TRUE AND TRUE return FALSE

TRUE AND FALSE return TRUE

FALSE AND TRUE return NULL

TRUE AND FALSE return FALSE (*)

Incorrect. See Section 18

40.  Which clause would you include in a SELECT statement to sort the rows returned by the LAST_NAME column?  Mark for Review(1) Points

ORDER BY (*)

WHERE

FROM

HAVING

Incorrect. See Section 18

Page 4 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 18

41.  Which comparison condition means “Less Than or Equal To?”  Mark for Review(1) Points

“=)”

“+<”

“>=”

“<=” (*)

Page 15: Test

Correct.

42.  You need to change the default sort order of the ORDER BY clause so that the data is displayed in reverse alphabetical order. Which keyword should you include in the ORDER BY clause?  Mark for Review(1) Points

DESC (*)

ASC

SORT

CHANGE

Correct.

43.  What value will the following SQL statement return?SELECT employee_idFROM employeesWHERE employee_id BETWEEN 100 AND 150OR employee_id IN(119, 175, 205)AND (employee_id BETWEEN 150 AND 200);

Mark for Review(1) Points

19

No rows will be returned

100, 101, 102, 103, 104, 107, 124, 141, 142, 143, 144, 149 (*)

200, 201, 202, 203, 204, 205, 206

Correct.

44.  Which SELECT statement should you use to limit the display of product information to those products with a price of less than 50?  Mark for Review(1) Points

SELECT product_id, product_nameFROM productsWHERE price < 50;(*)

SELECT product_id, product_nameFROM productsHAVING price < 50;

Page 16: Test

SELECT product_id, product_nameFROM productsWHERE price <= 50;

SELECT product_id, product_nameFROM productsGROUP BY price < 50;

SELECT product_id, product_nameFROM productsWHERE price < 50.00GROUP BY price;

Correct.

45.  Evaluate this SELECT statement:SELECT last_name, first_name, department_id, manager_idFROM employees;

You need to sort data by manager id values and then alphabetically by employee last name and first name values. Which ORDER BY clause could you use?Mark for Review(1) Points

ORDER BY department_id, last_name

ORDER BY manager_id, last_name, first_name (*)

ORDER BY last_name, first_name, manager_id

ORDER BY manager_id, first_name, last_name

Correct.

46.  Evaluate this SELECT statement:SELECT *FROM employeesWHERE salary > 30000AND department_id = 10OR email IS NOT NULL;Which statement is true?Mark for Review(1) Points

The OR condition will be evaluated before the AND condition.

The AND condition will be evaluated before the OR condition. (*)

The OR and AND conditions have the same precedence and will be evaluated from left to right

Page 17: Test

The OR and AND conditions have the same precedence and will be evaluated from right to left

Correct.

47.  Evaluate this SELECT statement:SELECT last_name, first_name, emailFROM employeesORDER BY email;

If the EMAIL column contains null values, which statement is true?Mark for Review(1) Points

Null email values will be displayed first in the result.

Null email values will be displayed last in the result. (*)

Null email values will not be displayed in the result.

The result will not be sorted.

Incorrect! See Section 18.

48.  Evaluate this SELECT statement:SELECT *FROM employeesWHERE department_id = 34OR department_id = 45OR department_id = 67;

Which operator is the equivalent of the OR conditions used in this SELECT statement?Mark for Review(1) Points

IN (*)

AND

LIKE

BETWEEN … AND …

Correct.

49.  The PLAYERS table contains these columns:PLAYERS TABLE:LAST_NAME VARCHAR2 (20)FIRST_NAME VARCHAR2 (20)SALARY NUMBER(8,2)

Page 18: Test

TEAM_ID NUMBER(4)MANAGER_ID NUMBER(9)POSITION_ID NUMBER(4)You must display the player name, team id, and salary for players whose salary is in the range from 25000 through 100000 and whose team id is in the range of 1200 through 1500. The results must be sorted by team id from lowest to highest and then further sorted by salary from highest to lowest. Which statement should you use to display the desired result?Mark for Review(1) Points

SELECT last_name, first_name, team_id, salaryFROM playersWHERE (salary > 25000 OR salary < 100000)AND team_id BETWEEN 1200 AND 1500ORDER BY team_id, salary;

SELECT last_name, first_name, team_id, salaryFROM playersWHERE salary BETWEEN 25000 AND 100000AND team_id BETWEEN 1200 AND 1500ORDER BY team_id, salary DESC;(*)

SELECT last_name, first_name, team_id, salaryFROM playersWHERE salary > 24999.99 AND salary < 100000AND team_id BETWEEN 1200 AND 1500ORDER BY team_id ASC, salary DESC;

SELECT last_name, first_name, team_id, salaryFROM playersWHERE salary BETWEEN 24999.99 AND 100000.01AND team_id BETWEEN 1200 AND 1500ORDER BY team_id DESC, salary DESC;

Correct.

50.  Evaluate this SQL statement:SELECT e.employee_id, e.last_name, e.first_name, m.manager_idFROM employees e, employees mORDER BY e.last_name, e.first_nameWHERE e.employee_id = m.manager_id;

This statement fails when executed. Which change will correct the problem?Mark for Review(1) Points

Reorder the clauses in the query. (*)

Remove the table aliases in the WHERE clause.

Page 19: Test

Remove the table aliases in the ORDER BY clause.

Include a HAVING clause.

Incorrect! See Section 18.

Page 5 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 12

1.  In a physical data model, a relationship is represented as a combination of: (Choose Two)  Mark for Review(1) Points

(Choose all correct answers)

Column

Primary Key or Unique Key (*)

Check Constraint or Unique Key

Foreign Key (*)

Correct

2.  In a physical data model, an attribute becomes a _____________.  Mark for Review(1) Points

Table

Foreign Key

Constraint

Column (*)

Correct

3.  Why would this table name NOT work in an Oracle database? this_year_end+next_year  Mark for Review(1) Points

Page 20: Test

Table names must begin with an alphabetic character

Too long

The Plus sign + is not allowed in object names (*)

None of the above

Correct

4.  When mapping supertypes, relationships at the supertype level transform as usual. Relationships at subtype level are implemented as foreign keys, but the foreign key columns all become mandatory. True or False?  Mark for Review(1) Points

True

False (*)

Correct

5.  Which of the following are reasons why you should consider using a Subtype Implementation?  Mark for Review(1) Points

The resulting table will reside in a single database and be used by just ONE user.

When the common access paths for the supertypes are different.

Business functionality and business rules, access paths and frequency of access are all very different between subtypes. (*)

Most of the relationships are at the supertype level

Correct

6.  The Oracle Database can implement a many to many relationship. You simply create two foreign keys between the two tables. True or False?  Mark for Review(1) Points

True

False (*)

Correct

7.  It is possible to implement non-transferability via a simple Foreign Key Relationship. True or False?  Mark for Review(1) Points

Page 21: Test

True

False (*)

Incorrect. Refer to Section 12

8.  The text below is an example of what constraint type:The value in the manager_id column of the EMPLOYEES table must match a value in the employee_id column in the EMPLOYEES table.Mark for Review(1) Points

Entity integrity

User-defined integrity

Column integrity

Referential integrity (*)

Correct

9.  Entity integrity refers to  Mark for Review(1) Points

Tables always containing text data

Tables always containing numeric data

Columns having Primary Keys, Foreign Keys, Unique Keys and Check constraints defined in the database.

Tables having Primary Keys, Foreign Keys, Unique Keys and Check constraints defined in the database. (*)

Incorrect. Refer to Section 12

10.  Identify all of the incorrect statements that complete this sentence: A primary key is: (Choose three)  Mark for Review(1) Points

(Choose all correct answers)

A single column that uniquely identifies each column in a table (*)

One or more columns in a table that uniquely identifies each row in that table

A set of columns in one table that uniquely identifies each row in another table (*)

Only one column that must be null (*)

Page 22: Test

Incorrect. Refer to Section 12

Page 1 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 12

11.  The explanation below is a column integrity constraint:A column must contain only values consistent with the defined data format of the column. True or False?Mark for Review(1) Points

True (*)

False

Correct

Section 13

12.  The DESCRIBE command returns all rows from a table. True or False?  Mark for Review(1) Points

True

False (*)

Correct.

13.  What command can be used to create a new row in a table in the database?  Mark for Review(1) Points

CREATE

NEW

ADD

INSERT (*)

Correct.

Page 23: Test

Section 16

14.  In a SQL statement, which clause specifies one or more columns to be returned by the query?  Mark for Review(1) Points

SELECT (*)

FROM

WHERE

Any of the above options, you can list columns wherever you want to in a SELECT statement.

Incorrect. See Section 16

15.  Which SQL keyword specifies that an alias will be substituted for a column name in the output of a SQL query?  Mark for Review(1) Points

AS (*)

OR

AND

SUBSTITUTE

Correct.

16.  The SELECT statement retrieves information from the database. In a SELECT statement, you can do all of the following EXCEPT:  Mark for Review(1) Points

Projection

Manipulation (*)

Joining

Selection

Correct.

17.  When listing columns in the SELECT list, what should you use to separate the columns?  Mark for Review(1) Points

Commas (*)

Page 24: Test

Semicolons

Dashes

Underscores

Correct.

18.  In the default order of precedence, which operator would be evaluated first?  Mark for Review(1) Points

Subtractions

Multiplications (*)

Additions

Divisions

Correct.

19.  When you use the SELECT clause to list one or two columns only from a table and no WHERE clause, which SQL capability is used?  Mark for Review(1) Points

Joining only

Selection only

Projection only (*)

Projection and Selection

Incorrect. See Section 16

20.  In which clause of a SELECT statement would you specify the name of the table or tables being queried?  Mark for Review(1) Points

The FROM clause (*)

The SELECT clause

The WHERE clause

Any of the above options, you can list tables wherever you want to in a SELECT statement.

Incorrect. See Section 16

Page 25: Test

Page 2 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 16

21.  There is only one kind of software used by all computers. True or False?  Mark for Review(1) Points

True

False (*)

Correct.

22.  In a SELECT statement Additions are evaluated before Multiplications. True or False?  Mark for Review(1) Points

True

False (*)

Correct.

Section 17

23.  If the EMPLOYEES table has the following columns, and you want to write a SELECT statement to return the employee last name and department number for employee number 176, which of the following SQL statements should you use?Name Type LengthEMPLOYEE_ID NUMBER 22FIRST_NAME VARCHAR2 20LAST_NAME VARCHAR2 25EMAIL VARCHAR2 25PHONE_NUMBER VARCHAR2 20SALARY NUMBER 22COMMISSION_PCT NUMBER 22MANAGER_ID NUMBER 22DEPARTMENT_ID NUMBER 22

Mark for Review(1) Points

Page 26: Test

SELECT last_name, department_idFROM employeesWHERE employee_id = 176;(*)

SELECT last_name, department_idFROM employeesWHERE employee_id equals 176;

SELECT first_name, employee_idFROM employeesWHERE employee_id = 176;

SELECT last_name, employee_idFROM employeesWHERE employee_id equals 176;

Correct.

24.  You want to retrieve a list of customers whose last names begin with the letters Fr . Which symbol should you include in the WHERE clause of your SELECT statement to achieve the desired result?  Mark for Review(1) Points

% (*)

~

#

*

Correct. See Section 17

25.  Evaluate this SELECT statement:SELECT last_name, first_name, salaryFROM employees;

How will the heading for the SALARY column appear in the display by default in Oracle Application Express?Mark for Review(1) Points

The heading will display with the first character capitalized and centered.

The heading will display with the first character capitalized and left justified.

The heading will display as uppercase and centered. (*)

The heading will display as uppercase and left justified.

Page 27: Test

Correct.

26.  Which SELECT statement will display both unique and non-unique combinations of the MANAGER_ID and DEPARTMENT_ID values from the EMPLOYEES table?  Mark for Review(1) Points

SELECT manager_id, department_id DISTINCT FROM employees;

SELECT manager_id, department_id FROM employees; (*)

SELECT DISTINCT manager_id, department_id FROM employees;

SELECT manager_id, DISTINCT department_id FROM employees;

Incorrect. See Section 17.

27.  You need to display all the employees whose last name starts with the letters Sm . Which WHERE clause should you use?  Mark for Review(1) Points

WHERE last_name LIKE ‘Sm%’ (*)

WHERE last_name LIKE ‘%Sm’

WHERE last_name LIKE ‘_Sm’

WHERE last_name LIKE ‘Sm_’

Correct. See Section 17

28.  The STUDENT table contains these columns:STUDENT_ID NUMBER(10) Primary KeyLAST_NAME VARCHAR2(25)FIRST_NAME VARCHAR2(25)MAIN_SUBJECT_ID NUMBER(3)ADVISOR_ID NUMBER(5)

Evaluate this statement:SELECT DISTINCT advisor_id, main_subject_idFROM student;

Which statement is true?Mark for Review(1) Points

Each ADVISOR_ID can be displayed only once.

Each MAIN_SUBJECT_ID can be displayed more than once per ADVISOR_ID. (*)

Page 28: Test

Each combination of ADVISOR_ID and MAIN_SUBJECT_ID can be displayed more than once.

Each MAIN_SUBJECT_ID can be displayed only once per query.

Correct. See Section 17

29.  The EMPLOYEES table contains these columns:EMPLOYEE_ID NUMBER(9) PrimaryKeyLAST_NAME VARCHAR2 (20)FIRST_NAME VARCHAR2 (20)DEPARTMENT_ID NUMBER(5) NOT NULLMANAGER_ID NUMBER(9) NOT NULL

Evaluate these two SELECT statements:1. SELECT DISTINCT employee_id, department_id, manager_id FROM employees;2. SELECT employee_id, department_id, manager_id FROM employees;

Which of the following statements is true?Mark for Review(1) Points

The two statements will display the same data. (*)

The first statement will display a particular DEPARTMENT_ID only once.

The first statement will NOT display values from all of the rows in the EMPLOYEES table

The second statement could display a unique combination of the EMPLOYEE_ID, MANAGER_ID, and DEPARTMENT_ID values more than once.

Correct. See Section 17

30.  If you write queries using the BETWEEN operator it does not matter in what order you enter the values, i.e. BETWEEN low value AND high value will give the same result as BETWEEN high value and low value. True or False?  Mark for Review(1) Points

True

False (*)

Correct.

Page 3 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Page 29: Test

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 17

31.  Which comparison condition would you use to select rows that match a character pattern?  Mark for Review(1) Points

IN

LIKE (*)

ALMOST

SIMILAR

Incorrect. See Section 17.

32.  You need to display employees whose salary is in the range of 30000 and 50000. Which comparison operator should you use?  Mark for Review(1) Points

IN

LIKE

BETWEEN…AND… (*)

IS NULL

Correct.

33.  What does the DISTINCT keyword do when it is used in a SELECT clause?  Mark for Review(1) Points

Hides NULL values

Eliminates all unique values and compares values

Eliminates duplicate rows in the result (*)

Eliminates only unique rows in the result

Correct. See Section 17

34.  Which comparison operator searches for a specified character pattern?  Mark for Review(1) Points

IN

Page 30: Test

LIKE (*)

BETWEEN…AND…

IS NULL

Incorrect. See Section 17.

35.  Where in a SQL statement can you not use arithmetic operators?  Mark for Review(1) Points

SELECT

FROM (*)

WHERE

NONE

Correct.

36.  Which symbol represents the not equal to condition?  Mark for Review(1) Points

#

‘+’

!= (*)

~

Correct.

Section 18

37.  Evaluate this SQL statement:SELECT e.employee_id, e.last_name, e.first_name, m.manager_idFROM employees e, employees mORDER BY e.last_name, e.first_nameWHERE e.employee_id = m.manager_id;

This statement fails when executed. Which change will correct the problem?Mark for Review(1) Points

Reorder the clauses in the query. (*)

Remove the table aliases in the WHERE clause.

Page 31: Test

Remove the table aliases in the ORDER BY clause.

Include a HAVING clause.

Correct.

38.  The PLAYERS table contains these columns:PLAYERS TABLE:LAST_NAME VARCHAR2 (20)FIRST_NAME VARCHAR2 (20)SALARY NUMBER(8,2)TEAM_ID NUMBER(4)MANAGER_ID NUMBER(9)POSITION_ID NUMBER(4)You must display the player name, team id, and salary for players whose salary is in the range from 25000 through 100000 and whose team id is in the range of 1200 through 1500. The results must be sorted by team id from lowest to highest and then further sorted by salary from highest to lowest. Which statement should you use to display the desired result?Mark for Review(1) Points

SELECT last_name, first_name, team_id, salaryFROM playersWHERE (salary > 25000 OR salary < 100000)AND team_id BETWEEN 1200 AND 1500ORDER BY team_id, salary;

SELECT last_name, first_name, team_id, salaryFROM playersWHERE salary BETWEEN 25000 AND 100000AND team_id BETWEEN 1200 AND 1500ORDER BY team_id, salary DESC;(*)

SELECT last_name, first_name, team_id, salaryFROM playersWHERE salary > 24999.99 AND salary < 100000AND team_id BETWEEN 1200 AND 1500ORDER BY team_id ASC, salary DESC;

SELECT last_name, first_name, team_id, salaryFROM playersWHERE salary BETWEEN 24999.99 AND 100000.01AND team_id BETWEEN 1200 AND 1500ORDER BY team_id DESC, salary DESC;

Correct.

39.  Which statement about the default sort order is true?  Mark for Review(1) Points

Page 32: Test

The lowest numeric values are displayed last.

The earliest date values are displayed first. (*)

Null values are displayed first.

Character values are displayed in reverse alphabetical order.

Correct.

40.  The ORDER BY clause always comes last. True or False?  Mark for Review(1) Points

True (*)

False

Correct.

Page 4 of 5

Test: Final Exam Semester 1

Review your answers, feedback, and question scores below. An asterisk (*) indicates a correct answer.

Semester 1 Final Term Exam covers Sections 11-18 of Database Design.

Section 18

41.  Which logical operator returns TRUE if either condition is true?  Mark for Review(1) Points

OR (*)

AND

NOT

BOTH

Correct.

42.  Which comparison condition means “Less Than or Equal To?”  Mark for Review(1) Points

“=)”

“+<”

Page 33: Test

“>=”

“<=” (*)

Correct.

43.  Which of the following is TRUE regarding the logical AND operator?  Mark for Review(1) Points

TRUE AND TRUE return FALSE

TRUE AND FALSE return TRUE

FALSE AND TRUE return NULL

TRUE AND FALSE return FALSE (*)

Correct.

44.  Which statement about the ORDER BY clause is true?  Mark for Review(1) Points

You can use a column alias in the ORDER BY clause. (*)

The default sort order of the ORDER BY clause is descending.

The ORDER BY clause can only contain columns that are included in the SELECT list.

The ORDER BY clause should immediately precede the FROM clause in a SELECT statement

Correct.

45.  You query the database with this SQL statement:SELECT priceFROM productsWHERE price IN(1, 25, 50, 250)AND (price BETWEEN 25 AND 40 OR price > 50);

Which two values could the statement return? (Choose two.)Mark for Review(1) Points

(Choose all correct answers)

1

50

25 (*)

Page 34: Test

10

250 (*)

100

Correct.

46.  Evaluate this SQL statement:SELECT product_id, product_name, priceFROM productsORDER BY product_name, price;

What occurs when the statement is executed?Mark for Review(1) Points

The results are sorted numerically only.

The results are sorted alphabetically only.

The results are sorted numerically and then alphabetically.

The results are sorted alphabetically and then numerically. (*)

Correct.

47.  Evaluate this SELECT statement:SELECT last_name, first_name, emailFROM employeesORDER BY email;

If the EMAIL column contains null values, which statement is true?Mark for Review(1) Points

Null email values will be displayed first in the result.

Null email values will be displayed last in the result. (*)

Null email values will not be displayed in the result.

The result will not be sorted.

Correct.

48.  What value will the following SQL statement return?SELECT employee_idFROM employeesWHERE employee_id BETWEEN 100 AND 150

Page 35: Test

OR employee_id IN(119, 175, 205)AND (employee_id BETWEEN 150 AND 200);

Mark for Review(1) Points

19

No rows will be returned

100, 101, 102, 103, 104, 107, 124, 141, 142, 143, 144, 149 (*)

200, 201, 202, 203, 204, 205, 206

Correct.

49.  Which SELECT statement should you use to limit the display of product information to those products with a price of less than 50?  Mark for Review(1) Points

SELECT product_id, product_nameFROM productsWHERE price < 50;(*)

SELECT product_id, product_nameFROM productsHAVING price < 50;

SELECT product_id, product_nameFROM productsWHERE price <= 50;

SELECT product_id, product_nameFROM productsGROUP BY price < 50;

SELECT product_id, product_nameFROM productsWHERE price < 50.00GROUP BY price;

Correct.

50.  Evaluate this SELECT statement:SELECT *FROM employeesWHERE department_id = 34OR department_id = 45OR department_id = 67;

Page 36: Test

Which operator is the equivalent of the OR conditions used in this SELECT statement?Mark for Review(1) Points

IN (*)

AND

LIKE

BETWEEN … AND …

Correct.